B\u00e0i 1 (trang 133 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ednh ph\u1ea7n th\u1ef1c ph\u1ea7n \u1ea3o c\u1ee7a s\u1ed1 ph\u1ee9c x, bi\u1ebft:<\/strong><\/span><\/p>\n a) z=1-\u03c0i<\/strong><\/span><\/p>\n b) z=\u221a2-i<\/strong><\/span><\/p>\n c) z=2 \u221a2<\/strong><\/span><\/p>\n d) z=-7i<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a) Ph\u1ea7n th\u1ef1c: 1, ph\u1ea7n \u1ea3o: -\u03c0<\/p>\n b) Ph\u1ea7n th\u1ef1c: \u221a2, ph\u1ea7n \u1ea3o: -1<\/p>\n c) Ph\u1ea7n th\u1ef1c: 2 \u221a2, ph\u1ea7n \u1ea3o: 0<\/p>\n d) Ph\u1ea7n th\u1ef1c: 0, ph\u1ea7n \u1ea3o: -7<\/p>\n B\u00e0i 2 (trang 133 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm c\u00e1c s\u1ed1 th\u1ef1c x v\u00e0 y, bi\u1ebft:<\/strong><\/span><\/p>\n a) (3x-2)+(2y+1)i=(x+1)-(y-5)i<\/strong><\/span><\/p>\n b) (1-2x)-i \u221a3=\u221a5+(1-3y)i<\/strong><\/span><\/p>\n c) (2x+y)+(2y-x)i=(x-2y+3)+(y+2x+1)i<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 3 (trang 133 SGK Gi\u1ea3i t\u00edch 12):\u00a0Tr\u00ean m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9 t\u00ecm t\u1eadp h\u1ee3p \u0111i\u1ec3m bi\u1ec3u di\u1ec5n c\u00e1c s\u1ed1 ph\u1ee9c z th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n:<\/strong><\/span><\/p>\n a) Ph\u1ea7n th\u1ef1c c\u1ee7a z b\u1eb3ng -2<\/strong><\/span><\/p>\n b) Ph\u1ea7n \u1ea3o c\u1ee7a z b\u1eb3ng 3<\/strong><\/span><\/p>\n c) Ph\u1ea7n th\u1ef1c c\u1ee7a z thu\u1ed9c kho\u1ea3ng (-1;2)<\/strong><\/span><\/p>\n d) Ph\u1ea7n \u1ea3o c\u1ee7a z thu\u1ed9c \u0111o\u1ea1n [1;3]<\/strong><\/span><\/p>\n e) Ph\u1ea7n th\u1ef1c v\u00e0 ph\u1ea7n \u1ea3o \u0111\u1ec1u thu\u1ed9c \u0111o\u1ea1n [-2; 2]<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a) T\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng x = -2<\/p>\n b) T\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng y = 3<\/p>\n c) T\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m thu\u1ed9c m\u1eb7t ph\u1eb3ng n\u1eb1m gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng song song x = -1 v\u00e0 x =2 (h\u00ecnh c\u00f3 g\u1ea1ch s\u1ecdc)<\/p>\n d) Ph\u1ea7n m\u1eb7t ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng song song y =1 v\u00e0 y = 3( k\u1ec3 c\u1ea3 c\u00e1c \u0111i\u1ec3m thu\u1ed9c hai \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u00f3).<\/p>\n e) C\u00e1c \u0111i\u1ec3m thu\u1ed9c h\u00ecnh ch\u1eef nh\u1eadt v\u1edbi c\u00e1c c\u1ea1nh n\u1eb1m tr\u00ean c\u00e1c \u0111\u01b0\u1eddng th\u1eb1ng x = -2, x = 2 , y= -2, y= 2.<\/p>\n B\u00e0i 4 (trang 134 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ednh |z|, v\u1edbi:<\/strong><\/span><\/p>\n a) z = -2 + i \u221a3<\/strong><\/span><\/p>\n b) z = \u221a2- 3i<\/strong><\/span><\/p>\n c) z = -5<\/strong><\/span><\/p>\n d) z = i\u221a3<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 5 (trang 134 SGK Gi\u1ea3i t\u00edch 12):\u00a0Tr\u00ean m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9, t\u00ecm t\u1eadp h\u1ee3p \u0111i\u1ec3m bi\u1ec3u di\u1ec5n c\u00e1c s\u1ed1 ph\u1ee9c z th\u1ecfa m\u00e3n t\u1eebng \u0111i\u1ec1u ki\u1ec7n:<\/strong><\/span><\/p>\n a) |z| = 1<\/strong><\/span><\/p>\n b) |z| \u2264 1<\/strong><\/span><\/p>\n c) 1<|z| \u2264 2<\/strong><\/span><\/p>\n d) |z| = 1 v\u00e0 ph\u1ea7n \u1ea3o c\u1ee7a z = 1<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a) Gi\u1ea3 s\u1eed \u0111i\u1ec3m M(x, y) bi\u1ec3u di\u1ec5n s\u1ed1 ph\u1ee9c z=x+y th\u1ecfa m\u00e3n:<\/p>\n |z|=|x+yi|=1 \u21d4\u221a(x2<\/sup>+y2<\/sup>\u00a0)=1<\/p>\n \u21d4x2<\/sup>+y2<\/sup>=1<\/p>\n V\u1eady M thu\u1ed9c \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m O(0; 0) b\u00e1n k\u00ednh R =1 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup>+y2<\/sup>=1.<\/p>\n b) T\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m tr\u00ean h\u00ecnh tr\u00f2n t\u00e2m x2<\/sup>+y2<\/sup>=1.<\/p>\n c) C\u00e1c \u0111i\u1ec3m n\u1eb1m trong h\u00ecnh v\u00e0nh kh\u0103n gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m O, b\u00e1n k\u00ednh tr\u00f2n nh\u1edf b\u1eb1ng 1,\u0111\u01b0\u1eddng tr\u00f2n l\u1edbn b\u1eb1ng 2, (h\u00ecnh t\u00f4 \u0111\u1eadm) kh\u00f4ng k\u1ec3 c\u00e1c \u0111i\u1ec3m thu\u1ed9c \u0111\u01b0\u1eddng tr\u00f2n nh\u1ecf.<\/p>\n d) Giao \u0111i\u1ec3m c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng y = 1 v\u00e0 \u0111\u01b0\u1eddng tr\u00f2n x2<\/sup>+y2<\/sup>=1.<\/p>\n B\u00e0i 6 (trang 134 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm z, bi\u1ebft:<\/strong><\/span><\/p>\n a) z=1-i \u221a2<\/strong><\/span><\/p>\n b) z=-\u221a2+i \u221a3<\/strong><\/span><\/p>\n c) z=5<\/strong><\/span><\/p>\n d) z=7i<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n <\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 1 (trang 133 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ednh ph\u1ea7n th\u1ef1c ph\u1ea7n \u1ea3o c\u1ee7a s\u1ed1 ph\u1ee9c x, bi\u1ebft: a) z=1-\u03c0i b) z=\u221a2-i c) z=2 \u221a2 d) z=-7i L\u1eddi gi\u1ea3i: a) Ph\u1ea7n th\u1ef1c: 1, ph\u1ea7n \u1ea3o: -\u03c0 b) Ph\u1ea7n th\u1ef1c: \u221a2, ph\u1ea7n \u1ea3o: -1 c) Ph\u1ea7n th\u1ef1c: 2 \u221a2, ph\u1ea7n \u1ea3o: 0 d) Ph\u1ea7n th\u1ef1c: 0, ph\u1ea7n […]<\/p>\n","protected":false},"author":3,"featured_media":20985,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1298],"tags":[1377,1356,1355],"yoast_head":"\n