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{"id":22658,"date":"2018-03-20T15:02:08","date_gmt":"2018-03-20T08:02:08","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=22658"},"modified":"2018-03-20T15:02:08","modified_gmt":"2018-03-20T08:02:08","slug":"dai-so-chuong-4-bai-tap-trac-nghiem-khach-quan-4","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/dai-so-chuong-4-bai-tap-trac-nghiem-khach-quan-4\/","title":{"rendered":"\u0110\u1ea1i s\u1ed1 – Ch\u01b0\u01a1ng 4 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m kh\u00e1ch quan 4"},"content":{"rendered":"

B\u00e0i 43 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

Ph\u1ea7n th\u1ef1c c\u1ee7a z = 2i l\u00e0:<\/p>\n

A. 2\u00a0\u00a0\u00a0B. 2i\u00a0\u00a0\u00a0C. 0\u00a0\u00a0\u00a0D. 1<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

S\u1ed1 z=2i=0+2i n\u00ean c\u00f3 ph\u1ea7n th\u1ef1c b\u1eb1ng 0. V\u1eady ch\u1ecdn C.<\/p>\n

B\u00e0i 44 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

Ph\u1ea7n \u1ea3o c\u1ee7a z = -2i l\u00e0:<\/p>\n

A. -2\u00a0\u00a0\u00a0B. -2i\u00a0\u00a0\u00a0C. 0\u00a0\u00a0\u00a0D. -1<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

S\u1ed1 z = -I = 0 \u2013 2i n\u00ean c\u00f3 ph\u1ea7n \u1ea3o l\u00e0 -2. V\u1eady ch\u1ecdn A<\/p>\n

B\u00e0i 45 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0S\u1ed1 z+z\u2212<\/i>\u00a0l\u00e0:<\/p>\n

A. S\u1ed1 th\u1ef1c \u00a0\u00a0\u00a0B. S\u1ed1 \u1ea3o\u00a0\u00a0\u00a0C. 0\u00a0\u00a0\u00a0D. 2<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Gi\u1ea3 s\u1eed z=a+bi=>z\u2212<\/i>=a-bi n\u00ean z +\u00a0z\u2212<\/i>\u00a0= 2a. v\u1eady ch\u1ecdn A<\/p>\n

B\u00e0i 46 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

S\u1ed1 z-z\u2212<\/i>\u00a0l\u00e0:<\/p>\n

A. S\u1ed1 th\u1ef1c \u00a0\u00a0\u00a0B. S\u1ed1 \u1ea3o\u00a0\u00a0\u00a0C. 0\u00a0\u00a0\u00a0D. 2i<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Gi\u1ea3 s\u1eed z=a+bi=>z\u2212<\/i>=a-bi n\u00ean z –\u00a0z\u2212<\/i>\u00a0= 2bi. V\u1eady ch\u1ecdn B<\/p>\n

B\u00e0i 47 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

\"\"<\/p>\n

A. 1+i\u00a0\u00a0\u00a0B. (1-i)\/2\u00a0\u00a0\u00a0C. 1-i\u00a0\u00a0\u00a0D. i<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

V\u1eady ch\u1ecdn B<\/p>\n

B\u00e0i 48 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

T\u1eadp h\u1ee3p c\u00e1c nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n

\"\"<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

<=> z(z+i)=z <=> z(z+i-1)=0<\/p>\n

<=> z = 0 v\u00e0 z = 1 \u2013 i. v\u1eady ch\u1ecdn A.<\/p>\n

B\u00e0i 49 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

M\u00f4 \u0111un c\u1ee7a 1 \u2013 2i b\u1eb1ng:<\/p>\n

A. 3\u00a0\u00a0\u00a0B. \u221a5\u00a0\u00a0\u00a0C. 2\u00a0\u00a0\u00a0D. 1<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

M\u00f4 \u0111un c\u1ee7a z = 1 \u2013 2i l\u00e0 |z| = \u221a(1+4)=\u221a5. V\u1eady ch\u1ecdn B.<\/p>\n

\n
\n

B\u00e0i 50 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

M\u00f4 \u0111un c\u1ee7a -2iz b\u1eb1ng:<\/p>\n

A. -2|z|\u00a0\u00a0\u00a0B. \u221a2 z\u00a0\u00a0\u00a0C. 2|z|\u00a0\u00a0\u00a0D. 2<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

M\u00f4 \u0111un c\u1ee7a z\u2019 = -2iz l\u00e0 |z\u2019| = 2.|z|. v\u1eady ch\u1ecdn C.<\/p>\n

B\u00e0i 51 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

Acgumen c\u1ee7a -1 + I b\u1eb1ng:<\/p>\n

\"\"<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

N\u00ean z c\u00f3 acgumen c\u1ee7a z l\u00e0:<\/p>\n

\"\"<\/p>\n

V\u1eady ch\u1ecdn A.<\/p>\n

B\u00e0i 52 (trang 211 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

N\u1ebfu acgumen c\u1ee7a z b\u1eb1ng (-\u03c0\/4) + k2\u03c0 th\u00ec:<\/p>\n

A. Ph\u1ea7n \u1ea3o c\u1ee7a z l\u00e0 s\u1ed1 d\u01b0\u01a1ng v\u00e0 ph\u1ea7n th\u1ef1c c\u1ee7a z b\u1eb1ng 0.<\/p>\n

B. Ph\u1ea7n \u1ea3o c\u1ee7a z l\u00e0 s\u1ed1 \u00e2m v\u00e0 ph\u1ea7n th\u1ef1c c\u1ee7a z b\u1eb1ng 0.<\/p>\n

C. Ph\u1ea7n th\u1ef1c c\u1ee7a z l\u00e0 s\u1ed1 \u00e2m v\u00e0 ph\u1ea7n \u1ea3o c\u1ee7a z b\u1eb1ng 0.<\/p>\n

D. Ph\u1ea7n th\u1ef1c v\u00e0 ph\u1ea7n th\u1ef1c c\u1ee7a z \u0111\u1ec1u l\u00e0 s\u1ed1 \u00e2m.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

N\u1ebfu acgumen c\u1ee7a z b\u1eb1ng (-\u03c0\/2)+k2 \u03c0 th\u00ec ta c\u00f3:<\/p>\n

\"\"<\/p>\n

N\u00ean z c\u00f3 ph\u1ea7n \u1ea3o l\u00e0 -r < 0 v\u00e0 ph\u1ea7n th\u1ef1c b\u1eb1ng 0. V\u1eady ch\u1ecdn B.<\/p>\n

B\u00e0i 53 (trang 211 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

N\u1ebfu z=cos\u2061\u03b1-i sin\u2061\u03b1 th\u00ec acgumen c\u1ee7a z b\u1eb1ng:<\/p>\n

A. \u03b1+k2 \u03c0 \u00a0\u00a0\u00a0 B. -\u03b1+k2 \u03c0<\/p>\n

C. \u03b1+\u03c0+k2 \u03c0 (k \u2208Z)\u00a0\u00a0\u00a0 D. pa-\u03b1+k2 \u03c0 (k \u2208Z)<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ta c\u00f3: z=cos\u2061\u03b1-i sin\u2061\u03b1=cos\u2061(-\u03b1)+i sin\u2061(-\u03b1) n\u00ean z c\u00f3 acgumen l\u00e0: -\u03b1+k2 \u03c0. V\u1eady ch\u1ecdn B.<\/p>\n

\n
\n

B\u00e0i 54 (trang 211 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n

N\u1ebfu z=-sin\u2061\u03b1-i cos\u2061\u03b1 th\u00ec acgumen c\u1ee7a z b\u1eb1ng:<\/p>\n

\"\"<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 43 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao): Ph\u1ea7n th\u1ef1c c\u1ee7a z = 2i l\u00e0: A. 2\u00a0\u00a0\u00a0B. 2i\u00a0\u00a0\u00a0C. 0\u00a0\u00a0\u00a0D. 1 L\u1eddi gi\u1ea3i: S\u1ed1 z=2i=0+2i n\u00ean c\u00f3 ph\u1ea7n th\u1ef1c b\u1eb1ng 0. V\u1eady ch\u1ecdn C. B\u00e0i 44 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao): Ph\u1ea7n \u1ea3o c\u1ee7a z = -2i l\u00e0: A. -2\u00a0\u00a0\u00a0B. -2i\u00a0\u00a0\u00a0C. […]<\/p>\n","protected":false},"author":3,"featured_media":22660,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1302],"tags":[1392,1393],"yoast_head":"\n\u0110\u1ea1i s\u1ed1 - Ch\u01b0\u01a1ng 4 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m kh\u00e1ch quan 4<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/dai-so-chuong-4-bai-tap-trac-nghiem-khach-quan-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ea1i s\u1ed1 - Ch\u01b0\u01a1ng 4 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m kh\u00e1ch quan 4\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 43 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao): Ph\u1ea7n th\u1ef1c c\u1ee7a z = 2i l\u00e0: A. 2\u00a0\u00a0\u00a0B. 2i\u00a0\u00a0\u00a0C. 0\u00a0\u00a0\u00a0D. 1 L\u1eddi gi\u1ea3i: S\u1ed1 z=2i=0+2i n\u00ean c\u00f3 ph\u1ea7n th\u1ef1c b\u1eb1ng 0. V\u1eady ch\u1ecdn C. B\u00e0i 44 (trang 210 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao): Ph\u1ea7n \u1ea3o c\u1ee7a z = -2i l\u00e0: A. -2\u00a0\u00a0\u00a0B. -2i\u00a0\u00a0\u00a0C. 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