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{"id":21764,"date":"2018-03-16T10:07:27","date_gmt":"2018-03-16T03:07:27","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=21764"},"modified":"2018-03-16T10:16:59","modified_gmt":"2018-03-16T03:16:59","slug":"hinh-hoc-chuong-3-mot-so-de-kiem-tra","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/hinh-hoc-chuong-3-mot-so-de-kiem-tra\/","title":{"rendered":"H\u00ecnh h\u1ecdc – Ch\u01b0\u01a1ng 3: M\u1ed9t s\u1ed1 \u0111\u1ec1 ki\u1ec3m tra"},"content":{"rendered":"

B\u00e0i t\u1eadp (trang 129-130 sgk H\u00ecnh H\u1ecdc 12 n\u00e2ng cao)<\/h2>\n

\u0110\u1ec1 s\u1ed1 1 (trang 129 sgk H\u00ecnh H\u1ecdc 12 n\u00e2ng cao):<\/b><\/span><\/p>\n

C\u00e2u 1:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u S.ABCD c\u00f3 \u0111\u00e1y b\u1eb1ng a, v\u00e0 c\u1ea1nh b\u00ean b\u1eb1ng a\u221a2.<\/p>\n

a) T\u00ednh th\u1ec3 t\u00edch c\u1ee7a h\u00ecnh ch\u00f3p \u0111\u00e3 cho.<\/p>\n

b) T\u00ednh b\u00e1n k\u00ednh m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u00f3p S.ABCD.<\/p>\n

c) G\u1ecdi A\u2019 v\u00e0 C l\u1ea7n l\u01b0\u1ee3t l\u00e0 trung \u0111i\u1ec3m c\u1ee7a hai c\u1ea1nh SA v\u00e0 Sc. Ch\u1ee9ng minh r\u1eb1ng h\u00ecnh ch\u00f3p A\u2019.ABCD v\u00e0 C\u2019CBAD b\u1eb1ng nhau.<\/p>\n

C\u00e2u 2:<\/b>\u00a0Trong kh\u00f4ng gian t\u1ecda \u0111\u1ed9 Oxyz cho c\u00e1c \u0111i\u1ec3m A(4; -1; 2); B(1; 2; 2), C(1; -1; 5)<\/p>\n

a) Ch\u1ee9ng minh r\u1eb1ng ABC l\u00e0 tam gi\u00e1c \u0111\u1ec1u.<\/p>\n

b) Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh mp(ABC). T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i t\u1ee9 di\u1ec7n gi\u1edbi h\u1ea1n b\u1edfi mp(ABC) v\u00e0 c\u00e1c m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9.<\/p>\n

c) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh tr\u1ee5c c\u1ee7a \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp \u0394ABC<\/p>\n

d) T\u00ecm t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m D sao cho ABCD l\u00e0 t\u1ee9 di\u1ec7n \u0111\u1ec1u.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

C\u00e2u 1:<\/b><\/span><\/p>\n

\"Gi\u1ea3i<\/p>\n

a) G\u1ecdi H l\u00e0 t\u00e2m c\u1ee7a h\u00ecnh vu\u00f4ng ABCD<\/p>\n

Ta c\u00f3 SH \u22a5 (ABCD)<\/p>\n

\"\"<\/p>\n

b) G\u1ecdi O l\u00e0 giao \u0111i\u1ec3m c\u1ee7a SH v\u00e0 v\u00e0 \u0111\u01b0\u1eddng trung tr\u1ef1c c\u1ea1nh SA, suy ra O l\u00e0 t\u00e2m m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp S.ABCD.<\/p>\n

Ta c\u00f3: SO.SH=SA’.SA (A’ l\u00e0 trung \u0111i\u1ec3m SA)<\/p>\n

\"\"<\/p>\n

c) Ta th\u1ea5y hai h\u00ecnh ch\u00f3p A\u2019.ABCD v\u00e0 C\u2019.ABCD \u0111\u1ed1i x\u1ee9ng v\u1edbi nhau qua mp(SBD) n\u00ean ch\u00fang b\u1eb1ng nhau. (\u0111pcm)<\/p>\n

C\u00e2u 2:<\/b><\/span><\/p>\n

a) Ta c\u00f3 AB = AC = BC = 3\u221a2 n\u00ean tam gi\u00e1c ABC l\u00e0 tam gi\u00e1c \u0111\u1ec1u.<\/p>\n

b) Mp(ABC) l\u00e0 m\u1eb7t ph\u1eb3ng \u0111ia qua A(4; -1; 2) v\u00e0 nh\u1eadn [AB\u2192<\/i>,AC\u2192<\/i>\u00a0]=(9;9;9) l\u00e0m vect\u01a1 ph\u00e1p tuy\u1ebfn n\u00ean c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u00e0: x+y+z-5=0<\/p>\n

M\u1eb7t ph\u1eb3ng (ABC) c\u1eaft tr\u1ee5c t\u1ecda \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t t\u1ea1i:<\/p>\n

M(5; 0; 0); N(0; 5; 0), P(0; 0; 5)<\/p>\n

Th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p OMNP l\u00e0:<\/p>\n

\"\"<\/p>\n

c) Tr\u1ee5c c\u1ee7a \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp tam gi\u00e1c ABC l\u00e0 \u0111\u01b0\u1eddng \u0111i qua t\u00e2m \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp \u0394ABC v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi mp(ABC). T\u00e2m \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp l\u00e0 \u0111i\u1ec3m M th\u00f5a m\u00e3n MA = MB = MC<\/p>\n

\"\"<\/p>\n

V\u1eady tr\u1ee5c c\u1ee7a \u0111\u01b0\u1eddng tr\u00f2n l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua M(2; 0; 3) v\u00e0 nh\u1eadn vect\u01a1 [AB\u2192<\/i>,AC\u2192<\/i>\u00a0]=(9;9;9) l\u00e0m vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng n\u00ean c\u00f3 Ph\u01b0\u01a1ng tr\u00ecnh l\u00e0:<\/p>\n

\"\"<\/p>\n

d) \u0110\u1ec3 ABCD l\u00e0 t\u1ee9 di\u1ec7n \u0111\u1ec1u th\u00ec D n\u1eb1m tr\u00ean tr\u1ee5c \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp \u0394ABC v\u00e0 DA = AB = 3\u221a2<\/p>\n

V\u00ec D n\u1eb1m tr\u00ean tr\u1ee5c \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp \u0394ABC n\u00ean t\u1ecda \u0111\u1ed9 c\u1ee7a D c\u00f3 d\u1ea1ng: D(2+t; t; 3+t).<\/p>\n

V\u00ec DA = 3\u221a2 <=> DA2<\/sup>=18 <=>(2-t)2<\/sup>+(1+t)2<\/sup>+(1+t)2<\/sup>=18<\/p>\n

<=> 3t2<\/sup>=12 => t2<\/sup>=4 => t=\u00b12<\/p>\n

V\u1edbi t = 2 => D(4; 2; 5); v\u1edbi t = -2=> D(0; -2; 1)<\/p>\n

V\u1eady c\u00f3 hai \u0111i\u1ec3m D th\u1ecfa m\u00e3n b\u00e0i to\u00e1n.<\/p>\n

\u0110\u1ec1 s\u1ed1 2 (trang 129 sgk H\u00ecnh H\u1ecdc 12 n\u00e2ng cao):<\/b><\/span><\/p>\n

C\u00e2u 1:<\/b>\u00a0Cho t\u1ee9 di\u1ec7n \u0111\u1ec1u ABCD c\u1ea1nh b\u1eb1ng a. G\u1ecdi B\u2019, C\u2019, D\u2019 l\u1ea7n l\u01b0\u1ee3t l\u00e0 trung \u0111i\u1ec3m c\u00e1c c\u1ea1nh AB, AC, AD.<\/p>\n

a) Ch\u1ee9ng minh r\u1eb1ng 6 \u0111i\u1ec3m B, C, D, B\u2019, C\u2019, D\u2019 n\u1eb1m tr\u00ean m\u1ed9t m\u1eb7t c\u1ea7u.<\/p>\n

b) T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p D.BCC\u2019B\u2019<\/p>\n

C\u00e2u 2:<\/b>\u00a0Trong kh\u00f4ng gian t\u1ecda \u0111\u1ed9 Oxyz cho c\u00e1c \u0111i\u1ec3m A(2; 0; 0); A\u2019(6; 0; 0), B(0; 3; 0); B\u2019(0; 4; 0); C(0; 0; 4); C\u2019(0; 0; 3).<\/p>\n

a) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u \u0111i qua 4 b\u1ed1n \u0111i\u1ec3m A, A\u2019, B, C. ch\u1ee9ng minh r\u1eb1ng: B\u2019 v\u00e0 C\u2019 c\u00f9ng n\u1eb1m tr\u00ean m\u1eb7t c\u1ea7u \u0111\u00f3.<\/p>\n

b) Ch\u1ee9ng minh r\u1eb1ng tr\u1ef1c t\u00e2m H c\u1ee7a tam gi\u00e1c ABC, tr\u1ecdng t\u00e2m G c\u1ee7a \u0394A’B’C’ c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua O. Vi\u1ebft Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u00f3.<\/p>\n

c) T\u00ednh kho\u1ea3ng c\u00e1ch t\u1eeb \u0111i\u1ec3m O t\u1edbi giao \u0111i\u1ec3m c\u1ee7a mp(ABC\u2019) v\u00e0 (A\u2019B\u2019C)<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

C\u00e2u 1:<\/b><\/span><\/p>\n

\"\"<\/p>\n

G\u1ecdi H l\u00e0 t\u00e2m c\u1ee7a \u0394BCD, khi \u0111\u00f3 AH \u22a5 (BCD) v\u00e0 AH l\u00e0 tr\u1ee5c \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp \u0394B’C’D’<\/p>\n

a) G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m BB\u2019 v\u00e0 O l\u00e0 giao \u0111i\u1ec3m c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng AH v\u1edbi \u0111\u01b0\u1eddng trung tr\u1ef1c OM c\u1ee7a c\u1ea1nh BB\u2019.<\/p>\n

Khi \u0111\u00f3 ta c\u00f3:<\/p>\n

\"\"<\/p>\n

=> O c\u00e1ch \u0111\u1ec1u 6 \u0111i\u1ec3m B, C, D, B\u2019, C\u2019, D\u2019 hay O l\u00e0 t\u00e2m m\u1eb7t c\u1ea7u \u0111i qau B, C, D, B\u2019, C\u2019, D\u2019. b\u00e1n k\u00ednh m\u1eb7t c\u1ea7u l\u00e0 R = OB.<\/p>\n

Ta c\u00f3:<\/p>\n

\"\"<\/p>\n

M\u1eb7t kh\u00e1c tam gi\u00e1c vu\u00f4ng AMO \u0111\u1ed3ng d\u1ea1ng tam gi\u00e1c vu\u00f4ng AHB<\/p>\n

\"\"<\/p>\n

c) T\u00ednh V(D.BCC.B.)<\/sub>. kho\u1ea3ng c\u00e1ch t\u1eeb D \u0111\u1ebfn mo(ABC) c\u0169ng b\u1eb1ng \u0111o\u1ea1n AH (v\u00ec t\u1ee9 di\u1ec7n ABCD \u0111\u1ec1u).<\/p>\n

Di\u1ec7n t\u00edch h\u00ecnh thang c\u00e2n B\u2019C\u2019CB l\u00e0<\/p>\n

\"\"<\/p>\n

V\u1eady th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p D.BCC\u2019B\u2019 l\u00e0:<\/p>\n

\"\"<\/p>\n

C\u00e2u 2:<\/b><\/span><\/p>\n

a) G\u1ecdi Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u \u0111i qua A, A\u2019, B, C l\u00e0:<\/p>\n

x2<\/sup>+y2<\/sup>+z2<\/sup>+ax+by+cz+d=0<\/p>\n

V\u00ec m\u1eb7t c\u1ea7u \u0111i qau A(2; 0; 0); A\u2019(6; 0; 0); B(0; 3; 0), C(0; 0; 4) n\u00ean ta c\u00f3 h\u1ec7:<\/p>\n

\"\"<\/p>\n

V\u1eady Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u l\u00e0: x2<\/sup>+y2<\/sup>+z2<\/sup>-8x-7y-7z+12=0<\/p>\n

Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m B\u2019 v\u00e0 C v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u th\u1ea5y th\u00f5a m\u00e3n. (\u0111pcm)<\/p>\n

b) Tr\u1ef1c t\u00e2m H c\u1ee7a \u0394ABC l\u00e0<\/p>\n

\"\"<\/p>\n

Tr\u1ecdng t\u00e2m G c\u1ee7a \u0394A’B’C’ l\u00e0<\/p>\n

\"\"<\/p>\n

Suy ra ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng HG l\u00e0:<\/p>\n

\"\"<\/p>\n

\u0110\u01b0\u1eddng th\u1eb3ng n\u00e0y \u0111i qua O(0; 0; 0). V\u1eady H, G, O th\u1eb3ng h\u00e0ng.<\/p>\n

c) Ph\u01b0\u01a1ng tr\u00ecnh mp(ABC\u2019) l\u00e0:<\/p>\n

\"\"<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh mp(A\u2019B\u2019C\u2019) l\u00e0:<\/p>\n

\"\"<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh giao tuy\u1ebfn c\u1ee7a \u0394 c\u1ee7a (ABC\u2019) v\u00e0 (A\u2019B\u2019C\u2019) l\u00e0:<\/p>\n

\"\"<\/p>\n

v\u00e0 c\u00f3 vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng\u00a0u\u2192<\/i>=(0; -5;5)<\/p>\n

Kho\u1ea3ng c\u00e1ch t\u1eeb O \u0111\u1ebfn \u0394 l\u00e0<\/p>\n

\"\"<\/p>\n

\u0110\u1ec1 s\u1ed1 3 (trang 130 sgk H\u00ecnh H\u1ecdc 12 n\u00e2ng cao):<\/b><\/span><\/p>\n

C\u00e2u 1:<\/b>\u00a0Cho h\u00ecnh h\u1ed9p ABCD.A\u2019B\u2019C\u2019D\u2019. G\u1ecdi N l\u00e0 \u0111i\u1ec3m n\u1eb1m tr\u00ean c\u1ea1nh AB, v\u00ec (\u03b1) l\u00e0 m\u1eb7t ph\u1eb3ng \u0111i qua 3 b\u1ed1n \u0111i\u1ec3m D, N, B\u2019.<\/p>\n

a) Mp(\u03b1) c\u1eaft h\u00ecnh h\u1ed9p \u0111\u00e3 cho thi\u1ebfu di\u1ec7n l\u00e0 h\u00ecnh g\u00ec?<\/p>\n

b) Ch\u1ee9ng minh r\u1eb1ng m\u1eb7t ph\u1eb3ng (\u03b1) ph\u1ea7n chia kh\u1ed1i h\u1ed9p \u0111\u00e3 cho th\u00e0nh hai kh\u1ed1i \u0111a di\u1ec7n H1<\/sub>\u00a0v\u00e0 H2<\/sub>\u00a0b\u1eb1ng nhau.<\/p>\n

c) T\u00ednh t\u1ec9 s\u1ed1 th\u1ec3 t\u00edch c\u1ee7a kh\u1ed1i \u0111a di\u1ec7n H1<\/sub>\u00a0v\u00e0 th\u1ec3 t\u00edch t\u1ee9 di\u1ec7n AA\u2019BD.<\/p>\n

C\u00e2u 2:<\/b>\u00a0Trong kh\u00f4ng gian t\u1ecda \u0111\u1ed9 Oxyz cho c\u00e1c \u0111i\u1ec3m: A(1; -3; -1); v\u00e0 B(-2; 1; 3)<\/p>\n

a) Ch\u1ee9ng t\u1ecf r\u1eb1ng hai \u0111i\u1ec3m A v\u00e0 B c\u00e1ch \u0111\u1ec1u tr\u1ee5c Ox.<\/p>\n

b) T\u00ecm \u0111i\u1ec3m C n\u1eb1m tr\u00ean Oz sao cho tam gi\u00e1c ABC vu\u00f4ng t\u1ea1i C.<\/p>\n

c) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh h\u00ecnh chi\u1ebfu c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng AB tr\u00ean mp(Oyz).<\/p>\n

d) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u \u0111i qua ba \u0111i\u1ec3m O, A, B v\u00e0 c\u00f3 t\u00e2m n\u1eb1m tr\u00ean mp(oyz).<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

C\u00e2u 1:<\/b><\/span><\/p>\n

\"\"<\/p>\n

a) V\u00ec s\u1ed1 m\u1eb7t ph\u1eb3ng c\u1eaft m\u1eb7t ph\u1eb3ng song song theo hai giao tuy\u1ebfn song song n\u00ean \u03b1 c\u1eaft h\u00ecnh h\u1ed9p theo thi\u1ebft di\u1ec7n l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh DNB\u2019N\u2019.<\/p>\n

b) H1<\/sub>\u00a0v\u00e0 H2<\/sub>\u00a0l\u00e0 hai h\u00ecnh \u0111a di\u1ec7n \u0111\u1ed1i x\u1ee9ng v\u1edbi nhau qua t\u00e2m O c\u1ee7a h\u00ecnh h\u1ed9p n\u00ean ch\u00fang b\u1eb1ng nhau.<\/p>\n

c) V\u00ec H1<\/sub>\u00a0v\u00e0 H2<\/sub>\u00a0b\u1eb1ng nhau n\u00ean th\u1ec3 t\u00edch c\u1ee7a ch\u00fang b\u1eb1ng m\u1ed9t th\u1ec3 t\u00edch h\u00ecnh h\u1ed9p.<\/p>\n

M\u1eb7t kh\u00e1c\"\"<\/p>\n

C\u00e2u 2:<\/b><\/span><\/p>\n

a) Ta c\u00f3: d(A,Ox)=d(B,Ox)=\u221a10 (\u0111pcm)<\/p>\n

b) G\u1ecdi C(0; 0; c) \u2208Oz l\u00e0 \u0111i\u1ec3m c\u1ea7n t\u00ecm.<\/p>\n

V\u00ec \u0394ABC vu\u00f4ng t\u1ea1i C n\u00ean CA2<\/sup>+CB2<\/sup>=AB2<\/sup><\/p>\n

<=> 1+9+(1+c)2<\/sup>+41+(3-c)2<\/sup>=9+16+16<\/p>\n

<=> 2c2<\/sup>-4c-16=0 <=> c = 4 v\u00e0 c = -2<\/p>\n

V\u1eady \u0111i\u1ec3m C th\u1ecfa m\u00e3n b\u00e0i to\u00e0n l\u00e0: C = (0; 0; 4) v\u00e0 C\u2019(0; 0; -2)<\/p>\n

c) H\u00ecnh chi\u1ebfu c\u1ee7a A(1; -3; -1) l\u00ean mp(Oyz) l\u00e0 A\u2019(0; -3; -1)<\/p>\n

H\u00ecnh chi\u1ebfu c\u1ee7a B(-2; 1; 3) l\u00ean mp(Oyz) l\u00e0 B\u2019(0; 1; 2)<\/p>\n

V\u1eady A\u2019B\u2019 ch\u00ednh l\u00e0 h\u00ecnh chi\u1ebfu c\u1ee7a AB l\u00ean mp(Oyz). Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng A\u2019B\u2019 l\u00e0:<\/p>\n

\"\"<\/p>\n

d) G\u1ecdi I(a; b; 0) \u2208 (Oxy) l\u00e0 t\u00e2m c\u1ee7a m\u1eb7t c\u1ea7u \u0111i qua O, A, B.<\/p>\n

Khi \u0111\u00f3 ta c\u00f3:<\/p>\n

\"\"<\/p>\n

V\u1eady ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u l\u00e0:<\/p>\n

\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i t\u1eadp (trang 129-130 sgk H\u00ecnh H\u1ecdc 12 n\u00e2ng cao) \u0110\u1ec1 s\u1ed1 1 (trang 129 sgk H\u00ecnh H\u1ecdc 12 n\u00e2ng cao): C\u00e2u 1:\u00a0Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u S.ABCD c\u00f3 \u0111\u00e1y b\u1eb1ng a, v\u00e0 c\u1ea1nh b\u00ean b\u1eb1ng a\u221a2. a) T\u00ednh th\u1ec3 t\u00edch c\u1ee7a h\u00ecnh ch\u00f3p \u0111\u00e3 cho. b) T\u00ednh b\u00e1n k\u00ednh m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp […]<\/p>\n","protected":false},"author":3,"featured_media":21765,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1302],"tags":[1392,1393],"yoast_head":"\nH\u00ecnh h\u1ecdc - Ch\u01b0\u01a1ng 3: M\u1ed9t s\u1ed1 \u0111\u1ec1 ki\u1ec3m tra<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/hinh-hoc-chuong-3-mot-so-de-kiem-tra\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"H\u00ecnh h\u1ecdc - 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