Ph\u00e2n t\u00edch:<\/em><\/strong><\/p>\n– Th\u00ed nghi\u1ec7m 1: X h\u1ebft, H2SO4 d\u01b0. Th\u00ed nghi\u1ec7m 2: Y h\u1ebft, NaOH d\u01b0. Th\u00ed nghi\u1ec7m 3: Z ph\u1ea3n \u1ee9ng ho\u00e0n to\u00e0n.<\/p>\n
– Kh\u00f4ng c\u1ea7n vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng m\u00e0 ch\u1ec9 c\u1ea7n x\u00e1c \u0111\u1ecbnh<\/p>\n
+ Dung d\u1ecbch Y g\u1ed3m FeSO4, MgSO4 v\u00e0 H2SO4 d\u01b0.<\/p>\n
+ K\u1ebft t\u1ee7a Z g\u1ed3m Fe(OH)2 v\u00e0 Mg(OH)2.<\/p>\n
+ Ch\u1ea5t r\u1eafn g\u1ed3m Fe2O3 v\u00e0 MgO (do nung trong kh\u00f4ng kh\u00ed n\u00ean thu \u0111\u01b0\u1ee3c s\u1eaft (III)).<\/p>\n
T\u00ednh to\u00e1n<\/em>: D\u00f9ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n nguy\u00ean t\u1ed1 \u00e1p d\u1ee5ng cho Fe v\u00e0 Mg (tr\u01b0\u1edbc th\u00ed nghi\u1ec7m \u0111\u1ea7u ti\u00ean v\u00e0 sau th\u00ed nghi\u1ec7m cu\u1ed1i c\u00f9ng):<\/p>\nn_(Fe_2 O_3 )=1\/2 n_Fe=0,1 (mol); n_MgO=n_Mg=0,1(mol)<\/p>\n
\u2192 mch\u1ea5tr\u1eafn = 160.0,1 + 40.0,4 = 20 (gam) \u2192 \u0110\u00e1p \u00e1n B.<\/p>\n
B\u00e0i 2<\/strong>\u00a0(tr\u00edch \u0111\u1ec1 thi kh\u1ed1i A-2008): \u0110un n\u00f3ng h\u1ed7n h\u1ee3p kh\u00ed X g\u1ed3m 0,06 mol C2H2 v\u00e0 0,04 mol H2 v\u1edbi x\u00fac t\u00e1c Ni, sau m\u1ed9t th\u1eddi gian thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p kh\u00ed Y. D\u1eabn to\u00e0n b\u1ed9 h\u1ed7n h\u1ee3p Y l\u1ed9i t\u1eeb t\u1eeb qua b\u00ecnh \u0111\u1ef1ng dung d\u1ecbch brom (d\u01b0) th\u00ec c\u00f2n l\u1ea1i 0,448 l\u00edt h\u1ed7n h\u1ee3p kh\u00ed Z (\u0111ktc) c\u00f3 t\u1ec9 kh\u1ed1i so v\u1edbi O2 l\u00e0 0,5. Kh\u1ed1i l\u01b0\u1ee3ng b\u00ecnh dung d\u1ecbch brom t\u0103ng l\u00e0<\/p>\nA. 1,04 gam. B. 1,64 gam. C. 1,32 gam. D. 1,20 gam.<\/p>\n
Ph\u00e2n t\u00edch:<\/em><\/strong><\/p>\n– Th\u00ed nghi\u1ec7m 1: C\u00f3 th\u1ec3 x\u1ea3y ra kh\u00f4ng ho\u00e0n to\u00e0n v\u00ec c\u00f3 c\u1ee5m t\u1eeb \u201cm\u1ed9t th\u1eddi gian\u201d n\u00ean Y ch\u1ee9a t\u1ed1i \u0111a 4 ch\u1ea5t. Th\u00ed nghi\u1ec7m 2: Ch\u1ea5t n\u00e0o trong Y ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch brom th\u00ec s\u1ebd h\u1ebft v\u00ec brom d\u01b0.<\/p>\n
– Kh\u00f4ng c\u1ea7n vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng v\u00ec n\u1ebfu vi\u1ebft th\u00ec ph\u1ea3i c\u00f3 2 ph\u1ea3n \u1ee9ng \u1edf th\u00ed nghi\u1ec7m 1 v\u00e0 2 ph\u1ea3n \u1ee9ng \u1edf th\u00ed nghi\u1ec7m 2. Khi \u0111\u00f3 t\u00ednh to\u00e1n s\u1ebd kh\u00f3 kh\u0103n h\u01a1n.<\/p>\n
T\u00ednh to\u00e1n<\/em>: mdung d\u1ecbch brom t\u0103ng = mY v\u00e0o \u2013 mZ ra<\/p>\n\u1ede th\u00ed nghi\u1ec7m 1: mY = mX<\/p>\n
\u2192 mdung d\u1ecbch brom t\u0103ng = (26.0,06 + 2.0,04) \u2013 32.0,5.0,02 = 1,32 (gam)<\/p>\n
\u2192 \u0110\u00e1p \u00e1n C.<\/p>\n
B\u00e0i 3<\/strong>\u00a0(tr\u00edch \u0111\u1ec1 thi kh\u1ed1i B-2010):H\u1ed7n h\u1ee3p X g\u1ed3m CuO v\u00e0 Fe2O3 v\u00e0 FeO. Ho\u00e0 tan ho\u00e0n to\u00e0n 22 gam X b\u1eb1ng dung d\u1ecbch HCl (d\u01b0), sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c dung d\u1ecbch ch\u1ee9a 42,625 gam mu\u1ed1i. M\u1eb7t kh\u00e1c, n\u1ebfu kh\u1eed ho\u00e0n to\u00e0n 22 gam X b\u1eb1ng CO (d\u01b0), cho h\u1ed7n h\u1ee3p kh\u00ed thu \u0111\u01b0\u1ee3c sau ph\u1ea3n \u1ee9ng l\u1ed9i t\u1eeb t\u1eeb qua dung d\u1ecbch Ba(OH)2(d\u01b0) th\u00ec thu \u0111\u01b0\u1ee3c m gam k\u1ebft t\u1ee7a. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0<\/p>\nA. 76,755. B.78,875. C. 147,750. D. 73,875.<\/p>\n
Ph\u00e2n t\u00edch:<\/em><\/strong><\/p>\n– Th\u00ed nghi\u1ec7m 1: X h\u1ebft v\u00ec HCl d\u01b0, th\u00ed nghi\u1ec7m 2: X h\u1ebft v\u00ec CO d\u01b0, th\u00ed nghi\u1ec7m 3: CO2 h\u1ebft v\u00ec Ba(OH)2 d\u01b0.<\/p>\n
– Th\u00ed nghi\u1ec7m 1 x\u1ea3y ra ph\u1ea3n \u1ee9ng trao \u0111\u1ed5i v\u00e0 thay O^(2-)b\u1eb1ngCl^- n\u00ean s\u1ebd d\u00f9ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n \u0111i\u1ec7n t\u00edch.<\/p>\n
– Th\u00ed nghi\u1ec7m 3 s\u1ebd d\u00f9ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n nguy\u00ean t\u1ed1 cacbon.<\/p>\n
– Theo c\u00e1c ph\u00e2n t\u00edch tr\u00ean th\u00ec kh\u00f4ng c\u1ea7n vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng v\u00ec n\u1ebfu vi\u1ebft th\u00ec b\u00e0i n\u00e0y c\u1ea7n c\u00f3 7 ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng.<\/p>\n
T\u00ednh to\u00e1n:<\/em><\/p>\n\u0110\u1eb7t s\u1ed1 mol O^(2-)trong X l\u00e0 a (mol) \u2192 s\u1ed1 mol Cl^- trong mu\u1ed1i l\u00e0 2a (mol)<\/p>\n
Th\u00ed nghi\u1ec7m 1: mmu\u1ed1i \u2013 mX = 35,5.2a \u2013 16.a = 42,625 \u2013 22 \u2192 a = 0,375<\/p>\n
Th\u00ed nghi\u1ec7m 2 v\u00e0 3: Do CO + O^(2-)\u2192 CO2 + 2e<\/p>\n
\u3016N\u00ean n\u3017_(BaCO_3 )=n_(CO_2 )=n_CO=n_(O^(2-) )= 0,375 (mol) \u2192 m_(BaCO_3 )= 197.0,375 = 73,875 (gam)<\/p>\n
\u2192 \u0110\u00e1p \u00e1n D.<\/p>\n
B\u00e0i 4<\/strong>\u00a0(tr\u00edch \u0111\u1ec1 thi kh\u00f4i A-2011):Ho\u00e0 tan h\u1ed7n h\u1ee3p b\u1ed9t g\u1ed3m m gam Cu v\u00e0 4,64 gam Fe3O4v\u00e0o dung d\u1ecbch H2SO4lo\u00e3ng, r\u1ea5t d\u01b0. Sau khi c\u00e1c ph\u1ea3n \u1ee9ng k\u1ebft th\u00fac, ch\u1ec9 thu \u0111\u01b0\u1ee3c dung d\u1ecbch X. Dung d\u1ecbch X ph\u1ea3n \u1ee9ng v\u1eeba \u0111\u1ee7 100 ml dung d\u1ecbch KMnO40,1M. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0<\/p>\nA. 0,96. B. 0,64. C. 3,2. D. 1,24.<\/p>\n
Ph\u00e2n t\u00edch:<\/em><\/strong><\/p>\n– Th\u00ed nghi\u1ec7m 1: H\u1ed7n h\u1ee3p h\u1ebft v\u00ec H2SO4 d\u01b0. Tuy nhi\u00ean, ta ch\u01b0a bi\u1ebft mu\u1ed1i s\u1eaft thu \u0111\u01b0\u1ee3c l\u00e0 s\u1eaft (II) hay c\u1ea3 s\u1eaft (III) v\u00ec ch\u01b0a bi\u1ebft s\u1ed1 mol Cu. Th\u00ed nghi\u1ec7m 2: X v\u00e0 KMnO4 \u0111\u1ec1u h\u1ebft v\u00ec c\u00f3 c\u1ee5m t\u1eeb \u201cv\u1eeba \u0111\u1ee7\u201d.<\/p>\n
– B\u00e0i n\u00e0y c\u00f3 hai th\u00ed nghi\u1ec7m \u1edf d\u1ea1ng chu\u1ed7i n\u00ean g\u1ed9p 2 th\u00ed nghi\u1ec7m th\u00e0nh 1 th\u00ed nghi\u1ec7m nh\u01b0 sau:<\/p>\n
H\u1ed7n h\u1ee3p \u0111\u1ea7u + dung d\u1ecbch H2SO4 d\u01b0 + dung d\u1ecbch KMnO4\u2192 Dung d\u1ecbch ch\u1ee9a CuSO4, Fe2(SO4)3, K2SO4, MnSO4 v\u00e0 H2SO4 d\u01b0.<\/p>\n
– KMnO4 trong trong m\u00f4i tr\u01b0\u1eddng axit l\u00e0 ch\u1ea5t oxi ho\u00e1 m\u1ea1nh n\u00ean s\u1ebd \u0111\u01b0a s\u1eaft l\u00ean s\u1ed1 oxi ho\u00e1 +3, c\u00f2n Mn chuy\u1ec3n v\u1ec1 s\u1ed1 oxi ho\u00e1 +2. V\u00ec v\u1eady, kh\u00f4ng c\u1ea7n vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng m\u00e0 d\u00f9ng c\u00f4ng th\u1ee9c c\u1ee7a \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n electron cho th\u00ed nghi\u1ec7m g\u1ed9p.<\/p>\n
T\u00ednh to\u00e1n:<\/em><\/p>\nD\u00f9ng c\u00f4ng th\u1ee9c c\u1ee7a \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n electron cho th\u00ed nghi\u1ec7m g\u1ed9p nh\u01b0 sau:<\/p>\n
\u30162n\u3017_Cu+n_(Fe_3 O_4 )=\u30165n\u3017_(KMnO_4 )\u2192 n_Cu=\u3016\u30161\/2(5n\u3017_(KMnO_4 )-n\u3017_(Fe_3 O_4 ))=0,015 (mol)<\/p>\n
\u2192 m = 64.0,015 = 0,96 (gam) \u2192 \u0110\u00e1p \u00e1n A.<\/p>\n
B\u00e0i 5<\/strong>: Chia 29,8 gam h\u1ed7n h\u1ee3p X g\u1ed3m Mg, Na, K v\u00e0 Ca th\u00e0nh 2 ph\u1ea7n b\u1eb1ng nhau. Ph\u1ea7n 1 t\u00e1c d\u1ee5ng ho\u00e0n to\u00e0n v\u1edbi dung d\u1ecbch HNO3 lo\u00e3ng, thu \u0111\u01b0\u1ee3c 1,568 l\u00edt kh\u00ed N2 duy nh\u1ea5t (\u0111ktc). Ph\u1ea7n 2 t\u00e1c d\u1ee5ng ho\u00e0n to\u00e0n v\u1edbi oxi, thu \u0111\u01b0\u1ee3c y gam h\u1ed7n h\u1ee3p 4 oxit. Gi\u00e1 tr\u1ecb c\u1ee7a y l\u00e0<\/p>\nA. 20,5. B. 35,4. C. 26,1. D. 41,0.<\/p>\n
Ph\u00e2n t\u00edch:<\/em><\/strong><\/p>\n– C\u1ea3 hai th\u00ed nghi\u1ec7m, X \u0111\u1ec1u ph\u1ea3n \u1ee9ng h\u1ebft v\u00ec c\u00f3 c\u1ee5m t\u1eeb \u201cho\u00e0n to\u00e0n\u201d.<\/p>\n
– Hai th\u00ed nghi\u1ec7m n\u00e0y \u0111\u1ed9c l\u1eadp, tho\u1ea3 m\u00e3n c\u1ea3 2 \u0111i\u1ec1u ki\u1ec7n c\u1ee7a ki\u1ec3u 3 (m\u1ee5c 2.d) n\u00ean c\u00f3 th\u1ec3 d\u00f9ng c\u00f4ng th\u1ee9c t\u01b0\u01a1ng \u1ee9ng trong m\u1ee5c 2.d. S\u1ed1 mol electron \u1edf th\u00ed nghi\u1ec7m 1 t\u00ednh theo s\u1ea3n ph\u1ea9m l\u00e0 N2, c\u00f2n s\u1ed1 mol electron \u1edf th\u00ed nghi\u1ec7m 2 t\u00ednh theo ch\u1ea5t tham gia l\u00e0 O2.<\/p>\n
– Kh\u00f4ng c\u1ea7n vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng v\u00ec n\u1ebfu vi\u1ebft th\u00ec \u1edf m\u1ed7i th\u00ed nghi\u1ec7m c\u00f3 t\u1edbi 4 ph\u1ea3n \u1ee9ng.<\/p>\n
T\u00ednh to\u00e1n<\/em>: Ta c\u00f3: ne th\u00ed nghi\u1ec7m 1 = ne th\u00ed nghi\u1ec7m 2\u2192\u3016 10n\u3017_(N_2 )=4n_(O_2 )\u2192n_(O_2 )=0,175 (mol)<\/p>\n\u1ede th\u00ed nghi\u1ec7m 2, d\u00f9ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n kh\u1ed1i l\u01b0\u1ee3ng:<\/p>\n
y=m_(ph\u1ea7n 2) + m_(O_2 ) = 29,8\/2+ 32.0,175 = 20,5(gam)<\/p>\n
\u2192 \u0110\u00e1p \u00e1n A.<\/p>\n
V\u1edbi c\u00e1ch ph\u00e2n t\u00edch v\u00e0 t\u00ednh to\u00e1n \u0111\u01b0\u1ee3c tr\u00ecnh b\u00e0y \u1edf tr\u00ean th\u00ec vi\u1ec7c gi\u1ea3i b\u00e0i t\u1eadp h\u00f3a h\u1ecdc s\u1ebd r\u1ea5t nhanh, ch\u00ednh x\u00e1c v\u00e0 \u0111\u1ea3m b\u1ea3o \u0111\u01b0\u1ee3c y\u00eau c\u1ea7u v\u1ec1 th\u1eddi gian c\u1ee7a m\u1ed9t \u0111\u1ec1 thi tr\u1eafc nghi\u1ec7m.<\/p>\n<\/div>\n<\/div>\n
Theo TS D\u01b0\u01a1ng Quang Hu\u1ea5n<\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n <\/p>\n","protected":false},"excerpt":{"rendered":"
\u0110\u1ec3 c\u00f3 th\u1ec3 l\u00e0m t\u1ed1t c\u00e1c b\u00e0i t\u1eadp trong \u0111\u1ec1 thi THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n H\u00f3a theo TS. D\u01b0\u01a1ng Quang Hu\u1ea5n – Tr\u01b0\u1eddng \u0110\u1ea1i h\u1ecdc S\u01b0 ph\u1ea1m H\u00e0 N\u1ed9i 2 h\u01b0\u1edbng d\u1eabn c\u00e1c th\u00ed sinh c\u00e1ch ph\u00e2n t\u00edch, t\u00ednh to\u00e1n cho h\u1ecdc sinh \u0111\u1ea1t hi\u1ec7u qu\u1ea3 h\u01a1n khi l\u00e0m b\u00e0i t\u1eadp. B\u00e0i 1\u00a0(tr\u00edch […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[159],"tags":[],"yoast_head":"\n
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