C\u00e2u h\u1ecfi 1 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0\u0110\u1ecbnh ngh\u0129a s\u1ef1 \u0111\u01a1n \u0111i\u1ec7u ( \u0111\u1ed3ng bi\u1ebfn, ngh\u1ecbch bi\u1ebfn) c\u1ee7a m\u1ed9t h\u00e0m s\u1ed1 tr\u00ean m\u1ed9t kho\u1ea3ng.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Cho h\u00e0m s\u1ed1 y = f(x) x\u00e1c \u0111\u1ecbnh tr\u00ean K, h\u00e0m s\u1ed1 f(x):<\/p>\n \u0110\u1ed3ng bi\u1ebfn ( t\u0103ng) tr\u00ean K n\u1ebfu \u2200 x1<\/sub>, x2<\/sub>\u00a0\u2208 K: x1<\/sub>\u00a0< x2<\/sub>\u00a0=> f(x1<\/sub>) < f(x2<\/sub>).<\/p>\n Ngh\u1ecbch bi\u1ebfn ( gi\u1ea3m) tr\u00ean K n\u1ebfu \u2200 x1<\/sub>, x2<\/sub>\u00a0\u2208: x1<\/sub>\u00a0< x2<\/sub>\u00a0=> f(x1<\/sub>) > f(x2<\/sub>)<\/p>\n H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn hay ngh\u1ecbch bi\u1ebfn tr\u00ean K g\u1ecdi l\u00e0 \u0111\u01a1n \u0111i\u1ec7u tr\u00ean K.<\/p>\n C\u00e2u h\u1ecfi 2 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0Ph\u00e1t bi\u1ec3u c\u00e1c \u0111i\u1ec1u ki\u1ec7n c\u1ea7n v\u00e0 \u0111\u1ee7 \u0111\u1ec3 h\u00e0m s\u1ed1 f(x) \u0111\u01a1n \u0111i\u1ec7u tr\u00ean m\u1ed9t kho\u1ea3ng.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Cho h\u00e0m s\u1ed1 y = f(x) c\u00f3 \u0111\u1ea1o h\u00e0m tr\u00ean K<\/p>\n N\u1ebfu f\u2019(x) > 0, x \u2208 K, f\u2019(x) = 0 ch\u1ec9 t\u1ea1i m\u1ed9t s\u1ed1 h\u1eefu h\u1ea1n \u0111i\u1ec3m th\u00ec h\u00e0m s\u1ed1 th\u00ec f(x) \u0111\u1ed3ng bi\u1ebfn tr\u00ean K.<\/p>\n N\u1ebfu f\u2019(x) < 0, x \u2208 K, f\u2019(x) = 0 ch\u1ec9 t\u1ea1i m\u1ed9t s\u1ed1 h\u1eefu h\u1ea1n \u0111i\u1ec3m th\u00ec h\u00e0m s\u1ed1 f(x) ngh\u1ecbch bi\u1ebfn tr\u00ean K.<\/p>\n C\u00e2u h\u1ecfi 3 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0Ph\u00e1t bi\u1ec3u c\u00e1c \u0111i\u1ec1u ki\u1ec7n \u0111\u1ee7 \u0111\u1ec3 h\u00e0m s\u1ed1 f(x) c\u00f3 c\u1ef1c tr\u1ecb ( c\u1ef1c \u0111\u1ea1i c\u1ef1c ti\u1ec3u) t\u1ea1i \u0111i\u1ec3m xo<\/sub><\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n \u0111\u1ec3 h\u00e0m c\u00f3 c\u1ef1c tr\u1ecb:<\/p>\n \u0110\u1ecbnh l\u00ed 1: Cho h\u00e0m s\u1ed1 y = f(x) li\u00ean t\u1ee5c tr\u00ean K = (x0<\/sub>\u00a0\u2013 h; x0<\/sub>\u00a0+ h), h > 0 v\u00e0 c\u00f3 \u0111\u1ea1o h\u00e0m tr\u00ean K ho\u1eb7c tr\u00ean K \\ {x0<\/sub>}, n\u1ebfu:<\/p>\n – f\u2019(x) > 0 tr\u00ean (x0<\/sub>\u00a0\u2013 h; x0<\/sub>) v\u00e0 f\u2019(x) < 0 tr\u00ean (x0<\/sub>; x0<\/sub>\u00a0+ h) th\u00ec x0<\/sub>\u00a0l\u00e0 m\u1ed9t \u0111i\u1ec3m c\u1ef1c \u0111\u1ea1i c\u1ee7a f(x).<\/p>\n – f\u2019(x) < 0 tr\u00ean (x0<\/sub>\u00a0\u2013 h; x0<\/sub>) v\u00e0 f\u2019(x) > 0 tr\u00ean (x0<\/sub>; x0<\/sub>\u00a0+ h) th\u00ec x0<\/sub>\u00a0l\u00e0 m\u1ed9t \u0111i\u1ec3m c\u1ef1c ti\u1ec3u c\u1ee7a f(x).<\/p>\n C\u00e2u h\u1ecfi 4 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0N\u00eau s\u01a1 \u0111\u1ed3 kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n B\u01b0\u1edbc 1: T\u00ecm t\u1eadp x\u00e1c \u0111\u1ecbnh c\u1ee7a h\u00e0m s\u1ed1<\/p>\n B\u01b0\u1edbc 2: X\u00e9t s\u1ef1 bi\u1ebfn thi\u00ean<\/p>\n – X\u00e9t chi\u1ec1u bi\u1ebfn thi\u00ean:<\/p>\n + T\u00ecm \u0111\u1ea1o h\u00e0m f\u2019(x)<\/p>\n + T\u00ecm c\u00e1c \u0111i\u1ec3m m\u00e0 t\u1ea1i \u0111\u00f3 f\u2019(x) b\u1eb1ng kh\u00f4ng ho\u1eb7c kh\u00f4ng x\u00e1c \u0111\u1ecbnh<\/p>\n + X\u00e9t d\u1ea5u c\u1ee7a \u0111\u1ea1o h\u00e0m f\u2019(x) v\u00e0 suy ra chi\u1ec1u bi\u1ebfn thi\u00ean c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n – T\u00ecm c\u1ef1c tr\u1ecb<\/p>\n – T\u00ecm gi\u1edbi h\u1ea1n v\u00f4 c\u1ef1c v\u00e0 ti\u1ec7m c\u1eadn ( n\u1ebfu c\u00f3)<\/p>\n – L\u1eadp b\u1ea3ng bi\u1ebfn thi\u00ean.<\/p>\n B\u01b0\u1edbc 3: V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<\/p>\n C\u00e2u h\u1ecfi 5 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0N\u00eau \u0111\u1ecbnh ngh\u0129a v\u00e0 c\u00e1c t\u00ednh ch\u1ea5t c\u01a1 b\u1ea3n c\u1ee7a loogarit.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n C\u00e2u h\u1ecfi 6 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh l\u00ed v\u1ec1 quy t\u1eafc logarit, c\u00f4ng th\u1ee9c \u0111\u1ed5i c\u01a1 s\u1ed1.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u2022 Quy t\u1eafc t\u00ednh logarit<\/strong><\/p>\n <\/p>\n \u2022 \u0110\u1ed5i c\u01a1 s\u1ed1<\/strong><\/p>\n <\/p>\n C\u00e2u h\u1ecfi 7 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0N\u00eau t\u00ednh ch\u1ea5t c\u1ee7a h\u00e0m s\u1ed1 m\u0169, h\u00e0m s\u1ed1 logarit, m\u1ed1i li\u00ean h\u1ec7 gi\u1eefa \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 m\u0169 c\u00e0 h\u00e0m s\u1ed1 logarit c\u00f9ng c\u01a1 s\u1ed1.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n 1. H\u00e0m s\u1ed1 m\u0169<\/strong><\/p>\n Cho s\u1ed1 a > 0, a \u2260 1. H\u00e0m s\u1ed1 y = ax<\/sup>\u00a0\u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 h\u00e0m s\u1ed1 m\u0169 c\u01a1 s\u1ed1 a.<\/p>\n Kh\u1ea3o s\u00e1t:<\/p>\n * D = R.<\/p>\n * N\u1ebfu:<\/p>\n – a > 1: h\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn<\/p>\n – 0 < a < 1: h\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn<\/p>\n * \u0110\u1ed3 th\u1ecb lu\u00f4n \u0111i qua hai \u0111i\u1ec3m ( 0; 1) v\u00e0 (1; a) c\u00f3 ti\u1ec7m c\u1eadn ngang l\u00e0 tr\u1ee5c Ox.<\/p>\n 2. H\u00e0m Logarit<\/strong><\/p>\n Cho s\u1ed1 a > 0, a \u2260 1 . H\u00e0m s\u1ed1<\/p>\n <\/p>\n \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 h\u00e0m logarit c\u01a1 s\u1ed1 a.<\/p>\n Kh\u1ea3o s\u00e1t:<\/p>\n * D = (0;+\u221e)<\/p>\n * N\u1ebfu:<\/p>\n – a > 1: H\u00e0m s\u1ed1 lu\u00f4n \u0111\u1ed3ng bi\u1ebfn tr\u00ean D<\/p>\n – 0 < a < 1: h\u00e0m s\u1ed1 lu\u00f4n ngh\u1ecbch bi\u1ebfn<\/p>\n * \u0110\u1ed3 th\u1ecb lu\u00f4n \u0111i qua hai \u0111i\u1ec3m (1; 0) v\u00e0 (a; 1) c\u00f3 ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 tr\u1ee5c Oy.<\/p>\n \u2022 Li\u00ean h\u1ec7 gi\u1eefa \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 m\u0169 v\u00e0 h\u00e0m s\u1ed1 logarit c\u00f9ng c\u01a1 s\u1ed1: \u0110\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 m\u0169 v\u00e0 \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 logarit \u0111\u1ed1i x\u1ee9ng nhau qua \u0111\u01b0\u1eddng ph\u00e2n gi\u00e1c g\u00f3c ph\u1ea7n t\u01b0 th\u1ee9 nh\u1ea5t.<\/p>\n C\u00e2u h\u1ecfi 8 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0N\u00eau \u0111\u1ecbnh ngh\u0129a v\u00e0 c\u00e1c ph\u01b0\u01a1ng ph\u00e1p t\u00ednh nguy\u00ean h\u00e0m.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Nguy\u00ean h\u00e0m<\/strong><\/p>\n Cho h\u00e0m s\u1ed1 f(x) x\u00e1c \u0111\u1ecbnh tr\u00ean K ( k l\u00e0 n\u1eeda kho\u1ea3ng hay \u0111o\u1ea1n c\u1ee7a tr\u1ee5c s\u1ed1). H\u00e0m s\u1ed1 F(x) \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 f(x) tr\u00ean K n\u1ebfu F\u2019(x) = f(x) v\u1edbi m\u1ecdi x thu\u1ed9c K.<\/p>\n Ph\u01b0\u01a1ng ph\u00e1p t\u00ednh nguy\u00ean h\u00e0m<\/p>\n * \u0110\u1ed5i bi\u1ebfn s\u1ed1:<\/strong><\/p>\n <\/p>\n C\u00e2u h\u1ecfi 9 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0N\u00eau \u0111\u1ecbnh ngh\u0129a v\u00e0 c\u00e1c ph\u01b0\u01a1ng ph\u00e1p t\u00ednh t\u00edch ph\u00e2n.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u2022 \u0110\u1ecbnh ngh\u0129a<\/strong><\/p>\n Cho h\u00e0m s\u1ed1 y = f(x) li\u00ean t\u1ee5c tr\u00ean [a; b] , F(x) l\u00e0 m\u1ed9t nguy\u00ean h\u00e0m c\u1ee7a f(x) tr\u00ean [a; b]. Hi\u1ec7u s\u1ed1 F(b) \u2013 F(a) \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 t\u00edch ph\u00e2n t\u1eeb a \u0111\u1ebfn b c\u1ee7a h\u00e0m s\u1ed1 f(x)<\/p>\n <\/p>\n \u2022 Ph\u01b0\u01a1ng ph\u00e1p t\u00ednh t\u00edch ph\u00e2n<\/p>\n a) \u0110\u1ed5i bi\u1ebfn s\u1ed1:<\/strong><\/p>\n \u0110\u1ecbnh l\u00ed 1: Cho h\u00e0m s\u1ed1 f(x) li\u00ean t\u1ee5c tr\u00ean [a; b]. Gi\u1ea3 s\u1eed h\u00e0m s\u1ed1 x = \u03c6(t) c\u00f3 \u0111\u1ea1o h\u00e0m li\u00ean t\u1ee5c tr\u00ean \u0111o\u1ea1n [ \u03b1;\u03b2] sao cho \u03c6(\u03b1) = a; \u03c6(\u03b2) = \u03b2v\u00e0 a \u2264 \u03c6(t) \u2264 b v\u1edbi m\u1ecdi t \u2208 [\u03b1;\u03b2]. Khi \u0111\u00f3:<\/p>\n <\/p>\n b) T\u00edch ph\u00e2n t\u1eebng ph\u1ea7n<\/strong><\/p>\n N\u1ebfu u = u(x) v\u00e0 v = v(x) l\u00e0 hai h\u00e0m s\u1ed1 c\u00f3 \u0111\u1ea1o h\u00e0m li\u00ean t\u1ee5c tr\u00ean \u0111o\u1ea1n [a; b] th\u00ec:<\/p>\n<\/div>\n <\/p>\n <\/p>\n C\u00e2u h\u1ecfi 10 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0Nh\u1eafc l\u1ea1i \u0111\u1ecbnh ngh\u0129a s\u1ed1 ph\u1ee9c, s\u1ed1 ph\u1ee9c li\u00ean h\u1ee3p, m\u00f4 \u0111un c\u1ee7a s\u1ed1 ph\u1ee9c. Bi\u1ec3u di\u1ec5n h\u00ecnh h\u1ecdc c\u1ee7a s\u1ed1 ph\u1ee9c.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n 1. S\u1ed1 ph\u1ee9c<\/strong><\/p>\n M\u1ed7i bi\u1ec3u th\u1ee9c d\u1ea1ng a + bi, trong \u0111\u00f3: a, b \u2208 R;i2<\/sup>= -1 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 s\u1ed1 ph\u1ee9c. Trong \u0111\u00f3 a \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 ph\u1ea7n th\u1ef1c, b g\u1ecdi l\u00e0 ph\u1ea7n \u1ea3o, s\u1ed1 i l\u00e0 \u0111\u01a1n v\u1ecb \u1ea3o.<\/p>\n 2. M\u00f4 \u0111un<\/strong><\/p>\n Cho s\u1ed1 ph\u1ee9c z = a + bi, \u0111\u01b0\u1ee3c bi\u1ec3u di\u1ec5n b\u1edfi \u0111i\u1ec3m M(a;b) tr\u00ean t\u1ecda \u0111\u1ed9 Oxy. Ta g\u1ecdi m\u00f4 \u0111un c\u1ee7a s\u1ed1 ph\u1ee9c z, k\u00ed hi\u1ec7u l\u00e0 |z| l\u00e0 \u0111\u1ecd d\u00e0i c\u1ee7a vect\u01a1 OM.<\/p>\n <\/p>\n 3. S\u1ed1 ph\u1ee9c li\u00ean h\u1ee3p<\/strong><\/p>\n Cho s\u1ed1 ph\u1ee9c z = a + bi, ta g\u1ecdi a \u2013 bi l\u00e0 s\u1ed1 ph\u1ee9c li\u00ean h\u1ee3p c\u1ee7a z<\/p>\n <\/p>\n B\u00e0i 1 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0Cho h\u00e0m s\u1ed1 f(x)=ax2<\/sup>-2(a+1)x+a+2 (a \u2260 0)<\/span><\/strong><\/p>\n a) Ch\u1ee9ng t\u1ecf r\u1eb1ng ph\u01b0\u01a1ng tr\u00ecnh f(x)=0 lu\u00f4n c\u00f3 nghi\u1ec7m th\u1ef1c. T\u00ednh c\u00e1c nghi\u1ec7m \u0111\u00f3.<\/span><\/strong><\/p>\n b) T\u00ednh t\u1ed5ng S v\u00e0 t\u00edch P c\u1ee7a c\u00e1c nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh f(x) =0. Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb c\u1ee7a S v\u00e0 P theo a.<\/span><\/strong><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u1ea3ng bi\u1ebfn thi\u00ean:<\/strong><\/p>\n <\/p>\n \u0110\u1ed3 th\u1ecb (h\u00ecnh thang tr\u00ean).<\/strong><\/p>\n <\/p>\n \u0110\u1ed3 th\u1ecb ( h\u00ecnh tr\u00ean).<\/strong><\/p>\n <\/p>\n B\u00e0i 2 (trang 145 SGK Gi\u1ea3i t\u00edch 12):\u00a0Cho h\u00e0m s\u1ed1<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 3 (trang 146 SGK Gi\u1ea3i t\u00edch 12):\u00a0Cho h\u00e0m s\u1ed1 y = x3<\/sup>\u00a0+ ax2<\/sup>\u00a0+ bx+1<\/strong><\/span><\/p>\n a) T\u00ecm a v\u00e0 b \u0111\u1ec3 \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 \u0111i qua hai \u0111i\u1ec3m: A(1;2)v\u00e0 B(-2;-1).<\/strong><\/span><\/p>\n b) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb (C ) c\u1ee7a h\u00e0m s\u1ed1 \u1ee9ng v\u1edbi c\u00e1c gi\u00e1 tr\u1ecb t\u00ecm \u0111\u01b0\u1ee3c c\u1ee7a a v\u00e0 b.<\/strong><\/span><\/p>\n c) T\u00ednh th\u1ec3 t\u00edch v\u1eadt th\u1ec3 tr\u00f2n xoay thu \u0111\u01b0\u1ee3c khi quay h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c \u0111\u01b0\u1eddng y = 0, x = 0, x = 1 v\u00e0 \u0111\u1ed3 th\u1ecb (C ) xung quanh tr\u1ee5c ho\u00e0nh.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 4 (trang 146 SGK Gi\u1ea3i t\u00edch 12):\u00a0X\u00e9t chuy\u1ec3n \u0111\u1ed9ng th\u1eb3ng \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh b\u1edfi ph\u01b0\u01a1ng tr\u00ecnh:<\/strong><\/span><\/p>\n Trong \u0111\u00f3 t \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng gi\u00e2y v\u00e0 S \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng m\u00e9t.<\/strong><\/span><\/p>\n a) T\u00ednh v(2), a(2), bi\u1ebft v(t), a(t) l\u1ea7n l\u01b0\u1ee3t l\u00e0 v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c chuy\u1ec3n \u0111\u1ed9ng \u0111\u00e3 cho.<\/strong><\/span><\/p>\n b) T\u00ecm th\u1eddi \u0111i\u1ec3m t m\u00e0 t\u1ea1i \u0111\u00f3 v\u1eadn t\u1ed1c b\u1eb1ng 0.<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Theo \u00fd ngh\u0129a c\u01a1 h\u1ecdc c\u1ee7a \u0111\u1ea1o h\u00e0m ta c\u00f3:<\/p>\n v(t)=s‘<\/sup>(t)=t3<\/sup>-3t2<\/sup>+t-3<\/p>\n v(2)=23<\/sup>-3.22<\/sup>+2-3=-5 (m\/s)<\/p>\n a(t)=v‘<\/sup>(t)=s”<\/sup>(t)=3t2<\/sup>-6t+1<\/p>\n a(2)=3.22<\/sup>-6.2+1=1 (m\/s2<\/sup>)<\/p>\n v(t)=t3<\/sup>-3t2<\/sup>+t-3=0<\/p>\n (t-3)(t1<\/sup>+1)=0 => t = 3<\/p>\n V\u1eady th\u1eddi \u0111i\u1ec3m to<\/sub>=3s th\u00ec v\u1eadn t\u1ed1c b\u1eb1ng 0.<\/p>\n B\u00e0i 5 (trang 146 SGK Gi\u1ea3i t\u00edch 12):\u00a0Cho h\u00e0m s\u1ed1 y = x4<\/sup>\u00a0+ a4<\/sup>\u00a0+ b<\/strong><\/span><\/p>\n a) T\u00ednh a, b \u0111\u1ec3 h\u00e0m s\u1ed1 c\u1ef1c tr\u1ecb b\u1eb1ng 3\/2 khi x =1.<\/strong><\/span><\/p>\n b) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb (C) c\u1ee7a h\u00e0m s\u1ed1 \u0111\u00e3 cho khi:<\/strong><\/span><\/p>\n a=-1\/2,b=1<\/strong><\/span><\/p>\n c) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a (C) t\u1ea1i c\u00e1c \u0111i\u1ec3m c\u00f3 tung \u0111\u1ed9 b\u1eb1ng 1.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 6 (trang 146 SGK Gi\u1ea3i t\u00edch 12):<\/strong><\/span><\/p>\n <\/strong><\/span>a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb (C ) c\u1ee7a h\u00e0m s\u1ed1 khi m = 2.<\/strong><\/span><\/p>\n b) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn d c\u1ee7a \u0111\u1ed3 thi (C ) t\u1ea1i \u0111i\u1ec3m M c\u00f3 ho\u00e0nh \u0111\u1ed9 a \u2260 -1.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 7 (trang 146 SGK Gi\u1ea3i t\u00edch 12):\u00a0Cho h\u00e0m s\u1ed1<\/strong><\/span><\/p>\n <\/p>\n <\/p>\n a) Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb (C ) c\u1ee7a h\u00e0m s\u1ed1 \u0111\u00e3 cho.<\/p>\n b) T\u00ecm giao \u0111i\u1ec3m c\u1ee7a (C ) v\u00e0 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y=x2<\/sup>+1 . Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a (C ) t\u1ea1i m\u1ed7i giao \u0111i\u1ec3m.<\/p>\n c) T\u00ednh th\u1ec3 t\u00edch v\u1eadt tr\u00f2n xoay thu \u0111\u01b0\u1ee3c khi h\u00ecnh ph\u1eb3ng H gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb (C ) v\u00e0 c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng y = 0; x = 1 xung quanh tr\u1ee5c Ox.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u00a0<\/p>\n <\/p>\n B\u00e0i 8 (trang 147 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t v\u00e0 nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n <\/p>\n B\u00e0i 9 (trang 147 SGK Gi\u1ea3i t\u00edch 12):\u00a0Gi\u1ea3i c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n <\/p>\n <\/p>\n <\/p>\n B\u00e0i 10 (trang 147 SGK Gi\u1ea3i t\u00edch 12):\u00a0Gi\u1ea3i c\u00e1c b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh sau:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n <\/p>\n B\u00e0i 11 (trang 147 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ednh c\u00e1c t\u00edch ph\u00e2n sau b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p t\u00edch ph\u00e2n t\u1eebng ph\u1ea7n:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n <\/p>\n B\u00e0i 12 (trang 147 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ednh c\u00e1c t\u00edch ph\u00e2n sau b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ed5i bi\u1ebfn s\u1ed1:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n <\/p>\n B\u00e0i 13 (trang 148 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ednh di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c \u0111\u01b0\u1eddng:<\/strong><\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n <\/p>\n B\u00e0i 14 (trang 148 SGK Gi\u1ea3i t\u00edch 12):\u00a0T\u00ecm th\u1ec3 t\u00edch v\u1eadt th\u1ec3 tr\u00f2n xoay thu \u0111\u01b0\u1ee3c khi quay h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi c\u00e1c \u0111\u01b0\u1eddng y = 2x2<\/sup>\u00a0v\u00e0 y = x3<\/sup>\u00a0xung quanh tr\u1ee5c Ox.<\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ta c\u00f3: 2x2<\/sup>\u00a0= x3<\/sup> \u21d4 x2<\/sup>\u00a0(2 – x) = 0 \u21d4 x = 0 v\u00e0 x = 2<\/p>\n Ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m c\u1ee7a hai \u0111\u01b0\u1eddng cong l\u00e0: x = 0 v\u00e0 x =2<\/p>\n B\u1edfi v\u00ec 2x2<\/sup>=x3<\/sup>=x2<\/sup>\u00a0(2-x)\u22650 v\u1edbi x\u22642 n\u00ean \u0111\u01b0\u1eddng cong y=2x2<\/sup>\u00a0n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng cong y=x3<\/sup>\u00a0trong kho\u1ea3ng (0; 2). Do \u0111\u00f3 th\u1ec3 t\u00edch c\u1ea7n t\u00ednh l\u00e0:<\/p>\n <\/p>\n B\u00e0i 15 (trang 148 SGK Gi\u1ea3i t\u00edch 12):\u00a0Gi\u1ea3i c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau tr\u00ean t\u1eadp s\u1ed1 ph\u1ee9c:<\/strong><\/span><\/p>\n (3+2i)z-(4+7i)=2-5i<\/strong><\/span><\/p>\n (7-3i)z+(2+3i)=(5-4i)z<\/strong><\/span><\/p>\n z2<\/sup>-2z+13=0<\/span><\/p>\n z4<\/sup>-z2<\/sup>-6=0<\/span><\/p>\n L\u1eddi gi\u1ea3i<\/strong><\/p>\n