B\u00e0i 1 (trang 30 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm c\u00e1c ti\u1ec7m c\u1eadn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n a) Ta c\u00f3<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = 2.<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = \u20131.<\/p>\n b)<\/b>\u00a0Ta c\u00f3:<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = \u20131.<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = \u20131.<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = 2\/5.<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = 2\/5.<\/p>\n d)<\/b>\u00a0Ta c\u00f3:<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = 0 (tr\u1ee5c Ox).<\/p>\n <\/p>\n \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = -1.<\/p>\n B\u00e0i 2 (trang 30 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm c\u00e1c ti\u1ec7m c\u1eadn \u0111\u1ee9ng v\u00e0 ngang c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n a) V\u00ec<\/p>\n <\/p>\n n\u00ean \u0111\u1ed3 th\u1ecb c\u00f3 hai \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = -3 v\u00e0 x = 3.<\/p>\n <\/p>\n => \u0111\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = 0.<\/p>\n b)<\/b>\u00a0V\u00ec<\/p>\n <\/p>\n n\u00ean \u0111\u1ed3 th\u1ecb c\u00f3 hai \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = -1 v\u00e0 x = 3\/5.<\/p>\n <\/p>\n => \u0111\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = -1\/5.<\/p>\n C) Ta c\u00f3<\/p>\n <\/p>\n => \u0111\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = -1.<\/p>\n <\/p>\n => \u0111\u1ed3 th\u1ecb kh\u00f4ng c\u00f3 ti\u1ec7m c\u1eadn ngang.<\/p>\n d)<\/b>\u00a0Ta c\u00f3:<\/p>\n <\/p>\n => \u0111\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = 1.<\/p>\n <\/p>\n => \u0111\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = 1.<\/p>\n <\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 1 (trang 30 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm c\u00e1c ti\u1ec7m c\u1eadn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1: L\u1eddi gi\u1ea3i a) Ta c\u00f3 \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = 2. \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 y = \u20131. b)\u00a0Ta c\u00f3: \u21d2 \u0110\u1ed3 th\u1ecb c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = […]<\/p>\n","protected":false},"author":3,"featured_media":21452,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1298],"tags":[1377,1356,1355],"yoast_head":"\n