B\u00e0i 12 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\n X\u00e9t m\u1ec7nh \u0111\u1ec1: \u201cv\u1edbi c\u00e1c s\u1ed1 th\u1ef1c a, b, x n\u1ebfu 0 < a < b th\u00ec ax<\/sup>\u00a0< bxm<\/sup>. v\u1edbi \u0111i\u1ec1u ki\u1ec7n n\u00e0o sau \u0111\u00e2y c\u1ee7a x th\u00ec m\u1ec7nh \u0111\u1ec1 \u0111\u00fang.<\/p>\n A. X b\u1ea5t k\u00ec \u00a0\u00a0\u00a0 B. x > 0 \u00a0\u00a0\u00a0 C. x < 0<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n B. v\u00ec theo t\u00ednh ch\u1ea5t c\u1ee7a l\u0169y th\u1eeba v\u1edbi s\u1ed1 m\u0169 th\u1ef1c.<\/p>\n B\u00e0i 13 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\n X\u00e9t m\u1ec7nh \u0111\u1ec1: \u201cV\u1edbi c\u00e1c s\u1ed1 th\u1ef1c a, x, y n\u1ebfu x < y th\u00ec ax<\/sup>\u00a0< ayn<\/sup>. V\u1edbi \u0111i\u1ec1u ki\u1ec7n n\u00e0o sau \u0111\u00e2y c\u1ee7a a th\u00ec m\u1ec7nh \u0111\u1ec1 \u0111\u00f3 \u0111\u00fang?<\/p>\n A. A b\u1ea5t k\u00ec \u00a0\u00a0\u00a0 B. a > 0 \u00a0\u00a0\u00a0 C. a > 1<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n C. v\u00ec theo t\u00ednh ch\u1ea5t c\u1ee7a l\u0169y th\u1eeba v\u1edbi s\u1ed1 m\u0169 th\u1ef1c.<\/p>\n B\u00e0i 14 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\n Cho c\u00e1c s\u1ed1 th\u1ef1c c\u1ee7a l\u0169y th\u1eeba v\u1edbi s\u1ed1 m\u0169 th\u1ef1c.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Theo t\u00ednh ch\u1ea5t l\u0169y th\u1eeba v\u1edbi s\u1ed1 m\u0169 th\u1ef1c th\u00ec \u0111i\u1ec1u ki\u1ec7n c\u1ee7a a l\u00e0: 0 < a < 1<\/p>\n B\u00e0i 15 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\n T\u00ednh c\u00e1c bi\u1ec3u th\u1ee9c:<\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 16 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\n \u0110\u01a1n gi\u1ea3n bi\u1ec3u th\u1ee9c:<\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ta c\u00f3:<\/p>\n <\/p>\n B\u00e0i 17 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0<\/span><\/p>\n M\u1ed9t ng\u01b0\u1eddi g\u1eedi 15 tri\u1ec1u \u0111\u1ed3ng v\u00e0o ng\u00e2n h\u00e0ng theo th\u1ec3 th\u1ee9c l\u00e3i k\u00e9p k\u00ec h\u1ea1n 1 n\u0103m v\u1edbi l\u00e3i xu\u1ea5t 7, 56% m\u1ed9t n\u0103m. Gi\u1ea3 s\u1eed l\u00e3i xu\u1ea5t kh\u00f4ng thay \u0111\u1ed5i. h\u1ecfi s\u1ed1 ti\u1ec1n l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 thu \u0111\u01b0\u1ee3c (c\u1ea3 v\u1ed1n l\u1eabn l\u00e3i) sau 5 n\u0103m l\u00e0 bao nhi\u00eau tri\u1ec7u \u0111\u1ed3ng?<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c l\u00e3i k\u00e9p C=A(1+r)N<\/sup><\/p>\n Trong \u0111\u00f3 A =15, r = 7,56%, N = 5 => C = 15(1+7,56)5<\/sup>=15.1,07565<\/sup>\u224821,59 tri\u1ec7u \u0111\u1ed3ng.<\/p>\n B\u00e0i 12 (trang 81 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):\u00a0 X\u00e9t m\u1ec7nh \u0111\u1ec1: \u201cv\u1edbi c\u00e1c s\u1ed1 th\u1ef1c a, b, x n\u1ebfu 0 < a < b th\u00ec ax\u00a0< bxm. v\u1edbi \u0111i\u1ec1u ki\u1ec7n n\u00e0o sau \u0111\u00e2y c\u1ee7a x th\u00ec m\u1ec7nh \u0111\u1ec1 \u0111\u00fang. A. X b\u1ea5t k\u00ec \u00a0\u00a0\u00a0 B. x > 0 \u00a0\u00a0\u00a0 C. x < 0 […]<\/p>\n","protected":false},"author":3,"featured_media":23546,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1302],"tags":[1392,1393],"yoast_head":"\n