<\/div>\n
Gi\u1ea3 s\u1eed d\u1ee5ng m\u00e1y n m\u00e1y \u0111\u1ec3 in (n = 1; 2; 3; 4; 5; 6; 7; 8)<\/p>\n
Khi \u0111\u00f3, t\u1ed5ng chi ph\u00ed \u0111\u1ec3 in 50000 t\u1edd qu\u1ea3ng c\u00e1o l\u00e0:<\/p>\n
<\/p>\n
B\u1ea3ng bi\u1ebfn thi\u00ean c\u1ee7a f(n)<\/p>\n
<\/p>\n
\u0110\u1ec3 ta \u0111\u01b0\u1ee3c l\u00e3i nhi\u1ec1u nh\u1ea5t th\u00ec t\u1ed5ng chi ph\u00ed ph\u1ea3i l\u00e0 \u00edt nh\u1ea5t.<\/p>\n
V\u1eady ta c\u1ea7n t\u00ecm n \u2208{1;2;3;4;5;6;7;8} \u0111\u1ec3 f(n) nh\u1ecf nh\u1ea5t. ta c\u00f3 f(5) < f(6), k\u1ebft h\u1ee3p v\u1edbi b\u1ea3ng bi\u1ebfn thi\u00ean c\u1ee7a f(n) th\u00ec khi n = 5 t\u1ed5ng chi ph\u00ed s\u1ebd b\u00e9 nh\u1ea5t.<\/p>\n
V\u1eady n\u00ean ch\u1ecdn 5 m\u00e1y.<\/p>\n
B\u00e0i 5 (trang 121 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0T\u00ecm gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t v\u00e0 nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n<\/div>\n
Theo gi\u1ea3 thi\u1ebft ta c\u00f3: loga<\/sub>\u2061b=\u221a3 => b = a\u221a3<\/sup><\/p>\n<\/p>\n
B\u00e0i 8 (trang 212 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
a) T\u00ednh \u0111\u1ea1o h\u00e0m c\u1ee7a c\u00e1c h\u00e0m s\u1ed1: y=cosx.e2<\/sup>tanx v\u00e0 y=log2<\/sub>(sin\u2061x)<\/p>\nb) Ch\u1ee9ng minh r\u1eb1ng h\u00e0m s\u1ed1 y=e4x<\/sub>+2.e-x<\/sup>\u00a0th\u00f5a m\u00e3n h\u1ec7 th\u1ee9c.<\/p>\ny”’-13y’-12y=0<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
<\/p>\n
b) Ta c\u00f3: y’=(e4x<\/sub>+2e-x<\/sup>=4e4x<\/sub>-2e-x<\/sup><\/p>\ny”=(4e4x<\/sub>-2e-x<\/sup>\u00a0)’=16e4x<\/sub>+2e-x<\/sup><\/p>\ny”’=(4e4x<\/sub>-2e-x<\/sup>\u00a0)’=64e4x<\/sub>-2e-x<\/sup><\/p>\nV\u1eady y”’-13y’-12y=64e4x<\/sub>-2e-x<\/sup>-13(16e4x<\/sub>+2e-x<\/sup>\u00a0)-12(4e4x<\/sub>-2e-x<\/sup>)<\/p>\n=64e4x<\/sub>-2e-x<\/sup>-52e4x<\/sub>+26e-x<\/sup>-12e4x<\/sub>-24e-x<\/sup>=0 (\u0111pcm)<\/p>\nB\u00e0i 9 (trang 212 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
a) V\u1ebd \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y=2x<\/sup>,y=(\u221a2)x<\/sup>;y=(\u221a3)x<\/sup>\u00a0tr\u00ean c\u00f9ng m\u1ed9t m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9. H\u00e3y nh\u1eadn x\u00e9t v\u1ecb tr\u1ecb t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a ba \u0111\u1ed3 th\u1ecb.<\/p>\nb) V\u1ebd \u0111\u1ed3 th\u1ecb y=log3<\/sub>x. T\u1eeb \u0111\u00f3 suy ra \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y=2+log3<\/sub>\u2061x v\u00e0 \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y=log3<\/sub>(x+2)<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) V\u1ebd \u0111\u1ed3 th\u1ecb c\u00e1c h\u00e0m s\u1ed1: y=2x<\/sup>,y=(\u221a2)x<\/sup>;y=(\u221a3)x<\/sup><\/p>\nnh\u1eadn x\u00e9t:<\/p>\n
Trong kho\u1ea3ng (-\u221e;0) \u0111\u1ed3 th\u1ecb s\u1eafp x\u1ebfp theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00ean xu\u1ed1ng d\u01b0\u1edbi l\u00e0: ,y=(\u221a2)x<\/sup>;y=(\u221a3)x<\/sup>;y=2x<\/sup><\/p>\n\u0110\u1ed3 th\u1ecb c\u1ea3 ba h\u00e0m s\u1ed1 \u0111i qua \u0111i\u1ec3m (0; 1)<\/p>\n
Kho\u1ea3ng (0; +\u221e) \u0111\u1ed3 th\u1ecb s\u1eafp x\u1ebfp theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00ean xu\u1ed1ng d\u01b0\u1edbi l\u00e0:<\/p>\n
y=2x<\/sup>,y=(\u221a3)x<\/sup>;y=(\u221a2)x<\/sup><\/p>\nNh\u01b0 v\u1eady \u201c\u0111\u1ed9 d\u1ed1c\u201d c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 t\u0103ng theo gi\u00e1 tr\u1ecb c\u01a1 s\u1ed1:<\/p>\n
\u221a2<\u221a3<2<\/p>\n
b) V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y=log3<\/sub>\u2061x (C )<\/p>\n<\/p>\n
\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = 2 + log3<\/sub>x c\u00f3 \u0111\u01b0\u1ee3c b\u1eb1ng c\u00e1ch t\u1ecbnh ti\u1ebfn (C) l\u00ean tr\u00ean theo ph\u01b0\u01a1ng Oy 2 \u0111\u01a1n v\u1ecb.<\/p>\n\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y=log3<\/sub>x+2 c\u00f3 \u0111\u01b0\u1ee3c b\u1eb1ng c\u00e1ch t\u00ednh ti\u1ebfn (C) sang b\u00ean tr\u00e1i theo ph\u01b0\u01a1ng Ox 2 \u0111\u01a1n v\u1ecb.<\/p>\n<\/p>\n
B\u00e0i 10 (trang 212 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
Gi\u1ea3i c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau:<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) Ph\u01b0\u01a1ng tr\u00ecnh: 81sin2\u2061x<\/sup>\u00a0+ 81cos2x<\/sup>\u00a0=30 <=> 81sin2\u2061x<\/sup>\u00a0+ 811-sin2\u2061x<\/sup>\u00a0=30<\/p>\n\u0110\u1eb7t t=81sin2\u2061x<\/sup>\u00a0,t>0, ta c\u00f3 Ph\u01b0\u01a1ng tr\u00ecnh: t+81\/t=30<\/p>\n<=> t2<\/sup>-30t+81=0 <=> t = 27; t = 3<\/p>\nV\u1edbi t = 27 => 81sin2\u2061x<\/sup>\u00a0=27 <=> 34 sin2\u2061x<\/sup>=33<\/sup>\u00a0<=> 4 sin2<\/sup>x=3<\/p>\n<\/p>\n
V\u1eady Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u00e3 cho c\u00f3 4 h\u1ecd nghi\u1ec7m:<\/p>\n
<\/p>\n
b) \u0110\u1eb7t log1\/2<\/sub>\u2061x=t v\u1edbi x > 0, ta c\u00f3 Ph\u01b0\u01a1ng tr\u00ecnh.<\/p>\n<\/p>\n
V\u1eady ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 hai nghi\u1ec7m l\u00e0 x = 2; x = 1\/16<\/p>\n
c) \u0110\u1eb7t log\u2061x=t ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n
<\/p>\n
Ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n
<\/p>\n
V\u1eady Ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 1 nghi\u1ec7m<\/p>\n
<\/p>\n
Thay y=1\/3x v\u00e0o (1) ta \u0111\u01b0\u1ee3c.<\/p>\n
<\/p>\n
V\u1edbi x = 2 => y=1\/6. V\u1eady h\u1ec7 c\u00f3 1 nghi\u1ec7m l\u00e0<\/p>\n
<\/p>\n
B\u00e0i 11 (trang 213 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0T\u1eadp h\u1ee3p x\u00e1c \u0111\u1ecbnh c\u1ee7a c\u00e1c h\u00e0m s\u1ed1 sau:<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) H\u00e0m s\u1ed1 y=log\u2061(1-log\u2061(x2<\/sup>-5x+16)) x\u00e1c \u0111\u1ecbnh khi:<\/p>\n<\/p>\n
<=> x2<\/sup>-5x+6<0 <=> x \u2208(2;3)<\/p>\nV\u1eady t\u1eadp x\u00e1c \u0111\u1ecbnh c\u1ee7a h\u00e0m s\u1ed1 l\u00e0 kho\u1ea3ng (2; 3)<\/p>\n
<\/p>\n
B\u00e0i 12 (trang 213 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
T\u00ecm h\u1ecd nguy\u00ean h\u00e0m c\u1ee7a m\u1ed7i h\u00e0m s\u1ed1 sau tr\u00ean kho\u1ea3ng x\u00e1c \u0111\u1ecbnh c\u1ee7a n\u00f3.<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) T\u00ecm F(x) = \u222bx3<\/sup>(1+x4<\/sup>\u00a0)3<\/sup>. \u0110\u1eb7t u=1+x4<\/sup>\u00a0=> du = 4x3<\/sup>\u00a0dx<\/p>\n<\/p>\n
b) T\u00ecm F(x) = \u222bcosx.sin2x dx=2 \u222bcos2<\/sup>\u2061x.sinxdx<\/p>\n\u0110\u1eb7t cosx = u => -sinxdx=du. Ta c\u00f3:<\/p>\n
<\/p>\n
B\u00e0i 13 (trang 213 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0T\u00ecm h\u00e0m s\u1ed1 f(x) bi\u1ebft<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
<\/p>\n
B\u00e0i 14 (trang 213 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
T\u00ednh c\u00e1c t\u00edch ph\u00e2n sau:<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
<\/p>\n
<\/p>\n
c) Theo c\u00f4ng th\u1ee9c t\u00edch ph\u00e2n t\u1eebng ph\u1ea7n, ta c\u00f3:<\/p>\n
<\/p>\n
B\u00e0i 15 (trang 214 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
T\u00ednh di\u1ec7 t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c \u0111\u01b0\u1eddng.<\/p>\n
a) y+x2<\/sup>=0 v\u00e0 y+3x2<\/sup>=2<\/p>\nb) y2<\/sup>-4x=4 v\u00e0 4x-y=16<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
<\/p>\n
a) Ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng: y=-x2<\/sup>\u00a0v\u00e0 y=-3x2<\/sup>+2 l\u00e0 nghi\u1ec7m c\u1ee7a Ph\u01b0\u01a1ng tr\u00ecnh: -x2<\/sup>=-3x2<\/sup>+2 <=> x2<\/sup>=1 <=> x=\u00b11<\/p>\nV\u1eady di\u1ec7n t\u00edch c\u1ea7n t\u00ecm l\u00e0:<\/p>\n
<\/p>\n
b) Di\u1ec7n t\u00edch c\u1ea7n t\u00ecm l\u00e0 S=S1<\/sub>-S2<\/sub>\u00a0(h\u00ecnh v\u1ebd)<\/p>\nHai \u0111\u01b0\u1eddng \u0111\u00e3 cho c\u1eaft nhau t\u1ea1i hai \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 l\u00e0 3 v\u00e0 21\/4<\/p>\n
S1<\/sub>\u00a0l\u00e0 di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3n gi\u1edbi h\u1ea1n b\u1edfi \u0111\u01b0\u1eddng y2<\/sup>-4x-4=0 v\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng x=21\/4<\/p>\nTa c\u00f3:<\/p>\n
<\/p>\n
S2<\/sub>\u00a0l\u00e0 di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi 3 \u0111\u01b0\u1eddng: y2<\/sup>=4x+4;y=4x-16 v\u00e0 x=21\/4<\/p>\nTa c\u00f3:<\/p>\n
<\/p>\n
B\u00e0i 16 (trang 213 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
a) Cho h\u00ecnh thang cong A gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y=ex<\/sup>, tr\u1ee5c ho\u00e0nh v\u00e0 c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng x = 0 v\u00e0 x = 1. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i tr\u00f2n xoay t\u1ea1o \u0111\u01b0\u1ee3c khi quay A quang tr\u1ee5c ho\u00e0nh.<\/p>\nb) Cho h\u00ecnh ph\u1eb3ng B gi\u1edbi h\u1ea1n b\u1edfi parabol y=x2<\/sup>+1 v\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng y = 2. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i tr\u00f2n xoay t\u1ea1o \u0111\u01b0\u1ee3c khi quay B quanh tr\u1ee5c tung.<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) Th\u1ec3 t\u00edch c\u1ea7n t\u00ecm l\u00e0:<\/p>\n
<\/p>\n
b) Th\u1ec3 t\u00edch c\u1ea7n t\u00ecm l\u00e0:<\/p>\n
<\/p>\n
B\u00e0i 17 (trang 213 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
Cho c\u00e1c s\u1ed1 ph\u1ee9c z1<\/sub>=1+i;z2<\/sub>=1-2i. H\u00e3y t\u00ednh v\u00e0 bi\u1ec3u di\u1ec5n h\u00ecnh h\u1ecdc c\u00e1c s\u1ed1 ph\u1ee9c: z1<\/sub>2<\/sup>;z1<\/sub>\u00a0z2<\/sub>,2z1<\/sub>-z2<\/sub>,z1<\/sub>.Z2<\/sup>\u2212<\/i>;v\u00e0 z2<\/sub>\/z1<\/sub>\u00a0.<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ta c\u00f3: z1<\/sub>2<\/sup>=(1+i)2<\/sup>=1+2i+i2<\/sup>=1+2i-1=2i<\/p>\nz1<\/sub>\u00a0z2<\/sub>=(1+i)(1-2i)=1+2+i-2i=3-i<\/p>\n2z1<\/sub>-z2<\/sub>=2(1+i)-(1-2i)=1+4i<\/p>\nz1<\/sub>.\u00af(z2<\/sub>\u00a0)=(1+i)(1+2i)=-1+3i<\/p>\n<\/p>\n
C\u00e1c \u0111i\u1ec3m A, B, C, D, D l\u1ea7n l\u01b0\u1ee3t bi\u1ec3u di\u1ec5n c\u00e1c s\u1ed1:<\/p>\n
<\/p>\n
B\u00e0i 18 (trang 214 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
T\u00ednh<\/p>\n
a) (\u221a3+i)2<\/sup>-(\u221a3-i)2<\/sup><\/p>\nb) (\u221a3+i)2<\/sup>+(\u221a3-i)2<\/sup><\/p>\nc) (\u221a3+i)3<\/sup>-(\u221a3-i)3<\/sup><\/p>\n<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) (\u221a3+i)2<\/sup>-(\u221a3-i)2<\/sup>=(3+2 \u221a3 i-1)-(3-2 \u221a3 i-1)=4 \u221a3 i<\/p>\nb) (\u221a3+i)2<\/sup>+(\u221a3-i)2<\/sup>=(3+2 \u221a3 i-1)+(3-2 \u221a3 i-1)=4<\/p>\nc) (\u221a3+i)3<\/sup>-(\u221a3-i)3<\/sup>=(3 \u221a3+9i-3 \u221a3-i)-(3 \u221a3-9i-3 \u221a3+i)=16i<\/p>\n<\/p>\n
B\u00e0i 19 (trang 214 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
a) X\u00e1c \u0111\u1ecbnh ph\u1ea7n th\u1ef1c c\u1ee7a s\u1ed1 ph\u1ee9c<\/p>\n
<\/p>\n
b) Ch\u1ee9ng minh r\u1eb1ng n\u1ebfu<\/p>\n
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) Gi\u1ea3 s\u1eed z=a+bi v\u1edbi a2<\/sup>+b2<\/sup>=1 v\u00e0 a+bi \u2260 1<\/p>\n<\/p>\n
(v\u00ec a2<\/sup>+b2<\/sup>=1=>(a+1)(a-1)+b2<\/sup>=0)<\/p>\nV\u1eady s\u1ed1 ph\u1ee9c (z+1)\/(z-1) c\u00f3 ph\u1ea7n th\u1ef1c b\u1eb1ng 0.<\/p>\n
b) Theo c\u00e2u a, ta c\u00f3:<\/p>\n
<\/p>\n
N\u00ean (z+1)\/(z-1) l\u00e0 s\u1ed1 \u1ea3o th\u00ec a2<\/sup>+b2<\/sup>-1=0 <=> a2<\/sup>+b2<\/sup>=1 <=> |z| = 1 (\u0111pcm)<\/p>\n\n
<\/div>\n
\n
B\u00e0i 20 (trang 214 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b>\u00a0X\u00e1c \u0111\u1ecbnh t\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m M tr\u00ean m\u1eb7t ph\u1eb3ng ph\u1ee9c bi\u1ec3u di\u1ec5n c\u00e1c s\u1ed1 ph\u1ee9c (+i\u221a3)z+2, trong \u0111\u00f3 |z-1|\u22642<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Gi\u1ea3 s\u1eed z=x+yi,v\u00ec |z-1|\u22642 n\u00ean (x-1)2<\/sup>+y4<\/sup>\u22644 (1)<\/p>\nTa c\u00f3:<\/p>\n
w=(1+\u221a3 i)z+2=(1+\u221a3 i)(x+yi)+2=(x-\u221a3 y+2)+i(x\u221a3+y)<\/p>\n
G\u1ecdi N l\u00e0 \u0111i\u1ec3m bi\u1ec3u di\u1ec5n s\u1ed1 ph\u1ee9c w => N(x-\u221a3 y+2;x\u221a3+y)<\/p>\n
T\u1eeb (1) ta c\u00f3: 4[(x-1)2<\/sup>+y2<\/sup>\u00a0]\u226416 <=> (x-1)2<\/sup>+3y2<\/sup>]+[3(x-1)2<\/sup>+y2<\/sup>\u00a0]\u226416<\/p>\n<=> (x-1-\u221a3 y)2<\/sup>+(\u221a3 (x-1)+y)2<\/sup>\u226416 <=> (xN<\/sub>-3)2<\/sup>+(yN<\/sub>-\u221a3)2<\/sup>\u226416<\/p>\nV\u1eady t\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m N n\u1eb1m trong h\u00ecnh tr\u00f2n c\u00f3 t\u00e2m A(3;\u221a3) c\u00f3 b\u00e1n k\u00ednh R = 4.<\/p>\n
B\u00e0i 21 (trang 214 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
T\u00ecm c\u0103n b\u1eadc hai c\u1ee7a m\u1ed7i s\u1ed1 ph\u1ee9c: -8+6i;3+4i;1-2\u221a2 i<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
G\u1ecdi a+bi l\u00e0 c\u0103n b\u1eadc hai c\u1ee7a -8+6i, ta c\u00f3:<\/p>\n
(a+bi)2<\/sup>=-8+6i <=>(a2<\/sup>-b2<\/sup>\u00a0)+2abi=-8+6i<\/p>\n<\/p>\n
V\u1eady s\u1ed1 -8+6i c\u0103n b\u1eadc hai l\u00e0: 1 +3i; 1 \u2013 3i.<\/p>\n
T\u01b0\u01a1ng t\u1ef1, s\u1ed1 3 + 4i c\u00f3 c\u0103n b\u1eadc hai l\u00e0: 2 +I; 2 -I;<\/p>\n
S\u1ed1 1-2 \u221a2 i c\u00f3 c\u0103n b\u1eadc hai l\u00e0: \u221a2-i v\u00e0 – \u221a2+i<\/p>\n
B\u00e0i 22 (trang 214 sgk Gi\u1ea3i T\u00edch 12 n\u00e2ng cao):<\/b><\/p>\n
a) Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh: z2<\/sup>-3+3=0<\/p>\nb) Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh: z2<\/sup>-(cos\u2061\u03b1+i sin\u2061\u03b1 )z+i sin\u2061\u03b1 cos\u2061\u03b1=0<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) Ta c\u00f3 bi\u1ec7 s\u1ed1 \u0394=-3+4i=(2i-1)2<\/sup>\u00a0n\u00ean Ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 hai nghi\u1ec7m l\u00e0 z1<\/sub>=i+1;z2<\/sub>=2-1<\/p>\nb) Ta c\u00f3 bi\u1ec7t hi\u1ec7u s\u1ed1 \u0394=(cos\u2061\u03b1+i sin\u2061\u03b1 )