\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh 2016 t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 4, \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt th\u1ee9 s\u00e1u ng\u00e0y 16\/10\/2015.<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh<\/p>\n<\/div>\n
\nC\u00e2u 1. (ID: 100376)<\/strong>Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c?<\/p>\n(1) Trong c\u00e1c m\u1ee9c c\u1ea5u tr\u00fac si\u00eau hi\u1ec3n vi c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3, s\u1ee3i nhi\u1ec5m s\u1eafc c\u00f3 \u0111\u01b0\u1eddng k\u00ednh 700 nm.<\/p>\n
(2) V\u00f9ng \u0111\u1ea7u m\u00fat c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f3 t\u00e1c d\u1ee5ng b\u1ea3o v\u1ec7 c\u00e1c nhi\u1ec5m s\u1eafc th\u1ec3 c\u0169ng nh\u01b0 l\u00e0m cho c\u00e1c nhi\u1ec5m s\u1eafc th\u1ec3 kh\u00f4ng d\u00ednh v\u00e0o nhau.<\/p>\n
(3) Th\u00e0nh ph\u1ea7n ch\u1ee7 y\u1ebfu c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c g\u1ed3m ADN m\u1ea1ch k\u00e9p v\u00e0 pr\u00f4t\u00eain lo\u1ea1i hist\u00f4n.<\/p>\n
(4) Trong c\u00e1c m\u1ee9c c\u1ea5u tr\u00fac si\u00eau hi\u1ec3n vi c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3, s\u1ee3i c\u01a1 b\u1ea3n v\u00e0 s\u1ee3i nhi\u1ec5m s\u1eafc c\u00f3 \u0111\u01b0\u1eddng k\u00ednh l\u1ea7n l\u01b0\u1ee3t l\u00e0 30 nm v\u00e0 300 nm.<\/p>\n
A. 1 B.<\/strong>2 C.<\/strong>3. D.<\/strong>4.<\/p>\nC\u00e2u 2<\/strong>.(ID: 100377)<\/strong>M\u1ed9t nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f3 c\u00e1c \u0111o\u1ea1n kh\u00e1c nhau s\u1eafp x\u1ebfp theo tr\u00ecnh t\u1ef1 ABCDEG*HKM \u0111\u00e3 b\u1ecb \u0111\u1ed9t bi\u1ebfn. Nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u1ed9t bi\u1ebfn c\u00f3 tr\u00ecnh t\u1ef1 ABCDCDEG*HKM. Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 d\u1ea1ng \u0111\u1ed9t bi\u1ebfn n\u00e0y<\/p>\n(1) th\u01b0\u1eddng l\u00e0m xu\u1ea5t hi\u1ec7n nhi\u1ec1u gen m\u1edbi trong qu\u1ea7n th\u1ec3.<\/p>\n
(2) th\u01b0\u1eddng g\u00e2y ch\u1ebft cho c\u01a1 th\u1ec3 mang nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u1ed9t bi\u1ebfn.<\/p>\n
(3) th\u01b0\u1eddng l\u00e0m thay \u0111\u1ed5i s\u1ed1 nh\u00f3m gen li\u00ean k\u1ebft c\u1ee7a lo\u00e0i. <\/p>\n<\/div>\n
\n(4) th\u01b0\u1eddng l\u00e0m t\u0103ng ho\u1eb7c gi\u1ea3m c\u01b0\u1eddng \u0111\u1ed9 bi\u1ec3u hi\u1ec7n c\u1ee7a t\u00ednh tr\u1ea1ng.<\/p>\n
(5) th\u01b0\u1eddng t\u1ea1o \u0111i\u1ec1u ki\u1ec7n cho \u0111\u1ed9t bi\u1ebfn gen, t\u1ea1o n\u00ean c\u00e1c gen m\u1edbi trong qu\u00e1 tr\u00ecnh ti\u1ebfn h\u00f3a.<\/p>\n
A.<\/strong>1 B.<\/strong>2. C.<\/strong>3. D.<\/strong>4<\/p>\nC\u00e2u 3<\/strong>.(ID: 100378)<\/strong>M\u1ed9t trong nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m c\u1ee7a gen ngo\u00e0i nh\u00e2n l\u00e0<\/p>\nA. kh\u00f4ng b\u1ecb \u0111\u1ed9t bi\u1ebfn d\u01b0\u1edbi t\u00e1c \u0111\u1ed9ng c\u1ee7a c\u00e1c t\u00e1c nh\u00e2n \u0111\u1ed9t bi\u1ebfn.<\/p>\n
B. c\u00f3 kh\u1ea3 n\u0103ng nh\u00e2n \u0111\u00f4i v\u00e0 phi\u00ean m\u00e3.<\/p>\n
C. lu\u00f4n lu\u00f4n t\u1ed3n t\u1ea1i th\u00e0nh t\u1eebng c\u1eb7p alen.<\/p>\n
D.<\/strong>ch\u1ec9 m\u00e3 h\u00f3a cho c\u00e1c protein tham gia c\u1ea5u tr\u00fac nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\nC\u00e2u 4<\/strong>.(ID: 100379)<\/strong>\u1ede m\u1ed9t sinh v\u1eadt v\u1edbi s\u1ed1 l\u01b0\u1ee3ng nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u01a1n l\u00e0 12 (n=12), M\u1ed9t tr\u1ee9ng s\u1ebd \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh ch\u1ee9a c\u1ea3 12 nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f3 ngu\u1ed3n g\u1ed1c t\u1eeb m\u1eb9, c\u00f3 x\u00e1c su\u1ea5t l\u00e0 bao nhi\u00eau?<\/p>\nA.<\/strong>(1\/12) B.<\/strong>(1\/10)<\/p>\n12<\/dd>\n C.<\/strong>(1\/2)<\/p>\n12<\/dd>\n D.<\/strong>(10\/12)<\/p>\n12<\/dd>\n<\/p>\nC\u00e2u 5 .<\/strong>(ID: 100380)<\/strong>Khi n\u00f3i v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf t\u1ebf b\u00e0o nh\u00e2n th\u1ef1c, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y \u0111\u00fang?<\/p>\nA. \u0110\u01a1n v\u1ecb c\u1ea5u tr\u00fac c\u01a1 b\u1ea3n c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0 nucl\u00ea\u00f4x\u00f4m.<\/p>\n
B. Nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0 v\u1eadt ch\u1ea5t di truy\u1ec1n \u1edf c\u1ea5p \u0111\u1ed9 ph\u00e2n t\u1eed.<\/p>\n
C.<\/strong>Th\u00e0nh ph\u1ea7n ho\u00e1 h\u1ecdc ch\u1ee7 y\u1ebfu c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0 ARN v\u00e0 pr\u00f4t\u00eain.<\/p>\nD.<\/strong>C\u1ea5u tr\u00fac cu\u1ed9n xo\u1eafn t\u1ea1o \u0111i\u1ec1u ki\u1ec7n cho s\u1ef1 nh\u00e2n \u0111\u00f4i nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\nC\u00e2u 6<\/strong>.(ID: 100381)<\/strong>\u1ede m\u1ed9t gia \u0111\u00ecnh n\u1ecd, ng\u01b0\u1eddi b\u1ed1 m\u0103c b\u1ec7nh m\u00f9 m\u00e0u \u0111\u1ecf l\u1ee5c c\u00f2n ng\u01b0\u1eddi m\u1eb9 d\u1ecb h\u1ee3p v\u1ec1 t\u00ednh tr\u1ea1ng n\u00e0y. \u0110\u1ee9a con trai c\u1ee7a h\u1ecd b\u1ecb m\u00f9 m\u00e0u v\u00e0 m\u1eafc h\u1ed9i ch\u1ee9ng Claifent\u01a1 (XXY). Cho r\u1eb1ng kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn gen c\u0169ng nh\u01b0 \u0111\u1ed9t bi\u1ebfn nhi\u1ec5m s\u1eafc th\u1ec3 x\u1ea3y ra. \u0110i\u1ec1u kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y l\u00e0 ch\u00ednh x\u00e1c?<\/p>\nA. \u1ede gi\u1ea3m ph\u00e2n I, m\u1eb9 gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng c\u00f2n b\u1ed1 kh\u00f4ng c\u00f3 s\u1ef1 ph\u00e2n ly nhi\u1ec5m s\u1eafc th\u1ec3 trong gi\u1ea3m ph\u00e2n I.<\/p>\n
B. Trong gi\u1ea3m ph\u00e2n I, \u1edf b\u1ed1 kh\u00f4ng c\u00f3 s\u1ef1 ph\u00e2n ly nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f2n \u1edf m\u1eb9 gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng.<\/p>\n
C. \u1ede c\u1ea3 b\u1ed1 v\u00e0 m\u1eb9, \u1edf gi\u1ea3m ph\u00e2n II c\u00f3 r\u1ed1i lo\u1ea1n kh\u00f4ng ph\u00e2n ly nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\n
D. Qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n h\u00ecnh th\u00e0nh giao t\u1eed \u1edf ng\u01b0\u1eddi b\u1ed1 di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng, tuy nh\u1ec9\u00ean \u1edf gi\u1ea3m ph\u00e2n II nhi\u1ec5m s\u1eafc th\u1ec3 gi\u1edbi t\u00ednh c\u1ee7a ng\u01b0\u1eddi m\u1eb9 kh\u00f4ng ph\u00e2n ly.<\/p>\n
C\u00e2u 7<\/strong>.(ID: 100382)<\/strong>Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang khi n\u00f3i v\u1ec1 th\u1ec3 d\u1ecb \u0111a b\u1ed9i? <\/p>\n<\/div>\n(1) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i c\u00f3 vai tr\u00f2 quan tr\u1ecdng trong qu\u00e1 tr\u00ecnh h\u00ecnh th\u00e0nh lo\u00e0i m\u1edbi.<\/p>\n
(2) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i c\u00f3 th\u1ec3 sinh tr\u01b0\u1edfng, ph\u00e1t tri\u1ec3n v\u00e0 sinh s\u1ea3n h\u1eefu t\u00ednh b\u00ecnh th\u01b0\u1eddng.<\/p>\n
(3) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i th\u01b0\u1eddng g\u1eb7p \u1edf \u0111\u1ed9ng v\u1eadt, \u00edt g\u1eb7p \u1edf th\u1ef1c v\u1eadt.<\/p>\n
(4) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh do lai xa k\u1ebft h\u1ee3p v\u1edbi \u0111a b\u1ed9i ho\u00e1<\/p>\n
A.<\/strong>l B.<\/strong>2 C.<\/strong>3 D 4<\/p>\nC\u00e2u 8.<\/strong>(ID: 100383)<\/strong>Trong m\u1ed9t t\u1ebf b\u00e0o sinh tinh, x\u00e9t hai c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u01b0\u1ee3c k\u00ed hi\u1ec7u l\u00e0 Aa v\u00e0 Bb. Khi t\u1ebf b\u00e0o n\u00e0y gi\u1ea3m ph\u00e2n c\u1eb7p Aa ph\u00e2n li b\u00ecnh th\u01b0\u1eddng, c\u1eb7p Bb kh\u00f4ng ph\u00e2n li trong gi\u1ea3m ph\u00e2n I, gi\u1ea3m ph\u00e2n II di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng. C\u00e1c lo\u1ea1i giao t\u1eed c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1eeb qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a t\u1ebf b\u00e0o tr\u00ean l\u00e0<\/p>\nA. Abb v\u00e0 B ho\u1eb7c ABB v\u00e0 b. B.<\/strong>ABb v\u00e0 A ho\u1eb7c aBb v\u00e0 a.<\/p>\nC. ABB v\u00e0 abb ho\u1eb7c A\u1ea0B v\u00e0 aab. D<\/strong>. ABb v\u00e0 a ho\u1eb7c aBb v\u00e0 A.<\/p>\nC\u00e2u 9.<\/strong>(ID: 100384)<\/strong>D\u00f9ng c\u00f4nsixin d\u1ec3 x\u1eed l\u00ed c\u00e1c h\u1ee3p t\u1eed l\u01b0\u1ee1ng b\u1ed9i c\u00f3 ki\u1ec3u gen Aa thu \u0111\u01b0\u1ee3c c\u00e1c th\u1ec3 t\u1ee9 b\u1ed9i. Cho c\u00e1c th\u1ec3 t\u1ee9 b\u1ed9i tr\u00ean giao ph\u1ea5n v\u1edbi nhau, trong tr\u01b0\u1eddng h\u1ee3p c\u00e1c c\u00e2y b\u1ed1 m\u1eb9 gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng, t\u00ednh theo l\u00ed thuy\u1ebft t\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen \u1edf \u0111\u1eddi con l\u00e0:<\/p>\nA. 1AAAA: 4AAAa : 6AAaa : 4Aaaa : laaaa.<\/p>\n
B. 1AAAA : 8AAAa : 18AAaa : 8Aaaa : laaaa.<\/p>\n
C. 1AAAA : 8AAAa : 18Aaaa : 8AAaa: laaaa.<\/p>\n
D.<\/strong>1AAAA : 8AAaa : 18AAAa : 8Aaaa : laaaa.<\/p>\nC\u00e2u 10<\/strong>.(ID: 100385)<\/strong>C\u00e0 \u0111\u1ed9c d\u01b0\u1ee3c c\u00f3 2n=24. m\u1ed9t th\u1ec3 \u0111\u1ed9t bi\u1ebfn c\u00f3 m\u1ed9t chi\u1ebfc c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 1 b\u1ecb m\u1ea5t m\u1ed9t \u0111o\u1ea1n, m\u1ed9t chi\u1ebfc c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 5 b\u1ecb \u0111\u1ea3o m\u1ed9t \u0111o\u1ea1n, m\u1ed9t chi\u1ebfc c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 3 \u0111\u01b0\u1ee3c l\u1eb7p m\u1ed9t \u0111o\u1ea1n, khi gi\u1ea3m ph\u00e2n n\u1ebfu c\u00e1c c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 ph\u00e2n li b\u00ecnh th\u01b0\u1eddng kh\u00f4ng c\u00f3 trao \u0111\u1ed5i ch\u00e9o th\u00ec giao t\u1eed b\u1ecb \u0111\u1ed9t bi\u1ebfn c\u00f3 t\u1ec9 l\u1ec7:<\/p>\nA.<\/strong>12,5% B.<\/strong>87,5% C.<\/strong>75% D.<\/strong>25%<\/p>\nC\u00e2u ll<\/strong>.(ID: 100386)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt, alen A quy \u0111\u1ecbnh qu\u1ea3 \u0111\u1ecf tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen a quy \u0111\u1ecbnh qu\u1ea3 v\u00e0ng; alen B quy \u0111\u1ecbnh qu\u1ea3 ng\u1ecdt tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen b quy \u0111\u1ecbnh qu\u1ea3 chua.<\/strong>Bi\u1ebft r\u1eb1ng kh\u00f4ng ph\u00e1t sinh \u0111\u1ed9t bi\u1ebfn m\u1edbi v\u00e0 c\u00e1c c\u00e2y t\u1ee9 b\u1ed9i gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng cho c\u00e1c giao t\u1eeb 2n c\u00f3 kh\u1ea3 n\u0103ng th\u1ee5 tinh. Cho c\u00e2y t\u1ee9 b\u1ed9i c\u00f3 ki\u1ec3u gen AAaaBbbb t\u1ef1 th\u1ee5 ph\u1ea5n. Theo l\u00ed thuy\u1ebft, ti l\u1ec7 ph\u00e2n li ki\u1ec3u h\u00ecnh \u1edf \u0111\u1eddi con l\u00e0<\/p>\nA. 105:35:3:1. B.<\/strong>105:35:9:1. C. 35:35:1:1. D.<\/strong>33:ll:l:l.<\/p>\nC\u00e2u 12<\/strong>.(ID: 100387)<\/strong>Nh\u1eadn \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y l\u00e0 ch\u00ednh x\u00e1c khi n\u00f3i v\u1ec1 quy lu\u1eadt di truy\u1ec1n li\u00ean k\u1ebft kh\u00f4ng ho\u00e0n to\u00e0n<\/p>\nA. C\u00e1c gen c\u00e0ng g\u1ea7n nhau c\u00e0ng d\u1ec5 x\u1ea3y ra trao \u0111\u1ed5i d\u1eabn t\u1edbi hi\u1ec7n t\u01b0\u1ee3ng ho\u00e1n v\u1ecb gen v\u00e0 ng\u01b0\u1ee3c l\u1ea1i.<\/p>\n
B. T\u00f9y lo\u00e0i m\u00e0 ho\u00e1n v\u1ecb gen ch\u1ec9 x\u1ea3y ra \u1edf gi\u1edbi \u0111\u1ef1c, hay gi\u1edbi c\u00e1i ho\u1eb7c c\u1ea3 hai gi\u1edbi.<\/p>\n
C. Qu\u00e1 tr\u00ecnh ti\u1ebfp h\u1ee3p trao \u0111\u1ed5i ch\u00e9o x\u1ea3y ra gi\u1eefa hai cromatit ch\u1ecb em c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 k\u00e9p.<\/p>\n
D. Qu\u00e1 tr\u00ecnh ti\u1ebfp h\u1ee3p trao \u0111\u1ed5i ch\u00e9o x\u1ea3y ra \u1edf k\u1ef3 gi\u1eefa c\u1ee7a gi\u1ea3m ph\u00e2n I.<\/p>\n
C\u00e2u 13.<\/strong>(ID: 100388)<\/strong>Theo qui lu\u1eadt ph\u00e2n ly \u0111\u1ed9c l\u1eadp, n\u1ebfu F<\/p>\n1<\/dd>\nc\u00f3 n c\u1eb7p gen d\u1ecb h\u1ee3p t\u1eed, quy \u0111\u1ecbnh ki\u1ec3u h\u00ecnh tr\u1ed9i l\u1eb7n ho\u00e0n to\u00e0n th\u00ec F<\/p>\n
2<\/dd>\nc\u00f3 s\u1ed1 lo\u1ea1i ki\u1ec3u h\u00ecnh l\u00e0<\/p>\n
A.<\/strong>2<\/p>\nn <\/dd>\n B.<\/strong>4<\/p>\nn<\/dd>\n C.<\/strong>3<\/p>\nn+1<\/dd>\n D.<\/strong>3<\/p>\nn<\/dd>\n<\/p>\nC\u00e2u 14<\/strong>.(ID: 100389)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt ki\u1ec3u gen A-B- cho hoa m\u00e0u t\u00edm, ki\u1ec3u gen A-bb cho hoa \u0111\u1ecf, ki\u1ec3u gen aaB- cho hoa m\u00e0u v\u00e0ng v\u00e0 aabb cho hoa tr\u1eafng. Gen D quy \u0111\u1ecbnh th\u00e2n cao tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi d quy \u0111\u1ecbnh th\u00e2n th\u1ea5p. Cho c\u00e2y F1 hoa t\u00edm, th\u00e2n cao lai ph\u00e2n t\u00edch \u0111\u01b0\u1ee3c 20% hoa t\u00edm, th\u00e2n th\u1ea5p : 20% hoa v\u00e0ng, th\u00e2n th\u1ea5p : 20% hoa \u0111\u1ecf, th\u00e2n cao : 20% hoa tr\u1eafng, th\u00e2n cao : 5% hoa t\u00edm, th\u00e2n cao : 5% hoa v\u00e0ng, th\u00e2n cao: 5% hoa \u0111\u1ecf, th\u00e2n th\u1eafp : 5% hoa tr\u1eafng, th\u00e2n th\u1ea5p. X\u00e1c \u0111\u1ecbnh ki\u1ec3u gen F1.<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1016\/de-thi-thu-thptqg-2016-sinh-de-4-2.png\")
<\/p>\n
\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 4<\/strong><\/h3>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1016\/de-thi-thu-thptqg-2016-sinh-de-4-3.png\")
<\/strong><\/p>\n<\/p>\nT\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh 2016 t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 4, \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt th\u1ee9 s\u00e1u ng\u00e0y 16\/10\/2015. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh C\u00e2u 1. (ID: 100376)Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c? […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[129],"tags":[],"yoast_head":"\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh n\u0103m 2016 - \u0110\u1ec1 s\u1ed1 4<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-thu-thpt-quoc-gia-mon-sinh-nam-2016-de-so-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh n\u0103m 2016 - \u0110\u1ec1 s\u1ed1 4\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh 2016 t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 4, \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt th\u1ee9 s\u00e1u ng\u00e0y 16\/10\/2015. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh C\u00e2u 1. (ID: 100376)Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c? 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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh C\u00e2u 1. (ID: 100376)Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c? 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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh<\/p>\n<\/div>\n
C\u00e2u 1. (ID: 100376)<\/strong>Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c?<\/p>\n (1) Trong c\u00e1c m\u1ee9c c\u1ea5u tr\u00fac si\u00eau hi\u1ec3n vi c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3, s\u1ee3i nhi\u1ec5m s\u1eafc c\u00f3 \u0111\u01b0\u1eddng k\u00ednh 700 nm.<\/p>\n (2) V\u00f9ng \u0111\u1ea7u m\u00fat c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f3 t\u00e1c d\u1ee5ng b\u1ea3o v\u1ec7 c\u00e1c nhi\u1ec5m s\u1eafc th\u1ec3 c\u0169ng nh\u01b0 l\u00e0m cho c\u00e1c nhi\u1ec5m s\u1eafc th\u1ec3 kh\u00f4ng d\u00ednh v\u00e0o nhau.<\/p>\n (3) Th\u00e0nh ph\u1ea7n ch\u1ee7 y\u1ebfu c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c g\u1ed3m ADN m\u1ea1ch k\u00e9p v\u00e0 pr\u00f4t\u00eain lo\u1ea1i hist\u00f4n.<\/p>\n (4) Trong c\u00e1c m\u1ee9c c\u1ea5u tr\u00fac si\u00eau hi\u1ec3n vi c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3, s\u1ee3i c\u01a1 b\u1ea3n v\u00e0 s\u1ee3i nhi\u1ec5m s\u1eafc c\u00f3 \u0111\u01b0\u1eddng k\u00ednh l\u1ea7n l\u01b0\u1ee3t l\u00e0 30 nm v\u00e0 300 nm.<\/p>\n A. 1 B.<\/strong>2 C.<\/strong>3. D.<\/strong>4.<\/p>\n C\u00e2u 2<\/strong>.(ID: 100377)<\/strong>M\u1ed9t nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f3 c\u00e1c \u0111o\u1ea1n kh\u00e1c nhau s\u1eafp x\u1ebfp theo tr\u00ecnh t\u1ef1 ABCDEG*HKM \u0111\u00e3 b\u1ecb \u0111\u1ed9t bi\u1ebfn. Nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u1ed9t bi\u1ebfn c\u00f3 tr\u00ecnh t\u1ef1 ABCDCDEG*HKM. Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 d\u1ea1ng \u0111\u1ed9t bi\u1ebfn n\u00e0y<\/p>\n (1) th\u01b0\u1eddng l\u00e0m xu\u1ea5t hi\u1ec7n nhi\u1ec1u gen m\u1edbi trong qu\u1ea7n th\u1ec3.<\/p>\n (2) th\u01b0\u1eddng g\u00e2y ch\u1ebft cho c\u01a1 th\u1ec3 mang nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u1ed9t bi\u1ebfn.<\/p>\n (3) th\u01b0\u1eddng l\u00e0m thay \u0111\u1ed5i s\u1ed1 nh\u00f3m gen li\u00ean k\u1ebft c\u1ee7a lo\u00e0i. <\/p>\n<\/div>\n (4) th\u01b0\u1eddng l\u00e0m t\u0103ng ho\u1eb7c gi\u1ea3m c\u01b0\u1eddng \u0111\u1ed9 bi\u1ec3u hi\u1ec7n c\u1ee7a t\u00ednh tr\u1ea1ng.<\/p>\n (5) th\u01b0\u1eddng t\u1ea1o \u0111i\u1ec1u ki\u1ec7n cho \u0111\u1ed9t bi\u1ebfn gen, t\u1ea1o n\u00ean c\u00e1c gen m\u1edbi trong qu\u00e1 tr\u00ecnh ti\u1ebfn h\u00f3a.<\/p>\n A.<\/strong>1 B.<\/strong>2. C.<\/strong>3. D.<\/strong>4<\/p>\n C\u00e2u 3<\/strong>.(ID: 100378)<\/strong>M\u1ed9t trong nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m c\u1ee7a gen ngo\u00e0i nh\u00e2n l\u00e0<\/p>\n A. kh\u00f4ng b\u1ecb \u0111\u1ed9t bi\u1ebfn d\u01b0\u1edbi t\u00e1c \u0111\u1ed9ng c\u1ee7a c\u00e1c t\u00e1c nh\u00e2n \u0111\u1ed9t bi\u1ebfn.<\/p>\n B. c\u00f3 kh\u1ea3 n\u0103ng nh\u00e2n \u0111\u00f4i v\u00e0 phi\u00ean m\u00e3.<\/p>\n C. lu\u00f4n lu\u00f4n t\u1ed3n t\u1ea1i th\u00e0nh t\u1eebng c\u1eb7p alen.<\/p>\n D.<\/strong>ch\u1ec9 m\u00e3 h\u00f3a cho c\u00e1c protein tham gia c\u1ea5u tr\u00fac nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\n C\u00e2u 4<\/strong>.(ID: 100379)<\/strong>\u1ede m\u1ed9t sinh v\u1eadt v\u1edbi s\u1ed1 l\u01b0\u1ee3ng nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u01a1n l\u00e0 12 (n=12), M\u1ed9t tr\u1ee9ng s\u1ebd \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh ch\u1ee9a c\u1ea3 12 nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f3 ngu\u1ed3n g\u1ed1c t\u1eeb m\u1eb9, c\u00f3 x\u00e1c su\u1ea5t l\u00e0 bao nhi\u00eau?<\/p>\n A.<\/strong>(1\/12) B.<\/strong>(1\/10)<\/p>\n C.<\/strong>(1\/2)<\/p>\n D.<\/strong>(10\/12)<\/p>\n C\u00e2u 5 .<\/strong>(ID: 100380)<\/strong>Khi n\u00f3i v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf t\u1ebf b\u00e0o nh\u00e2n th\u1ef1c, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y \u0111\u00fang?<\/p>\n A. \u0110\u01a1n v\u1ecb c\u1ea5u tr\u00fac c\u01a1 b\u1ea3n c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0 nucl\u00ea\u00f4x\u00f4m.<\/p>\n B. Nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0 v\u1eadt ch\u1ea5t di truy\u1ec1n \u1edf c\u1ea5p \u0111\u1ed9 ph\u00e2n t\u1eed.<\/p>\n C.<\/strong>Th\u00e0nh ph\u1ea7n ho\u00e1 h\u1ecdc ch\u1ee7 y\u1ebfu c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 l\u00e0 ARN v\u00e0 pr\u00f4t\u00eain.<\/p>\n D.<\/strong>C\u1ea5u tr\u00fac cu\u1ed9n xo\u1eafn t\u1ea1o \u0111i\u1ec1u ki\u1ec7n cho s\u1ef1 nh\u00e2n \u0111\u00f4i nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\n C\u00e2u 6<\/strong>.(ID: 100381)<\/strong>\u1ede m\u1ed9t gia \u0111\u00ecnh n\u1ecd, ng\u01b0\u1eddi b\u1ed1 m\u0103c b\u1ec7nh m\u00f9 m\u00e0u \u0111\u1ecf l\u1ee5c c\u00f2n ng\u01b0\u1eddi m\u1eb9 d\u1ecb h\u1ee3p v\u1ec1 t\u00ednh tr\u1ea1ng n\u00e0y. \u0110\u1ee9a con trai c\u1ee7a h\u1ecd b\u1ecb m\u00f9 m\u00e0u v\u00e0 m\u1eafc h\u1ed9i ch\u1ee9ng Claifent\u01a1 (XXY). Cho r\u1eb1ng kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn gen c\u0169ng nh\u01b0 \u0111\u1ed9t bi\u1ebfn nhi\u1ec5m s\u1eafc th\u1ec3 x\u1ea3y ra. \u0110i\u1ec1u kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y l\u00e0 ch\u00ednh x\u00e1c?<\/p>\n A. \u1ede gi\u1ea3m ph\u00e2n I, m\u1eb9 gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng c\u00f2n b\u1ed1 kh\u00f4ng c\u00f3 s\u1ef1 ph\u00e2n ly nhi\u1ec5m s\u1eafc th\u1ec3 trong gi\u1ea3m ph\u00e2n I.<\/p>\n B. Trong gi\u1ea3m ph\u00e2n I, \u1edf b\u1ed1 kh\u00f4ng c\u00f3 s\u1ef1 ph\u00e2n ly nhi\u1ec5m s\u1eafc th\u1ec3 c\u00f2n \u1edf m\u1eb9 gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng.<\/p>\n C. \u1ede c\u1ea3 b\u1ed1 v\u00e0 m\u1eb9, \u1edf gi\u1ea3m ph\u00e2n II c\u00f3 r\u1ed1i lo\u1ea1n kh\u00f4ng ph\u00e2n ly nhi\u1ec5m s\u1eafc th\u1ec3.<\/p>\n D. Qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n h\u00ecnh th\u00e0nh giao t\u1eed \u1edf ng\u01b0\u1eddi b\u1ed1 di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng, tuy nh\u1ec9\u00ean \u1edf gi\u1ea3m ph\u00e2n II nhi\u1ec5m s\u1eafc th\u1ec3 gi\u1edbi t\u00ednh c\u1ee7a ng\u01b0\u1eddi m\u1eb9 kh\u00f4ng ph\u00e2n ly.<\/p>\n C\u00e2u 7<\/strong>.(ID: 100382)<\/strong>Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang khi n\u00f3i v\u1ec1 th\u1ec3 d\u1ecb \u0111a b\u1ed9i? <\/p>\n<\/div>\n (1) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i c\u00f3 vai tr\u00f2 quan tr\u1ecdng trong qu\u00e1 tr\u00ecnh h\u00ecnh th\u00e0nh lo\u00e0i m\u1edbi.<\/p>\n (2) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i c\u00f3 th\u1ec3 sinh tr\u01b0\u1edfng, ph\u00e1t tri\u1ec3n v\u00e0 sinh s\u1ea3n h\u1eefu t\u00ednh b\u00ecnh th\u01b0\u1eddng.<\/p>\n (3) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i th\u01b0\u1eddng g\u1eb7p \u1edf \u0111\u1ed9ng v\u1eadt, \u00edt g\u1eb7p \u1edf th\u1ef1c v\u1eadt.<\/p>\n (4) Th\u1ec3 d\u1ecb \u0111a b\u1ed9i \u0111\u01b0\u1ee3c h\u00ecnh th\u00e0nh do lai xa k\u1ebft h\u1ee3p v\u1edbi \u0111a b\u1ed9i ho\u00e1<\/p>\n A.<\/strong>l B.<\/strong>2 C.<\/strong>3 D 4<\/p>\n C\u00e2u 8.<\/strong>(ID: 100383)<\/strong>Trong m\u1ed9t t\u1ebf b\u00e0o sinh tinh, x\u00e9t hai c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 \u0111\u01b0\u1ee3c k\u00ed hi\u1ec7u l\u00e0 Aa v\u00e0 Bb. Khi t\u1ebf b\u00e0o n\u00e0y gi\u1ea3m ph\u00e2n c\u1eb7p Aa ph\u00e2n li b\u00ecnh th\u01b0\u1eddng, c\u1eb7p Bb kh\u00f4ng ph\u00e2n li trong gi\u1ea3m ph\u00e2n I, gi\u1ea3m ph\u00e2n II di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng. C\u00e1c lo\u1ea1i giao t\u1eed c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1eeb qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u1ee7a t\u1ebf b\u00e0o tr\u00ean l\u00e0<\/p>\n A. Abb v\u00e0 B ho\u1eb7c ABB v\u00e0 b. B.<\/strong>ABb v\u00e0 A ho\u1eb7c aBb v\u00e0 a.<\/p>\n C. ABB v\u00e0 abb ho\u1eb7c A\u1ea0B v\u00e0 aab. D<\/strong>. ABb v\u00e0 a ho\u1eb7c aBb v\u00e0 A.<\/p>\n C\u00e2u 9.<\/strong>(ID: 100384)<\/strong>D\u00f9ng c\u00f4nsixin d\u1ec3 x\u1eed l\u00ed c\u00e1c h\u1ee3p t\u1eed l\u01b0\u1ee1ng b\u1ed9i c\u00f3 ki\u1ec3u gen Aa thu \u0111\u01b0\u1ee3c c\u00e1c th\u1ec3 t\u1ee9 b\u1ed9i. Cho c\u00e1c th\u1ec3 t\u1ee9 b\u1ed9i tr\u00ean giao ph\u1ea5n v\u1edbi nhau, trong tr\u01b0\u1eddng h\u1ee3p c\u00e1c c\u00e2y b\u1ed1 m\u1eb9 gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng, t\u00ednh theo l\u00ed thuy\u1ebft t\u1ec9 l\u1ec7 ph\u00e2n li ki\u1ec3u gen \u1edf \u0111\u1eddi con l\u00e0:<\/p>\n A. 1AAAA: 4AAAa : 6AAaa : 4Aaaa : laaaa.<\/p>\n B. 1AAAA : 8AAAa : 18AAaa : 8Aaaa : laaaa.<\/p>\n C. 1AAAA : 8AAAa : 18Aaaa : 8AAaa: laaaa.<\/p>\n D.<\/strong>1AAAA : 8AAaa : 18AAAa : 8Aaaa : laaaa.<\/p>\n C\u00e2u 10<\/strong>.(ID: 100385)<\/strong>C\u00e0 \u0111\u1ed9c d\u01b0\u1ee3c c\u00f3 2n=24. m\u1ed9t th\u1ec3 \u0111\u1ed9t bi\u1ebfn c\u00f3 m\u1ed9t chi\u1ebfc c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 1 b\u1ecb m\u1ea5t m\u1ed9t \u0111o\u1ea1n, m\u1ed9t chi\u1ebfc c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 5 b\u1ecb \u0111\u1ea3o m\u1ed9t \u0111o\u1ea1n, m\u1ed9t chi\u1ebfc c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 s\u1ed1 3 \u0111\u01b0\u1ee3c l\u1eb7p m\u1ed9t \u0111o\u1ea1n, khi gi\u1ea3m ph\u00e2n n\u1ebfu c\u00e1c c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 ph\u00e2n li b\u00ecnh th\u01b0\u1eddng kh\u00f4ng c\u00f3 trao \u0111\u1ed5i ch\u00e9o th\u00ec giao t\u1eed b\u1ecb \u0111\u1ed9t bi\u1ebfn c\u00f3 t\u1ec9 l\u1ec7:<\/p>\n A.<\/strong>12,5% B.<\/strong>87,5% C.<\/strong>75% D.<\/strong>25%<\/p>\n C\u00e2u ll<\/strong>.(ID: 100386)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt, alen A quy \u0111\u1ecbnh qu\u1ea3 \u0111\u1ecf tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen a quy \u0111\u1ecbnh qu\u1ea3 v\u00e0ng; alen B quy \u0111\u1ecbnh qu\u1ea3 ng\u1ecdt tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi alen b quy \u0111\u1ecbnh qu\u1ea3 chua.<\/strong>Bi\u1ebft r\u1eb1ng kh\u00f4ng ph\u00e1t sinh \u0111\u1ed9t bi\u1ebfn m\u1edbi v\u00e0 c\u00e1c c\u00e2y t\u1ee9 b\u1ed9i gi\u1ea3m ph\u00e2n b\u00ecnh th\u01b0\u1eddng cho c\u00e1c giao t\u1eeb 2n c\u00f3 kh\u1ea3 n\u0103ng th\u1ee5 tinh. Cho c\u00e2y t\u1ee9 b\u1ed9i c\u00f3 ki\u1ec3u gen AAaaBbbb t\u1ef1 th\u1ee5 ph\u1ea5n. Theo l\u00ed thuy\u1ebft, ti l\u1ec7 ph\u00e2n li ki\u1ec3u h\u00ecnh \u1edf \u0111\u1eddi con l\u00e0<\/p>\n A. 105:35:3:1. B.<\/strong>105:35:9:1. C. 35:35:1:1. D.<\/strong>33:ll:l:l.<\/p>\n C\u00e2u 12<\/strong>.(ID: 100387)<\/strong>Nh\u1eadn \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y l\u00e0 ch\u00ednh x\u00e1c khi n\u00f3i v\u1ec1 quy lu\u1eadt di truy\u1ec1n li\u00ean k\u1ebft kh\u00f4ng ho\u00e0n to\u00e0n<\/p>\n A. C\u00e1c gen c\u00e0ng g\u1ea7n nhau c\u00e0ng d\u1ec5 x\u1ea3y ra trao \u0111\u1ed5i d\u1eabn t\u1edbi hi\u1ec7n t\u01b0\u1ee3ng ho\u00e1n v\u1ecb gen v\u00e0 ng\u01b0\u1ee3c l\u1ea1i.<\/p>\n B. T\u00f9y lo\u00e0i m\u00e0 ho\u00e1n v\u1ecb gen ch\u1ec9 x\u1ea3y ra \u1edf gi\u1edbi \u0111\u1ef1c, hay gi\u1edbi c\u00e1i ho\u1eb7c c\u1ea3 hai gi\u1edbi.<\/p>\n C. Qu\u00e1 tr\u00ecnh ti\u1ebfp h\u1ee3p trao \u0111\u1ed5i ch\u00e9o x\u1ea3y ra gi\u1eefa hai cromatit ch\u1ecb em c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 k\u00e9p.<\/p>\n D. Qu\u00e1 tr\u00ecnh ti\u1ebfp h\u1ee3p trao \u0111\u1ed5i ch\u00e9o x\u1ea3y ra \u1edf k\u1ef3 gi\u1eefa c\u1ee7a gi\u1ea3m ph\u00e2n I.<\/p>\n C\u00e2u 13.<\/strong>(ID: 100388)<\/strong>Theo qui lu\u1eadt ph\u00e2n ly \u0111\u1ed9c l\u1eadp, n\u1ebfu F<\/p>\n c\u00f3 n c\u1eb7p gen d\u1ecb h\u1ee3p t\u1eed, quy \u0111\u1ecbnh ki\u1ec3u h\u00ecnh tr\u1ed9i l\u1eb7n ho\u00e0n to\u00e0n th\u00ec F<\/p>\n c\u00f3 s\u1ed1 lo\u1ea1i ki\u1ec3u h\u00ecnh l\u00e0<\/p>\n A.<\/strong>2<\/p>\n B.<\/strong>4<\/p>\n C.<\/strong>3<\/p>\n D.<\/strong>3<\/p>\n C\u00e2u 14<\/strong>.(ID: 100389)<\/strong>\u1ede m\u1ed9t lo\u00e0i th\u1ef1c v\u1eadt ki\u1ec3u gen A-B- cho hoa m\u00e0u t\u00edm, ki\u1ec3u gen A-bb cho hoa \u0111\u1ecf, ki\u1ec3u gen aaB- cho hoa m\u00e0u v\u00e0ng v\u00e0 aabb cho hoa tr\u1eafng. Gen D quy \u0111\u1ecbnh th\u00e2n cao tr\u1ed9i ho\u00e0n to\u00e0n so v\u1edbi d quy \u0111\u1ecbnh th\u00e2n th\u1ea5p. Cho c\u00e2y F1 hoa t\u00edm, th\u00e2n cao lai ph\u00e2n t\u00edch \u0111\u01b0\u1ee3c 20% hoa t\u00edm, th\u00e2n th\u1ea5p : 20% hoa v\u00e0ng, th\u00e2n th\u1ea5p : 20% hoa \u0111\u1ecf, th\u00e2n cao : 20% hoa tr\u1eafng, th\u00e2n cao : 5% hoa t\u00edm, th\u00e2n cao : 5% hoa v\u00e0ng, th\u00e2n cao: 5% hoa \u0111\u1ecf, th\u00e2n th\u1eafp : 5% hoa tr\u1eafng, th\u00e2n th\u1ea5p. X\u00e1c \u0111\u1ecbnh ki\u1ec3u gen F1.<\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh 2016 t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 4, \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt th\u1ee9 s\u00e1u ng\u00e0y 16\/10\/2015. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh C\u00e2u 1. (ID: 100376)Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, c\u00f3 bao nhi\u00eau ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 nhi\u1ec5m s\u1eafc th\u1ec3 \u1edf sinh v\u1eadt nh\u00e2n th\u1ef1c? […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[129],"tags":[],"yoast_head":"\n<\/p>\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n Sinh n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 4<\/strong><\/h3>\n
<\/strong><\/p>\n<\/p>\n