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{"id":24295,"date":"2018-03-28T22:23:42","date_gmt":"2018-03-28T15:23:42","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24295"},"modified":"2018-03-28T22:35:35","modified_gmt":"2018-03-28T15:35:35","slug":"chuong-7-bai-38-luyen-tap-tinh-chat-hoa-hoc-cua-crom-dong-va-hop-chat-cua-chung","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-7-bai-38-luyen-tap-tinh-chat-hoa-hoc-cua-crom-dong-va-hop-chat-cua-chung\/","title":{"rendered":"Ch\u01b0\u01a1ng 7 – B\u00e0i 38: Luy\u1ec7n t\u1eadp: T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc c\u1ee7a crom, \u0111\u1ed3ng v\u00e0 h\u1ee3p ch\u1ea5t c\u1ee7a ch\u00fang"},"content":{"rendered":"

B\u00e0i 1 (trang 166 SGK H\u00f3a 12):\u00a0Ho\u00e0n th\u00e0nh ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ph\u1ea3n \u1ee9ng trong d\u00e3y chuy\u1ec3n \u0111\u1ed5i sau:<\/strong><\/p>\n

Cu \u2192 CuS \u2192 Cu(NO3<\/sub>)2<\/sub>\u00a0\u2192 Cu(OH)2<\/sub>\u00a0\u2192 CuCl2<\/sub>\u00a0\u2192 Cu.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Cu + S \u2192 CuS<\/p>\n

3CuS + 14HNO3<\/sub>\u00a0\u2192 3Cu(NO3<\/sub>)2<\/sub>\u00a0+3H2<\/sub>SO4<\/sub>\u00a0+ 8NO + 4H2<\/sub>O<\/p>\n

Cu(NO3<\/sub>)2<\/sub>\u00a0+ 2NaOH \u2192 Cu(OH)2<\/sub>\u00a0+ 2NaNO3<\/sub><\/p>\n

Cu(OH)2<\/sub>\u00a0+ 2HCl \u2192 CuCl2<\/sub>\u00a0+ 2H2<\/sub>O<\/p>\n

CuCl2<\/sub>\u00a0\u2192 Cu +Cl2<\/sub>.<\/p>\n

B\u00e0i 2 (trang 166 SGK H\u00f3a 12):\u00a0Khi cho 100 g h\u1ee3p kim g\u1ed3m c\u00f3 Fe, Cr v\u00e0 Al t\u00e1c d\u1ee5ng v\u1edbi l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch NaOH thu \u0111\u01b0\u1ee3c 6,72 l\u00edt kh\u00ed. L\u1ea5y b\u00e3 r\u1eafn kh\u00f4ng tan cho t\u00e1c d\u1ee5ng m\u1ed9t l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch HCl (khi kh\u00f4ng c\u00f3 kh\u00f4ng kh\u00ed) thu 38,08 l\u00edt kh\u00ed. C\u00e1c th\u1ec3 t\u00edch \u0111o \u1edf \u0111ktc. X\u00e1c \u0111\u1ecbnh th\u00e0nh ph\u1ea7n % c\u1ee7a h\u1ee3p kim.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc:<\/p>\n

2Al + 2NaOH \u2192 2NaAlO2<\/sub>\u00a0+ 3H2<\/sub>\u00a0(1)<\/p>\n

Ph\u1ea7n kh\u00f4ng tan l\u00e0 Fe v\u00e0 Cr<\/p>\n

Fe + 2HCl \u2192 FeCl2<\/sub>\u00a0+ H2<\/sub>\u00a0(2)<\/p>\n

Cr + 2HCl \u2192 CrCl2<\/sub>\u00a0+ H2<\/sub>\u00a0(3)<\/p>\n

S\u1ed1 mol H2<\/sub>\u00a0(1) nH2<\/sub>(1)= 6,72 \/ 22,4 = 0,3(mol)<\/p>\n

S\u1ed1 mol H2<\/sub>\u00a0(2), (3) l\u00e0 nH2<\/sub>\u00a0= 38,08 \/ 22,4 = 1,7(mol)<\/p>\n

G\u1ecdi x, y, z l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a Fe, Cr, Al<\/p>\n

Theo b\u00e0i ra ta c\u00f3 h\u1ec7 ph\u01b0\u01a1ng tr\u00ecnh<\/p>\n

56x + 52y + 27z = 100<\/p>\n

x+y=1,7<\/p>\n

3z\/2 = 0,3<\/p>\n

=> x=1,55 y=0,15 z=0,2.<\/p>\n

Th\u00e0nh ph\u1ea7n % theo kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a h\u1ed7n h\u1ee3p l\u00e0 :<\/p>\n

%mFe<\/sub>\u00a0= 1,55 x 56 \/ 100 x 100% = 86,8%<\/p>\n

%mCr<\/sub>\u00a0= 0,15 x 52 \/ 100 x 100% = 7,8%<\/p>\n

%mAl<\/sub>\u00a0= 0,2 x27 \/ 100 x 100% = 5,4%<\/p>\n

B\u00e0i 3 (trang 167 SGK H\u00f3a 12):\u00a0H\u1ed7n h\u1ee3p X g\u1ed3m Cu v\u00e0 Fe trong \u0111\u00f3 Cu chi\u1ebfm 43,24% kh\u1ed1i l\u01b0\u1ee3ng . Cho 14,8 gam X t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch HCl th\u1ea5y c\u00f3 V l\u00edt kh\u00ed (\u0111ktc) bay ra. Gi\u00e1 tr\u1ecb c\u1ee7a V l\u00e0:<\/strong><\/p>\n

A. 1,12 l\u00edt<\/p>\n

B. 2,24 l\u00edt<\/p>\n

C. 4,48 l\u00edt<\/p>\n

D. 3,36 l\u00edt<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n D.<\/p>\n

%Fe = 100% – 43,24% = 56,76%<\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Fe l\u00e0 mFe<\/sub>\u00a0= 14,8 x 56,76 \/ 100 = 8,4 (g)\u2192 nFe<\/sub>\u00a0= 8,4 \/ 56 = 0,15 (mol)<\/p>\n

Fe + 2HCl \u2192 FeCl2 + H2<\/sub><\/p>\n

Th\u1ec3 t\u00edch kh\u00ed H2<\/sub>: VH2<\/sub>\u00a0= 0,15 x 22,4 = 3,36 (lit)<\/p>\n

\n
\n

B\u00e0i 4 (trang 167 SGK H\u00f3a 12):\u00a0Kh\u1eed m gam b\u1ed9t CuO b\u1eb1ng kh\u00ed H2<\/sub>\u00a0\u1edf nhi\u1ec7t \u0111\u1ed9 cao thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p ch\u1ea5t r\u1eafn X. \u0110\u1ec3 h\u00f2a tan h\u1ebft X c\u1ea7n v\u1eeba \u0111\u1ee7 1 l\u00edt dung d\u1ecbch HNO3<\/sub>\u00a01M, thu \u0111\u01b0\u1ee3c 4,48 l\u00edt NO (\u0111ktc). Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng kh\u1eed CuO b\u1eb1ng bao nhi\u00eau?<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

A. 70%<\/p>\n

B. 75%<\/p>\n

C. 80%<\/p>\n

D. 85%<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

B\u00e0i 5 (trang 167 SGK H\u00f3a 12):\u00a0Nh\u00fang thanh s\u1eaft v\u00e0o dung d\u1ecbch CuSO4<\/sub>\u00a0sau m\u1ed9t th\u1eddi gian l\u1ea5y thanh s\u1eaft ra r\u1eeda s\u1ea1ch s\u1ea5y kh\u00f4 th\u1ea5y kh\u1ed1i l\u01b0\u1ee3ng t\u0103ng 1,2g. C\u00f3 bao nhi\u00eau gam Cu \u0111\u00e3 b\u00e1m v\u00e0o thanh s\u1eaft?<\/strong><\/p>\n

\n

A. 9,3 g.<\/p>\n

B. 9,4 g.<\/p>\n

C. 9,5 g.<\/p>\n

D. 9,6 g.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n D.<\/p>\n

G\u1ecdi x l\u00e0 s\u1ed1 mol Fe ph\u1ea3n \u1ee9ng<\/p>\n

Fe + CuSO4<\/sub>\u00a0\u2192 FeSO4<\/sub>\u00a0+ Cu<\/p>\n

1,2 = 64x \u2013 56x \u2192 x = 0,15<\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng Cu mCu<\/sub>\u00a0= 0,15 x 64 = 9,6 (g)<\/p>\n

B\u00e0i 6 (trang 167 SGK H\u00f3a 12):\u00a0Cho Cu t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch h\u1ed7n h\u1ee3p g\u1ed3m NaNO3<\/sub>v\u00e0 H2<\/sub>SO4<\/sub>\u00a0lo\u00e3ng s\u1ebd gi\u1ea3i ph\u00f3ng kh\u00ed n\u00e0o sau \u0111\u00e2y?<\/strong><\/p>\n

A. NO2<\/sub>.<\/p>\n

B. NO.<\/p>\n

C. N2<\/sub>O.<\/p>\n

D. NH3<\/sub>.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B.<\/p>\n

 <\/p>\n

<\/div>\n
\n

 <\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

<\/div>\n
\n
<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 166 SGK H\u00f3a 12):\u00a0Ho\u00e0n th\u00e0nh ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ph\u1ea3n \u1ee9ng trong d\u00e3y chuy\u1ec3n \u0111\u1ed5i sau: Cu \u2192 CuS \u2192 Cu(NO3)2\u00a0\u2192 Cu(OH)2\u00a0\u2192 CuCl2\u00a0\u2192 Cu. L\u1eddi gi\u1ea3i: Cu + S \u2192 CuS 3CuS + 14HNO3\u00a0\u2192 3Cu(NO3)2\u00a0+3H2SO4\u00a0+ 8NO + 4H2O Cu(NO3)2\u00a0+ 2NaOH \u2192 Cu(OH)2\u00a0+ 2NaNO3 Cu(OH)2\u00a0+ 2HCl \u2192 CuCl2\u00a0+ 2H2O CuCl2\u00a0\u2192 Cu […]<\/p>\n","protected":false},"author":3,"featured_media":24296,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1305],"tags":[1419,1420],"yoast_head":"\nCh\u01b0\u01a1ng 7 - B\u00e0i 38: Luy\u1ec7n t\u1eadp: T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc c\u1ee7a crom, \u0111\u1ed3ng v\u00e0 h\u1ee3p ch\u1ea5t c\u1ee7a ch\u00fang<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-7-bai-38-luyen-tap-tinh-chat-hoa-hoc-cua-crom-dong-va-hop-chat-cua-chung\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 7 - B\u00e0i 38: Luy\u1ec7n t\u1eadp: T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc c\u1ee7a crom, \u0111\u1ed3ng v\u00e0 h\u1ee3p ch\u1ea5t c\u1ee7a ch\u00fang\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 166 SGK H\u00f3a 12):\u00a0Ho\u00e0n th\u00e0nh ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ph\u1ea3n \u1ee9ng trong d\u00e3y chuy\u1ec3n \u0111\u1ed5i sau: Cu \u2192 CuS \u2192 Cu(NO3)2\u00a0\u2192 Cu(OH)2\u00a0\u2192 CuCl2\u00a0\u2192 Cu. L\u1eddi gi\u1ea3i: Cu + S \u2192 CuS 3CuS + 14HNO3\u00a0\u2192 3Cu(NO3)2\u00a0+3H2SO4\u00a0+ 8NO + 4H2O Cu(NO3)2\u00a0+ 2NaOH \u2192 Cu(OH)2\u00a0+ 2NaNO3 Cu(OH)2\u00a0+ 2HCl \u2192 CuCl2\u00a0+ 2H2O CuCl2\u00a0\u2192 Cu […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/chuong-7-bai-38-luyen-tap-tinh-chat-hoa-hoc-cua-crom-dong-va-hop-chat-cua-chung\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:published_time\" content=\"2018-03-28T15:23:42+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2018-03-28T15:35:35+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/bai-5-trang-165-sgk-hoa-12.png\" \/>\n\t<meta property=\"og:image:width\" content=\"532\" \/>\n\t<meta property=\"og:image:height\" content=\"313\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"H\u00e0 Trang\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"H\u00e0 Trang\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-7-bai-38-luyen-tap-tinh-chat-hoa-hoc-cua-crom-dong-va-hop-chat-cua-chung\/\",\"url\":\"https:\/\/lop12.edu.vn\/chuong-7-bai-38-luyen-tap-tinh-chat-hoa-hoc-cua-crom-dong-va-hop-chat-cua-chung\/\",\"name\":\"Ch\u01b0\u01a1ng 7 - 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