\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, gi\u00fap c\u00e1c em chu\u1ea9n b\u1ecb t\u1ed1t cho k\u00ec thi quan tr\u1ecdng s\u1eafp t\u1edbi:<\/strong><\/h2>\n\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3<\/strong><\/h4>\nC\u00e2u 1(ID:118390)<\/strong>: Cho h\u1ed7n h\u1ee3p g\u1ed3m Fe v\u00e0 Mg v\u00e0o dung d\u1ecbch AgNO<\/p>\n3<\/dd>\n, khi c\u00e1c ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n t\u00f2an thu \u0111\u01b0\u1ee3c dung d\u1ecbch X(ch\u1ee9a 2 mu\u1ed1i) v\u00e0 ch\u1ea5t r\u1eafn Y (ch\u1ee9a 2 kim lo\u1ea1i). Hai mu\u1ed1i trong X l\u00e0 :<\/p>\n
A. AgNO<\/p>\n
3<\/dd>\n v\u00e0 Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n B. Mg(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n v\u00e0 Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
3<\/dd>\n<\/p>\nC. Mg(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n v\u00e0 Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n D. Mg(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\nv\u00e0 AgNO<\/p>\n
3<\/dd>\n<\/p>\nC\u00e2u 2(ID:118391)<\/strong>: Cho h\u1ed7n h\u1ee3p c\u00e1c kim lo\u1ea1i Fe, Mg, Zn v\u00e0o c\u1ed1c \u0111\u1ef1ng dung d\u1ecbch CuSO<\/p>\n4<\/dd>\n d\u01b0, th\u1ee9 t\u1ef1 c\u00e1c kim lo\u1ea1i t\u00e1c d\u1ee5ng v\u1edbi mu\u1ed1i l\u00e0:<\/p>\n
A. Fe, Zn,Mg B. Mg, Zn,Fe C. Mg,Fe, Zn D. Zn,Mg, Fe<\/p>\n
C\u00e2u 3(ID:118392)<\/strong>: Cho 20g Fe t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch HNO<\/p>\n3<\/dd>\n lo\u00e3ng, sau khi ph\u1ea3n \u1ee9ng k\u1ebft th\u00fac thu \u0111\u01b0\u1ee3c V l\u00edt kh\u00ed NO duy nh\u1ea5t (\u0111ktc) v\u00e0 3,2g ch\u1ea5t r\u1eafn. Gi\u00e1 tr\u1ecb c\u1ee7a V l\u00e0 :<\/p>\n
A. 0,896 l\u00edt B. 4,48 l\u00edt C. 6,72 l\u00edt D. 2,24 l\u00edt<\/p>\n
C\u00e2u 4(ID:118393)<\/strong>: Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang:<\/p>\nA. \u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng, c\u00e1c kim lo\u1ea1i \u0111\u1ec1u \u1edf th\u1ec3 r\u1eafn.<\/p>\n
B. C\u00e1c kim lo\u1ea1i \u0111\u1ec1u c\u00f3 duy nh\u1ea5t m\u1ed9t s\u1ed1 oxi h\u00f3a duy nh\u1ea5t trong m\u1ecdi h\u1ee3p ch\u1ea5t.<\/p>\n
C. T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc \u0111\u1eb7c tr\u01b0ng c\u1ee7a kim lo\u1ea1i l\u00e0 t\u00ednh kh\u1eed.<\/p>\n
D. \u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng, c\u00e1c kim lo\u1ea1i \u0111\u1ec1u n\u1eb7ng h\u01a1n n\u01b0\u1edbc.<\/p>\n
![](\"http:\/\/img.toanhoc247.com\/picture\/2016\/0220\/de-thi-thu-thptqg-hoa-nam-2016-thpt-chuyen-thai-binh-lan-3_1.png\")
<\/p>\n
\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3<\/strong><\/h4>\nC\u00e2u 1<\/p>\n
C\u00e1c th\u1ee9 t\u1ef1 ph\u1ea3n \u1ee9ng c\u00f3 th\u1ec3 x\u1ea3y ra :<\/p>\n
(1) Mg + 2AgNO<\/p>\n
3<\/dd>\n -> Mg(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n + 2Ag<\/p>\n
(2) Fe + 2AgNO<\/p>\n
3<\/dd>\n -> Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n + 2Ag<\/p>\n
(3) Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n + AgNO<\/p>\n
3<\/dd>\n -> Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
3<\/dd>\n + Ag<\/p>\n
Ch\u1ea5t r\u1eafn Y ch\u1ee9a 2 kim lo\u1ea1i => Y : Ag ; Fe => kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng (3)<\/p>\n
X ch\u1ee9a 2 mu\u1ed1i \u0111\u00f3 l\u00e0 Mg(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2<\/dd>\n v\u00e0 Fe(NO<\/p>\n
3<\/dd>\n)<\/p>\n
2 <\/dd>\n=>C<\/p>\n
C\u00e2u 2<\/p>\n
Th\u1ee9 t\u1ef1 ph\u1ea3n \u1ee9ng tu\u00e2n theo d\u00e3y \u0111i\u1ec7n h\u00f3a kim lo\u1ea1i =>B<\/p>\n
C\u00e2u 3<\/p>\n
Do Fe d\u01b0 n\u00ean Fe -> Fe<\/p>\n
2+<\/dd>\n => m<\/p>\n
Fe p\u1ee9<\/dd>\n = 20 – 3,2 = 16,8g<\/p>\n
B\u1ea3o to\u00e0n e : 2n<\/p>\n
Fe p\u1ee9<\/dd>\n = 3n<\/p>\n
NO <\/dd>\n => n<\/p>\n
NO<\/dd>\n = 0,2 mol<\/p>\n
=>V = 4,48 lit =>B<\/p>\n
C\u00e2u 4<\/p>\n
\u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng , Hg l\u00e0 kim lo\u1ea1i \u1edf th\u1ec3 l\u1ecfng<\/p>\n
Kim lo\u1ea1i Fe c\u00f3 th\u1ec3 c\u00f3 2 s\u1ed1 oxi h\u00f3a trong h\u1ee3p ch\u1ea5t +2 v\u00e0 +3 ..<\/p>\n
C\u00f3 nhi\u1ec1u kim lo\u1ea1i nh\u1eb9 h\u01a1n n\u01b0\u1edbc. VD : Li c\u00f3 d = 0,5g\/cm<\/p>\n
3 <\/dd>\n=>C<\/p>\n
C\u00e2u 5<\/p>\n
Mg , Be \u1edf nh\u00f3m IIA nh\u01b0ng kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc \u1edf nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng =>B<\/p>\n
C\u00e2u 6<\/p>\n
D\u1ef1a v\u00e0o ph\u1ea3n \u1ee9ng :<\/p>\n
Fe + 2Fe<\/p>\n
3+<\/dd>\n -> 3Fe<\/p>\n
2+<\/dd>\n<\/p>\nCu + 2Fe<\/p>\n
3+<\/dd>\n -> 2Fe<\/p>\n
2+<\/dd>\n + Cu<\/p>\n
2+<\/dd>\n<\/p>\n=>A<\/p>\n
C\u00e2u 7 =>A<\/p>\n
C\u00e2u 8<\/p>\n
(2) CuS ; (3) H<\/p>\n
2<\/dd>\nSiO<\/p>\n
3<\/dd>\n ; (5) Al(OH)<\/p>\n
3<\/dd>\n ; (6) BaSO<\/p>\n
4 <\/dd>\n=>C<\/p>\n
C\u00e2u 9<\/p>\n
H<\/p>\n
2<\/dd>\nSO<\/p>\n
4<\/dd>\n.3SO<\/p>\n
3<\/dd>\n + 3H<\/p>\n
2<\/dd>\nO -> 4H<\/p>\n
2<\/dd>\nSO<\/p>\n
4<\/dd>\n<\/p>\n=> n<\/p>\n
H2SO4<\/dd>\n = \u00bd n<\/p>\n
KOH<\/dd>\n = 0,02 mol<\/p>\n
=> n<\/p>\n
Oleum<\/dd>\n = 0,005 mol<\/p>\n
=> m = 1,69g =>C<\/p>\n
C\u00e2u 10<\/p>\n
Ch\u1ea5t l\u01b0\u1ee1ng t\u00ednh v\u00f3 th\u1ec3 ph\u1ea3n \u1ee9ng v\u1edbi c\u1ea3 axit v\u00e0 bazo m\u1ea1nh =>D<\/p>\n
Xem \u0111\u00e1p \u00e1n chi ti\u1ebft t\u1ea1i \u0111\u00e2y: http:\/\/tuyensinh247.com\/khoa-98-de-thi-thu-thpt-quoc-gia-mon-hoa-hay-nhat-cua-cac-truong-chuyen-tren-toan-quoc-nam-2016-k160.html<\/p><\/p>\n","protected":false},"excerpt":{"rendered":"
\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, gi\u00fap c\u00e1c em chu\u1ea9n b\u1ecb t\u1ed1t cho k\u00ec thi quan tr\u1ecdng s\u1eafp t\u1edbi: \u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 C\u00e2u 1(ID:118390): Cho h\u1ed7n h\u1ee3p g\u1ed3m Fe […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[24],"tags":[],"yoast_head":"\n
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THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/","og_locale":"en_US","og_type":"article","og_title":"\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a - THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3","og_description":"\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, gi\u00fap c\u00e1c em chu\u1ea9n b\u1ecb t\u1ed1t cho k\u00ec thi quan tr\u1ecdng s\u1eafp t\u1edbi: \u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 C\u00e2u 1(ID:118390): Cho h\u1ed7n h\u1ee3p g\u1ed3m Fe […]","og_url":"https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/","og_site_name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam","article_author":"www.facebook.com\/lop12.edu.vn\/","article_published_time":"2016-03-19T23:03:35+00:00","article_modified_time":"2016-03-20T16:06:03+00:00","og_image":[{"url":"http:\/\/img.toanhoc247.com\/picture\/2016\/0220\/de-thi-thu-thptqg-hoa-nam-2016-thpt-chuyen-thai-binh-lan-3_1.png"}],"author":"Lop12","twitter_card":"summary_large_image","twitter_misc":{"Written by":"Lop12","Est. reading time":"4 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/","url":"https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/","name":"\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a - THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3","isPartOf":{"@id":"https:\/\/lop12.edu.vn\/#website"},"datePublished":"2016-03-19T23:03:35+00:00","dateModified":"2016-03-20T16:06:03+00:00","author":{"@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/8219caa3d91a087a4ce81b8b5ac734b5"},"breadcrumb":{"@id":"https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/lop12.edu.vn\/de-thi-thu-thptqg-nam-2016-mon-hoa-thpt-chuyen-thai-binh-lan-3\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/lop12.edu.vn\/"},{"@type":"ListItem","position":2,"name":"\u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3"}]},{"@type":"WebSite","@id":"https:\/\/lop12.edu.vn\/#website","url":"https:\/\/lop12.edu.vn\/","name":"Lop12.edu.vn - 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C\u00e2u 1(ID:118390)<\/strong>: Cho h\u1ed7n h\u1ee3p g\u1ed3m Fe v\u00e0 Mg v\u00e0o dung d\u1ecbch AgNO<\/p>\n , khi c\u00e1c ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n t\u00f2an thu \u0111\u01b0\u1ee3c dung d\u1ecbch X(ch\u1ee9a 2 mu\u1ed1i) v\u00e0 ch\u1ea5t r\u1eafn Y (ch\u1ee9a 2 kim lo\u1ea1i). Hai mu\u1ed1i trong X l\u00e0 :<\/p>\n A. AgNO<\/p>\n v\u00e0 Fe(NO<\/p>\n )<\/p>\n B. Mg(NO<\/p>\n )<\/p>\n v\u00e0 Fe(NO<\/p>\n )<\/p>\n C. Mg(NO<\/p>\n )<\/p>\n v\u00e0 Fe(NO<\/p>\n )<\/p>\n D. Mg(NO<\/p>\n )<\/p>\n v\u00e0 AgNO<\/p>\n C\u00e2u 2(ID:118391)<\/strong>: Cho h\u1ed7n h\u1ee3p c\u00e1c kim lo\u1ea1i Fe, Mg, Zn v\u00e0o c\u1ed1c \u0111\u1ef1ng dung d\u1ecbch CuSO<\/p>\n d\u01b0, th\u1ee9 t\u1ef1 c\u00e1c kim lo\u1ea1i t\u00e1c d\u1ee5ng v\u1edbi mu\u1ed1i l\u00e0:<\/p>\n A. Fe, Zn,Mg B. Mg, Zn,Fe C. Mg,Fe, Zn D. Zn,Mg, Fe<\/p>\n C\u00e2u 3(ID:118392)<\/strong>: Cho 20g Fe t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch HNO<\/p>\n lo\u00e3ng, sau khi ph\u1ea3n \u1ee9ng k\u1ebft th\u00fac thu \u0111\u01b0\u1ee3c V l\u00edt kh\u00ed NO duy nh\u1ea5t (\u0111ktc) v\u00e0 3,2g ch\u1ea5t r\u1eafn. Gi\u00e1 tr\u1ecb c\u1ee7a V l\u00e0 :<\/p>\n A. 0,896 l\u00edt B. 4,48 l\u00edt C. 6,72 l\u00edt D. 2,24 l\u00edt<\/p>\n C\u00e2u 4(ID:118393)<\/strong>: Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang:<\/p>\n A. \u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng, c\u00e1c kim lo\u1ea1i \u0111\u1ec1u \u1edf th\u1ec3 r\u1eafn.<\/p>\n B. C\u00e1c kim lo\u1ea1i \u0111\u1ec1u c\u00f3 duy nh\u1ea5t m\u1ed9t s\u1ed1 oxi h\u00f3a duy nh\u1ea5t trong m\u1ecdi h\u1ee3p ch\u1ea5t.<\/p>\n C. T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc \u0111\u1eb7c tr\u01b0ng c\u1ee7a kim lo\u1ea1i l\u00e0 t\u00ednh kh\u1eed.<\/p>\n D. \u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng, c\u00e1c kim lo\u1ea1i \u0111\u1ec1u n\u1eb7ng h\u01a1n n\u01b0\u1edbc.<\/p>\n C\u00e2u 1<\/p>\n C\u00e1c th\u1ee9 t\u1ef1 ph\u1ea3n \u1ee9ng c\u00f3 th\u1ec3 x\u1ea3y ra :<\/p>\n (1) Mg + 2AgNO<\/p>\n -> Mg(NO<\/p>\n )<\/p>\n + 2Ag<\/p>\n (2) Fe + 2AgNO<\/p>\n -> Fe(NO<\/p>\n )<\/p>\n + 2Ag<\/p>\n (3) Fe(NO<\/p>\n )<\/p>\n + AgNO<\/p>\n -> Fe(NO<\/p>\n )<\/p>\n + Ag<\/p>\n Ch\u1ea5t r\u1eafn Y ch\u1ee9a 2 kim lo\u1ea1i => Y : Ag ; Fe => kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng (3)<\/p>\n X ch\u1ee9a 2 mu\u1ed1i \u0111\u00f3 l\u00e0 Mg(NO<\/p>\n )<\/p>\n v\u00e0 Fe(NO<\/p>\n )<\/p>\n =>C<\/p>\n C\u00e2u 2<\/p>\n Th\u1ee9 t\u1ef1 ph\u1ea3n \u1ee9ng tu\u00e2n theo d\u00e3y \u0111i\u1ec7n h\u00f3a kim lo\u1ea1i =>B<\/p>\n C\u00e2u 3<\/p>\n Do Fe d\u01b0 n\u00ean Fe -> Fe<\/p>\n => m<\/p>\n = 20 – 3,2 = 16,8g<\/p>\n B\u1ea3o to\u00e0n e : 2n<\/p>\n = 3n<\/p>\n => n<\/p>\n = 0,2 mol<\/p>\n =>V = 4,48 lit =>B<\/p>\n C\u00e2u 4<\/p>\n \u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng , Hg l\u00e0 kim lo\u1ea1i \u1edf th\u1ec3 l\u1ecfng<\/p>\n Kim lo\u1ea1i Fe c\u00f3 th\u1ec3 c\u00f3 2 s\u1ed1 oxi h\u00f3a trong h\u1ee3p ch\u1ea5t +2 v\u00e0 +3 ..<\/p>\n C\u00f3 nhi\u1ec1u kim lo\u1ea1i nh\u1eb9 h\u01a1n n\u01b0\u1edbc. VD : Li c\u00f3 d = 0,5g\/cm<\/p>\n =>C<\/p>\n C\u00e2u 5<\/p>\n Mg , Be \u1edf nh\u00f3m IIA nh\u01b0ng kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc \u1edf nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng =>B<\/p>\n C\u00e2u 6<\/p>\n D\u1ef1a v\u00e0o ph\u1ea3n \u1ee9ng :<\/p>\n Fe + 2Fe<\/p>\n -> 3Fe<\/p>\n Cu + 2Fe<\/p>\n -> 2Fe<\/p>\n + Cu<\/p>\n =>A<\/p>\n C\u00e2u 7 =>A<\/p>\n C\u00e2u 8<\/p>\n (2) CuS ; (3) H<\/p>\n SiO<\/p>\n ; (5) Al(OH)<\/p>\n ; (6) BaSO<\/p>\n =>C<\/p>\n C\u00e2u 9<\/p>\n H<\/p>\n SO<\/p>\n .3SO<\/p>\n + 3H<\/p>\n O -> 4H<\/p>\n SO<\/p>\n => n<\/p>\n = \u00bd n<\/p>\n = 0,02 mol<\/p>\n => n<\/p>\n = 0,005 mol<\/p>\n => m = 1,69g =>C<\/p>\n C\u00e2u 10<\/p>\n Ch\u1ea5t l\u01b0\u1ee1ng t\u00ednh v\u00f3 th\u1ec3 ph\u1ea3n \u1ee9ng v\u1edbi c\u1ea3 axit v\u00e0 bazo m\u1ea1nh =>D<\/p>\n Xem \u0111\u00e1p \u00e1n chi ti\u1ebft t\u1ea1i \u0111\u00e2y: http:\/\/tuyensinh247.com\/khoa-98-de-thi-thu-thpt-quoc-gia-mon-hoa-hay-nhat-cua-cac-truong-chuyen-tren-toan-quoc-nam-2016-k160.html<\/p><\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, gi\u00fap c\u00e1c em chu\u1ea9n b\u1ecb t\u1ed1t cho k\u00ec thi quan tr\u1ecdng s\u1eafp t\u1edbi: \u0110\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3 C\u00e2u 1(ID:118390): Cho h\u1ed7n h\u1ee3p g\u1ed3m Fe […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[24],"tags":[],"yoast_head":"\n<\/p>\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPTQG n\u0103m 2016 m\u00f4n H\u00f3a – THPT Chuy\u00ean Th\u00e1i B\u00ecnh l\u1ea7n 3<\/strong><\/h4>\n