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B\u00e0i 53 (trang 50 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/span><\/p>\n

a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n

b) Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00e3 cho t\u1ea1i giao \u0111i\u1ec3m c\u1ee7a A v\u1edbi tr\u1ee5c tung.<\/p>\n

c) Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb song song v\u1edbi ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m A.<\/p>\n

V\u1eady h\u00e0m s\u1ed1 \u0111\u00e3 cho lu\u00f4n ngh\u1ecbch bi\u1ebfn tr\u00ean (-\u221e,2) v\u00e0 (2; +\u221e)<\/p>\n

b) A l\u00e0 giao \u0111i\u1ec3m c\u1ee7a tr\u1ee5c tung n\u00ean A(0; 1\/2) Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn t\u1ea1i A c\u00f3 d\u1ea1ng<\/p>\n

c) G\u1ecdi \u0394 l\u00e0 Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn song song v\u1edbi d n\u00ean \u0394 c\u00f3 h\u1ec7 s\u1ed1<\/p>\n

=> Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn \u0394 c\u00f3 d\u1ea1ng<\/p>\n

V\u00ec \u0394 l\u00e0 ti\u1ebfp tuy\u1ebfn c\u1ee7a (C) n\u00ean ta c\u00f3:<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng \u0394 l\u00e0:<\/p>\n

B\u00e0i 54 (trang 50 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/span><\/p>\n

a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb H c\u1ee7a h\u00e0m s\u1ed1<\/p>\n

b) T\u1eeb \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 (H) suy ra c\u00e1ch v\u1ebd \u0111\u1ed3 th\u1ecb<\/p>\n

H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean kho\u1ea3ng (-\u221e; -1) v\u00e0 (-1; +\u221e)<\/p>\n

V\u1eady \u0111\u01b0\u1eddng th\u1eb3ng x = -1 l\u00e0 ti\u1ec7m c\u1eadn \u0111\u1ee9ng.<\/p>\n

V\u1eady \u0111\u01b0\u1eddng th\u1eb3ng y = 1 l\u00e0 ti\u1ec7m c\u1eadn ngang.<\/p>\n

=> C\u00e1ch v\u1ebd \u0111\u1ed3 th\u1ecb (C): \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u1ed1i x\u1ee9ng v\u1edbi (H) qua tr\u1ee5c ho\u00e0nh.<\/p>\n

B\u00e0i 55 (trang 50 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/span><\/p>\n

a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n

b) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 d\u00e1 cho bi\u1ebft r\u1eb1ng ti\u1ebfp tuy\u1ebfn \u0111\u00f3 \u0111i qua \u0111i\u1ec3m A(3; 3)<\/p>\n

V\u1eady h\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean (-\u221e;1)v\u00e0 (1; +\u221e)<\/p>\n

V\u1eady \u0111\u01b0\u1eddng th\u1eb3ng x = 1 l\u00e0 ti\u1ec7m c\u1eadn \u0111\u1ee9ng.<\/p>\n

b) G\u1ecdi Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng (d) c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c k \u0111i qua A(3; 3) c\u00f3 d\u1ea1ng y-3=k(x-3) <=> y=k(x-3)+3<\/p>\n

(d) l\u00e0 ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 khi v\u00e0 ch\u1ec9 khi h\u1ec7 Ph\u01b0\u01a1ng tr\u00ecnh sau c\u00f3 nghi\u1ec7m\u201d<\/p>\n

(*) => (x^{2<\/sup>-x-2)(x-1)=(x^{2<\/sup>-2x+3)(x-3)+3(x-1)^{2<\/sup><\/p>\n}}}

V\u1edbi x = 2 => k = 3. V\u1eady ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn l\u00e0<\/p>\n

\n
B\u00e0i 56 (trang 50 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/span><\/p>\n
a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb (C) c\u1ee7a h\u00e0m s\u1ed1<\/p>\n
$\"\"$ <\/p>\n
b) T\u1eeb \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00e3 cho suy ra c\u00e1ch v\u1ebd \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1<\/p>\n
$\"\"$ <\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) TX\u0110: D = R \\ {-1}<\/p>\n
$\"\"$ <\/p>\n
H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean kho\u1ea3ng (-\u221e; -2) v\u00e0 (0; +\u221e)<\/p>\n
H\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean (-2; -1) v\u00e0 (-1; 0)<\/p>\n
y_{C\u0110<\/sub>=y(-2)=-4;y_{CT<\/sub>=y(0)=0<\/p>\n}}
$\"\"$ <\/p>\n
V\u1eady \u0111\u01b0\u1eddng th\u1eb3ng x = -1 l\u00e0 ti\u1ec7m c\u1eadn \u0111\u1ee9ng.<\/p>\n
$\"\"$ <\/p>\n
V\u1eady \u0111\u01b0\u1eddng th\u1eb3ng y = x \u2013 1 l\u00e0 ti\u1ec7m c\u1eadn xi\u00ean<\/p>\n
B\u1ea3ng bi\u1ebfn thi\u00ean.<\/p>\n
\n
$\"\"$ <\/div>\n<\/div>\n
\u0110\u1ed3 th\u1ecb<\/p>\n<\/div>\n
$\"\"$ <\/div>\n
$\"Gi\u1ea3i$ Do \u0111\u00f3 (H) \u0111\u01b0\u1ee3c suy ra t\u1eeb (C) nh\u01b0 sau: (H) v\u00e0 (C) tr\u00f9ng nhau khi (C) \u1edf ph\u00eda tr\u00ean tr\u1ee5c ho\u00e0nh. (H) v\u00e0 (C) \u0111\u1ed1i x\u1ee9ng nhau qua tr\u1ee5c ho\u00e0nh khi (C) \u1edf ph\u00eda d\u01b0\u1edbi tr\u1ee5c ho\u00e0nh.<\/p>\n
$\"\"$ <\/div>\n","protected":false},"excerpt":{"rendered":"
B\u00e0i 53 (trang 50 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao): a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 b) Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00e3 cho t\u1ea1i giao \u0111i\u1ec3m c\u1ee7a A v\u1edbi tr\u1ee5c tung. c) Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb song song v\u1edbi ti\u1ebfp […]<\/p>\n","protected":false},"author":3,"featured_media":23765,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1302],"tags":[1392,1393],"yoast_head":"\n\u0110\u1ea1i s\u1ed1 - Ch\u01b0\u01a1ng 1 - Luy\u1ec7n t\u1eadp (trang 50)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/dai-so-chuong-1-luyen-tap-trang-50\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ea1i s\u1ed1 - 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