B\u00e0i 1 (trang 47 SGK Gi\u1ea3i t\u00edch 12):\u00a0S\u1ed1 \u0111i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y = – 1\/3 x3<\/sup>\u00a0– x + 7 l\u00e0:<\/strong><\/span><\/p>\n (A) 1 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (B) 0 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (C) 3 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (D) 2<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n – Ch\u1ecdn \u0111\u00e1p \u00e1n\u00a0B<\/b><\/p>\n – Ta c\u00f3: y’ = -x2<\/sup>\u00a0– 1 < 0 \u2200 x \u2208 R<\/p>\n H\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn tr\u00ean t\u1eadp x\u00e1c \u0111\u1ecbnh n\u00ean kh\u00f4ng c\u00f3 c\u1ef1c tr\u1ecb.<\/p>\n B\u00e0i 2 (trang 47 SGK Gi\u1ea3i t\u00edch 12):\u00a0S\u1ed1 \u0111i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a h\u00e0m s\u1ed1 y = x4<\/sup>\u00a0+ 100 l\u00e0:<\/strong><\/span><\/p>\n (A) 0 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (B) 1 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (C) 2 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (D) 3<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n – Ch\u1ecdn \u0111\u00e1p \u00e1n\u00a0A<\/b><\/p>\n – Ta c\u00f3: y’ = 4x3<\/sup>\u00a0= 0 \u21d4 x = 0<\/p>\n H\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean (-\u221e; 0) v\u00e0 \u0111\u1ed3ng bi\u1ebfn tr\u00ean (0; +\u221e) => h\u00e0m s\u1ed1 ch\u1ec9 c\u00f3 c\u1ef1c ti\u1ec3u ch\u1ee9 kh\u00f4ng c\u00f3 c\u1ef1c \u0111\u1ea1i.<\/p>\n (B\u1ea1n c\u00f3 th\u1ec3 v\u1ebd b\u1ea3ng bi\u1ebfn thi\u00ean \u0111\u1ec3 th\u1ea5y r\u00f5 h\u01a1n.)<\/p>\n B\u00e0i 3 (trang 47 SGK Gi\u1ea3i t\u00edch 12):\u00a0S\u1ed1 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/strong><\/span><\/p>\n <\/p>\n <\/p>\n l\u00e0: (A) 1 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (B) 2 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (C) 3 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (D) 0<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n – Ch\u1ecdn \u0111\u00e1p \u00e1n\u00a0B<\/b><\/p>\n – Ta c\u00f3: 1 + x =0 \u21d4 x = -1<\/p>\n <\/p>\n <\/p>\n \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng x = -1.<\/p>\n <\/p>\n <\/p>\n \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3 ti\u1ec7m c\u1eadn ngang y = -1.<\/p>\n => \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u00f3\u00a02<\/b>\u00a0\u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn.<\/p>\n B\u00e0i 4 (trang 47 SGK Gi\u1ea3i t\u00edch 12):\u00a0H\u00e0m s\u1ed1<\/strong><\/span><\/p>\n <\/p>\n <\/p>\n \u0111\u1ed3ng bi\u1ebfn tr\u00ean: (A) R ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (B) (-\u221e;3) ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (C) (-3; +\u221e) ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (D) R \\ {-3}<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n – Ch\u1ecdn \u0111\u00e1p \u00e1n\u00a0D<\/b><\/p>\n – TX\u0110: D = R \\ {-3}<\/p>\n <\/p>\n <\/p>\n => H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean D = R \\ {-3}.<\/p>\n B\u00e0i 5 (trang 47 SGK Gi\u1ea3i t\u00edch 12):\u00a0Ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m c\u1ef1c ti\u1ec3u c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1:<\/strong><\/span><\/p>\n <\/p>\n <\/p>\n (A) Song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng x = 1;<\/p>\n (B) Song song v\u1edbi tr\u1ee5c ho\u00e0nh;<\/p>\n (C) C\u00f3 h\u1ec7 s\u1ed1 g\u00f3c d\u01b0\u01a1ng;<\/p>\n (D) C\u00f3 h\u1ec7 s\u1ed1 g\u1ecdc b\u1eb1ng -1.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n – Ch\u1ecdn \u0111\u00e1p \u00e1n\u00a0B<\/b><\/p>\n – Ta c\u00f3: y’ = x2<\/sup>\u00a0– 4x + 3<\/p>\n y’ = 0 \u21d4 x = 1 ; x = 3<\/p>\n y”= 2x – 4<\/p>\n Ta c\u00f3: y”(3) = 2 > 0<\/p>\n => h\u00e0m s\u1ed1 \u0111\u1ea1t c\u1ef1c ti\u1ec3u t\u1ea1i x = 3 (Quy t\u1eafc 2).<\/p>\n M\u1eb7t kh\u00e1c, ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn t\u1ea1i \u0111i\u1ec3m c\u1ef1c ti\u1ec3u c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c l\u00e0 y'(3) = 0. Do \u0111\u00f3 ti\u1ebfp tuy\u1ebfn song song v\u1edbi tr\u1ee5c ho\u00e0nh.<\/p>\n <\/p>\n <\/p>\n B\u00e0i 1 (trang 47 SGK Gi\u1ea3i t\u00edch 12):\u00a0S\u1ed1 \u0111i\u1ec3m c\u1ef1c tr\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y = – 1\/3 x3\u00a0– x + 7 l\u00e0: (A) 1 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (B) 0 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (C) 3 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 (D) 2 L\u1eddi gi\u1ea3i: – Ch\u1ecdn \u0111\u00e1p \u00e1n\u00a0B – Ta c\u00f3: y’ = -x2\u00a0– 1 < 0 […]<\/p>\n","protected":false},"author":3,"featured_media":21191,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1298],"tags":[1377,1356,1355],"yoast_head":"\n