Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh<\/p>\n<\/div>\n
C\u00e2u 1:<\/strong>(ID:91203) <\/strong>M\u1ed9t gia \u0111\u00ecnh: ch\u1ed3ng c\u00f3 m\u1ed9t t\u00fam l\u00f4ng \u1edf tai, v\u1ee3 b\u00ecnh th\u01b0\u1eddng. C\u00e1c con trai c\u1ee7a h\u1ecd<\/p>\n A. <\/strong>t\u1ea5t c\u1ea3 \u0111\u1ec1u c\u00f3 t\u00fam l\u00f4ng \u1edf tai<\/p>\n B. <\/strong>m\u1ed9t n\u1eeda b\u00ecnh th\u01b0\u1eddng, m\u1ed9t n\u1eeda c\u00f3 t\u00fam l\u00f4ng \u1edd tai.<\/p>\n C.<\/strong>t\u1ea5t c\u1ea3 \u0111\u1ec1u b\u00ecnh th\u01b0\u1eddng.<\/p>\n D.<\/strong>m\u1ed9t ph\u1ea7n t\u01b0 c\u00f3 t\u00fam l\u00f4ng \u1edf tai, ba ph\u1ea7n t\u01b0 b\u00ecnh th\u01b0\u1eddng<\/p>\n C\u00e2u 2<\/strong>:(ID:91204)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt, alen A quy \u0111\u1ecbnh th\u00e2n cao tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen a quy \u0111\u1ecbnh th\u00e2n th\u1ea5p; alen B quy \u0111\u1ecbnh hoa \u0111\u1ecf tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen b quy \u0111\u1ecbnh hoa tr\u1eafng; alen D quy \u0111\u1ecbnh qu\u1ea3 tr\u00f2n tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen d quy \u0111\u1ecbnh qu\u1ea3 d\u00e0i. Cho c\u00e2y th\u00e2n cao, hoa \u0111\u1ecf, qu\u1ea3 tr\u00f2n (P) t\u1ef1 th\u1ee5 ph\u1ea5n, thu \u0111\u01b0\u1ee3c F<\/p>\n g\u1ed3m 301 c\u00e2y th\u00e2n cao, hoa \u0111\u1ecf, qu\u1ea3 d\u00e0i; 99 c\u00e2y th\u00e2n cao, hoa tr\u1eafng, qu\u1ea3 d\u00e0i; 600 c\u00e2y th\u00e2n cao, hoa \u0111\u1ecf, qu\u1ea3 tr\u00f2n; 199 c\u00e2y th\u00e2n cao, hoa tr\u1eafng, qu\u1ea3 tr\u00f2n; 301 c\u00e2y th\u00e2n th\u1ea5p, hoa \u0111\u1ecf, qu\u1ea3 tr\u00f2n; 100 c\u00e2y th\u00e2n th\u1ea5p, hoa tr\u1eafng, qu\u1ea3 tr\u00f2n. Bi\u1ebft r\u1eb1ng kh\u00f4ng x\u1ea3y ra \u0111\u1ed9t bi\u1ebfn, ki\u1ec3u gen c\u1ee7a (P) l\u00e0 <\/p>\n<\/div>\n A.<\/strong>Aa Bd \/bD<\/p>\n B. <\/strong>AD\/ad Bb<\/p>\n C.<\/strong>AB\/abDd<\/p>\n D.<\/strong> Ad\/aDBb <\/p>\n<\/div>\n C\u00e2u 3<\/strong>:(ID:91205)<\/strong>H\u00ecnh b\u00ean ghi l\u1ea1i \u0111\u01b0\u1eddng cong t\u0103ng tr\u01b0\u1edfng c\u1ee7a c\u1ee7a qu\u1ea7n th\u1ec3 tr\u00f9ng \u0111\u1ebf gi\u00e0y \u0111\u01b0\u1ee3c nu\u00f4i trong ph\u00f2ng th\u00ed nghi\u1ec7m. Qu\u1ea7n th\u1ec3 n\u00e0y:<\/p>\n A. <\/strong>c\u00f3 \u0111i\u1ec1u ki\u1ec7n s\u1ed1ng ho\u00e0n to\u00e0n tho\u1ea3 m\u00e3n nhu c\u1ea7u c\u1ee7a c\u00e1c c\u00e1 th\u1ec3.<\/p>\n B. <\/strong>c\u00f3 ngu\u1ed3n s\u1ed1ng d\u1ed3i d\u00e0o, kh\u00f4ng gian c\u01b0 tr\u00fa kh\u00f4ng gi\u1edbi h\u1ea1n<\/p>\n C.<\/strong>t\u0103ng tr\u01b0\u1eddng theo ti\u1ec1m n\u0103ng sinh h\u1ecdc<\/p>\n D.<\/strong>c\u00f3 \u0111i\u1ec1u s\u1ed1ng kh\u00f4ng ho\u00e0n to\u00e0n thu\u1eadn l\u1ee3i<\/p>\n C\u00e2u 4:<\/strong>(ID:91206)<\/strong>M\u1ed9t gen \u1edf t\u1ebf b\u00e0o nh\u00e2n s\u01a1 c\u00f3 2400 nucl\u00ea\u00f4tit. Tr\u00ean m\u1ea1ch 1 c\u1ee7a gen, hi\u1ec7u s\u1ed1 t\u1ec9 l\u1ec7 % gi\u1eefa A v\u1edbi T b\u1eb1ng 20% s\u1ed1 nucl\u00ea\u00f4tit c\u1ee7a m\u1ea1ch. Tr\u00ean m\u1ea1ch 2 c\u00f3 s\u1ed1 nucl\u00ea\u00f4tit lo\u1ea1i A chi\u1ebfm 15% s\u1ed1 nucl\u00ea\u00f4tit c\u1ee7a m\u1ea1ch v\u00e0 b\u1eb1ng 1\/2 s\u1ed1 nucl\u00ea\u00f4tit c\u1ee7a G. Khi gen phi\u00ean m\u00e3 1 s\u1ed1 l\u1ea7n \u0111\u00e3 l\u1ea5y t\u1eeb m\u00f4i tr\u01b0\u1eddng n\u1ed9i b\u00e0o 540 Uraxin. S\u1ed1 l\u01b0\u1ee3ng nucl\u00ea\u00f4tit t\u1eebng lo\u1ea1i tr\u00ean mARN \u0111\u01b0\u1ee3c t\u1ed5ng h\u1ee3p t\u1eeb gen n\u00f3i tr\u00ean l\u00e0<\/p>\n A.<\/strong>A = 180 ; U = 420 ; X = 240 ; G = 360.<\/p>\n B.<\/strong>A= 180 ; U = 420 ; X = 360 ; G = 240.<\/p>\n C.<\/strong>A = 420 ; U = 180 ; X = 360 ; G = 240<\/p>\n D.<\/strong>A = 840 ; U = 360 ; X = 720 ; G = 480<\/p>\n C\u00e2u<\/strong>5<\/strong>: (ID:91207)<\/strong>B\u1ec7nh Ph\u00eanink\u00eato ni\u1ec7u l\u00e0 b\u1ec7nh di truy\u1ec1n do m\u1ed9t \u0111\u1ed9t bi\u1ebfn gen l\u1eb7n n\u1eb1m tr\u00ean NST th\u01b0\u1eddng. Trong m\u1ed9t gia \u0111\u00ecnh, c\u1ea3 b\u1ed1 v\u00e0 m\u1eb9 \u0111\u1ec1u d\u1ecb h\u1ee3p t\u1eed v\u1ec1 b\u1ec7nh n\u00e0y. X\u00e1c su\u1ea5t \u0111\u1ec3 h\u1ecd sinh l\u1ea7n l\u01b0\u1ee3t 1 con trai b\u1ecb b\u1ec7nh, 1 con trai b\u00ecnh th\u01b0\u1eddng v\u00e0 1 con g\u00e1i b\u00ecnh th\u01b0\u1eddng l\u00e0 bao nhi\u00eau?<\/p>\n A.<\/strong>56,25%. B.<\/strong>1,7578%. C.<\/strong>18,75%. D.<\/strong>14,0625%.<\/p>\n C\u00e2u 6:<\/strong>(ID:91208)<\/strong>Trong qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a m\u1ed9t t\u1ebf b\u00e0o sinh tinh \u1edf c\u01a1 th\u1ec3 c\u00f3 ki\u1ec3u gen AB\/ab \u0111\u00e3 x\u1ea3y ra ho\u00e1n v\u1ecb gen gi\u1eefa alen A v\u00e0 a.<\/strong>Cho bi\u1ebft kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn x\u1ea3y ra.<\/strong>t\u00ednh theo l\u00fd thuy\u1ebft, s\u1ed1 lo\u1ea1i giao t\u1eed v\u00e0 t\u1ec9 l\u1ec7 t\u1eebng lo\u1ea1i giao t\u1eed \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1eeb qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a t\u1ebf b\u00e0o tr\u00ean l\u00e0<\/p>\n A. <\/strong>4 lo\u1ea1i v\u1edbi t\u1ec9 l\u1ec7 1 : 1 : 1 : 1.<\/p>\n B. <\/strong>2 lo\u1ea1i v\u1edbi t\u1ec9 l\u1ec7 1 : l<\/p>\n C.<\/strong>4 lo\u1ea1i v\u1edbi t\u1ec9 l\u1ec7 ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb gen.<\/p>\n D.<\/strong>2 lo\u1ea1i v\u1edbi t\u1ec9 l\u1ec7 ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb gen.<\/p>\n C\u00e2u 7<\/strong>:(ID:91209)<\/strong>Gen A c\u00f3 chi\u1ec1u d\u00e0i 2805A<\/p>\n v\u00e0 2074 li\u00ean k\u1ebft H. Gen b\u1ecb \u0111\u1ed9t bi\u1ebfn \u0111i\u1ec3m l\u00e0m gi\u1ea3m 3 li\u00ean k\u1ebft hi\u0111r\u00f4 th\u00e0nh genA<\/strong>.<\/strong>S\u1ed1 nucleotit m\u1ed7i lo\u1ea1i m\u00e0 m\u00f4i tr\u01b0\u1eddng cung c\u1ea5p cho c\u1eb7p gen Aa nh\u00e2n \u0111\u00f4i 3 l\u1ea7n l\u00e0 bao nhi\u00eau?<\/p>\n A. <\/strong>A= T = 5635; G = X = 5915. <\/p>\n B. <\/strong>A= T = 2807; G= X = 2968.<\/p>\n C. <\/strong>A = T = 2807; G=X = 2961.<\/p>\n D. <\/strong>A= T = 5614; G=X = 5929<\/p>\n C\u00e2u 8<\/strong>:ID:91210)<\/strong>C\u00e1c nh\u00e0 khoa h\u1ecdc Vi\u1ec7t Nam \u0111\u00e3 lai gi\u1ed1ng c\u00e2y d\u00e2u t\u1eb1m t\u1ee9 b\u1ed9i v\u1edbi gi\u1ed1ng c\u00e2y d\u00e2u t\u1eb1m l\u01b0\u1ee1ng b\u1ed9i t\u1ea1o gi\u1ed1ng c\u00e2y d\u00e2u t\u1eb1m tam b\u1ed9i d\u00f9ng cho ch\u0103n nu\u00f4i t\u1eb1m m\u00e0 kh\u00f4ng d\u00f9ng tr\u1ef1c ti\u1ebfp gi\u1ed1ng d\u00e2u t\u1eb1m t\u1ee9 b\u1ed9i v\u00ec<\/p>\n A.<\/strong>gi\u1ed1ng tam b\u1ed9i th\u01b0\u1eddng h\u1eefu th\u1ee5 n\u00ean cho c\u1ea3 l\u00e1 v\u00e0 qu\u1ea3 mang l\u1ea1i hi\u1ec7u qu\u1ea3 kinh t\u1ebf cao h\u01a1n gi\u1ed1ng t\u1ee9 b\u1ed9i.<\/p>\n B.<\/strong>gi\u1ed1ng tam b\u1ed9i c\u00f3 kh\u1ea3 n\u0103ng ch\u1ed1ng ch\u1ecbu v\u1edbi \u0111i\u1ec1u ki\u1ec7n b\u1ea5t l\u1ee3i c\u1ee7a ngo\u1ea1i c\u1ea3nh cao h\u01a1n gi\u1ed1ng t\u1ee9 b\u1ed9i.<\/p>\n C.<\/strong>gi\u1ed1ng tam b\u1ed9i th\u01b0\u1eddng b\u1ea5t th\u1ee5 n\u00ean c\u00f3 th\u1eddi gian sinh tr\u01b0\u1edfng d\u00e0i cho n\u0103ng su\u1ea5t l\u00e1 cao h\u01a1n gi\u1ed1ng t\u1ee9 b\u1ed9i.<\/p>\n D.<\/strong>gi\u1ed1ng tam b\u1ed9i c\u00f3 k\u00edch th\u01b0\u1edbc c\u01a1 quan sinh d\u01b0\u1ee1ng l\u1edbn n\u00ean cho n\u0103ng su\u1ea5t l\u00e1 cao h\u01a1n gi\u1ed1ng t\u1ee9 b\u1ed9i.<\/p>\n C\u00e2u 9<\/strong>:(ID:91211)<\/strong>Nhi\u1ec1u th\u1eed nghi\u1ec7m \u0111\u00e3 \u0111\u01b0\u1ee3c ti\u1ebfn h\u00e0nh \u0111\u1ec3 \u0111\u00e1nh gi\u00e1 kh\u1ea3 n\u0103ng tr\u00ed tu\u1ec7 c\u1ee7a con ng\u01b0\u1eddi. S\u1ef1 \u0111\u00e1nh gi\u00e1 d\u1ef1a v\u00e0o c\u00e1c tr\u1eafc nghi\u1ec7m v\u1edbi c\u00e1c b\u00e0i t\u1eadp c\u00f3 \u0111\u1ed9 kh\u00f3 t\u0103ng d\u1ea7n th\u00f4ng qua c\u00e1c h\u00ecnh v\u1ebd, c\u00e1c con s\u1ed1 v\u00e0 c\u00e1c c\u00e2u h\u1ecfi. Ch\u1ec9 s\u1ed1 IQ \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh b\u1eb1ng<\/p>\n A. <\/strong>t\u1ed5ng trung b\u00ecnh c\u1ee7a c\u00e1c l\u1eddi gi\u1ea3i \u0111\u01b0\u1ee3c t\u00ednh th\u1ed1ng k\u00ea theo tu\u1ed5i tr\u00ed tu\u1ec7 chia cho tu\u1ed5i kh\u00f4n v\u00e0 nh\u00e2n 100<\/p>\n B. <\/strong>t\u1ed5ng trung b\u00ecnh c\u1ee7a c\u00e1c l\u1eddi gi\u1ea3i \u0111\u01b0\u1ee3c t\u00ednh th\u1ed1ng k\u00ea theo tu\u1ed5i kh\u00f4n chia cho tu\u1ed5i sinh h\u1ecdc v\u00e0 nh\u00e2n 100<\/p>\n C. <\/strong> t\u1ed5ng trung b\u00ecnh c\u1ee7a c\u00e1c l\u1eddi gi\u1ea3i \u0111\u01b0\u1ee3c t\u00ednh th\u1ed1ng k\u00ea theo tu\u1ed5i kh\u00f4n chia cho tu\u1ed5i tr\u00ed tu\u1ec7 v\u00e0 nh\u00e2n 100<\/p>\n D. <\/strong>t\u00f4ng trung b\u00ecnh c\u1ee7a c\u00e1c l\u1eddi gi\u1ea3i \u0111\u01b0\u1ee3c t\u00ednh th\u00f4ng k\u00ea theo tu\u1ed5i sinh h\u1ecdc chia cho tu\u1ed5i kh\u00f4n v\u00e0 nh\u00e2n v\u1edbi 100<\/p>\n C\u00e2u 10:<\/strong>(ID:91212)<\/strong>Hi\u1ec7n t\u01b0\u1ee3ng n\u00e0o sau \u0111\u00e2y \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng l\u1ea1i t\u1ed5?<\/p>\n A.<\/strong>ng\u01b0\u1eddi c\u00f3 3 \u0111\u1ebfn 4 \u0111\u00f4i v\u00fa. <\/p>\n B.<\/strong>ph\u00f4i ng\u01b0\u1eddi giai \u0111o\u1ea1n 5 th\u00e1ng c\u00f3 \u0111u\u00f4i,<\/p>\n C.<\/strong>ngu\u1eddi \u0111i xa tr\u1edf v\u1ec1 th\u0103m qu\u00ea h\u01b0\u01a1ng, t\u1ed3 ti\u00ean.<\/p>\n D.<\/strong>ng\u01b0\u1eddi c\u00f3 ru\u1ed9t th\u1eeba v\u00e0 n\u1ebfp th\u1ecbt \u1edf kho\u00e9 m\u1eaft.<\/p>\n C\u00e2u 11<\/strong>:(ID:91213)<\/strong>Cho c\u00e1c ph\u01b0\u01a1ng ph\u00e1p sau:<\/p>\n Trong c\u00e1c ph\u01b0\u01a1ng ph\u00e1p k\u1ec3 tr\u00ean c\u00f3 m\u1ea5y ph\u01b0\u01a1ng ph\u00e1p t\u1ea1o gi\u1ed1ng m\u1edbi?<\/p>\n<\/div>\n A.<\/strong>5 <\/p>\n B.<\/strong>6. <\/p>\n C.<\/strong>3. <\/p>\n D.<\/strong>4. <\/p>\n<\/div>\n C\u00e2u 12:<\/strong>(ID:91214)<\/strong>Ng\u01b0\u1eddi ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng d\u1ea1ng \u0111\u1ed9t bi\u1ebfn c\u1ea5u tr\u00fac n\u00e0o sau \u0111\u00e2y \u0111\u1ec3 lo\u1ea1i b\u1ecf nh\u1eefng gen kh\u00f4ng mong mu\u1ed1n ra kh\u1ecfi nhi\u1ec5m s\u1eafc th\u1ec3?<\/p>\n A. <\/strong>\u0110\u1ed9t bi\u1ebfn chuy\u1ec3n \u0111o\u1ea1n nhi\u1ec5m s\u1eafc th\u1ec3. <\/p>\n B. <\/strong>\u0110\u1ed9t bi\u1ebfn m\u1ea5t \u0111o\u1ea1n nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\n C. <\/strong>\u0110\u1ed9t bi\u1ebfn \u0111\u1ea3o \u0111o\u1ea1n nhi\u1ec5m s\u1ea5c th\u1ec3<\/p>\n D. <\/strong> \u0110\u1ed9t bi\u1ebfn l\u1eb7p \u0111o\u1ea1n nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\n C\u00e2u 13:<\/strong>(ID:91215)<\/strong>N\u1ed9i dung n\u00e0o kh\u00f4ng \u0111\u00fang v\u1edbi quy lu\u1eadt ph\u00e2n ly?<\/p>\n A.<\/strong>m\u1ed7i t\u00ednh tr\u1ea1ng \u0111\u01b0\u1ee3c quy \u0111\u1ecbnh b\u1edfi m\u1ed9t c\u1eb7p alen.<\/p>\n B.<\/strong>khi gi\u1ea3m ph\u00e2n c\u1eb7p nh\u00e2n t\u1ed1 di truy\u1ec1n ph\u00e2n ly \u0111\u1ed3ng \u0111\u1ec1u v\u1ec1 c\u00e1c giao t\u1eed.<\/p>\n C.<\/strong>c\u00e1c c\u1eb7p alen ph\u00e2n ly \u0111\u1ed9c l\u1eadp v\u00e0 t\u1ed5 h\u1ee3p t\u1ef1 do trong qu\u00e1 tr\u00ecnh h\u00ecnh th\u00e0nh giao t\u1eed.<\/p>\n D.<\/strong>s\u1ef1 ph\u00e2n ly c\u1ee7a c\u1eb7p NST t\u01b0\u01a1ng \u0111\u1ed3ng d\u1eabn \u0111\u1ebfn s\u1ef1 ph\u00e2n ly c\u1ee7a c\u1eb7p alen t\u01b0\u01a1ng \u1ee9ng.<\/p>\n C\u00e2u 14<\/strong>:(ID:91216)<\/strong>Trong m\u1ed9t ph\u00e9p lai ph\u00e2n t\u00edch gi\u1eefa c\u00e2y ng\u00f4 d\u1ecb h\u1ee3p t\u1eed v\u1ec1 3 gen v\u1edbi c\u00e2y \u0111\u1ed3ng h\u1ee3p t\u1eed l\u1eb7n v\u1ec1 3 gen \u0111\u00f3, thu \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 sau:A-B-C-: 113 c\u00e2y; aabbcc: 105 c\u00e2y; A-B-cc: 70 c\u00e2y; aabbC-: 64 c\u00e2y; A-bbcc: 17 c\u00e2y; aaB-C-:21 c\u00e2y.Tr\u1eadt t\u1ef1 ph\u00e2n b\u1ed1 3 gen v\u00e0 kho\u1ea3ng c\u00e1ch gi\u1eefa c\u00e1c gen l\u00e0<\/p>\n A.<\/strong>BAC; AB-9,7; BC-34,4. B.<\/strong>ABC; AB-9,7; BC-34,4.<\/p>\n C.<\/strong>BAC; AB- 34,4; BC-9,7<\/p>\n D.<\/strong>ABC; AB-34,4; BC-9,7.<\/p>\n C\u00e2u 1<\/strong>5<\/strong>:<\/strong>(ID:91217)<\/strong>Qu\u1ea7n th\u1ec3 (Q) t\u1ef1 th\u1ee5 ph\u1ea5n qua 2 th\u1ebf h\u1ec7 t\u1ea1o n\u00ean qu\u1ea7n th\u1ec3 (Q<\/p>\n ) c\u00f3 th\u00e0nh ph\u1ea7n ki\u1ec3u gen l\u00e0 0,525AA:0,15Aa:0,325aa.<\/strong>Bi\u1ebft r\u1eb1ng qu\u00e1 tr\u00ecnh n\u00e0y kh\u00f4ng ch\u1ecbu t\u00e1c \u0111\u1ed9ng c\u1ee7a c\u00e1c nh\u00e2n t\u1ed1 ti\u1ebfn h\u00f3a kh\u00e1c.<\/strong>Th\u00e0nh ph\u1ea7n ki\u1ec3u gen c\u1ee7a qu\u1ea7n th\u1ec3 (Q) l\u00e0: <\/p>\n<\/div>\n A.<\/strong>0,35AA:0,6Aa:0,05aa <\/p>\n B.<\/strong>0,1AA:0,6Aa:0,3aa.<\/strong><\/p>\n C.<\/strong>0,3AA:0,6Aa:0,laa.<\/strong> <\/p>\n D.<\/strong>0,05AA:0,6Aa:0,35aa.<\/strong> <\/p>\n<\/div>\n C\u00e2u 16:<\/strong>(ID:91218)<\/strong>Cho c\u00e1 th\u1ec3 m\u1eaft \u0111\u1ecf thu\u1ea7n ch\u1ee7ng lai v\u1edbi c\u00e1 th\u1ec3 m\u1eaft tr\u1eafng \u0111\u01b0\u1ee3c F<\/p>\n \u0111\u1ec1u m\u1eaft \u0111\u1ecf. Cho con c\u00e1i F<\/p>\n lai ph\u00e2n t\u00edch v\u1edbi \u0111\u1ef1c m\u1eaft tr\u1eafng thu \u0111\u01b0\u1ee3c t\u1ec9 l\u1ec7 3 m\u1eaft tr\u1eafng: 1 m\u1eaft \u0111\u1ecf, trong \u0111\u00f3 m\u1eaft \u0111\u1ecf \u0111\u1ec1u l\u00e0 con \u0111\u1ef1c.<\/strong>K\u1ebft lu\u1eadn n\u00e0o sau l\u00e0 \u0111\u00fang<\/p>\n A.<\/strong>M\u00e0u m\u1eaft di truy\u1ec1n tr\u1ed9i l\u1eb7n ho\u00e0n to\u00e0n P \u2640X<\/p>\n X<\/p>\n \u2642X<\/p>\n Y<\/p>\n B.<\/strong>M\u00e0u m\u1eaft di truy\u1ec1n theo tr\u1ed9i ho\u00e0n to\u00e0n. P: \u2640X<\/p>\n X<\/p>\n \u2642 X<\/p>\n Y.<\/p>\n C.<\/strong>M\u00e0u m\u1eaft di truy\u1ec1n theo t\u01b0\u01a1ng t\u00e1c b\u1ed5 sung. P: \u2640AAX<\/p>\n X<\/p>\n \u2642 aaX<\/p>\n Y.<\/p>\n D.<\/strong>M\u00e0u m\u1eaft di truy\u1ec1n theo t\u01b0\u01a1ng t\u00e1c b\u1ed5 sung. \u2642 P: AAX<\/p>\n X<\/p>\n \u2640aaX<\/p>\n Y.<\/p>\n C\u00e2u 17<\/strong>:(ID:91219)<\/strong>T\u1eeb qu\u1ea7n th\u1ec3 c\u00e2y 2n, ng\u01b0\u1eddi ta t\u1ea1o \u0111\u01b0\u1ee3c qu\u1ea7n th\u1ec3 c\u00e2y 4n, c\u00f3 th\u1ec3 xem qu\u1ea7n th\u1ec3 c\u00e2y 4n l\u00e0 m\u1ed9t lo\u00e0i m\u1edbi v\u00ec qu\u1ea7n th\u1ec3 c\u00e2y 4n<\/p>\n A. <\/strong>c\u00f3 s\u1ef1 kh\u00e1c bi\u1ec7t v\u1edbi qu\u1ea7n th\u1ec3 c\u00e2y 2n v\u1ec1 s\u1ed1 l\u01b0\u1ee3ng nhi\u1ec5m s\u1eafc th\u1ec3<\/p>\n B. <\/strong>khi giao ph\u1ea5n v\u1edbi qu\u1ea7n th\u1ec3 c\u00e2v 2n cho ra con lai b\u1ea5t th\u1ee5.<\/p>\n C. <\/strong>C\u00f3 \u0111\u1eb7c \u0111i\u1ec3m h\u00ecnh th\u1ea3i kh\u00e1c h\u1eb3n qu\u1ea7n th\u1ec3 c\u00e2y 2n.<\/p>\n D.<\/strong>kh\u00f4ng th\u1ec3 giao ph\u1ea5n v\u1edbi qu\u1ea7n th\u1ec3 c\u00e2y 2n.<\/p>\n C\u00e2u 18:<\/strong>(ID:91220)<\/strong>Theo qui lu\u1eadt di truy\u1ec1n ph\u00e2n ly \u0111\u1ed9c l\u1eadp, v\u1edbi c\u00e1c gen tr\u1ed9i l\u1eb7n ho\u00e0n to\u00e0n. N\u1ebfu P thu\u1ea7n ch\u1ee7ng kh\u00e1c nhau b\u1edfi n c\u1eb7p t\u00ednh tr\u1ea1ng t\u01b0\u01a1ng ph\u1ea3n th\u00ec s\u1ed1 l\u01b0\u1ee3ng ki\u1ec3u gen c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1ed1i \u0111a \u1edf F<\/p>\n l\u00e0<\/p>\n<\/div>\n A.<\/strong>5<\/p>\n B.<\/strong>2<\/p>\n C.<\/strong>4<\/p>\n <\/p>\n D.<\/strong>3<\/p>\n .<\/p>\n<\/div>\n C\u00e2u 19<\/strong>:(ID:91221)<\/strong>\u1edf m\u1ed9t lo\u00e0i th\u00fa, x\u00e9t m\u1ed9t gen c\u00f3 2 alen A v\u00e0 a n\u1eb1m tr\u00ean NST gi\u1edbi t\u00ednh X. Bi\u1ebft r\u1eb1ng qu\u1ea7n th\u1ec3 kh\u1edfi \u0111\u1ea7u c\u00f3 t\u1ec9 l\u1ec7 c\u00e1c ki\u1ec3u gen l\u00e0 0,7X<\/p>\n Y : 0,3X<\/p>\n