\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh n\u0103m 2016 t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 3, \u0111\u1ec1 thi g\u1ed3m 50 c\u00e2u h\u1ecfi v\u00e0 \u0111\u01b0\u1ee3c gi\u1ea3i \u0111\u00e1p chi ti\u1ebft d\u01b0\u1edbi \u0111\u00e2y:<\/strong><\/h2>\n

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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh<\/p>\n<\/div>\n

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C\u00e2u 1. (ID: 82627)<\/strong>\u1ede sinh v\u1eadt nh\u00e2n th\u1ef1c, codon n\u00e0o sau \u0111\u00e2y m\u00e3 h\u00f3a axit amin m\u00eati\u00f4nin?<\/p>\n

A. 5\u2019AGU3\u2019        B.<\/strong>5\u2019UUG3\u2019       C.<\/strong>5\u2019UAG3\u2019       D.<\/strong>5\u2019AUG3\u2019<\/p>\n

C\u00e2u 2. (ID: 82628)<\/strong> \u0110\u1eb7c \u0111i\u1ec3m di truy\u1ec1n c\u1ee7a gen ngo\u00e0i nh\u00e2n<\/p>\n

A.<\/strong>K\u1ebft qu\u1ea3 lai thu\u1eadn ngh\u1ecbch kh\u00e1c nhau, t\u00ednh tr\u1ea1ng bi\u1ec3u hi\u1ec7n \u0111\u1ed3ng \u0111\u1ec1u \u1edf 2 gi\u1edbi.<\/p>\n

B. <\/strong>K\u1ebft qu\u1ea3 lai thu\u1eadn ngh\u1ecbch gi\u1ed1ng nhau, con lai lu\u00f4n bi\u1ec3u hi\u1ec7n t\u00ednh tr\u1ea1ng c\u1ee7a m\u1eb9<\/p>\n

C.<\/strong>K\u1ebft qu\u1ea3 lai thu\u1eadn ngh\u1ecbch gi\u1ed1ng nhau, t\u00ednh tr\u1ea1ng bi\u1ec3u hi\u1ec7n \u0111\u1ed3ng \u0111\u1ec1u \u1edf 2 gi\u1edbi.<\/p>\n

D.<\/strong>K\u1ebft qu\u1ea3 lai thu\u1eadn ngh\u1ecbch kh\u00e1c nhau \u1edf 2 gi\u1edbi<\/p>\n

C\u00e2u 3. (ID: 82629 )<\/strong>Theo d\u00f5i s\u1ef1 di truy\u1ec1n c\u1ee7a 2 c\u1eb7p t\u00ednh tr\u1ea1ng \u0111\u01b0\u1ee3c quy \u0111\u1ecbnh b\u1edfi 2 c\u1eb7p gen v\u00e0 di truy\u1ec1n tr\u1ed9i ho\u00e0n to\u00e0n. N\u1ebfu F<\/p>\n

1<\/dd>\n

c\u00f3 t\u1ef7 l\u1ec7 ki\u1ec3u h\u00ecnh 7A-B- : 8A-bb : 3aaB- : 2aabb th\u00ec ki\u1ec3u gen c\u1ee7a P v\u00e0 t\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb gen l\u00e0<\/p>\n

A.<\/strong>AB\/ab x AB\/ab; ho\u00e1n v\u1ecb 2 b\u00ean v\u1edbi f = 25%            B. <\/strong>Ab\/aB x Ab\/aB; f = 8,65%<\/p>\n

C.<\/strong>AB\/ab x Ab\/ab; f = 25%                                    D.<\/strong>Ab\/aB x Ab\/ab; f = 40%<\/p>\n

C\u00e2u 4: (ID :<\/strong>82630 )<\/strong>Th\u1ef1c ch\u1ea5t c\u1ee7a th\u01b0\u1eddng bi\u1ebfn l\u00e0?<\/p>\n

A.<\/strong>Thay \u0111\u1ed5i ki\u1ec3u gen, kh\u00f4ng thay \u0111\u1ed5i ki\u1ec3u h\u00ecnh                     B. <\/strong>Kh\u00f4ng thay \u0111\u1ed5i ki\u1ec3u gen, kh\u00f4ng thay \u0111\u1ed5i ki\u1ec3u h\u00ecnh<\/p>\n

C.<\/strong>Kh\u00f4ng thay \u0111\u1ed5i ki\u1ec3u gen, ch\u1ec9 thay \u0111\u1ed5i ki\u1ec3u h\u00ecnh                D.<\/strong>Thay \u0111\u1ed5i ki\u1ec3u gen, thay \u0111\u1ed5i ki\u1ec3u h\u00ecnh<\/p>\n

C\u00e2u 5. (ID :<\/strong>82631 )<\/strong>T\u1ea7n s\u1ed1 c\u1ee7a m\u1ed9t lo\u1ea1i ki\u1ec3u gen n\u00e0o \u0111\u00f3 trong qu\u1ea7n th\u1ec3 \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng t\u1ec9 l\u1ec7 gi\u1eefa<\/p>\n

A.<\/strong>S\u1ed1 c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen \u0111\u00f3 tr\u00ean t\u1ed5ng s\u1ed1 c\u00e1 th\u1ec3 c\u1ee7a qu\u1ea7n th\u1ec3<\/p>\n

B. <\/strong>S\u1ed1 l\u01b0\u1ee3ng alen \u0111\u00f3 tr\u00ean t\u1ed5ng s\u1ed1 alen c\u1ee7a qu\u1ea7n th\u1ec3<\/p>\n

C.<\/strong>S\u1ed1 c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen \u0111\u00f3 tr\u00ean t\u1ed5ng s\u1ed1 alen c\u1ee7a qu\u1ea7n th\u1ec3<\/p>\n

D.<\/strong>S\u1ed1 l\u01b0\u1ee3ng alen \u0111\u00f3 tr\u00ean t\u1ed5ng s\u1ed1 c\u00e1 th\u1ec3 c\u1ee7a qu\u1ea7n th\u1ec3<\/p>\n

C\u00e2u 6<\/strong>.(ID :<\/strong>82632)<\/strong>C\u00e1c ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y m\u00f4 t\u1ea3 qu\u00e1 tr\u00ecnh phi\u00ean m\u00e3 \u1edf sinh v\u1eadt nh\u00e2n s\u01a1 v\u00e0 sinh v\u1eadt nh\u00e2n th\u1ef1c, trong c\u00e1c ph\u00e1t bi\u1ec3u th\u00ec c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang<\/p>\n

(1)Enzim tham gia v\u00e0o qu\u00e1 tr\u00ecnh phi\u00ean m\u00e3 l\u00e0 enzim ARN p\u00f4limeraza<\/p>\n

(2)Phi\u00ean m\u00e3 b\u1eaft \u0111\u1ea7u t\u1eeb v\u00f9ng \u0111i\u1ec1u h\u00f2a c\u1ee7a gen<\/p>\n

(3)M\u1ea1ch khu\u00f4n \u0111\u01b0\u1ee3c d\u00f9ng \u0111\u1ec3 t\u1ed5ng h\u1ee3p ARN c\u00f3 chi\u1ec1u 5\u2019 \u2013 3\u2019 ho\u1eb7c 3\u2019 \u2013 5\u2019<\/p>\n

(4)Qu\u00e1 tr\u00ecnh t\u1ed5ng h\u1ee3p mARN di\u1ec5n ra theo nguy\u00ean t\u1eafc b\u1ed5 sung A-U, T-A, G-X, X-G<\/p>\n

(5)Enzim p\u00f4limeraza tr\u01b0\u1ee3t tr\u00ean m\u1ea1ch khu\u00f4n theo chi\u1ec1u 3\u2019 \u2013 5\u2019.<\/p>\n

(6)Qu\u00e1 tr\u00ecnh phi\u00ean m\u00e3 s\u1eed d\u1ee5ng c\u1ea3 2 m\u1ea1ch c\u1ee7a gen l\u00e0m khu\u00f4n<\/p>\n<\/div>\n

A.<\/strong>5                 B. <\/strong>4          C.<\/strong>3                D.<\/strong>6<\/p>\n

C\u00e2u 7<\/strong>.(ID :<\/strong>82633)<\/strong>Trong qu\u00e1 tr\u00ecnh ph\u00e1t tri\u1ec3n ph\u00f4i s\u1edbm \u1edf ru\u1ed3i gi\u1ea5m \u0111\u1ef1c c\u00f3 th\u00e0nh ph\u1ea7n ki\u1ec3u gen AaBbddXY, \u1edf l\u1ea7n ph\u00e2n b\u00e0o th\u1ee9 4 ng\u01b0\u1eddi ta th\u1ea5y \u1edf m\u1ed9t s\u1ed1 t\u1ebf b\u00e0o c\u1eb7p NST mang c\u1eb7p gen Dd kh\u00f4ng ph\u00e2n ly. Cho r\u1eb1ng ph\u00f4i \u0111\u00f3 ph\u00e1t tri\u1ec3n th\u00e0nh th\u1ec3 \u0111\u1ed9t bi\u1ebfn th\u00ec c\u00f3 m\u1ea5y d\u00f2ng t\u1ebf b\u00e0o kh\u00e1c nhau v\u1ec1 s\u1ed1 l\u01b0\u1ee3ng nhi\u1ec5m s\u1eafc th\u1ec3?<\/p>\n

A.<\/strong>2 d\u00f2ng t\u1ebf b\u00e0o \u0111\u1ed9t bi\u1ebfn ( n + 1 v\u00e0 n \u2013 1)<\/p>\n

B. <\/strong>1 d\u00f2ng t\u1ebf b\u00e0o b\u00ecnh th\u01b0\u1eddng (2n) v\u00e0 2 d\u00f2ng t\u1ebf b\u00e0o d\u1ed9t bi\u1ebfn (2n+1 v\u00e0 2n-1)<\/p>\n

C.<\/strong>1 d\u00f2ng t\u1ebf b\u00e0o b\u00ecnh th\u01b0\u1eddng (n) v\u00e0 2 d\u00f2ng t\u1ebf b\u00e0o \u0111\u1ed9t bi\u1ebfn (n+1 v\u00e0 n-1)<\/p>\n

D.<\/strong>1 d\u00f2ng t\u1ebf b\u00e0o b\u00ecnh th\u01b0\u1eddng (2n) v\u00e0 2 d\u00f2ng t\u1ebf b\u00e0o \u0111\u1ed9t bi\u1ebfn (2n+2 v\u00e0 2n-2)<\/p>\n

C\u00e2u 8 . (ID: 82634<\/strong>) Qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a m\u1ed9t t\u1ebf b\u00e0o sinh tinh c\u00f3 ki\u1ec3u gen Aa Bd\/bD kh\u00f4ng x\u1ea3y ra \u0111\u1ed9t bi\u1ebfn nh\u01b0ng x\u1ea3y ra ho\u00e1n v\u1ecb gen gi\u1eefa alen D v\u00e0 alen d.<\/strong>Theo l\u00ed thuy\u1ebft, c\u00e1c lo\u1ea1i giao t\u1eed \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1eeb qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a t\u1ebf b\u00e0o tr\u00ean l\u00e0<\/p>\n

A.<\/strong>Abd<\/u>, abD<\/u>, ABD<\/u>, abd<\/u>ho\u1eb7c aBd<\/u>, aBD<\/u>, AbD<\/u>, Abd<\/u>                 B. <\/strong>ABD<\/u>, abd<\/u>, aBD<\/u>, Abd<\/u>ho\u1eb7c aBd<\/u>, abd<\/u>, aBD<\/u>, AbD.<\/strong><\/u><\/p>\n

C.<\/strong>Abd<\/u>, AbD<\/u>, aBd<\/u>, aBD<\/u>ho\u1eb7c ABD<\/u>, ABd<\/u>, abd<\/u>, abD<\/u>                 D.<\/strong>Abd<\/u>, aBD<\/u>, abD<\/u>, Abd<\/u>ho\u1eb7c Abd<\/u>, aBD<\/u>, AbD<\/u>, abd<\/u><\/p>\n

C\u00e2u 9. (ID: 82635)<\/strong>Cho c\u00e1c ph\u00e9p lai sau \u0111\u00e2y<\/p>\n

(1)AAaa x AAaa                      (2)Aaaa x AAAa                (3)aaBb x AABb              (4)AAAABBBb x aaaaBBBb<\/p>\n

(5)AAaa x Aaaa                     (6)AaaaBbbb x AaaaBbbb<\/p>\n

Bi\u1ebft r\u1eb1ng qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng. Theo l\u00fd thuy\u1ebft, trong c\u00e1c ph\u00e9p lai tr\u00ean, s\u1ed1 ph\u00e9p lai cho \u0111\u1eddi con c\u00f3 ki\u1ec3u gen ph\u00e2n li theo t\u1ec9 l\u1ec7 1: 2: 1 l\u00e0<\/p>\n

A.<\/strong>2              B. <\/strong>3             C.<\/strong>4                   D.<\/strong>5<\/p>\n

C\u00e2u 10. (ID: 82636)<\/strong>T\u1ebf b\u00e0o c\u1ee7a m\u1ed9t lo\u00e0i sinh v\u1eadt nh\u00e2n s\u01a1 khi ph\u00e2n chia b\u1ecb nhi\u1ec5m t\u00e1c nh\u00e2n h\u00f3a h\u1ecdc 5-BU, l\u00e0m cho gen A \u0111\u1ed9t bi\u1ebfn \u0111i\u1ec3m th\u00e0nh alen a c\u00f3 120 chu k\u00ec xo\u1eafn v\u00e0 2800 li\u00ean k\u1ebft hi\u0111r\u00f4. S\u1ed1 l\u01b0\u1ee3ng t\u1eebng lo\u1ea1i nucl\u00ea\u00f4tit c\u1ee7a gen A l\u00e0<\/p>\n

A.<\/strong>A = T = 201; G = X = 399.  <\/p>\n

B. <\/strong>A = T = 800; G = X = 400<\/p>\n

C.<\/strong>A = T = 801; G = X = 399<\/p>\n

D.<\/strong>A = T = 401; G = X = 199<\/p>\n

C\u00e2u 11. (ID: 82637)<\/strong>\u0110\u1ed9t bi\u1ebfn gen th\u01b0\u1eddng g\u00e2y h\u1ea1i cho c\u01a1 th\u1ec3 mang \u0111\u1ed9t bi\u1ebfn v\u00ec<\/p>\n

A.<\/strong>L\u00e0m bi\u1ebfn \u0111\u1ed5i c\u1ea5u tr\u00fac gen d\u1eabn t\u1edbi c\u01a1 th\u1ec3 sinh v\u1eadt kh\u00f4ng ki\u1ec3m so\u00e1t \u0111\u01b0\u1ee3c qu\u00e1 tr\u00ecnh t\u00e1i b\u1ea3n c\u1ee7a gen<\/p>\n

B. <\/strong>L\u00e0m sai l\u1ec7ch th\u00f4ng tin di truy\u1ec1n d\u1eabn t\u1edbi l\u00e0m r\u1ed1i lo\u1ea1n qu\u00e1 tr\u00ecnh sinh t\u1ed5ng h\u1ee3p protein<\/p>\n

C.<\/strong>Gen b\u1ecb bi\u1ebfn \u0111\u1ed5i d\u1eabn \u0111\u1ebfn kh\u00f4ng k\u1ebf t\u1ee5c v\u1eadt  ch\u1ea5t di truy\u1ec1n qua c\u00e1c th\u1ebf h\u1ec7<\/p>\n

D.<\/strong>L\u00e0m ng\u1eebng tr\u1ec7 qu\u00e1 tr\u00ecnh phi\u00ean m\u00e3, kh\u00f4ng t\u1ed5ng h\u1ee3p \u0111\u01b0\u1ee3c protein<\/p>\n

C\u00e2u 12. (ID: 82638<\/strong> ) B\u1ec7nh, h\u1ed9i ch\u1ee9ng n\u00e0o sau \u0111\u00e2y \u1edf ng\u01b0\u1eddi chiu h\u1eadu qu\u1ea3 c\u1ee7a \u0111\u1ed9t bi\u1ebfn c\u1ea5u tr\u00fac nhi\u1ec5m s\u1eafc th\u1ec3?<\/p>\n

A.<\/strong>B\u1ec7nh ung th\u01b0 m\u00e1u             B. <\/strong>H\u1ed9i ch\u1ee9ngClaiphent\u01a1               C.<\/strong>H\u1ed9i ch\u1ee9ng \u0110ao                 D.<\/strong>H\u1ed9i ch\u1ee9ng t\u01a1cn\u01a1<\/p>\n

C\u00e2u 13. (ID: 82639)<\/strong>Cho bi\u1ebft m\u1ed7i t\u00ednh tr\u1ea1ng do 1 gen quy \u0111\u1ecbnh v\u00e0 t\u00ednh tr\u1ea1ng tr\u1ed9i l\u00e0 tr\u1ed9i ho\u00e0n to\u00e0n, \u1edf ph\u00e9p lai: AB\/ab Dd x AB\/ab dd n\u1ebfu x\u1ea3y ra ho\u00e1n v\u1ecb gen \u1edf c\u1ea3 2 gi\u1edbi v\u1edbi t\u1ea7n s\u1ed1 l\u00e0 20% th\u00ec ki\u1ec3u h\u00ecnh aabbdd \u1edf \u0111\u1eddi con chi\u1ebfm t\u1ef7 l\u1ec7<\/p>\n

A.<\/strong>12%            B. <\/strong>8%            C.<\/strong>0,5%             D.<\/strong>16%<\/p>\n

C\u00e2u 14. (ID: 82640 )<\/strong>S\u1ef1 t\u0103ng m\u1ed9t s\u1ed1 nguy\u00ean l\u1ea7n NST \u0111\u01a1n b\u1ed9i c\u1ee7a m\u1ed9t lo\u00e0i l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng<\/p>\n

A.<\/strong>D\u1ecb \u0111a b\u1ed9i             B. <\/strong>t\u1ee9 b\u1ed9i                   C.<\/strong>t\u1ef1 \u0111a b\u1ed9i                 D.<\/strong>tam b\u1ed9i<\/p>\n

C\u00e2u 15. (ID: 82641)<\/strong>M\u1ed9t t\u1ebf b\u00e0o sinh d\u01b0\u1ee1ng c\u1ee7a m\u1ed9t lo\u00e0i c\u00f3 b\u1ed9 nhi\u1ec5m s\u1eafc th\u1ec3 k\u00ed hi\u1ec7u: AaBbddEe b\u1ecb r\u1ed1i lo\u1ea1n ph\u00e2n li trong ph\u00e2n b\u00e0o \u1edf 1 nhi\u1ec5m s\u1eafc th\u1ec3 k\u00e9p trong c\u1eb7p Bb s\u1ebd t\u1ea1o ra 2 t\u1ebf b\u00e0o con c\u00f3 k\u00ed hi\u1ec7u nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0:<\/p>\n

A.<\/strong>AaBbddEe v\u00e0 AaBbddEe                B. <\/strong>AaBbbddEe v\u00e0 AaBddEe<\/p>\n

C.<\/strong>AaBbDddEe v\u00e0 AaBbddEe              D.<\/strong>AaBBbddEe v\u00e0 AaBddEe<\/p>\n

C\u00e2u 16. (ID: 82642<\/strong>) C\u00e2y t\u1ee9 b\u1ed9i c\u00f3 ki\u1ec3u gen AAaaBBbb, bi\u1ebft c\u00e1c gen ph\u00e2n li \u0111\u1ed9c l\u1eadp, tr\u00ecnh gi\u1ea3m ph\u00e2n di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng. T\u00ednh theo l\u00fd thuy\u1ebft, t\u1ef7 l\u1ec7 giao t\u1eed mang ki\u1ec3u gen Aabb \u0111\u01b0\u1ee3c sinh ra t\u1eeb c\u00e2y n\u00e0y l\u00e0:<\/p>\n

A.<\/strong>4\/36                    B. <\/strong>6\/36                    C.<\/strong>16\/36                    D.<\/strong>12\/36<\/p>\n

C\u00e2u 17. (ID: 82643)<\/strong>Trong c\u00e1c m\u1ee9c c\u1ea5u tr\u00fac si\u00eau hi\u1ec3n vi c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 \u0111i\u1ec3n h\u00ecnh \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c , m\u1ee9c c\u1ea5u tr\u00fac n\u00e0o sau \u0111\u00e2y c\u00f3 \u0111\u01b0\u1eddng k\u00ednh 30 nm?<\/p>\n

A.<\/strong>Cr\u00f4matit     B.<\/strong>S\u1ee3i c\u01a1 b\u1ea3n        C.<\/strong>S\u1ee3i nhi\u1ec5m s\u1eafc.       D.<\/strong>V\u00f9ng x\u1ebfp cu\u1ed9n<\/p>\n

C\u00e2u 18. (ID: 82644<\/strong>) Bi\u1ebft r\u1eb1ng m\u1ed7i gen quy \u0111\u1ecbnh m\u1ed9t t\u00ednh tr\u1ea1ng, gen tr\u1ed9i l\u00e0 tr\u1ed9i ho\u00e0n to\u00e0n. Ph\u00e9p lai n\u00e0o sau \u0111\u00e2y t\u1ea1o ra \u1edf \u0111\u1eddi con nhi\u1ec1u lo\u1ea1i ki\u1ec3u gen v\u00e0 ki\u1ec3u h\u00ecnh nh\u1ea5t?<\/p>\n

A.<\/strong>AaBb x AaBB.<\/strong>   B.<\/strong>Ab\/aB x Ab\/aB   C.<\/strong>AaX<\/p>\n

B<\/dd>\n

X<\/p>\n

b<\/dd>\n

x AaX<\/p>\n

b<\/dd>\n

Y  D.<\/strong>AaX<\/p>\n

B<\/dd>\n

X<\/p>\n

B<\/dd>\n

x AaX<\/p>\n

b<\/dd>\n

Y<\/p>\n

C\u00e2u 19. (ID: 82645)<\/strong>X\u00e9t 1 gen c\u00f3 2 alen, qu\u00e1 tr\u00ecnh ng\u1eabu ph\u1ed1i \u0111\u00e3 t\u1ea1o ra 5 ki\u1ec3u gen kh\u00e1c nhau trong qu\u1ea7n th\u1ec3. Cho r\u1eb1ng kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn x\u1ea3y ra, qu\u1ea7n th\u1ec3 v\u00e0 gen n\u00f3i tr\u00ean c\u00f3 \u0111\u1eb7c \u0111i\u1ec3m g\u00ec?<\/p>\n

(1)Qu\u1ea7n th\u1ec3 t\u1ee9 b\u1ed9i, gen n\u1eb1m tr\u00ean NST th\u01b0\u1eddng.<\/p>\n

(2)Qu\u1ea7n th\u1ec3 tam b\u1ed9i, gen n\u1eb1m tr\u00ean NST th\u01b0\u1eddng.<\/p>\n

(3)Qu\u1ea7n th\u1ec3 l\u01b0\u1ee1ng b\u1ed9i, gen n\u1eb1m tr\u00ean NST th\u01b0\u1eddng.<\/p>\n

(4)Qu\u1ea7n th\u1ec3 l\u01b0\u1ee1ng b\u1ed9i, gen n\u1eb1m tr\u00ean NST X v\u00e0 kh\u00f4ng c\u00f3 alen t\u01b0\u01a1ng \u1ee9ng tr\u00ean NST Y.<\/p>\n

(5)Qu\u1ea7n th\u1ec3 l\u01b0\u1ee1ng b\u1ed9i, gen n\u1eb1m tr\u00ean NST Y v\u00e0 kh\u00f4ng c\u00f3 alen t\u01b0\u01a1ng \u1ee9ng tr\u00ean NST X.<\/p>\n

C\u00e1c ph\u00e1t bi\u1ec3u \u0111\u00fang l\u00e0<\/p>\n

A.<\/strong>2       B.<\/strong>4     C.<\/strong>3     D.<\/strong>1<\/p>\n

C\u00e2u 20. (ID :<\/strong>82646)<\/strong>\u01afu th\u1ebf lai l\u00e0 g\u00ec?<\/p>\n

A.<\/strong>Bi\u1ec3u hi\u1ec7n cao nh\u1ea5t \u1edf F<\/p>\n

1<\/dd>\n

, sau \u0111\u00f3 gi\u1ea3m d\u1ea7n qua c\u00e1c th\u1ebf h\u1ec7<\/p>\n

B. <\/strong>L\u00e0 hi\u1ec7n t\u01b0\u1ee3ng b\u1ed1 m\u1eb9 c\u00f3 n\u0103ng su\u1ea5t, ph\u1ea9m ch\u1ea5t, s\u1ee9c ch\u1ed1ng ch\u1ecbu v\u00e0 kh\u1ea3 n\u0103ng sinh tr\u01b0\u1edfng ph\u00e1t tri\u1ec3n v\u01b0\u1ee3t tr\u1ed9i so v\u1edbi c\u00e1c d\u1ea1ng con lai<\/p>\n

C.<\/strong>L\u00e0 hi\u1ec7n t\u01b0\u1ee3ng con lai c\u00f3 n\u0103ng su\u1ea5t, ph\u1ea9m ch\u1ea5t, s\u1ee9c ch\u1ed1ng ch\u1ecbu v\u00e0 kh\u1ea3 n\u0103ng sinh tr\u01b0\u1edfng ph\u00e1t tri\u1ec3n v\u01b0\u1ee3t tr\u1ed9i so v\u1edbi c\u00e1c d\u1ea1ng b\u1ed1 m\u1eb9<\/p>\n

D.<\/strong>Bi\u1ec3u hi\u1ec7n r\u00f5 nh\u1ea5t \u1edf lai kh\u00e1c d\u00f2ng<\/p>\n

C\u00e2u 21. (ID :<\/strong>82647 )<\/strong>Y\u1ebfu t\u1ed1 n\u00e0o kh\u00f4ng thay \u0111\u1ed5i \u1edf c\u00e1c th\u1ebf h\u1ec7 trong qu\u1ea7n th\u1ec3 t\u1ef1 th\u1ee5?<\/p>\n

A.<\/strong>T\u1ea7n s\u1ed1 ki\u1ec3u gen v\u00e0 ki\u1ec3u h\u00ecnh<\/p>\n

B. <\/strong>T\u1ea7n s\u1ed1 c\u1ee7a c\u00e1c alen<\/p>\n

C.<\/strong>T\u1ea7n s\u1ed1 ki\u1ec3u gen<\/p>\n

D.<\/strong>T\u1ea7n s\u1ed1 ki\u1ec3u h\u00ecnh<\/p>\n

C\u00e2u 22. (ID: 82648)<\/strong>Khi n\u00f3i v\u1ec1 \u01b0u th\u1ebf lai, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2u kh\u00f4ng \u0111\u00fang?<\/p>\n

A.<\/strong>\u0110\u1ec3 t\u1ea1o ra nh\u1eefng con lai c\u00f3 \u01b0u th\u1ebf lai cao v\u1ec1 m\u1ed9t s\u1ed1 \u0111\u1eb7c t\u00ednh t\u1ed1t n\u00e0o \u0111\u00f3, ng\u01b0\u1eddi ta th\u01b0\u1eddng b\u1eaft \u0111\u1ea7u b\u1eb1ng c\u00e1ch t\u1ea1o ra nh\u1eefng d\u00f2ng thu\u1ea7n ch\u1ee7ng kh\u00e1c nhau<\/p>\n

B. <\/strong>M\u1ed9t trong nh\u1eefng gi\u1ea3 thuy\u1ebft \u0111\u1ec3 gi\u1ea3i th\u00edch c\u01a1 s\u1edf di truy\u1ec1n c\u1ee7a \u01b0u th\u1ebf lai \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi th\u1eeba nh\u1eadn l\u00e0 gi\u1ea3 thuy\u1ebft si\u00eau tr\u1ed9i<\/p>\n

C.<\/strong>Trong m\u1ed9t s\u1ed1 tr\u01b0\u1eddng h\u1ee3p, lai gi\u1eefa hai d\u00f2ng nh\u1ea5t \u0111\u1ecbnh thu \u0111\u01b0\u1ee3c con lai kh\u00f4ng c\u00f3 \u01b0u th\u1ebf lai, nh\u01b0ng n\u1ebfu cho con lai n\u00e0y lai v\u1edbi d\u00f2ng th\u1ee9 ba th\u00ec \u0111\u1eddi con l\u1ea1i c\u00f3 \u01b0u th\u1ebf lai.<\/p>\n

D.<\/strong>Ng\u01b0\u1eddi ta t\u1ea1o ra nh\u1eefng con lai kh\u00e1c d\u00f2ng c\u00f3 \u01b0u th\u1ebf lai cao \u0111\u1ec3 s\u1eed d\u1ee5ng cho vi\u1ec7c nh\u00e2n gi\u1ed1ng.<\/p>\n

C\u00e2u 23. (ID: 82649)<\/strong>\u1edf c\u00e0 chua gen A quy \u0111\u1ecbnh th\u00e2n cao, a th\u00e2n th\u1ea5p, B: qu\u1ea3 tr\u00f2n, b: qu\u1ea3 b\u1ea7u d\u1ee5c.<\/strong>Gi\u1ea3 s\u1eed 2 c\u1eb7p gen n\u00e0y c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t NST t\u01b0\u01a1ng \u0111\u1ed3ng. Gi\u1ea3 s\u1eed khi lai gi\u1eefa 2 th\u1ee9 c\u00e0 chua thu\u1ea7n ch\u1ee7ng kh\u00e1c nhau b\u1edfi 2 c\u1eb7p t\u00ednh tr\u1ea1ng t\u01b0\u01a1ng ph\u1ea3n n\u00f3i tr\u00ean \u0111\u01b0\u1ee3c F<\/p>\n

1<\/dd>\n

, cho F<\/p>\n

1<\/dd>\n

giao ph\u1ed1i v\u1edbi c\u00e1 th\u1ec3 kh\u00e1c F<\/p>\n

2<\/dd>\n

thu \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3: 54% cao-tr\u00f2n, 21% th\u1ea5p-tr\u00f2n, 21% cao-b\u1ea7u d\u1ee5c, 4% th\u1ea5p-b\u1ea7u d\u1ee5c. Cho bi\u1ebft qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n t\u1ea1o no\u00e3n v\u00e0 t\u1ea1o ph\u00e2n di\u1ec5n ra gi\u1ed1ng nhau, h\u00e3y x\u00e1c \u0111\u1ecbnh ki\u1ec3u gen c\u1ee7a F<\/p>\n

1<\/dd>\n

v\u00e0 t\u1ea7n s\u1ed1 trao \u0111\u1ed5i ch\u00e9o f gi\u1eefa c\u00e1c gen?<\/p>\n

A.<\/strong>Ab\/aB, f = 40%     B.<\/strong>AB\/ab, f = 20%    C.<\/strong>AB\/aB, f = 20%   D.<\/strong>AB\/ab, f = 40%<\/p>\n

C\u00e2u 24. (ID: 82650)<\/strong>\u1ede c\u00e0 chua t\u00ednh tr\u1ea1ng qu\u1ea3 \u0111\u1ecf tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi t\u00ednh tr\u1ea1ng qu\u1ea3 v\u00e0ng. Cho qu\u1ea7n th\u1ec3 P : 2\/3AA + 1\/3 Aa = 1 t\u1ef1 th\u1ee5 ph\u1ea5n. T\u1ec9 l\u1ec7 ki\u1ec3u h\u00ecnh \u1edf \u0111\u1eddi con l\u00e0<\/p>\n

A.<\/strong>7 \u0111\u1ecf : 1 v\u00e0ng       B.<\/strong>9 \u0111\u1ecf : 7 v\u00e0ng   C.<\/strong>3 \u0111\u1ecf : 1 v\u00e0ng   D.<\/strong>11 \u0111\u1ecf : 1 v\u00e0ng<\/p>\n

C\u00e2u 25. (ID: 82651 )<\/strong>\u1ede t\u1eb1m , gen A quy \u0111\u1ecbnh tr\u1ee9ng m\u00e0u tr\u1eafng, gen a quy \u0111\u1ecbnh tr\u1ee9ng m\u00e0u s\u1eabm. Bi\u1ebft r\u1eb1ng t\u1eb1m \u0111\u1ef1c cho nhi\u1ec1u t\u01a1 h\u01a1n t\u1eb1m c\u00e1i. Ph\u00e9p lai n\u00e0o sau \u0111\u00e2y gi\u00fap c\u00e1c nh\u00e0 ch\u1ecdn gi\u1ed1ng ph\u00e2n bi\u1ec7t t\u1eb1m \u0111\u1ef1c v\u00e0 t\u1eb1m c\u00e1i ngay t\u1eeb giai \u0111o\u1ea1n tr\u1ee9ng?<\/p>\n

A.<\/strong>X<\/p>\n

A<\/dd>\n

X<\/p>\n

a<\/dd>\n

x X<\/p>\n

a<\/dd>\n

Y        B.<\/strong>X<\/p>\n

A<\/dd>\n

X<\/p>\n

A<\/dd>\n

x X<\/p>\n

a<\/dd>\n

YC<\/p>\n

.<\/dd>\n

<\/strong>X<\/p>\n

A<\/dd>\n

X<\/p>\n

a<\/dd>\n

x<\/dd>\n

X<\/p>\n

A<\/dd>\n

Y     D.<\/strong>X<\/p>\n

a<\/dd>\n

X<\/p>\n

a<\/dd>\n

x X<\/p>\n

A<\/dd>\n

Y<\/p>\n

C\u00e2u 26. (ID: 82652)<\/strong>\u1ede ng\u01b0\u1eddi, n\u1ebfu x\u1ea3y ra r\u1ed1i lo\u1ea1n ph\u00e2n li c\u1ee7a c\u1eb7p NST th\u1ee9 13 \u1edf gi\u1ea3m ph\u00e2n II t\u1ea1i 1 trong 2 t\u1ebf b\u00e0o con s\u1ebd t\u1ea1o ra<\/p>\n

A.<\/strong>2 tinh tr\u00f9ng b\u00ecnh th\u01b0\u1eddng, 1 tinh tr\u00f9ng c\u00f3 2 NST 13 v\u00e0 1 tinh tr\u00f9ng kh\u00f4ng c\u00f3 NST 13<\/p>\n

B. <\/strong>2 tinh tr\u00f9ng thi\u1ebfu 1 NST 13 v\u00e0 2 tinh tr\u00f9ng th\u1eeba 1 NST 13<\/p>\n

C.<\/strong>4 tinh tr\u00f9ng b\u00ecnh th\u01b0\u1eddng<\/p>\n

D.<\/strong>2 tinh tr\u00f9ng b\u00ecnh th\u01b0\u1eddng v\u00e0 2 tinh tr\u00f9ng th\u1eeba 1 NST 13<\/p>\n

C\u00e2u 27. (ID: 82653)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt, gen B quy \u0111\u1ecbnh hoa \u0111\u1ecf tr\u1ecdi ho\u00e0n to\u00e0n so v\u1edbi alen b quy \u0111\u1ecbnh hoa tr\u1eafng. Gen A \u00e1t ch\u1ebf s\u1ef1 bi\u1ec3u hi\u1ec7n c\u1ee7a B v\u00e0 b (ki\u1ec3u gen c\u00f3 ch\u1ee9a A s\u1ebd cho ki\u1ec3u h\u00ecnh hoa tr\u1eafng), alen l\u1eb7n a kh\u00f4ng \u00e1t ch\u1ebf. Gen D quy \u0111\u1ecbnh h\u1ea1t v\u00e0ng, tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi d h\u1ea1t xanh. Cho c\u00e2y d\u1ecb h\u1ee3p v\u1ec1 t\u1ea5t c\u1ea3 c\u00e1c c\u1eb7p gen (P) t\u1ef1 th\u1ee5 ph\u1ea5n, \u0111\u1eddi con F<\/p>\n

1<\/dd>\n

thu \u0111\u01b0\u1ee3c 3600 c\u00e2y 4 lo\u1ea1i ki\u1ec3u h\u00ecnh, trong \u0111\u00f3 ki\u1ec3u h\u00ecnh hoa \u0111\u1ecf, h\u1ea1t xanh c\u00f3 s\u1ed1 l\u01b0\u1ee3ng 189 c\u00e2y. H\u00e3y x\u00e1c \u0111\u1ecbnh ki\u1ec3u gen c\u1ee7a P v\u00e0 t\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb gen? (Bi\u1ebft r\u1eb1ng t\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb gen \u1edf t\u1ebf b\u00e0o sinh h\u1ea1t ph\u1ea5n v\u00e0 sinh no\u00e3n nh\u01b0 nhau v\u00e0 kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn x\u1ea3y ra)<\/p>\n

A.<\/strong>P: BD\/bd Aa x BD\/bd Aa, f = 40%                   B. <\/strong>P: Bd\/bD Aa x Bd\/bD Aa, f = 20%<\/p>\n

C.<\/strong>P: BD\/bd Aa x BD\/bd Aa, f = 10%                   D.<\/strong>P<\/strong>Bd\/bD Aa x Bd\/bD Aa, f = 40%<\/p>\n

C\u00e2u 28. (ID: 82654 )<\/strong>\u0110i\u1ec3m n\u00e0o sau \u0111\u00e2y \u0111\u00fang v\u1edbi hi\u1ec7n t\u01b0\u1ee3ng di truy\u1ec1n li\u00ean k\u1ebft kh\u00f4ng ho\u00e0n to\u00e0n (ho\u00e1n v\u1ecb gen)?<\/p>\n

A.<\/strong>L\u00e0m h\u1ea1n ch\u1ebf c\u00e1c bi\u1ebfn d\u1ecb t\u1ed5 h\u1ee3p                        B. <\/strong>Lu\u00f4n duy tr\u00ec c\u00e1c nh\u00f3m gen li\u00ean k\u1ebft qu\u00fd<\/p>\n

C.<\/strong>L\u00e0m xu\u1ea5t hi\u1ec7n c\u00e1c bi\u1ebfn d\u1ecb t\u1ed5 h\u1ee3p                      D.<\/strong>M\u1ed7i gen n\u1eb1m tr\u00ean 1 NST<\/p>\n

C\u00e2u 29. (ID: 82655)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt gen A qui \u0111\u1ecbnh qu\u1ea3 d\u00e0i, gen a qui \u0111\u1ecbnh qu\u1ea3 ng\u1eafn; B qui \u0111\u1ecbnh qu\u1ea3 ng\u1ecdt, b qui \u0111\u1ecbnh qu\u1ea3 chua.<\/strong>Hai c\u1eb7p gen c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t c\u1eb7p NST t\u01b0\u01a1ng \u0111\u1ed3ng, kho\u1ea3ng c\u00e1ch 2 gen l\u00e0 25 cM. Cho lai c\u00e2y thu\u1ea7n ch\u1ee7ng qu\u1ea3 d\u00e0i ng\u1ecdt lai v\u1edbi c\u00e2y c\u00f3 qu\u1ea3 ng\u1eafn chua thu \u0111\u01b0\u1ee3c F1 \u0111\u1ec1u c\u00f3 ki\u1ec3u h\u00ecnh qu\u1ea3 d\u00e0i ng\u1ecdt. Cho lai ph\u00e2n t\u00edch F<\/p>\n

1<\/dd>\n

thu \u0111\u01b0\u1ee3c t\u1ec9 l\u1ec7 c\u00e2y c\u00f3 qu\u1ea3 ng\u1eafn chua l\u00e0:<\/p>\n

A.<\/strong>75%       B.<\/strong>37,5%     C.<\/strong>25%     D.<\/strong>12,5%<\/p>\n

C\u00e2u 30. (ID: 82656)<\/strong>C\u00e1c gen li\u00ean k\u1ebft v\u1edbi nhau \u0111\u1ec1u c\u00f3 \u0111\u1eb7c t\u00ednh l\u00e0<\/p>\n

A.<\/strong>\u0110\u1ec1u thu\u1ed9c v\u1ec1 1 ADN     <\/p>\n

B. <\/strong>Th\u01b0\u1eddng c\u00f9ng bi\u1ec3u hi\u1ec7n<\/p>\n

C.<\/strong>C\u00f9ng c\u1eb7p t\u01b0\u01a1ng \u0111\u1ed3ng<\/p>\n

D.<\/strong>C\u00f3 l\u00f4cut kh\u00e1c nhau<\/p>\n

C\u00e2u 31. (ID: 82657 )<\/strong>Tr\u01b0\u1eddng h\u1ee3p n\u00e0o sau \u0111\u00e2y c\u00f3 s\u1ed1 l\u01b0\u1ee3ng NST c\u1ee7a t\u1ebf b\u00e0o l\u00e0 m\u1ed9t s\u1ed1 l\u1ebb<\/p>\n

(1)T\u1ebf b\u00e0o \u0111\u01a1n b\u1ed9i c\u1ea3i b\u1eafp<\/p>\n

(2)Th\u1ebf tam b\u1ed9i \u0111\u1eadu H\u00e0 Lan<\/p>\n

(3)T\u1ebf b\u00e0o xoma ch\u00e2u ch\u1ea5u \u0111\u1ef1c<\/p>\n

(4)Th\u1ec3 tam b\u1ed9i l\u00faa<\/p>\n

(5)Th\u1ec3 ba \u1edf ru\u1ed3i gi\u1ea5m<\/p>\n

(6)Th\u1ec3 m\u1ed9t \u1edf ng\u01b0\u1eddi<\/p>\n

(7)T\u1ebf b\u00e0o n\u1ed9i nh\u0169 \u0111\u1eadu h\u00e0 lan<\/p>\n

(8)T\u1ebf b\u00e0o t\u1ee9 b\u1ed9i c\u1ea3i c\u1ee7<\/p>\n

T\u1ed5 h\u1ee3p c\u00e1c \u00fd \u0111\u00fang l\u00e0:<\/p>\n

A.<\/strong>2, 3 4, 5, 7, 8    B.<\/strong>1, 2, 4, 5, 7, 8     C.<\/strong>2, 3, 4, 6, 7       D.<\/strong>1, 2, 3, 5, 6, 7<\/p>\n

C\u00e2u 32. (ID :<\/strong>82658)<\/strong>\u1ede ng\u01b0\u1eddi, gen quy \u0111\u1ecbnh d\u1ea1ng t\u00f3c do 2 alen A v\u00e0 a tr\u00ean NST th\u01b0\u1eddng qui \u0111\u1ecbnh; b\u1ec7nh m\u00e1u kh\u00f3 \u0111\u00f4ng do 2 alen M v\u00e0 m n\u1eb1m tr\u00ean NST X \u1edf \u0111o\u1ea1n kh\u00f4ng t\u01b0\u01a1ng \u0111\u1ed3ng Y. Gen qui \u0111\u1ecbnh nh\u00f3m m\u00e1u do 3 alen I<\/p>\n

A<\/dd>\n

, I<\/p>\n

B<\/dd>\n

(\u0111\u1ed3ng tr\u1ed9i) v\u00e0 I<\/p>\n

o<\/dd>\n

(l\u1eb7n) n\u1eb1m tr\u00ean c\u1eb7p NST th\u01b0\u1eddng kh\u00e1C.<\/strong>S\u1ed1 ki\u1ec3u gen v\u00e0 ki\u1ec3u h\u00ecnh t\u1ed1i \u0111a trong qu\u1ea7n th\u1ec3 \u0111\u1ed1i v\u1edbi 3 t\u00ednh tr\u1ea1ng tr\u00ean l\u00e0:<\/p>\n

A.<\/strong>54 ki\u1ec3u gen v\u00e0 16 ki\u1ec3u h\u00ecnh<\/p>\n

B. <\/strong>90 ki\u1ec3u gen v\u00e0 16 ki\u1ec3u h\u00ecnh<\/p>\n

C.<\/strong>90 ki\u1ec3u gen v\u00e0 12 ki\u1ec3u h\u00ecnh<\/p>\n

D.<\/strong>54 ki\u1ec3u gen v\u00e0 12 ki\u1ec3u h\u00ecnh<\/p>\n

C\u00e2u 33. (ID: 82659)<\/strong>K\u1ebft qu\u1ea3 th\u1ef1c nghi\u1ec7m t\u1ec9 l\u1ec7 1:2:1 v\u1ec1 ki\u1ec3u gen lu\u00f4n \u0111i \u0111\u00f4i v\u1edbi t\u1ec9 l\u1ec7 3:1 v\u1ec1 ki\u1ec3u h\u00ecnh, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o trong gi\u1ea3 thuy\u1ebft c\u1ee7a Men\u0111en l\u00e0 \u0111\u00fang<\/p>\n

A.<\/strong>M\u1ed7i c\u00e1 th\u1ec3 \u0111\u1eddi P cho m\u1ed9t laoij giao t\u1eed mang gen kh\u00e1c nhau<\/p>\n

B. <\/strong>Th\u1ec3 \u0111\u1ed3ng h\u1ee3p cho 1 lo\u1ea1i giao t\u1eed, th\u1ec3 d\u1ecb h\u1ee3p cho 2 lo\u1ea1i giao t\u1eed v\u1edbi t\u1ec9 l\u1ec7 1:1<\/p>\n

C.<\/strong>C\u01a1 th\u1ec3 lai F<\/p>\n

1<\/dd>\n

cho 2 lo\u1ea1i giao t\u1eed kh\u00e1c nhau v\u1edbi t\u1ec9 l\u1ec7 3:1<\/p>\n

D.<\/strong>M\u1ed7i c\u00e1 th\u1ec3 \u0111\u1eddi F<\/p>\n

1<\/dd>\n

cho m\u1ed9t lo\u1ea1i giao t\u1eed mang gen kh\u00e1c nhau<\/p>\n

C\u00e2u 34. (ID: 82660)<\/strong>Ng\u01b0\u1eddi ta chuy\u1ec3n m\u1ed9t s\u1ed1 ph\u00e2n t\u1eed ADN c\u1ee7a vi khu\u1ea9n E.coli ch\u1ec9 ch\u1ee9a N<\/p>\n

15<\/dd>\n

sang m\u00f4i tr\u01b0\u1eddng ch\u1ec9 ch\u1ee9a N<\/p>\n

14<\/dd>\n

. T\u1ea5t c\u1ea3 c\u00e1c ph\u00e2n t\u1eed ADN n\u00f3i tr\u00ean \u0111\u1ec1u th\u1ef1c hi\u1ec7n t\u00e1i b\u1ea3n 5 l\u1ea7n li\u00ean ti\u1ebfp t\u1ea1o \u0111\u01b0\u1ee3c 960 ph\u00e2n t\u1eed AND ch\u1ec9 ch\u1ee9a N<\/p>\n

14<\/dd>\n

. S\u1ed1 ph\u00e2n t\u1eed AND ban \u0111\u1ea7u l\u00e0<\/p>\n

A.<\/strong>64          B.<\/strong>16           C.<\/strong>32          D.<\/strong>5<\/p>\n

C\u00e2u 35. (ID: 82661 )<\/strong>\u0110\u1ecbnh lu\u1eadt Hac\u0111i-Vanbec ph\u1ea3n \u00e1nh s\u1ef1<\/p>\n

A.<\/strong>M\u1ea5t \u1ed5n \u0111\u1ecbnh t\u1ea7n s\u1ed1 c\u00e1c th\u1ec3 \u0111\u1ed3ng h\u1ee3p trong qu\u1ea7n th\u1ec3 ng\u1eabu ph\u1ed1i<\/p>\n

B. <\/strong>\u1ed5n \u0111\u1ecbnh v\u1ec1 t\u1ea7n s\u1ed1 alen v\u00e0 th\u00e0nh ph\u1ea7n ki\u1ec3u gentrong qu\u1ea7n th\u1ec3 ng\u1eabu ph\u1ed1i<\/p>\n

C.<\/strong>m\u1ea5t \u1ed5n \u0111\u1ecbnh t\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a c\u00e1c alen trong qu\u1ea7n th\u1ec3 ng\u1eabu ph\u1ed1i<\/p>\n

D.<\/strong>m\u1ea5t c\u00e2n b\u1eb1ng th\u00e0nh ph\u1ea7n ki\u1ec3u gen trong qu\u1ea7n th\u1ec3 ng\u1eabu ph\u1ed1i<\/p>\n

C\u00e2u 36. (ID: 82662 )<\/strong>M\u1ee9c \u0111\u1ed9 c\u00f3 l\u1ee3i hay c\u00f3 h\u1ea1i c\u1ee7a gen \u0111\u1ed9t bi\u1ebfn ph\u1ee5 thu\u1ed9c v\u00e0o<\/p>\n

A.<\/strong>m\u00f4i tr\u01b0\u1eddng s\u1ed1ng v\u00e0 t\u1ed5 h\u1ee3p gen<\/p>\n

B. <\/strong>t\u1ea7n s\u1ed1 ph\u00e1t sinh \u0111\u1ed9t bi\u1ebfn<\/p>\n

C.<\/strong>t\u1ec9 l\u1ec7 \u0111\u1ef1c, c\u00e1i trong qu\u1ea7n th\u1ec3<\/p>\n

D.<\/strong>s\u1ed1 l\u01b0\u1ee3ng c\u00e1 th\u1ec3 trong qu\u1ea7n th\u1ec3<\/p>\n

C\u00e2u 37. (ID: 82663)<\/strong>Gen C v\u00e0 T c\u00f9ng \u1edf 1 NST, c\u00f2n c v\u00e0 t c\u00f9ng \u1edf NST t\u01b0\u01a1ng \u0111\u1ed3ng. N\u1ebfu li\u00ean k\u1ebft ho\u00e0n to\u00e0n, s\u1ed1 ki\u1ec3u gen c\u00f3 th\u1ec3 c\u00f3 trong qu\u1ea7n th\u1ec3 l\u00e0<\/p>\n

A.<\/strong>9             B.<\/strong>4             C.<\/strong>3          D.<\/strong>10<\/p>\n

C\u00e2u 38. (ID: 82664)<\/strong>\u1ede ng\u01b0\u1eddi, alen A qui \u0111\u1ecbnh m\u00e0u da b\u00ecnh th\u01b0\u1eddng tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen a qui \u0111\u1ecbnh da b\u1ea1ch t\u1ea1ng. Ng\u01b0\u1eddi ch\u1ed3ng b\u1ecb b\u1ea1ch t\u1ea1ng, ng\u01b0\u1eddi v\u1ee3 b\u00ecnh th\u01b0\u1eddng, m\u1eb9 v\u1ee3 b\u00ecnh th\u01b0\u1eddng mang gen g\u00e2y b\u1ec7nh v\u00e0 b\u1ed1 v\u1ee3 b\u00ecnh th\u01b0\u1eddng c\u00f3 ki\u1ec3u gen \u0111\u1ed3ng h\u1ee3p t\u1eed. X\u00e1c su\u1ea5t c\u1eb7p v\u1ee3 ch\u1ed3ng n\u00e0y sinh con b\u00ecnh th\u01b0\u1eddng l\u00e0 bao nhi\u00eau? Bi\u1ebft r\u1eb1ng kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn gen v\u00e0 \u0111\u1ed9t bi\u1ebfn c\u1ea5u tr\u00fac nhi\u1ec5m s\u1eafc th\u1ec3, qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n \u1edf b\u1ed1 v\u00e0 m\u1eb9 di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng<\/p>\n

A.<\/strong>25%    B.<\/strong>75%     C.<\/strong>100%    D.<\/strong>50%<\/p>\n

C\u00e2u 39. (ID: 82665)<\/strong>S\u1ef1 kh\u00f4ng ph\u00e2n ly c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 t\u01b0\u01a1ng \u0111\u1ed3ng \u1edf h\u1ee3p t\u1eed s\u1ebd<\/p>\n

A.<\/strong>D\u1eabn t\u1edbi t\u1ea5t c\u1ea3 c\u00e1c t\u1ebf b\u00e0o c\u1ee7a c\u01a1 th\u1ec3 \u0111\u1ec1u mang \u0111\u1ed9t bi\u1ebfn l\u1ec7ch b\u1ed9i.<\/p>\n

B. <\/strong>Ch\u1ec9 c\u00e1c t\u1ebf b\u00e0o sinh d\u01b0\u1ee1ng mang \u0111\u1ed9t bi\u1ebfn<\/p>\n

C.<\/strong>D\u1eabn t\u1edbi trong c\u01a1 th\u1ec3 c\u00f3 d\u00f2ng t\u1ebf b\u00e0o b\u00ecnh th\u01b0\u1eddng v\u00e0 d\u00f2ng mang \u0111\u1ed9t bi\u1ebfn<\/p>\n

D.<\/strong>D\u1eabn t\u1edbi t\u1ea5t c\u00e1c t\u1ebf b\u00e0o c\u1ee7a c\u01a1 th\u1ec3 \u0111\u1ec1u mang \u0111\u1ed9t bi\u1ebfn \u0111a b\u1ed9i<\/p>\n

C\u00e2u 40. (ID: 82666)<\/strong>S\u1ef1 t\u1ef1 th\u1ee5 ph\u1ea5n x\u1ea3y ra trong qu\u1ea7n th\u1ec3 giao ph\u1ed1i s\u1ebd l\u00e0m<\/p>\n

A.<\/strong>T\u0103ng t\u1ec9 l\u1ec7 th\u1ec3 \u0111\u1ed3ng h\u1ee3p, gi\u1ea3m t\u1ec9 l\u1ec7 th\u1ec3 d\u1ecb h\u1ee3p<\/p>\n

B. <\/strong>T\u0103ng bi\u1ebfn d\u1ecb t\u1ed5 h\u1ee3p trong qu\u1ea7n th\u1ec3<\/p>\n

C.<\/strong>T\u0103ng t\u1ed1c \u0111\u1ed9 bi\u1ebfn h\u00f3a c\u1ee7a qu\u1ea7n th\u1ec3<\/p>\n

D.<\/strong>T\u0103ng s\u1ef1 \u0111a d\u1ea1ng v\u1ec1 ki\u1ec3u gen v\u00e0 ki\u1ec3u h\u00ecnh<\/p>\n

C\u00e2u 41. (ID: 82667)<\/strong>M\u1ed9t ph\u00e2n t\u1eed ARN c\u00f3 3 lo\u1ea1i nu U, G, X c\u00f3 th\u1ec3 c\u00f3 bao nhi\u00eau b\u1ed9 ba ch\u1ee9a 1 nu U?<\/p>\n

A.<\/strong>9              B.<\/strong>4             C.<\/strong>27   D.<\/strong>12<\/p>\n

C\u00e2u 42. (ID :<\/strong>82671)<\/strong>\u1ede m\u1ed9t qu\u1ea7n th\u1ec3 th\u1ef1c v\u1eadt l\u01b0\u1ee1ng b\u1ed9i, x\u00e9t m\u1ed9t gen c\u00f3 2 alen n\u1eb1m tr\u00ean nhi\u1ec5m s\u1eafc th\u1ec3 th\u01b0\u1eddng: alen A qui \u0111\u1ecbnh hoa \u0111\u1ecf tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen a qui \u0111\u1ecbnh hoa tr\u1eafng. Khi qu\u1ea7n th\u1ec3 n\u00e0y \u0111ang \u1edf tr\u1ea1ng th\u00e1i c\u00e2n b\u1eb1ng di truy\u1ec1n c\u00f3 s\u1ed1 c\u00e2y hoa tr\u1eafng chi\u1ebfm t\u1ec9 l\u1ec7 4%. Cho to\u00e0n b\u1ed9 c\u00e1c c\u00e2y hoa \u0111\u1ecf trong qu\u00e0n th\u1ec3 \u0111\u00f3 giao ph\u1ea5n ng\u1eabu nhi\u00ean v\u1edbi nhau, theo l\u00ed thuy\u1ebft, t\u1ec9 l\u1ec7 ki\u1ec3u h\u00ecnh thu \u0111\u01b0\u1ee3c \u1edf \u0111\u1eddi con l\u00e0<\/p>\n

A.<\/strong>3 c\u00e2y hoa \u0111\u1ecf : 1 c\u00e2y hoa tr\u1eafng<\/p>\n

B. <\/strong>24 c\u00e2y hoa \u0111\u1ecf : 1 c\u00e2y hoa tr\u1eafng<\/p>\n

C.<\/strong>15 c\u00e2y hoa \u0111\u1ecf : 1 c\u00e2y hoa tr\u1eafng<\/p>\n

D.<\/strong>35 c\u00e2y hoa \u0111\u1ecf : 1 c\u00e2y hoa tr\u1eafng<\/p>\n

C\u00e2u 43. (ID :<\/strong>82672)<\/strong>D\u1ea1ng \u0111\u1ed9t bi\u1ebfn c\u1ea5u tr\u00fac NST n\u00e0o g\u00e2y h\u1eadu qu\u1ea3 nghi\u00eam tr\u1ecdng nh\u1ea5t<\/p>\n

A.<\/strong>\u0110\u1ea3o \u0111o\u1ea1n  B.<\/strong>M\u1ea5t \u0111o\u1ea1n     C.<\/strong>L\u1eb7p \u0111o\u1ea1n    D.<\/strong>Chuy\u1ec3n \u0111o\u1ea1n<\/p>\n

C\u00e2u 44. (ID: 82673 )<\/strong>Phi\u00ean m\u00e3 l\u1ea7 qu\u00e1 tr\u00ecnh t\u1ed5ng h\u1ee3p n\u00ean ph\u00e2n t\u1eed<\/p>\n

A.<\/strong>ADN    B.<\/strong>Protein        C.<\/strong>ARN         D.<\/strong>AND v\u00e0 ARN<\/p>\n

C\u00e2u 45. (ID: 82674)<\/strong>M\u1ee9c ph\u1ea3n \u1ee9ng do y\u1ebfu t\u1ed1 n\u00e0o qui \u0111\u1ecbnh<\/p>\n

A.<\/strong>Th\u1eddi k\u00ec ph\u00e1t tri\u1ec3n<\/p>\n

B. <\/strong>\u0110i\u1ec1u ki\u1ec7n m\u00f4i tr\u01b0\u1eddng<\/p>\n

C.<\/strong>Ki\u1ec3u gen c\u01a1 th\u1ec3<\/p>\n

D.<\/strong>Th\u1eddi k\u00ec sinh tr\u01b0\u1edfng<\/p>\n

C\u00e2u 46. (ID: 82675 )<\/strong>C\u00e1c gen \u1edf \u0111o\u1ea1n kh\u00f4ng t\u01b0\u01a1ng \u0111\u1ed3ngtr\u00ean NST X c\u00f3 s\u1ef1 di truy\u1ec1n<\/p>\n

A.<\/strong>Theo d\u00f2ng m\u1eb9<\/p>\n

B. <\/strong>Nh\u01b0 c\u00e1c gen tr\u00ean NST th\u01b0\u1eddng<\/p>\n

C.<\/strong>Th\u1eb3ng<\/p>\n

D.<\/strong>Ch\u00e9o<\/p>\n

C\u00e2u 47. (ID: 82676)<\/strong>S\u1ef1 trao \u0111\u1ed5i ch\u00e9o kh\u00f4ng c\u00e2n gi\u1eefa 2 cromatit kh\u00e1c ngu\u1ed3n g\u1ed1c trong m\u1ed9t c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 t\u01b0\u01a1ng \u0111\u1ed3ng c\u00f3 th\u1ec3 l\u00e0m xu\u1ea5t hi\u1ec7n d\u1ea1ng \u0111\u1ed9t bi\u1ebfn<\/p>\n

A.<\/strong>L\u1eb7p \u0111o\u1ea1n v\u00e0 m\u1ea5t \u0111o\u1ea1n<\/p>\n

B. <\/strong>\u0110\u1ea3o \u0111o\u1ea1n v\u00e0 l\u1eb7p \u0111o\u1ea1n<\/p>\n

C.<\/strong>Chuy\u1ec3n \u0111o\u1ea1n v\u00e0 m\u1ea5t \u0111o\u1ea1n<\/p>\n

D.<\/strong>Chuy\u1ec3n \u0111o\u1ea1n t\u01b0\u01a1ng h\u1ed7<\/p>\n

C\u00e2u 48. (ID: 82677)<\/strong>\u1edf m\u1ed9t lo\u00e0i \u0111\u1ed9ng v\u1eadt giao ph\u1ed1i, x\u00e9t ph\u00e9p lai con \u0111\u1ef1c: AaBbDd x con c\u00e1i AaBbdd.<\/strong>Gi\u1ea3 s\u1eed trong qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a c\u01a1 th\u1ec3 \u0111\u1ef1c, \u1edf m\u1ed9t s\u1ed1 t\u1ebf b\u00e0o, c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 mang ki\u1ec3u gen Aa kh\u00f4ng ph\u00e2n li trong gi\u1ea3m ph\u00e2n, c\u00e1c s\u1ef1 ki\u1ec7n kh\u00e1c di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng; c\u01a1 th\u1ec3 c\u00e1i gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng. Theo l\u00ed thuy\u1ebft, s\u1ef1 k\u1ebft h\u1ee3p ng\u1eabu nhi\u00ean gi\u1eefa c\u00e1c lo\u1ea1i giao t\u1eed \u0111\u1ef1c v\u00e0 c\u00e1i trong th\u1ee5 tinh c\u00f3 th\u1ec3 t\u1ea1o ra t\u1ed1i \u0111a bao nhi\u00eau lo\u1ea1i h\u1ee3p t\u1eed l\u01b0\u1ee1ng b\u1ed9i v\u00e0 bao nhi\u00eau lo\u1ea1i h\u1ee3p t\u1eed l\u1ec7ch b\u1ed9i<\/p>\n

A.<\/strong>9 v\u00e0 12               B.<\/strong>32 v\u00e0 12        C.<\/strong>18 v\u00e0 24     D.<\/strong>12 v\u00e0 4<\/p>\n

C\u00e2u 49. (ID: 82678 )<\/strong>Sau \u0111\u00e2y l\u00e0 c\u00e1c ho\u1ea1t \u0111\u1ed9ng x\u1ea3y ra trong s\u1ef1 \u0111i\u1ec1u h\u00f2a ho\u1ea1t \u0111\u1ed9ng c\u1ee7a operon lac:<\/p>\n

(1)Protein \u1ee9c ch\u1ebf li\u00ean k\u1ebft v\u1edbi v\u00f9ng v\u1eadn h\u00e0nh<\/p>\n

(2)ARN polimeraza li\u00ean k\u1ebft v\u1edbi v\u00f9ng kh\u1edfi \u0111\u1ed9ng<\/p>\n

(3)Gen c\u1ea5u tr\u00fac ti\u1ebfn h\u00e0nh phi\u00ean m\u00e3<\/p>\n

(4)1 s\u1ed1 ph\u00e2n t\u1eed lactoso li\u00ean k\u1ebft v\u1edbi protein \u1ee9c ch\u1ebf<\/p>\n

(5)Enzim do gen c\u1ea5u tr\u00fac m\u00e3 h\u00f3a ph\u00e2n gi\u1ea3i lactozo<\/p>\n

(6)Gen \u0111i\u1ec1u h\u00f2a t\u1ed5ng h\u1ee3p protein \u1ee9c ch\u1ebf<\/p>\n

Th\u1ee9 t\u1ef1 \u0111\u00fang c\u1ee7a c\u00e1c s\u1ef1 ki\u1ec7n tr\u00ean l\u00e0<\/p>\n

A.<\/strong>6 -> 2 -> 1 -> 4 -> 3 -> 5<\/p>\n

B. <\/strong>6 -> 3 -> 4 -> 1 -> 2 -> 5<\/p>\n

C.<\/strong>6 -> 1 -> 4 -> 2 -> 3 -> 5<\/p>\n

D.<\/strong>6 -> 2 -> 3 -> 4 -> 5 -> 1<\/p>\n

C\u00e2u 50. (ID: 82679)<\/strong>C\u00e1c gen ph\u00e2n li \u0111\u1ed9c l\u1eadp, s\u1ed1 ki\u1ec3u gen d\u1ecb h\u1ee3p t\u1ea1o n\u00ean t\u1eeb ph\u00e9p lai AaBbDdEEff x AabbDdEeff l\u00e0:<\/p>\n

A.<\/strong>24            B.<\/strong>32                C.<\/strong>1          D.<\/strong>26<\/p>\n

\u0110\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh \u0111\u1ec1 s\u1ed1 3 n\u0103m 2016<\/strong><\/h3>\n

C\u00e2u 1.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Con don m\u00e3 h\u00f3a axit amin m\u00eati\u00f4nin \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c l\u00e0 5\u2019AUG3\u2019<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 2.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

\u0110\u1eb7c \u0111i\u1ec3m di truy\u1ec1n ngo\u00e0i nh\u00e2n l\u00e0 :<\/p>\n

K\u1ebft qu\u1ea3 lai thu\u1eadn ngh\u1ecbch kh\u00e1c nhau, t\u00ednh tr\u1ea1ng bi\u1ec3u hi\u1ec7n \u0111\u1ed3ng \u0111\u1ec1u \u1edf 2 gi\u1edbi.<\/p>\n

Di truy\u1ec1n thu\u1eadn ngh\u1ecbch kh\u00e1c nhau do ki\u1ec3u h\u00ecnh \u0111\u1eddi con gi\u1ed1ng h\u1ec7t ki\u1ec3u h\u00ecnh \u0111\u1eddi m\u1eb9.<\/p>\n

T\u00ednh tr\u1ea1ng bi\u1ec3u hi\u1ec7n \u0111\u1ed3ng \u0111\u1ec1u 2 gi\u1edbi do gen n\u1eb1m ngo\u00e0i nh\u00e2n, kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o gi\u1edbi t\u00ednh<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 3.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

C\u00f3 aabb = 0,1  ;     A-B- = 0,35<\/p>\n

    A-bb = 0,4 ;     aaB- = 0,15<\/p>\n

Do A-bb = 0,5 \u2013 aabb<\/p>\n

A-B- = 0,25 + aabb v\u00e0 aaB- = 0,25 \u2013 aabb<\/p>\n

\u00f0  Ph\u00e9p lai s\u1ebd l\u00e0 : (Aa,Bb)   x  Ab\/ab<\/p>\n

Ta c\u00f3 aabb = 0,1<\/p>\n

M\u00e0 Ab\/ab cho ab = 0,5<\/p>\n

\u00f0  V\u1eady Aa,Bb cho ab  = 0,2<\/p>\n

\u00f0  Giao t\u1eed ab l\u00e0 giao t\u1eed mang gen ho\u00e1n v\u1ecb v\u00e0 t\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb gen f = 40%<\/p>\n

\u00f0  Ph\u00e9p lai l\u00e0 : Ab\/aB   x  Ab\/ab v\u1edbi f = 40%<\/p>\n

\u00f0  \u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 4<\/strong>: L\u1eddi gi\u1ea3i:<\/p>\n

Th\u1ef1c ch\u1ea5t c\u1ee7a th\u01b0\u1eddng bi\u1ebfn l\u00e0:   Kh\u00f4ng thay \u0111\u1ed5i ki\u1ec3u gen, ch\u1ec9 thay \u0111\u1ed5i ki\u1ec3u h\u00ecnh<\/p>\n

M\u1ee5c \u0111\u00edch l\u00e0 \u0111\u1ec3 th\u00edch nghi h\u01a1n \u0111\u1ed1i v\u1edbi s\u1ef1 thay \u0111\u1ed5i c\u1ee7a m\u00f4i tr\u01b0\u1eddng<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 5<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

T\u1ea7n s\u1ed1 c\u1ee7a m\u1ed9t ki\u1ec3u gen = S\u1ed1 c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen \u0111\u00f3 tr\u00ean t\u1ed5ng s\u1ed1 c\u00e1 th\u1ec3 c\u1ee7a qu\u1ea7n th\u1ec3<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 6.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

C\u00e1c ph\u00e1t bi\u1ec3u \u0111\u00fang l\u00e0 : (1) (2) (4) (5)<\/p>\n

C\u00e2u (3) sai v\u00ec m\u1ea1ch khu\u00f4n d\u00f9ng \u0111\u1ec3 phi\u00ean m\u00e3 ch\u1ec9 c\u00f3 th\u1ec3 l\u00e0 m\u1ea1ch c\u00f3 chi\u1ec1u 3\u2019 \u2013 5\u2019<\/p>\n

C\u00e2u (6) sai v\u00ec qu\u00e1 tr\u00ecnh phi\u00ean m\u00e3 ch\u1ec9 x\u1ea3y ra tr\u00ean m\u1ea1ch m\u00e3 g\u1ed1c \u00f3 phi\u00ean m\u00e3 ch\u1ec9 x\u1ea3y ra tr\u00ean 1 m\u1ea1ch<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 7.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Do \u1edf l\u1ea7n ph\u00e2n b\u00e0o th\u1ee9 4 m\u1edbi x\u1ea3y ra \u0111\u1ed9t bi\u1ebfn tr\u00eanm\u1ed9t s\u1ed1<\/u>c\u00e1c t\u1ebf b\u00e0o n\u00ean<\/p>\n

–        C\u00e1c t\u1ebf b\u00e0o kh\u00f4ng b\u1ecb \u0111\u1ed9t bi\u1ebfn nguy\u00ean ph\u00e2n cho d\u00f2ng t\u1ebf b\u00e0o 2n b\u00ecnh th\u01b0\u1eddng<\/p>\n

–        C\u00e1c t\u1ebf b\u00e0o c\u00f3 1 c\u1eb7p NST Dd kh\u00f4ng ph\u00e2n li nguy\u00ean ph\u00e2n cho 2 d\u00f2ng t\u1ebf b\u00e0o l\u00e0 2n+2 v\u00e0 2n \u2013 2<\/p>\n

\u0110\u00e1p \u00e1n 1 d\u00f2ng t\u1ebf b\u00e0o b\u00ecnh th\u01b0\u1eddng (2n) v\u00e0 2 d\u00f2ng t\u1ebf b\u00e0o \u0111\u1ed9t bi\u1ebfn (2n+2 v\u00e0 2n-2)<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 8<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

1 t\u1ebf b\u00e0o sinh tinh gi\u1ea3m ph\u00e2n ch\u1ec9 cho t\u1ed1i \u0111a 4 lo\u1ea1i giao t\u1eed<\/p>\n

NST k\u00e9pBd<\/u>*Bd<\/u>\/bD<\/u>*bD<\/u>sau khi ho\u00e1n v\u1ecb gen tr\u1edf th\u00e0nhBd<\/u>*BD<\/u>\/bd<\/u>*bD<\/u><\/p>\n

4 lo\u1ea1i giao t\u1eed n\u00e0y l\u00e0 nh\u1eefng lo\u1ea1i n\u00e0o c\u00f2n ph\u1ee5 thu\u1ed9c v\u00e1o s\u1ef1 s\u1eafp x\u1ebfp c\u1ee7a 2 NST tr\u00ean m\u1eb7t ph\u1eb3ng ph\u00e2n b\u00e0o trong gi\u1ea3m ph\u00e2n I:<\/p>\n

A*A      a*a<\/p>\n

K\u1ebft h\u1ee3p v\u1edbi<\/p>\n

Bd<\/u>*BD<\/u>     bd<\/u>*bD<\/u><\/p>\n

Nh\u01b0 v\u1eady s\u1ebd cho 2 tr\u01b0\u1eddng h\u1ee3p:<\/p>\n

Abd<\/u>, AbD<\/u>, aBd<\/u>, aBD<\/u>ho\u1eb7c<\/p>\n

ABD<\/u>, ABd<\/u>, abd<\/u>, abD<\/u><\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 9.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

1:2:1 => b\u1ed1 m\u1eb9 \u0111\u1ec1u cho 2 lo\u1ea1i giao t\u1eed v\u1edbi t\u1ec9 l\u1ec7 ngang nhau<\/p>\n

Ta th\u1ea5y 1 cho 3 giao t\u1eed AA: Aa:aa<\/p>\n

2 c\u00f3 Aaaa cho hai lo\u1ea1i giao t\u1eed Aa: aa,  AAAa cho hai lo\u1ea1i giao t\u1eed AA: Aa=> cho t\u1ec9 l\u1ec7 ki\u1ec3u gen AAAa : 2 AAaa: 1 Aaaa<\/p>\n

3 hai b\u1ed1 m\u1eb9 \u0111\u1ec1u cho 2 giao t\u1eed =>F<\/p>\n

1<\/dd>\n

  1AaBB : 2AaBb : 1Aabb<\/p>\n

4 hai b\u1ed1 m\u1eb9 \u0111\u1ec1u cho 2 giao t\u1eed => F<\/p>\n

1<\/dd>\n

cho t\u1ec9  l\u1ec7ki\u1ec3u gen 1AAaaBBBB: 2AAaaBBBb: 1AAaaBBbb<\/p>\n

5 v\u00e0 6 lo\u1ea1i<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 10.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Alen a c\u00f3 t\u1ed5ng s\u1ed1 nu l\u00e0 : 120*10*2 = 2400 nu \u00f3 2A + 2G = 2400<\/p>\n

M\u00e0 alen a c\u00f3 2800 li\u00ean k\u1ebft Hidro \u00f3  2A + 3G = 2800<\/p>\n

V\u1eady alen a c\u00f3 :<\/p>\n

A = T = 800<\/p>\n

G = X = 400<\/p>\n

Do t\u1eeb alen A b\u1ecb \u0111\u1ed9t bi\u1ebfn 5-BU th\u00e0nh alen a \u00f3 t\u1eeb A \u0111\u1ed9t bi\u1ebfn thay A-T b\u1eb1ng G-X<\/p>\n

\u00f0  Alen A c\u00f3 : A = T = 801; G = X = 399<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 11.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

\u0110\u1ed9t bi\u1ebfn gen th\u01b0\u1eddng g\u00e2y h\u1ea1i v\u00ec : L\u00e0m sai l\u1ec7ch th\u00f4ng tin di truy\u1ec1n d\u1eabn t\u1edbi l\u00e0m r\u1ed1i lo\u1ea1n qu\u00e1 tr\u00ecnh sinh t\u1ed5ng h\u1ee3p protein<\/p>\n

Protein t\u1ed5ng h\u1ee3p \u0111\u01b0\u1ee3c ra ho\u1eb7c l\u00e0 b\u1ecb m\u1ea5t ch\u1ee9c n\u0103ng ho\u1eb7c l\u00e0 ch\u1ee9c n\u0103ng sai l\u1ec7ch g\u00e2y r\u1ed1i lo\u1ea1n chuy\u1ec3n h\u00f3a trong c\u00f3 th\u1ec3 khi\u1ebfn cho c\u01a1 th\u1ec3 gi\u1ea3m s\u1ee9c s\u1ed1ng, th\u01b0\u1eddng d\u1eabn t\u1edbi sinh v\u1eadt b\u1ecb ch\u1ebft<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 12.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

B\u1ec7nh do \u0111\u1ed9t bi\u1ebfn NST l\u00e0 b\u1ec7nh ung th\u01b0 m\u00e1u<\/p>\n

3 b\u1ec7nh c\u00f2n l\u1ea1i \u0111\u1ec1u do \u0111\u1ed9t bi\u1ebfn s\u1ed1 l\u01b0\u1ee3ng NST g\u00e2y ra<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 13<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

AB\/ab   x  AB\/ab v\u1edbi f = 20%<\/p>\n

\u0110\u1eddi con, aabb = 0,4*0,4 = 0,16<\/p>\n

Dd x dd<\/p>\n

\u0110\u1eddi con, dd  = 0,5<\/p>\n

V\u1eady KH aabbdd \u1edf \u0111\u1eddi con chi\u1ebfm t\u1ec9 l\u1ec7: 0,16*0,5 = 0,08 = 8%<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 14.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

S\u1ef1 t\u0103ng m\u1ed9t s\u1ed1 nguy\u00ean l\u1ea7n b\u1ed9 NST \u0111\u01a1n b\u1ed9i c\u1ee7a 1 lo\u00e0i l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng t\u1ef1 \u0111a b\u1ed9i<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

D\u1ecb \u0111a b\u1ed9i l\u00e0 b\u1ed9 NST g\u1ed3m c\u00f3 2 b\u1ed9 NST l\u01b0\u1ee1ng b\u1ed9i c\u1ee7a 2 lo\u00e0i kh\u00e1c nhau<\/p>\n

Tam b\u1ed9i 3n, t\u1ee9 b\u1ed9i 4n l\u00e0 c\u00e1c th\u1ec3 \u0111a b\u1ed9i c\u00f3 b\u1ed9 NST g\u1ea5p 3; 4 l\u1ea7n b\u1ed9 NST \u0111\u01a1n b\u1ed9i<\/p>\n

C\u00e2u 15.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

R\u1ed1i lo\u1ea1n ph\u00e2n b\u00e0o 1 NST k\u00e9p trong c\u1eb7p Bb t\u1ee9c l\u00e0 ho\u1eb7c l\u00e0 B kh\u00f4ng ph\u00e2n li ho\u1eb7c l\u00e0 b kh\u00f4ng ph\u00e2n li<\/p>\n

2 t\u1ebf b\u00e0o con s\u1ebd l\u00e0 : AaBbbddEe v\u00e0 AaBddEe<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 16<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

AAaa cho giao t\u1eed : 1\/6AA: 4\/6Aa : 1\/6aa<\/p>\n

BBbb cho giao t\u1eed : 1\/6BB : 4\/6Bb : 1\/6bb<\/p>\n

T\u1ec9 l\u1ec7 giao t\u1eed Aabb \u0111\u01b0\u1ee3c t\u1ea1o ra l\u00e0 : 4\/6 x 1\/6 = 4\/36<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 17.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

M\u1ee9c c\u1ea5u tr\u00fac c\u00f3 \u0111\u01b0\u1eddng k\u00ednh 30 nm l\u00e0 s\u1ee3i nhi\u1ec5m s\u1eafc<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 18.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Ph\u00e9p lai A t\u1ea1o ra 9 KG, 4 KH<\/p>\n

Ph\u00e9p lai B t\u1ea1o ra 10 KG, 4 KH<\/p>\n

Ph\u00e9p lai C t\u1ea1o ra 12KG, 8KH<\/p>\n

Ph\u00e9p lai C t\u1ea1o ra 6 KG , 4KH<\/p>\n

V\u1eady ph\u00e9p laic ho \u0111\u1eddi con c\u00f3 nhi\u1ec1u KG v\u00e0 KH nh\u1ea5t l\u00e0 ph\u00e9p lai C<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 19<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

C\u00e1c ph\u00e1t bi\u1ec3u \u0111\u00fang l\u00e0 (1)  (4)<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

5 KG c\u1ee7a (1) l\u00e0 AAAA, AAAa, AAaa, Aaaa, aaaa<\/p>\n

5KG c\u1ee7a (4) l\u00e0 X<\/p>\n

A<\/dd>\n

X<\/p>\n

A<\/dd>\n

, X<\/p>\n

A<\/dd>\n

X<\/p>\n

a<\/dd>\n

, X<\/p>\n

a<\/dd>\n

X<\/p>\n

a<\/dd>\n

, X<\/p>\n

A<\/dd>\n

Y, X<\/p>\n

a<\/dd>\n

Y<\/p>\n

C\u00e2u 20<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

\u01afu th\u1ebf lai l\u00e0 l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng con lai c\u00f3 n\u0103ng su\u1ea5t, ph\u1ea9m ch\u1ea5t, s\u1ee9c ch\u1ed1ng ch\u1ecbu v\u00e0 kh\u1ea3 n\u0103ng sinh tr\u01b0\u1edfng ph\u00e1t tri\u1ec3n v\u01b0\u1ee3t tr\u1ed9i so v\u1edbi c\u00e1c d\u1ea1ng b\u1ed1 m\u1eb9<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 21<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Y\u1ebfu t\u1ed1 kh\u00f4ng thay \u0111\u1ed5i \u1edf qu\u1ea7n th\u1ec3 t\u1ef1 th\u1ee5 l\u00e0 t\u1ea7n s\u1ed1 c\u00e1c alen<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 22<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Ph\u00e1t bi\u1ec3u kh\u00f4ng \u0111\u00fang l\u00e0 : ng\u01b0\u1eddi ta t\u1ea1o ra nh\u1eefng con lai kh\u00e1c d\u00f2ng c\u00f3 \u01b0u th\u1ebf lai cao \u0111\u1ec3 s\u1eed d\u1ee5ng cho vi\u1ec7c nh\u00e2n gi\u1ed1ng.<\/p>\n

\u0110i\u1ec1u n\u00e0y l\u00e0 sai v\u00ec con lai trong \u01b0u th\u1ebf lai mang gen d\u1ecb h\u1ee3p. khi \u0111em ra l\u00e0m gi\u1ed1ng th\u00ec \u0111\u1eddi sau s\u1ebd c\u00e0ng ng\u00e0y c\u00e0ng ph\u00e2n h\u00f3a, l\u00e0m tho\u00e1i h\u00f3a. Con lai trong \u01b0u th\u1ebf lai th\u01b0\u1eddng \u0111\u01b0\u1ee3c \u0111em ra ph\u1ee5c v\u1ee5 cho ch\u0103n nu\u00f4i, mua b\u00e1n<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 23.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

F1 x c\u00e2y X<\/p>\n

F2: 54% A-B : 21%A-bb : 21%aaB- : 4% aabb<\/p>\n

A-B- = 0,5 + aabb<\/p>\n

A-bb = aaB- = 0,25 \u2013 aabb<\/p>\n

\u00f0  Hai c\u00e2y  \u0111em lai l\u00e0 c\u00e2y d\u1ecb h\u1ee3p 2 c\u1eb7p gen ( Aa,Bb)<\/p>\n

\u00f0  Ta c\u00f3 ( Aa,Bb) x( Aa,Bb)<\/p>\n

C\u00f3 \u0111\u1eddi con aabb = 0.04 = 0.2 x 0.2 = 0.4 x 0.1 <\/p>\n

\u00f0  aabb = 0.04 = 0.2ab x 0.2ab => Ab\/aB x Ab\/aB ho\u00e1n v\u1ecb f = 40 %<\/p>\n

\u00f0  Ho\u1eb7c aabb = 0.04 = 0.4 ab x 0.1 ab => AB\/aB x Ab\/aB ho\u00e1n v\u1ecb f = 20%<\/p>\n

Qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n t\u1ea1o no\u00e3n v\u00e0 t\u1ea1o ph\u1ea5n di\u1ec5n ra gi\u1ed1ng nhau n\u00ean ki\u1ec3u gen c\u1ee7a F<\/p>\n

1<\/dd>\n

l\u00e0 Ab\/aB v\u00e0  f = 40%  <\/p>\n

\u0110\u00e1p \u00e1n A  <\/p>\n

C\u00e2u 24<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Do t\u1ef1 th\u1ee5 => \u0111\u1eddi con, t\u1ec9 l\u1ec7 hoa v\u00e0ng l\u00e0 : 1\/3 x 1\/4 = 1\/12<\/p>\n

V\u1eady \u0111\u1eddi con : 11 \u0111\u1ecf : 1 v\u00e0ng<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 25<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Phep lai m\u00e0 c\u00f3 th\u1ec3 ph\u00e2n bi\u1ec7t \u0111\u01b0\u1ee3c  t\u1eb1m con ngay t\u1eeb gian \u0111o\u1ea1n tr\u1ee9ng l\u00e0 X<\/p>\n

a<\/dd>\n

X<\/p>\n

a<\/dd>\n

x X<\/p>\n

A<\/dd>\n

Y<\/p>\n

\u0110\u1eddi con : X<\/p>\n

A<\/dd>\n

X<\/p>\n

a<\/dd>\n

: X<\/p>\n

a<\/dd>\n

Y<\/p>\n

Tr\u1ee9ng cho gi\u1edbi \u0111\u1ef1c m\u00e0u s\u1eabm<\/p>\n

Tr\u1ee9ng cho gi\u1edbi c\u00e1i m\u00e0u tr\u1eafng<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 26<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

T\u1ebf b\u00e0o con 1 b\u00ecnh th\u01b0\u1eddng Gp II cho 2 tinh tr\u00f9ng b\u00ecnh th\u01b0\u1eddng<\/p>\n

T\u1ebf b\u00e0o con 2 \u0111\u1ed9t bi\u1ebfn t\u1ea1o 2 tinh tr\u00f9ng l\u00e0 n +1 = 13 ( c\u00f3 2 chi\u1ebfc s\u1ed1 13) v\u00e0 n-1 = 11 ( kh\u00f4ng c\u00f3 chi\u1ebfc s\u1ed1 13)<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 27.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

P d\u1ecb h\u1ee3p 3 c\u1eb7p t\u1ef1 th\u1ee5<\/p>\n

F1: aaB-dd = 5,25%%<\/p>\n

Gi\u1ea3 s\u1eed 3 gen PLDL, v\u1eady Kh aaB-dd \u1edf \u0111\u1eddi con l\u00e0 : 1\/4  x 3\/4  x 1\/4 = 4,6875% kh\u00e1c \u0111\u1ec1 b\u00e0i<\/p>\n

\u00f0  3 gen kh\u00f4ng th\u1ec3 ph\u00e2n li \u0111\u1ed9c l\u1eadp<\/p>\n

\u00f0  2 trong 3 gen c\u00f9ng tr\u00ean 1 NST<\/p>\n

\u00f0  Gi\u1ea3 s\u1eed \u0111\u00f3 l\u00e0 gen B v\u00e0 gen D<\/p>\n

Ta c\u00f3 aaB-dd = 5,25%<\/p>\n

\u00f0  B-dd = 21%%<\/p>\n

\u00f0  Kh bbdd = 4%<\/p>\n

\u00f0  Giao t\u1eed bd = 20% l\u00e0 giao t\u1eed mang gen ho\u00e1n v\u1ecb<\/p>\n

\u00f0  T\u1ea7n s\u1ed1 ho\u00e1n v\u1ecb f = 40%<\/p>\n

\u00f0  P : Aa  Bd\/dB<\/p>\n

\u00f0  \u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 28.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Di truy\u1ec1n li\u00ean k\u1ebft kh\u00f4ng ho\u00e0n t\u00f2an l\u00e0m xu\u1ea5t hi\u1ec7n c\u00e1c bi\u1ebfn d\u1ecb t\u1ed5 h\u1ee3p<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 29<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Ptc : AB\/AB  x  ab\/ab<\/p>\n

F1: AB\/ab<\/p>\n

F1 lai ph\u00e2n t\u00edch, f = 25%<\/p>\n

Giao t\u1eed : AB = ab = 37,5%<\/p>\n

         Ab = aB = 12,5%<\/p>\n

F2: t\u1ec9 l\u1ec7 c\u00e2y c\u00f3 qu\u1ea3 ng\u1eb5n chua ab\/ab l\u00e0 37,5%<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 30<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

C\u00e1c gen li\u00ean k\u1ebft v\u1edbi nhau c\u00f3 \u0111\u1eb7c t\u00ednh l\u00e0 thu\u1ed9c v\u1ec1 c\u00f9ng 1 ADN<\/p>\n

B sai do c\u00f3 th\u1ec3 2 gen li\u00ean k\u1ebft v\u1edbi nhau nh\u01b0ng trong \u0111\u00f3 ch\u1ec9 c\u00f3 1 gen bi\u1ec3u hi\u1ec7n, gen c\u00f2n l\u1ea1i th\u00ec b\u1ecb gen kh\u00e1c \u00e1t ch\u1ebf n\u00ean kh\u00f4ng bi\u1ec3u hi\u1ec7n<\/p>\n

C sai do thu\u1ed9c c\u00f9ng c\u1eb7p t\u01b0\u01a1ng \u0111\u1ed3ng nh\u01b0ng ch\u01b0a ch\u1eafc \u0111\u00e3 li\u00ean k\u1ebft v\u1edbi nhau v\u00ec c\u00f3 th\u1ec3 n\u1eb1m tr\u00ean 2 NST kh\u00e1c nhau<\/p>\n

D ch\u01b0a ch\u00ednh x\u00e1c v\u00ec 2 gen c\u00f3 locut kh\u00e1c nhau nh\u01b0ng c\u00f3 th\u1ec3 gen n\u00e0y c\u00f3 locut tr\u00ean NST n\u00e0y, gen kia l\u1ea1i c\u00f3 locut tr\u00ean NST kh\u00e1c<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 31<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

T\u1ed5 h\u1ee3p \u00fd \u0111\u00fang l\u00e0 : 1, 2, 3, 5, 6, 7<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

1 \u0111\u00fang v\u00ec c\u1ea3i b\u1eafp c\u00f3 b\u1ed9 NST l\u01b0\u1ee1ng b\u1ed9i 2n = 18 n\u00ean b\u1ed9 NST \u0111\u01a1n b\u1ed9i n = 9<\/p>\n

2 \u0111\u00fang v\u00ec \u0111\u1eadu H\u00e0 lan c\u00f3 b\u1ed9 NST l\u01b0\u1ee1ng b\u1ed9i 2n = 14 n\u00ean b\u1ed9 NST tam b\u1ed9i 3n  = 21<\/p>\n

4 sai do l\u00faa 2n = 4 n\u00ean th\u1ec3 tam b\u1ed9i l\u00faa 3n = 6 ch\u1eb5n<\/p>\n

8 sai do th\u1ec3 t\u1ee9 b\u1ed9i 4n lu\u00f4n l\u00e0 1 s\u1ed1 ch\u1eb5n NST<\/p>\n

C\u00e2u 32.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

C\u1eb7p gen A, a c\u00f3 : KG : 3 , KH : 2<\/p>\n

3 alen I<\/p>\n

A<\/dd>\n

, I<\/p>\n

B<\/dd>\n

, I<\/p>\n

O<\/dd>\n

c\u00f3 KG: 3+3C2 = 6<\/p>\n

v\u00e0 KH : 4 KH : A, B, O, AB<\/p>\n

C\u1eb7p gen M,m tr\u00ean NST gi\u1edbi t\u00ednh X c\u00f3: KG: 2+2C1+2 = 5<\/p>\n

                      V\u00e0 KH : 2 KH<\/p>\n

V\u1eady s\u1ed1 KG t\u1ed1i \u0111a : 90<\/p>\n

S\u1ed1 KH t\u1ed1i \u0111a: 16<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 33<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

K\u1ebft lu\u1eadn \u0111\u00fang l\u00e0 Th\u1ec3 \u0111\u1ed3ng h\u1ee3p cho 1 lo\u1ea1i giao t\u1eed, th\u1ec3 d\u1ecb h\u1ee3p cho 2 lo\u1ea1i giao t\u1eed v\u1edbi t\u1ec9 l\u1ec7 1:1<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 34<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

G\u1ecdi s\u1ed1 ph\u00e2n t\u1eed AND ban \u0111\u1ea7u, ch\u1ec9 ch\u1ee9a N<\/p>\n

15<\/dd>\n

l\u00e0x<\/em><\/p>\n

T\u00e1i b\u1ea3n 5 l\u1ea7n, s\u1ed1 ph\u00e2n t\u1eed ADN ch\u1ec9 ch\u1ee9a N<\/p>\n

14<\/dd>\n

l\u00e0   x.<\/em>2<\/p>\n

5<\/dd>\n

\u2013 2x = 960<\/p>\n

\u00f0  V\u1eady x = 32<\/p>\n

\u00f0  \u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 35.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

\u0110\u1ecbnh lu\u1eadt Hac \u0111i Vanbec ph\u1ea3n \u00e1nh s\u1ef1 \u1ed5n \u0111\u1ecbnh v\u1ec1 t\u1ea7n s\u1ed1 alen v\u00e0 th\u00e0nh ph\u1ea7n ki\u1ec3u gentrong qu\u1ea7n th\u1ec3 ng\u1eabu ph\u1ed1i.<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 36<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

M\u1ee9c \u0111\u1ed9 c\u00f3 l\u1ee3i hay c\u00f3 h\u1ea1i c\u1ee7a gen \u0111\u1ed9t bi\u1ebfn ph\u1ee5 thu\u1ed9c v\u00e0o m\u00f4i tr\u01b0\u1eddng s\u1ed1ng v\u00e0 t\u1ed5 h\u1ee3p gen<\/p>\n

–        C\u01a1  th\u1ec3 \u1edf m\u00f4i tr\u01b0\u1eddng n\u00e0y gen \u0111\u00f3 l\u00e0 gen c\u00f3 l\u1ee3i nh\u01b0ng sang m\u00f4i tr\u01b0\u1eddng kh\u00e1c, ki\u1ec3u h\u00ecnh do gen \u0111\u00f3 qui \u0111\u1ecbnh b\u1ecb CLTN lo\u1ea1i b\u1ecf th\u00ec \u0111\u00f3 l\u00e0 gen c\u00f3 h\u1ea1i<\/p>\n

–        T\u01b0\u01a1ng t\u1ef1 v\u1edbi t\u1ed5 h\u1ee3p gen<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 37<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

V\u00ec Gen C v\u00e0 T c\u00f9ng \u1edf 1 NST, c\u00f2n c v\u00e0 t c\u00f9ng \u1edf NST => ch\u1ec9 t\u1ea1o ra hai lo\u1ea1i giao t\u1eed CT v\u00e0 ct => t\u1ea1o ra 3 ki\u1ec3u gen CT\/ CT; CT\/ ct; ct\/ct<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 38.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Ch\u1ed3ng b\u1ea1ch t\u1ea1ng aa<\/p>\n

V\u1ee3 b\u00ecnh th\u01b0\u1eddng A- c\u00f3<\/p>\n

M\u1eb9 v\u1ee3 b\u00ecnh th\u01b0\u1eddng mang alen g\u00e2y b\u1ec7nh : Aa<\/p>\n

B\u1ed1 v\u1ee3 b\u00ecnh th\u01b0\u1eddng, KG \u0111\u1ed3ng h\u1ee3p t\u1eed : AA<\/p>\n

\u00f0  Ng\u01b0\u1eddi v\u1ee3 c\u00f3 d\u1ea1ng : (1\/2AA : 1\/2Aa)<\/p>\n

\u00f0  X\u00e1c su\u1ea5t h\u1ecd sinh con b\u1ea1ch t\u1ea1ng l\u00e0 1\/4<\/p>\n

\u00f0  X\u00e1c su\u1ea5t h\u1ecd sinh con b\u00ecnh th\u01b0\u1eddng l\u00e0 3\/4<\/p>\n

\u00f0  \u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 39.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

S\u1ef1 kh\u00f4ng ph\u00e2n li c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c c\u1eb7p NST t\u01b0\u01a1ng \u0111\u1ed3ng c\u1ee7a h\u1ee3p t\u1eed s\u1ebd d\u1eabn t\u1edbi t\u1ea5t c\u00e1c t\u1ebf b\u00e0o c\u1ee7a c\u01a1 th\u1ec3 \u0111\u1ec1u mang \u0111\u1ed9t bi\u1ebfn \u0111a b\u1ed9i: 2n => 4n, 8n\u2026<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 40.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

S\u1ef1 t\u1ef1 th\u1ee5 ph\u1ea5n s\u1ebd l\u00e0m t\u0103ng t\u1ec9 l\u1ec7 th\u1ec3 \u0111\u1ed3ng h\u1ee3p, gi\u1ea3m t\u1ec9 l\u1ec7 th\u1ec3 d\u1ecb h\u1ee3p<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 41<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

S\u1ed1 b\u1ed9 ba ch\u1ee9a 1 nu U, 2 nu c\u00f2n l\u1ea1i l\u00e0 G, X l\u00e0 3 x 2 = 6<\/p>\n

S\u1ed1 b\u1ed9 ba ch\u1ee9a 1 nu U, 2 nu G l\u00e0 3<\/p>\n

S\u1ed1 b\u1ed9 ba ch\u1ee9a 1 nu U, 2 nu X l\u00e0 3<\/p>\n

V\u1eady t\u1ed5ng c\u00f3 12 b\u1ed9 ba ch\u1ec9 ch\u1ee9a 1 nu U \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh t\u1eeb 3 nu tr\u00ean<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 42<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Qu\u1ea7n th\u1ec3 c\u00e2n b\u1eb1ng di truy\u1ec1n<\/p>\n

T\u1ec9 l\u1ec7 c\u00e2y hoa tr\u1eafng aa b\u1eb1ng 4%<\/p>\n

\u00f0  T\u1ea7n s\u1ed1 alen a l\u00e0 0,2<\/p>\n

\u00f0  C\u1ea5u tr\u00fac qu\u1ea7n th\u1ec3 l\u00e0 : 0,64AA : 0,32Aa : 0,04aa<\/p>\n

\u00f0  C\u00e1c c\u00e2y hoa \u0111\u1ecf c\u00f3 t\u1ec9 l\u1ec7 KG l\u00e0 2\/3AA : 1\/3Aa<\/p>\n

C\u00e1c c\u00e2y hoa \u0111\u1ecf giao ph\u1ea5n v\u1edbi nhau : (2\/3AA : 1\/3Aa)<\/p>\n

\u0110\u1eddi con cho ki\u1ec3u h\u00ecnh l\u1eb7n aa b\u1eb1ng 1\/6 x 1\/6 = 1\/36<\/p>\n

\u00f0  T\u1ec9 l\u1ec7 KH \u0111\u1eddi con l\u00e0 35 \u0111\u1ecf : 1 tr\u1eafng<\/p>\n

\u00f0  \u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 43<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

D\u1ea1ng \u0111\u1ed9t bi\u1ebfn g\u00e2y h\u1eadu qu\u1ea3 nghi\u00eam tr\u1ecdng nh\u1ea5t l\u00e0 : m\u1ea5t \u0111o\u1ea1n<\/p>\n

Do n\u00f3 l\u00e0m cho l\u01b0\u1ee3ng v\u1eadt ch\u1ea5t di truy\u1ec1n b\u1ecb gi\u1ea3m \u0111i d\u1eabn \u0111\u1ebfn g\u00e2y m\u1ea5t c\u00e2n b\u1eb1ng nghi\u00eam tr\u1ecdng h\u1ec7 gen d\u1eabn \u0111\u1ebfn c\u00e1 th\u1ec3 \u0111\u1ed9t bi\u1ebfn th\u01b0\u1eddng ch\u1ebft ho\u1eb7c l\u00e0 gi\u1ea3m s\u1ee9c s\u1ed1ng v\u00e0 kh\u1ea3 n\u0103ng sinh s\u1ea3n<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

C\u00e2u 44<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Phi\u00ean m\u00e3 l\u00e0 qu\u00e1 tr\u00ecnh t\u1ed5ng h\u1ee3p n\u00ean ARN<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 45.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

M\u1ee9c ph\u1ea3n \u1ee9ng do ki\u1ec3u gen qui \u0111\u1ecbnh.<\/p>\n

M\u1ee9c ph\u1ea3n \u1ee9ng l\u00e0 t\u1eadp h\u1ee3p c\u00e1c bi\u1ebfn \u0111\u1ed5i c\u1ee7a c\u01a1 th\u1ec3 sinh v\u1eadt tr\u01b0\u1edbc m\u00f4i tr\u01b0\u1eddng c\u1ee7a c\u00f9ng 1 ki\u1ec3u gen.<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 46<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

C\u00e1c gen tr\u00ean NST X di truy\u1ec1n ch\u00e9o.<\/p>\n

NST X c\u1ee7a XY truy\u1ec1n cho \u0111\u1eddi con XX, NST X c\u1ee7a gi\u1edbi XX truy\u1ec1n cho \u0111\u1eddi con XY, XX nh\u01b0ng v\u1eabn coi l\u00e0 ch\u00e9o v\u00ec t\u00ednh tr\u1ea1ng gi\u1edbi XX th\u01b0\u1eddng bi\u1ec3u hi\u1ec7n th\u00e0nh t\u00ednh tr\u1ea1ng gi\u1edbi XY v\u00e0 ng\u01b0\u1ee3c l\u1ea1i<\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

C\u00e2u 47<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

Trao \u0111\u1ed5i ch\u00e9o kh\u00f4ng c\u00e2n gi\u1eefa 2 NST kh\u00e1c ngu\u1ed3n g\u1ed1c trong c\u1eb7p t\u01b0\u01a1ng \u0111\u1ed3ng g\u00e2y ra d\u1ea1ng \u0111\u1ed9t bi\u1ebfn m\u1ea5t \u0111o\u1ea1n v\u00e0 l\u1eb7p \u0111o\u1ea1n<\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

C\u00e2u 48.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

X\u00e9t c\u1eb7p gen Aa<\/p>\n

C\u01a1 th\u1ec3 \u0111\u1ef1c cho giao t\u1eed : A , a , Aa, 0<\/p>\n

C\u01a1 th\u1ec3 c\u00e1i cho giao t\u1eed : A, a<\/p>\n

H\u1ee3p t\u1eed : 3 b\u00ecnh th\u01b0\u1eddng ;  4 \u0111\u1ed9t bi\u1ebfn<\/p>\n

X\u00e9t BbDd x Bbdd<\/p>\n

Cho \u0111\u1eddi con 3  x 2 = 6 lo\u1ea1i KG<\/p>\n

V\u1eady s\u1ed1 lo\u1ea1i h\u1ee3p t\u1eed l\u01b0\u1ee1ng b\u1ed9i l\u00e0 : 3 x 6 = 18<\/p>\n

S\u1ed1 lo\u1ea1i h\u1ee3p t\u1eed l\u1ec7ch b\u1ed9i l\u00e0 4 x 6 = 24<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

C\u00e2u 49<\/strong>. L\u1eddi gi\u1ea3i:<\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

Tr\u00ecnh t\u1ef1 l\u00e0 6 -> 1 -> 4 -> 2 -> 3 -> 5<\/p>\n

C\u00e2u 50.<\/strong>L\u1eddi gi\u1ea3i:<\/p>\n

Ph\u00e9p lai: AaBbDdEEff x AabbDdEeff<\/p>\n

S\u1ed1 ki\u1ec3u gen t\u1ed1i \u0111a t\u1ea1o ra l\u00e0 : 36<\/p>\n

S\u1ed1 ki\u1ec3u gen \u0111\u1ed3ng h\u1ee3p t\u1eed v\u1ec1 t\u1ea5t c\u1ea3 c\u00e1c gen l\u00e0 : 4<\/p>\n

V\u1eady s\u1ed1 ki\u1ec3u gen d\u1ecb h\u1ee3p t\u1eed l\u00e0 36 \u2013 4 = 32<\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n<\/p>\n

T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"

\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh n\u0103m 2016 t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 3, \u0111\u1ec1 thi g\u1ed3m 50 c\u00e2u h\u1ecfi v\u00e0 \u0111\u01b0\u1ee3c gi\u1ea3i \u0111\u00e1p chi ti\u1ebft d\u01b0\u1edbi \u0111\u00e2y: Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh C\u00e2u 1. (ID: 82627)\u1ede sinh v\u1eadt nh\u00e2n th\u1ef1c, codon n\u00e0o sau \u0111\u00e2y m\u00e3 h\u00f3a axit […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[129],"tags":[],"yoast_head":"\n