\n\u0110\u1ed3 th\u1ecb<\/td>\n | L\u1ed3i<\/td>\n | <\/td>\n | \u0111i\u1ec3m u\u1ed1n u(1; -1)<\/td>\n | <\/td>\n | l\u00f5m<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n H\u00e0m s\u1ed1 l\u1ed3i tr\u00ean kho\u1ea3ng (-\u221e;1)<\/p>\n H\u00e0m s\u1ed1 l\u00f5m tr\u00ean kho\u1ea3ng (1; +\u221e)<\/p>\n H\u00e0m s\u1ed1 c\u00f3 1 \u0111i\u00eam u\u1ed1n u(1; -1)<\/p>\n B\u1ea3ng bi\u1ebfn thi\u00ean.<\/p>\n <\/p>\n \u2022 \u0110\u1ed3 th\u1ecb<\/p>\n Giao v\u1edbi Oy (0; 1)<\/p>\n <\/p>\n b) x3<\/sup>-3x2<\/sup>+m+2=0\uf0f3 x3<\/sup>-3x2<\/sup>+1=-1-m (2)<\/p>\nS\u1ed1 nghi\u1ec7m c\u1ee7a Ph\u01b0\u01a1ng tr\u00ecnh (2) l\u00e0 s\u1ed1 giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb y=x3<\/sup>-3x2<\/sup>+1 v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng y = -1 \u2013 m.<\/p>\nD\u1ef1a v\u00e0o \u0111\u1ed3 th\u1ecb \u1edf c\u00e2u a) ta c\u00f3:<\/p>\n – N\u1ebfu -1-m > 1<=> m < -2 ph\u01b0\u01a1ng tr\u00ecnh (2) c\u00f3 1 nghi\u1ec7m.<\/p>\n – N\u1ebfu -1-m=1 <=> m = -2: Ph\u01b0\u01a1ng tr\u00ecnh (2) c\u00f3 2 nghi\u1ec7m.<\/p>\n – N\u1ebfu -3 < -1-m < 1 <=> -2 < m < 2: Ph\u01b0\u01a1ng tr\u00ecnh (2) c\u00f3 3 nghi\u1ec7m<\/p>\n – N\u1ebfu -1-m < -3 <=> m > 2: Ph\u01b0\u01a1ng tr\u00ecnh (2) c\u00f3 1 nghi\u1ec7m<\/p>\n K\u1ebft lu\u1eadn:<\/p>\n <\/p>\n -2 < m,2. Ph\u01b0\u01a1ng tr\u00ecnh (2) c\u00f3 3 nghi\u1ec7m<\/p>\n B\u00e0i 46 (trang 44 sgk Gi\u1ea3i T\u00edch 12 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\nCho h\u00e0m s\u1ed1 y=(x+1)(x2<\/sub>+2mx+m+2)<\/p>\na) T\u00ecm c\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a m \u0111\u1ec3 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00e3 cho c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i 3 \u0111i\u1ec3m ph\u00e2n bi\u1ec7t.<\/p>\n b) Kh\u1ea3o s\u00e1t v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi m = -1<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a) Ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (Cm<\/sub>) v\u1edbi tr\u1ee5c ho\u00e0nh l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n<\/p>\n \u0110\u1eb7t f(x) = x2<\/sup>+2mx+m+2<\/p>\n\u0110\u1ec3 \u0111\u1ed3 th\u1ecb h\u00e0m s\u00f3 (Cm<\/sub>\u00a0) c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i 3 \u0111i\u1ec3m ph\u00e2n bi\u1ec7t th\u00ec ph\u01b0\u01a1ng tr\u00ecnh f(x) = 0 ph\u1ea3i c\u00f3 2 nghi\u1ec7m ph\u00e2n bi\u1ec7t x1<\/sub>,x2<\/sub>\u00a0kh\u00e1c -1.<\/p>\n<\/p>\n V\u1eady v\u1edbi m th\u00f5a m\u00e3n (*) th\u00ec \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 Cm<\/sub>\u00a0c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i 3 \u0111i\u1ec3m ph\u00e2n bi\u1ec7t.<\/p>\nb) V\u1edbi m = -1. Ta c\u00f3: y=(x+1)(x2<\/sup>-2x+1)=x3<\/sup>-x2<\/sup>-x+1<\/p>\nTX\u0110: R<\/p>\n <\/p>\n B\u1ea3ng x\u00e9t d\u1ea5u y\u2019\u2019<\/p>\n \n\n\nX<\/td>\n | -\u221e<\/td>\n | <\/td>\n | 0<\/td>\n | <\/td>\n | +\u221e<\/td>\n<\/tr>\n | \nY\u2019\u2019<\/td>\n | <\/td>\n | –<\/td>\n | 0<\/td>\n | +<\/td>\n | <\/td>\n<\/tr>\n | \n\u0110\u1ed3 th\u1ecb<\/td>\n | L\u1ed3i<\/td>\n | <\/td>\n | \u0111i\u1ec3m u\u1ed1n u(1\/3;16\/27)<\/td>\n | <\/td>\n | l\u00f5m<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n H\u00e0m s\u1ed1 l\u1ed3i tr\u00ean kho\u1ea3ng (-\u221e;1\/3)<\/p>\n H\u00e0m s\u1ed1 l\u00f5m tr\u00ean kho\u1ea3ng (1\/3; +\u221e)<\/p>\n H\u00e0m s\u1ed1 c\u00f3 1 \u0111i\u1ec3m u\u1ed1n (1\/3;16\/27)<\/p>\n B\u1ea3ng bi\u1ebfn thi\u00ean<\/p>\n <\/p>\n \u2022 \u0110\u1ed3 th\u1ecb<\/p>\n Giao v\u1edbi Ox(-1; 0); (1; 0) giao v\u1edbi Oy (0; 1) \u0111i qua (2; 3)<\/p>\n <\/p>\n B\u00e0i 47 (trang 45 sgk Gi\u1ea3i T\u00edch 12 12 n\u00e2ng cao):<\/b><\/span><\/p>\nCho h\u00e0m s\u1ed1 y=x4<\/sup>-(m+1) x2<\/sup>+m<\/p>\na) Kh\u1ea3o s\u00e1t v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi m = 2.<\/p>\n b) CMR \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00e3 cho lu\u00f4n \u0111i qua hai \u0111i\u1ec3m c\u1ed1 \u0111\u1ecbnh v\u1edbi m\u1ecdi gi\u00e1 tr\u1ecb c\u1ee7a m.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a) V\u1edbi m = 2 ta c\u00f3: y=x4<\/sup>-3x2<\/sup>+2<\/p>\nTX\u0110: R<\/p>\n y’=4x3<\/sup>-6x=0 <=> 4x(2x3<\/sup>-3 )=0<\/p>\n<\/p>\n B\u1ea3ng x\u00e9t d\u1ea5u y\u2019\u2019<\/p>\n <\/p>\n B\u1ea3ng bi\u00ean thi\u00ean<\/p>\n <\/p>\n \u0110\u1ed3 th\u1ecb \u0111i qua (1; 0); (-1; 0) (-\u221a2;0),(\u221a2;0),(0;2)<\/p>\n <\/p>\n b) Gi\u1ea3 s\u1eed \u0111i\u1ec3m M(x0<\/sub>;y0<\/sub>) l\u00e0 \u0111i\u1ec3m c\u1ed1 \u0111\u1ecbnh m\u00e0 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00e3 cho lu\u00f4n di qua v\u1edbi m\u1ecdi m.<\/p>\nTa c\u00f3:<\/p>\n <\/p>\n V\u1eady h\u00e0m s\u1ed1 \u0111\u00e3 cho lu\u00f4n \u0111i qua 2 \u0111i\u1ec3m c\u1ed1 \u0111\u1ecbnh: M1<\/sub>\u00a0(-1;0);M2<\/sub>\u00a0(1;0)<\/p>\nB\u00e0i 48 (trang 45 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/span><\/p>\nCho h\u00e0m s\u1ed1 y=x4<\/sup>-2mx2<\/sup>+2m<\/p>\na) T\u00ecm c\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a m sao cho h\u00e0m s\u1ed1 c\u00f3 3 c\u1ef1c tr\u1ecb.<\/p>\n b) Kh\u1ea3o s\u00e1t v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 v\u1edbi m=1\/2. Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb t\u1ea1i 2 \u0111i\u1ec3m u\u1ed1n.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a) Ta c\u00f3 y’=4x3<\/sup>-4mx=4x(x2<\/sup>-m)<\/p>\n\u0110\u1ec3 h\u00e0m s\u1ed1 \u0111\u00e3 cho c\u00f3 3 c\u1ef1c tr\u1ecb th\u00ec Ph\u01b0\u01a1ng tr\u00ecnh y\u2019=0 c\u00f3 3 nghi\u1ec7m ph\u00e2n bi\u1ec7t.<\/p>\n <\/p>\n V\u1eady v\u1edbi m > 0 th\u00ec h\u00e0m s\u1ed1 \u0111\u00e3 cho c\u00f3 3 \u0111i\u1ec3m c\u1ef1c tr\u1ecb.<\/p>\n V\u1edbi m=1\/2 ta c\u00f3 y=x4<\/sup>-x2<\/sup>+1<\/p>\nTX\u0110: R<\/p>\n <\/p>\n B\u1ea3ng x\u00e9t d\u1ea5u y\u2019\u2019<\/p>\n <\/p>\n B\u1ea3ng bi\u1ebfn thi\u00ean<\/p>\n <\/p>\n \u0110\u1ed3 th\u1ecb \u0111i qua (0; 1)<\/p>\n <\/p>\n \n <\/div>\n<\/div>\n – y=x4<\/sup>-x2<\/sup>+1<\/p>\nH\u00e0m s\u1ed1 c\u00f3 2 \u0111i\u1ec3m u\u1ed1n l\u00e0<\/p>\n <\/p>\n Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m u\u1ed1n<\/p>\n <\/p>\n Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m u\u1ed1n<\/p>\n <\/p>\n V\u1eady 2 ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m u\u1ed1n l\u00e0:<\/p>\n <\/p>\n \n <\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 45 (trang 44 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao): a) Kh\u1ea3o s\u00e1t v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 sau: y=x3-3×2+1 b) T\u00f9y theo c\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a m h\u00e3y bi\u1ec7n lu\u1eadn s\u1ed1 nghi\u1ec7m c\u1ee7a Ph\u01b0\u01a1ng tr\u00ecnh x3-3×2+m+2=0 L\u1eddi gi\u1ea3i: a) TX\u0110: R y’=3×2-6x=3x(x-2)=0 y’> 0 tr\u00ean kho\u1ea3ng (-\u221e;0)\u222a(2; +\u221e) y’ < 0 tr\u00ean kho\u1ea3ng […]<\/p>\n","protected":false},"author":3,"featured_media":23849,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1302],"tags":[1392,1393],"yoast_head":"\n \u0110\u1ea1i s\u1ed1 - Ch\u01b0\u01a1ng 1 - Luy\u1ec7n t\u1eadp (trang 44-45)<\/title>\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n\n\n\n\t\n\t\n\t\n | |