\u0110\u1ec1 thi th\u1eed THPTQG 2016 m\u00f4n H\u00f3a – THPT \u0110\u1ed3ng \u0110\u1eadu l\u1ea7n 2 t\u1ed5 ch\u1ee9c thi th\u1eed cho h\u1ecdc sinh kh\u1ed1i 12, c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft c\u00e1c em tham kh\u1ea3o b\u00ean d\u01b0\u1edbi:<\/strong><\/h2>\n

\u0110\u1ec1 thi th\u1eed THPTQG 2016 m\u00f4n H\u00f3a – THPT \u0110\u1ed3ng \u0110\u1eadu l\u1ea7n 2<\/strong><\/h4>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

<\/strong><\/p>\n

\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPTQG 2016 m\u00f4n H\u00f3a – THPT \u0110\u1ed3ng \u0110\u1eadu l\u1ea7n 2<\/strong><\/h4>\n

C\u00e2u 1=>D<\/p>\n

C\u00e2u 2:  CuSO<\/p>\n

4<\/dd>\n

 khan d\u00f9ng \u0111\u1ec3 nh\u1eadn bi\u1ebft h\u01a1i n\u01b0\u1edbc ( chuy\u1ec3n t\u1eeb m\u00e0u tr\u1eafng th\u00e0nh xanh lam)<\/p>\n

Dd Ca(OH)<\/p>\n

2<\/dd>\n

 nh\u1eadn bi\u1ebft CO<\/p>\n

2<\/dd>\n

 ( k\u1ebft t\u1ee7a tr\u1eafng)  =>C<\/p>\n

C\u00e2u 3 =>A<\/p>\n

C\u00e2u 4:<\/p>\n

X : 3s<\/p>\n

1<\/dd>\n

 ; Y : 3s<\/p>\n

2<\/dd>\n

 ; Z : 4s<\/p>\n

1<\/dd>\n

 ( e l\u1edbp ngo\u00e0i c\u00f9ng )<\/p>\n

=> X(IA) ; Y(IIA) c\u00f9ng chu k\u1ef3 3; Z(IA) chu k\u1ef3 4<\/p>\n

C\u00f9ng chu k\u1ef3 th\u00ec t\u1eeb tr\u00e1i qua ph\u1ea3i b\u00e1n k\u00ednh gi\u1ea3m d\u1ea7n<\/p>\n

C\u00f9ng nh\u00f3m th\u00ec t\u1eeb tr\u00ean xu\u1ed1ng d\u01b0\u1edbi b\u00e1n k\u00ednh t\u0103ng d\u1ea7n<\/p>\n

=>A<\/p>\n

C\u00e2u 5: =>C<\/p>\n

C\u00e2u 6: D\u1ef1a v\u00e0o d\u00e3y \u0111i\u1ec7n h\u00f3a kim lo\u1ea1i =>C<\/p>\n

C\u00e2u 7: Este c\u00f3 c\u00f4ng th\u1ee9c C<\/p>\n

2<\/dd>\n

H<\/p>\n

4<\/dd>\n

O<\/p>\n

2<\/dd>\n

 ch\u1ec9 c\u00f3 th\u1ec3 l\u00e0 HCOOCH<\/p>\n

3<\/dd>\n

 c\u00f3 n = 0,15 mol<\/p>\n

=> Ph\u1ea3n \u1ee9ng v\u1eeba \u0111\u1ee7 v\u1edbi NaOH t\u1ea1o 0,15 mol HCOONa<\/p>\n

=> m = 10,2g =>C<\/p>\n

C\u00e2u 8: M<\/p>\n

X<\/dd>\n

 = 83.2 = 166g  = 12x + y + 16z<\/p>\n

Do este 2 ch\u1ee9c n\u00ean z = 4 => 12x + y = 102<\/p>\n

=> x = 8 ; y = 6<\/p>\n

=>X l\u00e0 C<\/p>\n

8<\/dd>\n

H<\/p>\n

6<\/dd>\n

O<\/p>\n

4<\/dd>\n<\/p>\n

1 mol X ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi AgNO<\/p>\n

3<\/dd>\n

\/NH<\/p>\n

3<\/dd>\n

 t\u1ea1o 4 mol Ag<\/p>\n

=> C\u00f3 th\u1ec3 X ch\u1ee9a 2 nh\u00f3m HCOO-.<\/p>\n

M\u00e0 1 mol X ph\u1ea3n \u1ee9ng \u0111\u1ee7 v\u1edbi 4 mol NaOH<\/p>\n

=> C\u00f3 th\u1ec3 X l\u00e0 este 2 ch\u1ee9c c\u1ee7a phenol<\/p>\n

CT th\u1ecfa m\u00e3n : o,m,p-(HCOO)<\/p>\n

2<\/dd>\n

C<\/p>\n

6<\/dd>\n

H<\/p>\n

4  <\/dd>\n

=>C<\/p>\n

C\u00e2u 9 =>A<\/p>\n

C\u00e2u 10: (2) S ; (3) Ag<\/p>\n

3<\/dd>\n

PO<\/p>\n

4<\/dd>\n

 ; (4) AgCl  =>D<\/p>\n

C\u00e2u 11: V\u00ec n<\/p>\n

NaOH<\/dd>\n

 : n<\/p>\n

H3PO4<\/dd>\n

 = 1,8 : 1 = 1,8<\/p>\n

=> Ph\u1ea3n \u1ee9ng t\u1ea1o x mol mu\u1ed1i NaH<\/p>\n

2<\/dd>\n

PO<\/p>\n

4<\/dd>\n

 v\u00e0 y mol Na<\/p>\n

2<\/dd>\n

HPO<\/p>\n

4<\/dd>\n<\/p>\n

=> n<\/p>\n

NaOH<\/dd>\n

 = x + 2y = 1,8 v\u00e0 n<\/p>\n

H3PO4<\/dd>\n

 = x + y = 1<\/p>\n

=> x = 0,2 mol ; y = 0,8 mol   =>A<\/p>\n

C\u00e2u 12: Glucozo -> 2C<\/p>\n

2<\/dd>\n

H<\/p>\n

5<\/dd>\n

OH + 2CO<\/p>\n

2<\/dd>\n<\/p>\n

=> n<\/p>\n

C2H5OH<\/dd>\n

 = 0,2 mol => m = 9,2g<\/p>\n

=> V<\/p>\n

r\u01b0\u1ee3u<\/dd>\n

 = (m<\/p>\n

ancol<\/dd>\n

\/d<\/p>\n

ancol<\/dd>\n

). 100\/90 = 12,78 ml  =>B<\/p>\n

C\u00e2u 13: CT : CH<\/p>\n

3<\/dd>\n

CH<\/p>\n

2<\/dd>\n

CH<\/p>\n

2<\/dd>\n

NH<\/p>\n

2<\/dd>\n

 ; (CH<\/p>\n

3<\/dd>\n

)<\/p>\n

2<\/dd>\n

CHNH<\/p>\n

2 <\/dd>\n

=>B<\/p>\n

C\u00e2u 14: n<\/p>\n

Fe<\/dd>\n

 = 0,1 ; n<\/p>\n

Cu(NO3)2<\/dd>\n

 = 0,1 ; n<\/p>\n

HCl<\/dd>\n

 = 0,2<\/p>\n

Do n<\/p>\n

HCl<\/dd>\n

 < 8\/3.n<\/p>\n

Fe<\/dd>\n

 n\u00ean ph\u1ea3n \u1ee9ng ch\u1ec9 t\u1ea1o Fe<\/p>\n

2+<\/dd>\n<\/p>\n

3Fe + 8H<\/p>\n

+<\/dd>\n

 + 2NO<\/p>\n

3<\/dd>\n

–<\/dd>\n

 -> 3Fe<\/p>\n

2+<\/dd>\n

 + 2NO + 4H<\/p>\n

2<\/dd>\n

O<\/p>\n

=> Sau ph\u1ea3n \u1ee9ng c\u00f2n l\u1ea1i : 0,1 \u2013 0,075 = 0,025 mol<\/p>\n

Fe + Cu<\/p>\n

2+<\/dd>\n

 -> Fe<\/p>\n

2+<\/dd>\n

 + Cu<\/p>\n

=> m = m<\/p>\n

Cu<\/dd>\n

 = 64.0,025 = 1,6g =>D<\/p>\n

C\u00e2u 15:<\/p>\n

+) X\u00e9t v\u1ec1 M : X c\u00f3 M l\u1edbn nh\u1ea5t => t<\/p>\n

0<\/dd>\n

 s\u00f4i cao nh\u1ea5t<\/p>\n

+) V\u1edbi Y,Z,T c\u00f3 M t\u01b0\u01a1ng \u0111\u01b0\u01a1ng. X\u00e9t kh\u1ea3 n\u0103ng t\u1ea1o li\u00ean k\u1ebft hidro li\u00ean ph\u00e2n t\u1eed :<\/p>\n

 Axit axetic > ancol etylic > dimetyl ete =>B<\/p>\n

 C\u00e2u 16<\/p>\n

 n<\/p>\n

CO2<\/dd>\n

 : n<\/p>\n

H2O<\/dd>\n

 = 1 : 2 => n<\/p>\n

C<\/dd>\n

 : n<\/p>\n

H<\/dd>\n

 = 1 : 4<\/p>\n

X\u00e9t c\u00e1c c\u1eb7p amin li\u00ean ti\u1ebfp m\u00e0 (H : C) 1 ch\u1ea5t  nh\u1ecf h\u01a1n 4 ; 1 ch\u1ea5t l\u1edbn h\u01a1n 4 th\u00ec th\u1ecfa m\u00e3n<\/p>\n

=>C<\/p>\n

C\u00e2u 17 =>D<\/p>\n

C\u00e2u 18: C\u00f3 th\u1ec3 x\u1ea3y ra 2 tr\u01b0\u1eddng h\u1ee3p :<\/p>\n

+) TH<\/p>\n

1<\/dd>\n

 : m\u1ed7i anken ph\u1ea3n \u1ee9ng t\u1ea1o 1 ancol<\/p>\n

+) TH<\/p>\n

2<\/dd>\n

 : c\u00f3 th\u1ec3 anken t\u1ea1o 2 ancol nh\u01b0ng tr\u00f9ng v\u1edbi ancol \u0111\u01b0\u1ee3c t\u1ea1o ra do anken c\u00f2n l\u1ea1i v\u00e0 t\u1ed5ng c\u00e1c lo\u1ea1i ancol v\u1eabn l\u00e0 2<\/p>\n

X\u00e9t 4 \u0111\u00e1p \u00e1n ch\u1ec9 c\u00f3 eten (t\u1ea1o C<\/p>\n

2<\/dd>\n

H<\/p>\n

5<\/dd>\n

OH) v\u00e0 But-2-en (T\u1ea1o CH<\/p>\n

3<\/dd>\n

CH(OH)C<\/p>\n

2<\/dd>\n

H<\/p>\n

5<\/dd>\n

)<\/p>\n

Th\u1ecfa m\u00e3n   =>B<\/p>\n

C\u00e2u 19: =>A<\/p>\n

C\u00e2u 20 : C\u00f3 nhi\u1ec1u protein kh\u00f4ng tan trong n\u01b0\u1edbc nh\u01b0 keratin (t\u00f3c) ….=>B<\/p>\n

C\u00e2u 21: Do s\u1ed1 mol c\u00e1c ch\u1ea5t kh\u00ed 2 v\u1ebf b\u1eb1ng nhau => s\u1ef1 thay \u0111\u1ed5i \u00e1p su\u1ea5t kh\u00f4ng \u1ea3nh h\u01b0\u1edfng \u0111\u1ebfn c\u00e2n b\u0103ng.<\/p>\n

Ch\u1ea5t x\u00fac t\u00e1c kh\u00f4ng l\u00e0m chuy\u1ec3n d\u1ecbch c\u00e2n b\u1eb1ng m\u00e0 ch\u1ec9 l\u00e0m cho c\u00e2n b\u1eb1ng nhanh ch\u00f3ng \u0111\u01b0\u1ee3c thi\u1ebft l\u1eadp<\/p>\n

=>D<\/p>\n

C\u00e2u 22: =>B<\/p>\n

C\u00e2u 23: C\u00e1c ch\u1ea5t c\u00f3 c\u00f9ng n\u1ed3ng \u0111\u1ed9 n\u00ean ph\u00e2n t\u1eed n\u00e0o ph\u00e2n ly \u0111\u01b0\u1ee3c nhi\u1ec1u H<\/p>\n

+<\/dd>\n

 h\u01a1n s\u1ebd c\u00f3 t\u00ednh axit m\u1ea1nh h\u01a1n => pH nh\u1ecf h\u01a1n => pH<\/p>\n

H2SO4<\/dd>\n

 < pH<\/p>\n

HCl<\/dd>\n<\/p>\n

KNO<\/p>\n

3<\/dd>\n

 l\u00e0 mu\u1ed1i trung h\u00f2a => pH > pH<\/p>\n

axit<\/dd>\n<\/p>\n

Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n

 l\u00e0 mu\u1ed1i c\u1ee7a axit y\u1ebfu v\u00e0 bazo m\u1ea1nh n\u00ean th\u1ee7y ph\u00e2n t\u1ea1o m\u00f4i tr\u01b0\u1eddng bazo<\/p>\n

=> pH > pH<\/p>\n

trung t\u00ednh<\/dd>\n

  =>C<\/p>\n

 C\u00e2u 24: n<\/p>\n

O2<\/dd>\n

 = 0,64125 mol ; m<\/p>\n

CO2<\/dd>\n

 + m<\/p>\n

H2O<\/dd>\n

 = 31,68g<\/p>\n

B\u1ea3o to\u00e0n kh\u1ed1i l\u01b0\u1ee3ng : m<\/p>\n

A<\/dd>\n

 + m<\/p>\n

O2<\/dd>\n

 = m<\/p>\n

CO2<\/dd>\n

 + m<\/p>\n

H2O<\/dd>\n

 + m<\/p>\n

N2<\/dd>\n<\/p>\n

=> n<\/p>\n

N2<\/dd>\n

 = 0,09 mol<\/p>\n

V\u00ec khi A + KOH t\u1ea1o mu\u1ed1i c\u1ee7a Gly , Ala , Val \u0111\u1ec1u l\u00e0 amino axit c\u00f3 1 nh\u00f3m NH<\/p>\n

2<\/dd>\n

 ; 1 nh\u00f3m COOH v\u00e0 no<\/p>\n

M\u1eb7t kh\u00e1c : 0,045 mol A ph\u1ea3n \u1ee9ng \u0111\u1ee7 v\u1edbi 0,12 mol KOH => n<\/p>\n

N<\/dd>\n

 = n<\/p>\n

KOH<\/dd>\n

 = 0,12 mol<\/p>\n

X\u00e9t 0,045 mol A : m<\/p>\n

A<\/dd>\n

 = 13,68.2\/3 = 9,12g<\/p>\n

B\u1ea3o to\u00e0n kh\u1ed1i l\u01b0\u1ee3ng : m<\/p>\n

A<\/dd>\n

 + m<\/p>\n

KOH<\/dd>\n

 = m<\/p>\n

mu\u1ed1i<\/dd>\n

 + m<\/p>\n

H2O<\/dd>\n<\/p>\n

( n<\/p>\n

H2O<\/dd>\n

 = n<\/p>\n

A<\/dd>\n

 = 0,045 mol = n<\/p>\n

COOH(A)<\/dd>\n

 ) => m<\/p>\n

mu\u1ed1i<\/dd>\n

 = 15,03g<\/p>\n

=> m<\/p>\n

mu\u1ed1i Gly<\/dd>\n

 = 5,085g => n<\/p>\n

mu\u1ed1i Gly<\/dd>\n

 = 0,045 mol<\/p>\n

=> m<\/p>\n

mu\u1ed1i Ala<\/dd>\n

 + m<\/p>\n

mu\u1ed1i Val<\/dd>\n

 = 127n<\/p>\n

Ala<\/dd>\n

 + 155n<\/p>\n

Val<\/dd>\n

 = 9,945g<\/p>\n

L\u1ea1i c\u00f3 : n<\/p>\n

Val<\/dd>\n

 + n<\/p>\n

Ala<\/dd>\n

 = n<\/p>\n

NaOH<\/dd>\n

 \u2013 n<\/p>\n

Gly<\/dd>\n

 = 0,075 mol<\/p>\n

=> n<\/p>\n

Val<\/dd>\n

 = 0,015 ; n<\/p>\n

Ala<\/dd>\n

 = 0,06 mol<\/p>\n

=> %m<\/p>\n

mu\u1ed1i Ala<\/dd>\n

 = 50,70 %  =>A<\/p>\n

C\u00e2u 25: C\u1ea3 4 ph\u00e1t bi\u1ec3u \u0111\u1ec1u \u0111\u00fang  =>D<\/p>\n

C\u00e2u 26: =>D<\/p>\n

C\u00e2u 27:  n<\/p>\n

CO2<\/dd>\n

 = n<\/p>\n

H2O<\/dd>\n

 => 2n<\/p>\n

C(X)<\/dd>\n

 = n<\/p>\n

H(X)<\/dd>\n<\/p>\n

M\u00e0 n<\/p>\n

X<\/dd>\n

 : n<\/p>\n

Ag<\/dd>\n

 = 1 : 4<\/p>\n

=> X l\u00e0 CH<\/p>\n

2<\/dd>\n

O hay HCHO =>D<\/p>\n

C\u00e2u 28:  X\u00e9t ttongr qu\u00e1t : Kh\u1eed <\/p>\n

m\u1ea1nh<\/dd>\n

 + OXH <\/p>\n

m\u1ea1nh<\/dd>\n

 -> Kh\u1eed <\/p>\n

y\u1ebfu<\/dd>\n

 + OXH <\/p>\n

y\u1ebfu<\/dd>\n<\/p>\n

(1) => T\u00ednh oxi h\u00f3a c\u1ee7a Br<\/p>\n

2<\/dd>\n

 m\u1ea1nh h\u01a1n Fe<\/p>\n

3+<\/dd>\n<\/p>\n

(2) => Cl<\/p>\n

2<\/dd>\n

 oxi h\u00f3a m\u1ea1nh h\u01a1n Br<\/p>\n

2<\/dd>\n<\/p>\n

=> Cl<\/p>\n

2<\/dd>\n

  oxi h\u00f3a m\u1ea1nh h\u01a1n Fe<\/p>\n

3+ <\/dd>\n

=>D<\/p>\n

 C\u00e2u 29: D\u1ef1a v\u00e0o 4 \u0111\u00e1p \u00e1n th\u1ea5y ch\u1ec9 c\u00f3 amino axit c\u00f3 1 nh\u00f3m COOH v\u00e0 1 nh\u00f3m NH<\/p>\n

2<\/dd>\n<\/p>\n

C\u00f3 d\u1ea1ng H<\/p>\n

2<\/dd>\n

NRCOOH + NaOH -> H<\/p>\n

2<\/dd>\n

NRCOONa + H<\/p>\n

2<\/dd>\n

O<\/p>\n

B\u1ea3o to\u00e0n kh\u1ed1i l\u01b0\u1ee3ng : m<\/p>\n

X<\/dd>\n

 + m<\/p>\n

NaOH<\/dd>\n

 = m<\/p>\n

mu\u1ed1i<\/dd>\n

 + m<\/p>\n

H2O<\/dd>\n<\/p>\n

C\u00f3 n<\/p>\n

X<\/dd>\n

 = n<\/p>\n

NaOH<\/dd>\n

 = n<\/p>\n

H2O<\/dd>\n<\/p>\n

=> n<\/p>\n

X<\/dd>\n

.(40 \u2013 18) = m<\/p>\n

mu\u1ed1i<\/dd>\n

 \u2013 m<\/p>\n

X<\/dd>\n

 => n<\/p>\n

X<\/dd>\n

 = 0,05 mol<\/p>\n

=>M<\/p>\n

X<\/dd>\n

 = 75g => H<\/p>\n

2<\/dd>\n

NCH<\/p>\n

2<\/dd>\n

COOH   =>C<\/p>\n

C\u00e2u 30:  n<\/p>\n

X<\/dd>\n

 = 0,1 mol ; n<\/p>\n

NaOH<\/dd>\n

 = 0,3 mol<\/p>\n

V\u00ec X + NaOH t\u1ea1o 2 kh\u00ed l\u00e0m xanh qu\u00ec t\u00edm \u1ea9m<\/p>\n

=> CT c\u1ee7a X l\u00e0 : NH<\/p>\n

4<\/dd>\n

OCOONH<\/p>\n

3<\/dd>\n

CH<\/p>\n

3<\/dd>\n<\/p>\n

NH<\/p>\n

4<\/dd>\n

OCOONH<\/p>\n

3<\/dd>\n

CH<\/p>\n

3<\/dd>\n

 + 2NaOH -> NH<\/p>\n

3<\/dd>\n

 + CH<\/p>\n

3<\/dd>\n

NH<\/p>\n

2<\/dd>\n

 + Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n

 + 2H<\/p>\n

2<\/dd>\n

O<\/p>\n

=> ch\u1ea5t r\u1eafn g\u1ed3m 0,1 mol Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n

 v\u00e0 0,1 mol NaOH=> m = 14,6g  =>C<\/p>\n

C\u00e2u 31: B\u1ea3o to\u00e0n kh\u1ed1i l\u01b0\u1ee3ng : m<\/p>\n

KL<\/dd>\n

 + m<\/p>\n

O<\/dd>\n

 = m<\/p>\n

oxit<\/dd>\n

 => n<\/p>\n

O<\/dd>\n

 = 0,26 mol<\/p>\n

Khi oxit ph\u1ea3n \u1ee9ng v\u1edbi HCl th\u00ec c\u0169ng t\u01b0\u01a1ng t\u1ef1 nh\u01b0 1 mol O b\u1ecb thay th\u1ebf b\u1edfi 2 mol Cl<\/p>\n

–<\/dd>\n<\/p>\n

=> n<\/p>\n

Cl<\/dd>\n

 = 2n<\/p>\n

O<\/dd>\n

 = 0,52 mol<\/p>\n

=> m<\/p>\n

KL<\/dd>\n

 + m<\/p>\n

Cl<\/dd>\n

 = m<\/p>\n

mu\u1ed1i<\/dd>\n

 => m + 0,52.35,5 = 3m + 1,82<\/p>\n

=> m = 8,32g<\/p>\n

m<\/p>\n

k\u1ebft t\u1ee7a<\/dd>\n

 = 9m + 4,06 = 78,94g<\/p>\n

n<\/p>\n

AgCl<\/dd>\n

 = n<\/p>\n

Cl<\/dd>\n

 = 0,52 mol => Gi\u1ea3 s\u1eed c\u00f3 Ag => n<\/p>\n

Ag<\/dd>\n

 = 0,04 mol<\/p>\n

Fe<\/p>\n

2+ <\/dd>\n

 + Ag<\/p>\n

+<\/dd>\n

 -> Fe<\/p>\n

3+<\/dd>\n

 + Ag<\/p>\n

=> n<\/p>\n

Fe2+<\/dd>\n

 = n<\/p>\n

Ag<\/dd>\n

 = 0,04 mol => n<\/p>\n

FeO(X)<\/dd>\n

 = 0,04<\/p>\n

V\u1eady trong 3,75m (g) h\u1ed7n h\u1ee3p X ( 31,2g) s\u1ebd c\u00f3 n<\/p>\n

FeO<\/dd>\n

 = 0,04.31,2\/(8,32 + 4,16) = 0,1<\/p>\n

Khi ph\u1ea3n \u1ee9ng v\u1edbi HNO<\/p>\n

3<\/dd>\n

 th\u00ec FeO -> Fe(NO<\/p>\n

3<\/dd>\n

)<\/p>\n

3<\/dd>\n

 ( Fe<\/p>\n

2+<\/dd>\n

 -1e -> Fe<\/p>\n

3+<\/dd>\n

)<\/p>\n

X\u00e9t 3,75m gam X : Ta th\u1ea5y n<\/p>\n

Cl(mu\u1ed1i)<\/dd>\n

 = n<\/p>\n

e trao \u0111\u1ed5i (1)<\/dd>\n

 = 1,3 mol<\/p>\n

Khi ph\u1ea3n \u1ee9ng v\u1edbi HNO<\/p>\n

3<\/dd>\n

 th\u00ec n<\/p>\n

e trao \u0111\u1ed5i (2)<\/dd>\n

 = n<\/p>\n

e trao \u0111\u1ed5i (1)<\/dd>\n

 + n<\/p>\n

FeO<\/dd>\n

 = n<\/p>\n

NO3 mu\u1ed1i<\/dd>\n

 = 1,4 mol<\/p>\n

=> m\u2019 = m<\/p>\n

KL<\/dd>\n

 + m<\/p>\n

NO3<\/dd>\n

 = 8,32.2,5 + 1,4.62 = 107,6g<\/p>\n

( N\u1ebfu x\u00e9t tr\u01b0\u1eddng h\u1ee3p kh\u00f4ng t\u1ea1o NH<\/p>\n

4<\/dd>\n

NO<\/p>\n

3<\/dd>\n

)  =>A<\/p>\n

C\u00e2u 32 : Mu\u1ed1i Y c\u00f3 th\u1ec3 tr\u00e1ng g\u01b0\u01a1ng => HCOONa<\/p>\n

Z h\u00f2a tan \u0111\u01b0\u1ee3c Cu(OH)<\/p>\n

2<\/dd>\n

 \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng => c\u00f3 nhi\u1ec1u nh\u00f3m OH k\u1ec1 nhau<\/p>\n

=> X l\u00e0 este c\u1ee7a ancol \u0111a ch\u1ee9c v\u00e0 HCOOH<\/p>\n

=> n<\/p>\n

ancol<\/dd>\n

 = n<\/p>\n

X<\/dd>\n

 = 0,1 mol => M<\/p>\n

ancol<\/dd>\n

 = 76g ( C<\/p>\n

3<\/dd>\n

H<\/p>\n

6<\/dd>\n

(OH)<\/p>\n

2<\/dd>\n

 )<\/p>\n

=> X l\u00e0 HCOOCH<\/p>\n

2<\/dd>\n

CH(CH<\/p>\n

3<\/dd>\n

)OOCH  =>B<\/p>\n

C\u00e2u 33: n<\/p>\n

H2SO4<\/dd>\n

 = 0,05 mol ; n<\/p>\n

HCl<\/dd>\n

 = 0,1 mol ;<\/p>\n

L\u1ea1i c\u00f3 n<\/p>\n

H2<\/dd>\n

 = 0,3 mol => 2n<\/p>\n

H2<\/dd>\n

 > (2n<\/p>\n

H2SO4<\/dd>\n

 + n<\/p>\n

HCl<\/dd>\n

)<\/p>\n

=> Na c\u00f2n t\u00e1c d\u1ee5ng v\u1edbi H<\/p>\n

2<\/dd>\n

O<\/p>\n

=> n<\/p>\n

NaOH<\/dd>\n

 = 2( n<\/p>\n

H2<\/dd>\n

 \u2013 \u00bd n<\/p>\n

H+<\/dd>\n

) = 0,4mol<\/p>\n

=> Mu\u1ed1i g\u1ed3m : 0,05 mol Na<\/p>\n

2<\/dd>\n

SO<\/p>\n

4<\/dd>\n

 ; 0,1 mol NaCl ; 0,4 mol NaOH<\/p>\n

=> m<\/p>\n

r\u1eafn khan<\/dd>\n

 = 28,95g  =>B<\/p>\n

C\u00e2u 34:   n<\/p>\n

NaOH<\/dd>\n

 = 0,2 mol ; n<\/p>\n

Na2CO3<\/dd>\n

 = 0,1 mol<\/p>\n

Gi\u1ea3 s\u1eed ph\u1ea3n \u1ee9ng ch\u1ec9 t\u1ea1o Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n<\/p>\n

=> m<\/p>\n

r\u1eafn<\/dd>\n

 = m<\/p>\n

Na2CO3<\/dd>\n

 = 106.(1\/2 .0,2 + 0,1) = 21,2g > m<\/p>\n

r\u1eafn theo \u0111\u1ec1 b\u00e0i<\/dd>\n<\/p>\n

=> C\u00f3 x mol NaOH ph\u1ea3n \u1ee9ng<\/p>\n

=> Ch\u1ea5t r\u1eafn g\u1ed3m (0,2 \u2013 x) mol NaOH v\u00e0 (0,1 + 0,5x) mol Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n<\/p>\n

=> m<\/p>\n

r\u1eafn<\/dd>\n

 = 40.(0,2 \u2013 x) + 106.(0,1 + 0,5x) = 19,9g<\/p>\n

=> x = 0,1 mol<\/p>\n

=> n<\/p>\n

CO2<\/dd>\n

 = \u00bd n<\/p>\n

NaOH p\u1ee9<\/dd>\n

 = 0,05 mol => V = 1,12 lit =>B <\/p>\n

C\u00e2u 35:   n<\/p>\n

CaCO3<\/dd>\n

 = n<\/p>\n

CO2<\/dd>\n

 = 1,35 mol<\/p>\n

,m<\/p>\n

dd gi\u1ea3m<\/dd>\n

 = m<\/p>\n

CaCO3<\/dd>\n

 \u2013 (m<\/p>\n

CO2<\/dd>\n

 + m<\/p>\n

H2O<\/dd>\n

)<\/p>\n

=> n<\/p>\n

H2O<\/dd>\n

 = 0,95 mol<\/p>\n

A + Na d\u01b0 => 2n<\/p>\n

H2<\/dd>\n

 = n<\/p>\n

ancol<\/dd>\n

 + n<\/p>\n

axit<\/dd>\n

 => n<\/p>\n

axit<\/dd>\n

  =0,1 mol<\/p>\n

A + NaOH d\u01b0 :<\/p>\n

+) N\u1ebfu Este c\u1ee7a phenol => 2n<\/p>\n

este<\/dd>\n

 + n<\/p>\n

axit<\/dd>\n

 = n<\/p>\n

NaOH<\/dd>\n<\/p>\n

=> n<\/p>\n

este<\/dd>\n

 = 0,1 mol v\u00e0 Este c\u00f3 d\u1ea1ng : RCOOC<\/p>\n

6<\/dd>\n

H<\/p>\n

4<\/dd>\n

R\u2019 => s\u1ed1 C<\/p>\n

este<\/dd>\n

 \u2265 7<\/p>\n

V\u00ec s\u1ed1 mol CO<\/p>\n

2<\/dd>\n

 l\u1ebb . S\u1ed1 C trong m\u1ed7i ch\u1ea5t > 1 => s\u1ed1 C trong ancol ph\u1ea3i l\u00e0 s\u1ed1 l\u1ebb v\u00e0 > 1<\/p>\n

=> S\u1ed1 C<\/p>\n

ancol<\/dd>\n

 \u2265 3<\/p>\n

=> n<\/p>\n

C(ancol)<\/dd>\n

 + n<\/p>\n

C(este)<\/dd>\n

  \u2265 1,15 mol<\/p>\n

=> s\u1ed1 C trong axit = 2 v\u00e0 s\u1ed1 C trong ancol = 3 ; este l\u00e0 HCOOC<\/p>\n

6<\/dd>\n

H<\/p>\n

5<\/dd>\n<\/p>\n

B\u1ea3o to\u00e0n H : n<\/p>\n

H(ancol)<\/dd>\n

 + n<\/p>\n

H(axit)<\/dd>\n

 = 2n<\/p>\n

H2O<\/dd>\n

 \u2013 n<\/p>\n

H(este)<\/dd>\n

 = 1,3 mol<\/p>\n

=> H<\/p>\n

ancol<\/dd>\n

 + H<\/p>\n

axit<\/dd>\n

 = 13<\/p>\n

M\u00e0 S\u1ed1 C trong ancol = 3 => s\u1ed1 H \u2264 8<\/p>\n

S\u1ed1 C trong axit = 2 => s\u1ed1 H \u2264 4<\/p>\n

=> Lo\u1ea1i<\/p>\n

+) N\u1ebfu este kh\u00f4ng ph\u1ea3i c\u1ee7a phenol => n<\/p>\n

axit<\/dd>\n

 + n<\/p>\n

este<\/dd>\n

 = n<\/p>\n

NaOH <\/dd>\n

=> n<\/p>\n

este<\/dd>\n

 = 0,2 mol<\/p>\n

X\u00e9t c\u1ea3 3 ch\u1ea5t trong h\u1ed7n h\u1ee3p A ta c\u00f3 th\u1ec3 g\u1ed9p 3 ch\u1ea5t l\u1ea1i th\u00e0nh : C<\/p>\n

1,35<\/dd>\n

H<\/p>\n

1,9<\/dd>\n

O<\/p>\n

0,55<\/dd>\n<\/p>\n

=> C<\/p>\n

27<\/dd>\n

H<\/p>\n

38<\/dd>\n

O<\/p>\n

11<\/dd>\n

 => s\u1ed1 pi = 9 => S\u1ed1 pi ph\u1ea3n \u1ee9ng v\u1edbi Brom = 9 \u2013 2 = 7<\/p>\n

=> n<\/p>\n

Br2<\/dd>\n

 = n<\/p>\n

pi (ancol)<\/dd>\n

 + n<\/p>\n

pi (axit)<\/dd>\n

 + n<\/p>\n

pi (este)<\/dd>\n

 = 0,15.a + 0,1.b + 0,1.c<\/p>\n

C\u00f3 a + b + c = 7 => 0,7 < n<\/p>\n

Br2<\/dd>\n

 < 1,05<\/p>\n

Ch\u1ec9 c\u00f3 gi\u00e1 tr\u1ecb 0,75 mol th\u1ecfa m\u00e3n   =>A<\/p>\n

 C\u00e2u 36: <\/p>\n

4Fe(OH)<\/p>\n

2<\/dd>\n

 + O<\/p>\n

2<\/dd>\n

 + 2H<\/p>\n

2<\/dd>\n

O -> 4Fe(OH)<\/p>\n

3<\/dd>\n<\/p>\n

2Fe(OH)<\/p>\n

3<\/dd>\n

 -> Fe<\/p>\n

2<\/dd>\n

O<\/p>\n

3<\/dd>\n

 + 3H<\/p>\n

2<\/dd>\n

O<\/p>\n

=>D<\/p>\n

C\u00e2u 37: 2Fe + 6H<\/p>\n

2<\/dd>\n

SO<\/p>\n

4<\/dd>\n

 -> Fe<\/p>\n

2<\/dd>\n

(SO<\/p>\n

4<\/dd>\n

)<\/p>\n

3<\/dd>\n

 + 3SO<\/p>\n

2<\/dd>\n

 + 6H<\/p>\n

2<\/dd>\n

O   =>A<\/p>\n

C\u00e2u 38: G\u1ecdi th\u1ec3 tich c\u1ea7n t\u00ecm l\u00e0 V lit<\/p>\n

,n<\/p>\n

H+<\/dd>\n

 = n<\/p>\n

OH-<\/dd>\n

 => n<\/p>\n

HCl<\/dd>\n

 + 2n<\/p>\n

H2SO4<\/dd>\n

 = n<\/p>\n

NaOH<\/dd>\n

 + 2n<\/p>\n

Ba(OH)2<\/dd>\n<\/p>\n

=> 0,1V + 2.0,05V = 0,1 + 2.0,15<\/p>\n

=> V = 2 lit =>D<\/p>\n

C\u00e2u 39: Khi cho t\u1eeb t\u1eeb NaOH v\u00e0o AlCl<\/p>\n

3<\/dd>\n

 l\u00fac \u0111\u1ea7u AlCl<\/p>\n

3<\/dd>\n

 r\u1ea5t d\u01b0 n\u00ean t\u1ea1o k\u1ebft t\u1ee7a tr\u1eafng keo. Sau \u0111\u00f3 NaOH d\u01b0 th\u00ec h\u00f2a tan k\u1ebft t\u1ee7a \u0111\u00f3  =>B<\/p>\n

C\u00e2u 40:  C\u00e2u h\u00ecnh e : 1s<\/p>\n

2<\/dd>\n

2s<\/p>\n

2<\/dd>\n

2p<\/p>\n

6<\/dd>\n

3s<\/p>\n

2<\/dd>\n

3p<\/p>\n

6<\/dd>\n

3d<\/p>\n

6<\/dd>\n

4s<\/p>\n

2<\/dd>\n<\/p>\n

Do e cu\u1ed1i \u0111i\u1ec1n v\u00e0o ph\u00e2n l\u1edbp d => nh\u00f3m B<\/p>\n

T\u1ed5ng e<\/p>\n

d<\/dd>\n

 + e<\/p>\n

4s<\/dd>\n

 = 8 => nh\u00f3m VIIIB  =>A<\/p>\n

C\u00e2u 41: Tham gia ph\u1ea3n \u1ee9ng tr\u00e1ng b\u1ea1c ph\u1ea3i c\u00f3 nh\u00f3m CHO =>C<\/p>\n

C\u00e2u 42: =>A<\/p>\n

C\u00e2u 43<\/p>\n

 <\/p>\n

D\u1ef1a v\u00e0o \u0111\u1ed3 th\u1ecb :<\/p>\n

(1) \u0110o\u1ea1n \u0111i l\u00ean : Ba(OH)<\/p>\n

2<\/dd>\n

 + CO<\/p>\n

2<\/dd>\n

 -> BaCO<\/p>\n

3<\/dd>\n

 + H<\/p>\n

2<\/dd>\n

O<\/p>\n

(2) \u0110o\u1ea1n ngang : 2NaOH + CO<\/p>\n

2<\/dd>\n

 -> Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n

 + H<\/p>\n

2<\/dd>\n

O<\/p>\n

          Na<\/p>\n

2<\/dd>\n

CO<\/p>\n

3<\/dd>\n

 + CO<\/p>\n

2<\/dd>\n

 + H<\/p>\n

2<\/dd>\n

O -> 2NaHCO<\/p>\n

3<\/dd>\n<\/p>\n

(3) \u0110o\u1ea1n \u0111i xu\u1ed1ng : BaCO<\/p>\n

3<\/dd>\n

 + CO<\/p>\n

2<\/dd>\n

 + H<\/p>\n

2<\/dd>\n

O -> Ba(HCO<\/p>\n

3<\/dd>\n

)<\/p>\n

2<\/dd>\n<\/p>\n

X\u00e9t (2) => n<\/p>\n

CO2<\/dd>\n

 = n<\/p>\n

NaOH<\/dd>\n

 = 0,5 mol => m = 20g<\/p>\n

,T\u1ed5ng s\u1ed1 mol CO<\/p>\n

2<\/dd>\n

 ph\u1ea3n \u1ee9ng l\u00e0 1,3 mol = n<\/p>\n

NaOH<\/dd>\n

 + 2n<\/p>\n

Ba(OH)2<\/dd>\n<\/p>\n

=> n<\/p>\n

Ba(OH)2<\/dd>\n

 = 0,4 mol = a<\/p>\n

=> a  + m = 20,4 =>C<\/p>\n

C\u00e2u 44: =>A<\/p>\n

C\u00e2u 45:Ta c\u00f3 : n<\/p>\n

Fe<\/dd>\n

 = n<\/p>\n

Cu<\/dd>\n

 = 0,15 mol<\/p>\n

\u0110\u1ec3 l\u01b0\u1ee3ng HNO<\/p>\n

3<\/dd>\n

 ph\u1ea3n \u1ee9ng \u00edt nh\u1ea5t th\u00ec Fe -> Fe<\/p>\n

2+<\/dd>\n

 ; Cu -> Cu<\/p>\n

2+<\/dd>\n<\/p>\n

=> B\u1ea3o to\u00e0n e : 2n<\/p>\n

Fe<\/dd>\n

 + 2n<\/p>\n

Cu<\/dd>\n

 = 3n<\/p>\n

NO<\/dd>\n

 => n<\/p>\n

NO<\/dd>\n

 = 0,2 mol<\/p>\n

=> n<\/p>\n

HNO3<\/dd>\n

 = 4n<\/p>\n

NO<\/dd>\n

 = 0,8 mol => C<\/p>\n

M(HNO3)<\/dd>\n

 = 0,8 lit =>C<\/p>\n

C\u00e2u 46: =>A<\/p>\n

C\u00e2u 47: =>B<\/p>\n

C\u00e2u 48: Gi\u1ea3 s\u1eed X c\u00f3 3 mol C<\/p>\n

2<\/dd>\n

H<\/p>\n

4<\/dd>\n

 v\u00e0 2 mol C<\/p>\n

3<\/dd>\n

H<\/p>\n

6<\/dd>\n<\/p>\n

Khi ph\u1ea3n \u1ee9ng v\u1edbi H<\/p>\n

2<\/dd>\n

O t\u1ea1o th\u00e0nh 3 mol C<\/p>\n

2<\/dd>\n

H<\/p>\n

5<\/dd>\n

OH ; x mol n-C<\/p>\n

3<\/dd>\n

H<\/p>\n

7<\/dd>\n

OH v\u00e0 (2 \u2013 x) mol i-C<\/p>\n

3<\/dd>\n

H<\/p>\n

7<\/dd>\n

OH<\/p>\n

 <\/p>\n

=> Trong Y c\u00f3 1,5 mol i-C<\/p>\n

3<\/dd>\n

H<\/p>\n

7<\/dd>\n

OH =>%m<\/p>\n

i-C3H7OH<\/dd>\n

 = 34,88%   =>C<\/p>\n

C\u00e2u 49 =>B<\/p>\n

C\u00e2u 50:  ta c\u00f3 : n<\/p>\n

e KL<\/dd>\n

 = 2n<\/p>\n

H2<\/dd>\n

 = 2.0,05 = 0,1 mol<\/p>\n

N\u1ebfu \u0111\u1ed1t ch\u00e1y h\u1ebft X b\u1eb1ng oxi thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p oxit Z th\u00ec n<\/p>\n

O2 p\u1ee9<\/dd>\n

 = \u00bc n<\/p>\n

e KL<\/dd>\n

 = 0,025 mol<\/p>\n

=> m<\/p>\n

Z<\/dd>\n

 = m<\/p>\n

O2<\/dd>\n

 + m<\/p>\n

X<\/dd>\n

 = 22,7g = m<\/p>\n

BaO<\/dd>\n

 + m<\/p>\n

Na2O<\/dd>\n<\/p>\n

L\u1ea1i c\u00f3 n<\/p>\n

Ba(OH)2<\/dd>\n

 = n<\/p>\n

BaO<\/dd>\n

 = 0,12 mol => n<\/p>\n

Na2O<\/dd>\n

 = 0,07 mol<\/p>\n

=> Y c\u00f3 : 0,12 mol Ba(OH)<\/p>\n

2<\/dd>\n

 ; 0,14 mol NaOH => n<\/p>\n

OH<\/dd>\n

 = 0,38 mol<\/p>\n

,n<\/p>\n

Al2(SO4)3<\/dd>\n

 = 0,05 mol => n<\/p>\n

Al3+<\/dd>\n

 = 0,1 mol<\/p>\n

=> n<\/p>\n

Al(OH)3<\/dd>\n

 = 4n<\/p>\n

Al3+<\/dd>\n

 – n<\/p>\n

OH<\/dd>\n

 = 0,02 mol<\/p>\n

=> K\u1ebft t\u1ee7a g\u1ed3m 0,02 mol Al(OH)<\/p>\n

3<\/dd>\n

 ; 0,12 mol BaSO<\/p>\n

4<\/dd>\n<\/p>\n

=> m = 29,52g  =>B<\/p>\n<\/p>\n

<\/strong><\/p>\n

T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"

\u0110\u1ec1 thi th\u1eed THPTQG 2016 m\u00f4n H\u00f3a – THPT \u0110\u1ed3ng \u0110\u1eadu l\u1ea7n 2 t\u1ed5 ch\u1ee9c thi th\u1eed cho h\u1ecdc sinh kh\u1ed1i 12, c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft c\u00e1c em tham kh\u1ea3o b\u00ean d\u01b0\u1edbi: \u0110\u1ec1 thi th\u1eed THPTQG 2016 m\u00f4n H\u00f3a – THPT \u0110\u1ed3ng \u0110\u1eadu l\u1ea7n 2 \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPTQG 2016 m\u00f4n H\u00f3a […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[24],"tags":[],"yoast_head":"\n