\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n v\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 2 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n.<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
Cho bi\u1ebft h\u1eb1ng s\u1ed1 pl\u0103ng h=6,625.10<\/p>\n
-34<\/dd>\nJs ; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng trong ch\u00e2n kh\u00f4ng c= 3.10<\/p>\n
8<\/dd>\nm\/s; \u0111\u1ed9 l\u1edbn \u0111i\u1ec7n t\u00edch nguy\u00ean t\u1ed1 e= 1,6.10<\/p>\n
-19<\/dd>\nC; s\u1ed1 Av\u00f4ga\u0111r\u00f4 N\u00ad<\/p>\n
A\u00ad<\/dd>\n=6,02.10<\/p>\n
23<\/dd>\nmol<\/p>\n
-1<\/dd>\n. <\/p>\n
C\u00e2u 1<\/strong>(ID: 96912)<\/strong>:<\/strong>\u0110\u1eb7t \u0111i\u1ec7n \u00e1p u = 120cos(100\u03c0t + \u03c0\/6 ) V v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch c\u00f3 R, L, C m\u1eafc n\u1ed1i ti\u1ebfp th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua m\u1ea1ch l\u00e0 i = cos(100\u03c0t- \u03c0\/6)A, C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch b\u1eb1ng<\/p>\nA.<\/strong>60\u221a3 W B.<\/strong>120 W C.<\/strong>60 W D.<\/strong>30 W<\/p>\nC\u00e2u 2<\/strong>(ID: 96913)<\/strong>:<\/strong>M\u1ed9t v\u1eadt nh\u1ecf dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 4cm v\u00e0 chu k\u00ec 2s. Qu\u00e3ng \u0111\u01b0\u1eddng v\u1eadt \u0111i \u0111\u01b0\u1ee3c trong 4s l\u00e0<\/p>\nA.<\/strong>16 cm B.<\/strong>64 cm C.<\/strong>8 cm D.<\/strong>32 cm<\/p>\nC\u00e2u 3<\/strong>(ID: 96914)<\/strong>:<\/strong>T\u1ea1i O c\u00f3 c\u00e1c ngu\u1ed3n \u00e2m gi\u1ed1ng nhau. N\u1ebfu t\u1ea1i O c\u00f3 4 ngu\u1ed3n th\u00ec t\u1ea1i \u0111i\u1ec3m A thu \u0111\u01b0\u1ee3c \u00e2m c\u00f3 m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m l\u00e0 50dB, n\u1ebfu t\u1ea1i M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a OA thu \u0111\u01b0\u1ee3c \u00e2m c\u00f3 m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m 60dB th\u00ec t\u1ea1i O c\u00f3 bao nhi\u00eau ngu\u1ed3n \u00e2m?<\/p>\nA.<\/strong>10 ngu\u1ed3n B.<\/strong>5 ngu\u1ed3n C.<\/strong>20 ngu\u1ed3n D.<\/strong>15 ngu\u1ed3n<\/p>\nC\u00e2u 4<\/strong>(ID: 96915)<\/strong>:<\/strong>\u0110\u1ec3 kh\u1eed tr\u00f9ng c\u00e1c d\u1ee5ng c\u1ee5 y t\u1ebf, ng\u01b0\u1eddi ta th\u01b0\u1eddng d\u00f9ng lo\u1ea1i tia n\u00e0o sau \u0111\u00e2y<\/p>\nA.<\/strong>Tia X B.<\/strong>Tia t\u1eed ngo\u1ea1i C.<\/strong>Tia h\u1ed3ng ngo\u1ea1i D.<\/strong>Tia Laze<\/p>\nC\u00e2u 5<\/strong>(ID: 96916)<\/strong>:<\/strong>Th\u1ef1c hi\u1ec7n giao thoa tr\u00ean m\u1eb7t ch\u1ea5t l\u1ecfng v\u1edbi hai ngu\u1ed3n S<\/p>\n1<\/dd>\n, S<\/p>\n
2<\/dd>\ngi\u1ed1ng nhau. Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng t\u1ea1i S<\/p>\n
1<\/dd>\nv\u00e0 S<\/p>\n
2<\/dd>\n\u0111\u1ec1u l\u00e0: u=2cos(40\u03c0t)(cm). V\u1eadn t\u1ed1c truy\u1ec1n s\u00f3ng tr\u00ean m\u1eb7t ch\u1ea5t l\u1ecfng l\u00e0 8(m\/s). B\u01b0\u1edbc s\u00f3ng c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o trong c\u00e1c gi\u00e1 tr\u1ecb sau<\/p>\n
A.<\/strong>12(cm) B.<\/strong>40(cm) C.<\/strong>16(cm) D.<\/strong>8(cm)<\/p>\nC\u00e2u 6<\/strong>(ID: 96917)<\/strong>:<\/strong>H\u1ea1t nh\u00e2n c\u00f3 \u0111\u1ed9 h\u1ee5t kh\u1ed1i c\u00e0ng l\u1edbn th\u00ec c\u00f3<\/p>\nA.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u00e0ng l\u1edbn B.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u00e0ng nh\u1ecf<\/p>\nC.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft ri\u00eang c\u00e0ng l\u1edbn D.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft ri\u00eang c\u00e0ng nh\u1ecf<\/p>\nC\u00e2u 7<\/strong>(ID: 96918)<\/strong>:<\/strong>Khi n\u00f3i v\u1ec1 \u00e2m thanh, \u0111i\u1ec1u n\u00e0o sau \u0111\u00e2y kh\u00f4ng \u0111\u00fang?<\/p>\nA.<\/strong>T\u1ed1c \u0111\u1ed9 \u00e2m thanh ph\u1ee5 thu\u1ed9c v\u00e0o kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang v\u00e0 t\u00ednh \u0111\u00e0n h\u1ed3i c\u1ee7a m\u00f4i tr\u01b0\u1eddng<\/p>\nB.<\/strong>T\u1ed1c \u0111\u1ed9 \u00e2m thanh kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o nhi\u1ec7t \u0111\u1ed9 m\u00f4i tr\u01b0\u1eddng<\/p>\nC.<\/strong>\u00c2m thanh truy\u1ec1n trong m\u00f4i tr\u01b0\u1eddng r\u1eafn, l\u1ecfng, kh\u00ed<\/p>\nD.<\/strong>\u00c2m thanh l\u00e0 s\u00f3ng \u00e2m c\u00f3 t\u1ea7n s\u1ed1 t\u1eeb 16 Hz \u0111\u1ebfn 20 000 Hz<\/p>\nC\u00e2u 8<\/strong>(ID: 96919)<\/strong>:<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k=2N\/m, v\u1eadt c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m=80g \u0111\u01b0\u1ee3c \u0111\u1eb7t tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang, h\u1ec7 s\u1ed1 ma s\u00e1t tr\u01b0\u1ee3t gi\u1eefa v\u1eadt v\u00e0 m\u1eb7t ngang l\u00e0 0,1. Ban \u0111\u1ea7u k\u00e9o v\u1eadt ra kh\u1ecfi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng m\u1ed9t \u0111o\u1ea1n 10cm r\u1ed3i th\u1ea3 nh\u1eb9. Cho gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g=10m\/s<\/p>\n2<\/dd>\n. Khi v\u1eadt c\u00f3 t\u1ed1c \u0111\u1ed9 l\u1edbn nh\u1ea5t th\u00ec th\u1ebf n\u0103ng \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo b\u1eb1ng<\/p>\n
A.<\/strong>1,6 J B.<\/strong>1,6 mJ C.<\/strong>0,16 mJ D.<\/strong>0,16 J<\/p>\nC\u00e2u 9<\/strong>(ID: 96920)<\/strong>:<\/strong>\u0110o\u1ea1n m\u1ea1ch RLC n\u1ed1i ti\u1ebfp \u0111ang c\u00f3 c\u1ed9ng h\u01b0\u1edfng \u0111i\u1ec7n. Ch\u1ecdn k\u1ebft lu\u1eadnsai<\/strong><\/p>\nA.<\/strong>H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ef1c \u0111\u1ea1i<\/p>\nB.<\/strong>u<\/p>\nL<\/dd>\n= u<\/p>\n
C<\/dd>\n<\/p>\nC.<\/strong>Khi t\u0103ng hay gi\u1ea3m C th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n hi\u1ec7u d\u1ee5ng \u0111\u1ec1u gi\u1ea3m<\/p>\nD.<\/strong>Z = R<\/p>\nC\u00e2u 10<\/strong>(ID: 96921)<\/strong>:<\/strong>Trong th\u00f4ng tin v\u0169 tr\u1ee5 ng\u01b0\u1eddi ta th\u01b0\u1eddng d\u00f9ngs\u00f3ng<\/p>\nA.<\/strong>S\u00f3ng trung v\u00ec b\u1ecb t\u1ea7ng \u0111i\u1ec7n li ph\u1ea3n x\u1ea1 B.<\/strong>V\u00f4 tuy\u1ebfn c\u1ef1c d\u00e0i v\u00ec n\u0103ng l\u01b0\u1ee3ng s\u00f3ng l\u1edbn<\/p>\nC.<\/strong>S\u00f3ng ng\u1eafn v\u00ec b\u1ecb t\u1ea7ng \u0111i\u1ec7n li ph\u1ea3n x\u1ea1 D.<\/strong>V\u00f4 tuy\u1ebfn c\u1ef1c ng\u1eafn v\u00ec c\u00f3 n\u0103ng l\u01b0\u1ee3ng l\u1edbn<\/p>\nC\u00e2u 11<\/strong>(ID: 96922)<\/strong>:<\/strong>M\u1ea1ch ch\u1ecdn s\u00f3ng c\u1ee7a m\u1ed9t m\u00e1y thu thanh g\u1ed3m cu\u1ed9n d\u00e2y thu\u1ea7n c\u1ea3m c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m kh\u00f4ng \u0111\u1ed5i v\u00e0 t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. Khi \u0111i\u1ec7n dung t\u1ee5 \u0111i\u1ec7n l\u00e0 C<\/p>\n1<\/dd>\nth\u00ec b\u01b0\u1edbc s\u00f3ng m\u00e0 m\u00e1y thu \u0111\u01b0\u1ee3c l\u00e0 10 m. T\u1eeb gi\u00e1 tr\u1ecb C<\/p>\n
1<\/dd>\n, n\u1ebfu t\u0103ng \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 \u0111i\u1ec7n th\u00eam 1 l\u01b0\u1ee3ng \u2206C th\u00ec m\u00e1y thu \u0111\u01b0\u1ee3c s\u00f3ng c\u00f3 b\u01b0\u1edbc s\u00f3ng l, c\u00f2n n\u1ebfu gi\u1ea3m \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 1 l\u01b0\u1ee3ng 2\u2206C th\u00ec m\u00e1y b\u1eaft \u0111\u01b0\u1ee3c s\u00f3ng c\u00f3 b\u01b0\u1edbc s\u00f3ng l\/2. N\u1ebfu t\u1eeb gi\u00e1 tr\u1ecb C<\/p>\n
1<\/dd>\nt\u0103ng \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 \u0111i\u1ec7n th\u00eam 1 l\u01b0\u1ee3ng 9\u2206C th\u00ec m\u00e1y b\u1eaft \u0111\u01b0\u1ee3c s\u00f3ng c\u00f3 b\u01b0\u1edbc s\u00f3ng<\/p>\n
A.<\/strong>40 m B.<\/strong>20 m C.<\/strong>4 m D.<\/strong>2 m<\/p>\n<\/p>\nC\u00e2u 12<\/strong>(ID: 96923)<\/strong>:<\/strong>M\u1ed9t m\u1ea1ch \u0111i\u1ec7n AB g\u1ed3m t\u1ee5 C n\u1ed1i ti\u1ebfp v\u1edbi cu\u1ed9n c\u1ea3m thu\u1ea7n L. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 t\u1ea7n s\u1ed1 \u03c9 = 2\/\u221aLC. \u0110i\u1ec3m gi\u1eefa C v\u00e0 L l\u00e0 M. Khi u<\/p>\nMB<\/dd>\n=40V th\u00ec u<\/p>\n
AB<\/dd>\nc\u00f3 gi\u00e1 tr\u1ecb<\/p>\n
A.<\/strong>160V B.<\/strong>\u2013 30V C.<\/strong>\u2013 120V D.<\/strong>200V<\/p>\nC\u00e2u 13<\/strong>(ID: 96924)<\/strong>:<\/strong>M\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 chi\u1ec1u d\u00e0i d\u00e2y treo l, dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c g. Khi gi\u1ea3m chi\u1ec1u d\u00e0i con l\u1eafc \u0111i 19% th\u00ec t\u1ea7n s\u1ed1 con l\u1eafc s\u1ebd<\/p>\nA.<\/strong>t\u0103ng 19% B.<\/strong>t\u0103ng 10% C.<\/strong>gi\u1ea3m 10% D.<\/strong>gi\u1ea3m 19%<\/p>\nC\u00e2u 14<\/strong>(ID: 96925)<\/strong>:<\/strong>M\u1ed9t ngu\u1ed3n s\u00e1ng c\u00f3 c\u00f4ng su\u1ea5t P=2W, ph\u00e1t ra \u00e1nh s\u00e1ng c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb=0,597\u00b5m t\u1ecfa ra \u0111\u1ec1u theo m\u1ecdi h\u01b0\u1edbng. N\u1ebfu coi \u0111\u01b0\u1eddng k\u00ednh con ng\u01b0\u01a1i c\u1ee7a m\u1eaft l\u00e0 4mm v\u00e0 m\u1eaft c\u00f2n c\u00f3 th\u1ec3 c\u1ea3m nh\u1eadn \u0111\u01b0\u1ee3c \u00e1nh s\u00e1ng khi t\u1ed1i thi\u1ec3u c\u00f3 80 ph\u00f4t\u00f4n l\u1ecdt v\u00e0o m\u1eaft trong 1s. B\u1ecf qua s\u1ef1 h\u1ea5p th\u1ee5 ph\u00f4t\u00f4n c\u1ee7a m\u00f4i tr\u01b0\u1eddng. Kho\u1ea3ng c\u00e1ch xa ngu\u1ed3n s\u00e1ng nh\u1ea5t m\u00e0 m\u1eaft c\u00f2n tr\u00f4ng th\u1ea5y ngu\u1ed3n l\u00e0<\/p>\nA.<\/strong>27 km B.<\/strong>470 km C.<\/strong>6 km D.<\/strong>274 km<\/p>\nC\u00e2u 15<\/strong>(ID: 96926)<\/strong>:<\/strong>C\u00f3 ba con l\u1eafc \u0111\u01a1n c\u00f9ng chi\u1ec1u d\u00e0i c\u00f9ng kh\u1ed1i l\u01b0\u1ee3ng c\u00f9ng \u0111\u01b0\u1ee3c treo trong \u0111i\u1ec7n tr\u01b0\u1eddng \u0111\u1ec1u c\u00f3 th\u1eb3ng \u0111\u1ee9ng. Con l\u1eafc th\u1ee9 nh\u1ea5t v\u00e0 th\u1ee9 hai t\u00edch \u0111i\u1ec7n q<\/p>\n1<\/dd>\nv\u00e0 q<\/p>\n
2<\/dd>\n, con l\u1eafc th\u1ee9 ba kh\u00f4ng t\u00edch \u0111i\u1ec7n. Chu k\u1ef3 dao \u0111\u1ed9ng nh\u1ecf c\u1ee7a ch\u00fang l\u1ea7n l\u01b0\u1ee3t l\u00e0 T<\/p>\n
1<\/dd>\n, T<\/p>\n
2<\/dd>\n, T<\/p>\n
3<\/dd>\nc\u00f3 T<\/p>\n
1<\/dd>\n= 1\/3T<\/p>\n
3<\/dd>\n; T<\/p>\n
2<\/dd>\n= 5\/3T<\/p>\n
3<\/dd>\n. T\u1ec9 s\u1ed1 q<\/p>\n
1<\/dd>\n\/q<\/p>\n
2<\/dd>\nl\u00e0:<\/p>\n
A.<\/strong>8 B.<\/strong>12,5 C.<\/strong>-12,5 D.<\/strong>-8<\/p>\nC\u00e2u 16<\/strong>(ID: 96927)<\/strong>:<\/strong>Th\u1ef1c hi\u1ec7n giao thoa s\u00f3ng v\u1edbi hai ngu\u1ed3n c\u00f9ng pha S<\/p>\n1<\/dd>\nS<\/p>\n
2<\/dd>\nc\u00e1ch nhau 20(cm). Bi\u1ebft v\u1eadn t\u1ed1c truy\u1ec1n s\u00f3ng tr\u00ean b\u1ec1 m\u1eb7t ch\u1ea5t l\u1ecfng l\u00e0 40(cm\/s), t\u1ea7n s\u1ed1 c\u1ee7a ngu\u1ed3n l\u00e0 f=8(Hz). H\u1ecfi tr\u00ean \u0111o\u1ea1n S<\/p>\n
1<\/dd>\nS<\/p>\n
2<\/dd>\nc\u00f3 bao nhi\u00eau \u0111i\u1ec3m dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i nh\u01b0ng ng\u01b0\u1ee3c pha v\u1edbi hai ngu\u1ed3n<\/p>\n
A.<\/strong>3 B.<\/strong>5 C.<\/strong>4 D.<\/strong>9<\/p>\nC\u00e2u 17<\/strong>(ID: 96928)<\/strong>:<\/strong>Hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch RLC, cu\u1ed9n d\u00e2y thu\u1ea7n c\u1ea3m, \u0111\u01b0\u1ee3c duy tr\u00ec \u0111i\u1ec7n \u00e1p u<\/p>\nAB<\/dd>\n=U<\/p>\n
0<\/dd>\ncos\u03c9t (V). Thay \u0111\u1ed5i R, khi \u0111i\u1ec7n tr\u1edf c\u00f3 gi\u00e1 tr\u1ecb R=24(\u03a9) th\u00ec c\u00f4ng su\u1ea5t \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i 300W. H\u1ecfi khi \u0111i\u1ec7n tr\u1edf b\u1eb1ng 18(\u03a9) th\u00ec m\u1ea1ch ti\u00eau th\u1ee5 c\u00f4ng su\u1ea5t b\u1eb1ng bao nhi\u00eau<\/p>\n
A.<\/strong>168(W) B.<\/strong>144(W) C.<\/strong>288(W) D.<\/strong>248(W)<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/0918\/de-thi-thu-thptqg-ly-2016-de-2-1.png\")
<\/p>\n
\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd 2016 – \u0110\u1ec1 s\u1ed1 2<\/strong><\/span><\/h3>\n\n\n\n\n1D<\/p>\n<\/td>\n
\n6A<\/p>\n<\/td>\n
\n11B<\/p>\n<\/td>\n
\n16C<\/p>\n<\/td>\n
\n21A<\/p>\n<\/td>\n
\n26C<\/p>\n<\/td>\n
\n31B<\/p>\n<\/td>\n
\n36B<\/p>\n<\/td>\n
\n41C<\/p>\n<\/td>\n
\n54C<\/p>\n<\/td>\n<\/tr>\n
\n\n2D<\/p>\n<\/td>\n
\n7B<\/p>\n<\/td>\n
\n12C<\/p>\n<\/td>\n
\n17A<\/p>\n<\/td>\n
\n22B<\/p>\n<\/td>\n
\n27A<\/p>\n<\/td>\n
\n32B<\/p>\n<\/td>\n
\n37D<\/p>\n<\/td>\n
\n42D<\/p>\n<\/td>\n
\n53C<\/p>\n<\/td>\n<\/tr>\n
\n\n3A<\/p>\n<\/td>\n
\n8B<\/p>\n<\/td>\n
\n13C<\/p>\n<\/td>\n
\n18C<\/p>\n<\/td>\n
\n23B<\/p>\n<\/td>\n
\n28A<\/p>\n<\/td>\n
\n33C<\/p>\n<\/td>\n
\n38C<\/p>\n<\/td>\n
\n43D<\/p>\n<\/td>\n
\n52B<\/p>\n<\/td>\n<\/tr>\n
\n\n4B<\/p>\n<\/td>\n
\n9B<\/p>\n<\/td>\n
\n14D<\/p>\n<\/td>\n
\n19D<\/p>\n<\/td>\n
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\n29A<\/p>\n<\/td>\n
\n34C<\/p>\n<\/td>\n
\n39A<\/p>\n<\/td>\n
\n44C<\/p>\n<\/td>\n
\n51D<\/p>\n<\/td>\n<\/tr>\n
\n\n5B<\/p>\n<\/td>\n
\n10D<\/p>\n<\/td>\n
\n15C<\/p>\n<\/td>\n
\n20A<\/p>\n<\/td>\n
\n25A<\/p>\n<\/td>\n
\n30A<\/p>\n<\/td>\n
\n35D<\/p>\n<\/td>\n
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\n45D<\/p>\n<\/td>\n
\n50C<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n v\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 2 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd Cho […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd 2016 - \u0110\u1ec1 s\u1ed1 2<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-thu-thpt-quoc-gia-mon-ly-2016-de-so-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd 2016 - \u0110\u1ec1 s\u1ed1 2\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n v\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 2 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n. 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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
Cho bi\u1ebft h\u1eb1ng s\u1ed1 pl\u0103ng h=6,625.10<\/p>\n
Js ; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng trong ch\u00e2n kh\u00f4ng c= 3.10<\/p>\n
m\/s; \u0111\u1ed9 l\u1edbn \u0111i\u1ec7n t\u00edch nguy\u00ean t\u1ed1 e= 1,6.10<\/p>\n
C; s\u1ed1 Av\u00f4ga\u0111r\u00f4 N\u00ad<\/p>\n
=6,02.10<\/p>\n
mol<\/p>\n
. <\/p>\n
C\u00e2u 1<\/strong>(ID: 96912)<\/strong>:<\/strong>\u0110\u1eb7t \u0111i\u1ec7n \u00e1p u = 120cos(100\u03c0t + \u03c0\/6 ) V v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch c\u00f3 R, L, C m\u1eafc n\u1ed1i ti\u1ebfp th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua m\u1ea1ch l\u00e0 i = cos(100\u03c0t- \u03c0\/6)A, C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch b\u1eb1ng<\/p>\n A.<\/strong>60\u221a3 W B.<\/strong>120 W C.<\/strong>60 W D.<\/strong>30 W<\/p>\n C\u00e2u 2<\/strong>(ID: 96913)<\/strong>:<\/strong>M\u1ed9t v\u1eadt nh\u1ecf dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 4cm v\u00e0 chu k\u00ec 2s. Qu\u00e3ng \u0111\u01b0\u1eddng v\u1eadt \u0111i \u0111\u01b0\u1ee3c trong 4s l\u00e0<\/p>\n A.<\/strong>16 cm B.<\/strong>64 cm C.<\/strong>8 cm D.<\/strong>32 cm<\/p>\n C\u00e2u 3<\/strong>(ID: 96914)<\/strong>:<\/strong>T\u1ea1i O c\u00f3 c\u00e1c ngu\u1ed3n \u00e2m gi\u1ed1ng nhau. N\u1ebfu t\u1ea1i O c\u00f3 4 ngu\u1ed3n th\u00ec t\u1ea1i \u0111i\u1ec3m A thu \u0111\u01b0\u1ee3c \u00e2m c\u00f3 m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m l\u00e0 50dB, n\u1ebfu t\u1ea1i M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a OA thu \u0111\u01b0\u1ee3c \u00e2m c\u00f3 m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m 60dB th\u00ec t\u1ea1i O c\u00f3 bao nhi\u00eau ngu\u1ed3n \u00e2m?<\/p>\n A.<\/strong>10 ngu\u1ed3n B.<\/strong>5 ngu\u1ed3n C.<\/strong>20 ngu\u1ed3n D.<\/strong>15 ngu\u1ed3n<\/p>\n C\u00e2u 4<\/strong>(ID: 96915)<\/strong>:<\/strong>\u0110\u1ec3 kh\u1eed tr\u00f9ng c\u00e1c d\u1ee5ng c\u1ee5 y t\u1ebf, ng\u01b0\u1eddi ta th\u01b0\u1eddng d\u00f9ng lo\u1ea1i tia n\u00e0o sau \u0111\u00e2y<\/p>\n A.<\/strong>Tia X B.<\/strong>Tia t\u1eed ngo\u1ea1i C.<\/strong>Tia h\u1ed3ng ngo\u1ea1i D.<\/strong>Tia Laze<\/p>\n C\u00e2u 5<\/strong>(ID: 96916)<\/strong>:<\/strong>Th\u1ef1c hi\u1ec7n giao thoa tr\u00ean m\u1eb7t ch\u1ea5t l\u1ecfng v\u1edbi hai ngu\u1ed3n S<\/p>\n , S<\/p>\n gi\u1ed1ng nhau. Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng t\u1ea1i S<\/p>\n v\u00e0 S<\/p>\n \u0111\u1ec1u l\u00e0: u=2cos(40\u03c0t)(cm). V\u1eadn t\u1ed1c truy\u1ec1n s\u00f3ng tr\u00ean m\u1eb7t ch\u1ea5t l\u1ecfng l\u00e0 8(m\/s). B\u01b0\u1edbc s\u00f3ng c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o trong c\u00e1c gi\u00e1 tr\u1ecb sau<\/p>\n A.<\/strong>12(cm) B.<\/strong>40(cm) C.<\/strong>16(cm) D.<\/strong>8(cm)<\/p>\n C\u00e2u 6<\/strong>(ID: 96917)<\/strong>:<\/strong>H\u1ea1t nh\u00e2n c\u00f3 \u0111\u1ed9 h\u1ee5t kh\u1ed1i c\u00e0ng l\u1edbn th\u00ec c\u00f3<\/p>\n A.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u00e0ng l\u1edbn B.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u00e0ng nh\u1ecf<\/p>\n C.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft ri\u00eang c\u00e0ng l\u1edbn D.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft ri\u00eang c\u00e0ng nh\u1ecf<\/p>\n C\u00e2u 7<\/strong>(ID: 96918)<\/strong>:<\/strong>Khi n\u00f3i v\u1ec1 \u00e2m thanh, \u0111i\u1ec1u n\u00e0o sau \u0111\u00e2y kh\u00f4ng \u0111\u00fang?<\/p>\n A.<\/strong>T\u1ed1c \u0111\u1ed9 \u00e2m thanh ph\u1ee5 thu\u1ed9c v\u00e0o kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang v\u00e0 t\u00ednh \u0111\u00e0n h\u1ed3i c\u1ee7a m\u00f4i tr\u01b0\u1eddng<\/p>\n B.<\/strong>T\u1ed1c \u0111\u1ed9 \u00e2m thanh kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o nhi\u1ec7t \u0111\u1ed9 m\u00f4i tr\u01b0\u1eddng<\/p>\n C.<\/strong>\u00c2m thanh truy\u1ec1n trong m\u00f4i tr\u01b0\u1eddng r\u1eafn, l\u1ecfng, kh\u00ed<\/p>\n D.<\/strong>\u00c2m thanh l\u00e0 s\u00f3ng \u00e2m c\u00f3 t\u1ea7n s\u1ed1 t\u1eeb 16 Hz \u0111\u1ebfn 20 000 Hz<\/p>\n C\u00e2u 8<\/strong>(ID: 96919)<\/strong>:<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k=2N\/m, v\u1eadt c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m=80g \u0111\u01b0\u1ee3c \u0111\u1eb7t tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang, h\u1ec7 s\u1ed1 ma s\u00e1t tr\u01b0\u1ee3t gi\u1eefa v\u1eadt v\u00e0 m\u1eb7t ngang l\u00e0 0,1. Ban \u0111\u1ea7u k\u00e9o v\u1eadt ra kh\u1ecfi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng m\u1ed9t \u0111o\u1ea1n 10cm r\u1ed3i th\u1ea3 nh\u1eb9. Cho gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g=10m\/s<\/p>\n . Khi v\u1eadt c\u00f3 t\u1ed1c \u0111\u1ed9 l\u1edbn nh\u1ea5t th\u00ec th\u1ebf n\u0103ng \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo b\u1eb1ng<\/p>\n A.<\/strong>1,6 J B.<\/strong>1,6 mJ C.<\/strong>0,16 mJ D.<\/strong>0,16 J<\/p>\n C\u00e2u 9<\/strong>(ID: 96920)<\/strong>:<\/strong>\u0110o\u1ea1n m\u1ea1ch RLC n\u1ed1i ti\u1ebfp \u0111ang c\u00f3 c\u1ed9ng h\u01b0\u1edfng \u0111i\u1ec7n. Ch\u1ecdn k\u1ebft lu\u1eadnsai<\/strong><\/p>\n A.<\/strong>H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ef1c \u0111\u1ea1i<\/p>\n B.<\/strong>u<\/p>\n = u<\/p>\n C.<\/strong>Khi t\u0103ng hay gi\u1ea3m C th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n hi\u1ec7u d\u1ee5ng \u0111\u1ec1u gi\u1ea3m<\/p>\n D.<\/strong>Z = R<\/p>\n C\u00e2u 10<\/strong>(ID: 96921)<\/strong>:<\/strong>Trong th\u00f4ng tin v\u0169 tr\u1ee5 ng\u01b0\u1eddi ta th\u01b0\u1eddng d\u00f9ngs\u00f3ng<\/p>\n A.<\/strong>S\u00f3ng trung v\u00ec b\u1ecb t\u1ea7ng \u0111i\u1ec7n li ph\u1ea3n x\u1ea1 B.<\/strong>V\u00f4 tuy\u1ebfn c\u1ef1c d\u00e0i v\u00ec n\u0103ng l\u01b0\u1ee3ng s\u00f3ng l\u1edbn<\/p>\n C.<\/strong>S\u00f3ng ng\u1eafn v\u00ec b\u1ecb t\u1ea7ng \u0111i\u1ec7n li ph\u1ea3n x\u1ea1 D.<\/strong>V\u00f4 tuy\u1ebfn c\u1ef1c ng\u1eafn v\u00ec c\u00f3 n\u0103ng l\u01b0\u1ee3ng l\u1edbn<\/p>\n C\u00e2u 11<\/strong>(ID: 96922)<\/strong>:<\/strong>M\u1ea1ch ch\u1ecdn s\u00f3ng c\u1ee7a m\u1ed9t m\u00e1y thu thanh g\u1ed3m cu\u1ed9n d\u00e2y thu\u1ea7n c\u1ea3m c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m kh\u00f4ng \u0111\u1ed5i v\u00e0 t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. Khi \u0111i\u1ec7n dung t\u1ee5 \u0111i\u1ec7n l\u00e0 C<\/p>\n th\u00ec b\u01b0\u1edbc s\u00f3ng m\u00e0 m\u00e1y thu \u0111\u01b0\u1ee3c l\u00e0 10 m. T\u1eeb gi\u00e1 tr\u1ecb C<\/p>\n , n\u1ebfu t\u0103ng \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 \u0111i\u1ec7n th\u00eam 1 l\u01b0\u1ee3ng \u2206C th\u00ec m\u00e1y thu \u0111\u01b0\u1ee3c s\u00f3ng c\u00f3 b\u01b0\u1edbc s\u00f3ng l, c\u00f2n n\u1ebfu gi\u1ea3m \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 1 l\u01b0\u1ee3ng 2\u2206C th\u00ec m\u00e1y b\u1eaft \u0111\u01b0\u1ee3c s\u00f3ng c\u00f3 b\u01b0\u1edbc s\u00f3ng l\/2. N\u1ebfu t\u1eeb gi\u00e1 tr\u1ecb C<\/p>\n t\u0103ng \u0111i\u1ec7n dung c\u1ee7a t\u1ee5 \u0111i\u1ec7n th\u00eam 1 l\u01b0\u1ee3ng 9\u2206C th\u00ec m\u00e1y b\u1eaft \u0111\u01b0\u1ee3c s\u00f3ng c\u00f3 b\u01b0\u1edbc s\u00f3ng<\/p>\n A.<\/strong>40 m B.<\/strong>20 m C.<\/strong>4 m D.<\/strong>2 m<\/p>\n<\/p>\n C\u00e2u 12<\/strong>(ID: 96923)<\/strong>:<\/strong>M\u1ed9t m\u1ea1ch \u0111i\u1ec7n AB g\u1ed3m t\u1ee5 C n\u1ed1i ti\u1ebfp v\u1edbi cu\u1ed9n c\u1ea3m thu\u1ea7n L. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 t\u1ea7n s\u1ed1 \u03c9 = 2\/\u221aLC. \u0110i\u1ec3m gi\u1eefa C v\u00e0 L l\u00e0 M. Khi u<\/p>\n =40V th\u00ec u<\/p>\n c\u00f3 gi\u00e1 tr\u1ecb<\/p>\n A.<\/strong>160V B.<\/strong>\u2013 30V C.<\/strong>\u2013 120V D.<\/strong>200V<\/p>\n C\u00e2u 13<\/strong>(ID: 96924)<\/strong>:<\/strong>M\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 chi\u1ec1u d\u00e0i d\u00e2y treo l, dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c g. Khi gi\u1ea3m chi\u1ec1u d\u00e0i con l\u1eafc \u0111i 19% th\u00ec t\u1ea7n s\u1ed1 con l\u1eafc s\u1ebd<\/p>\n A.<\/strong>t\u0103ng 19% B.<\/strong>t\u0103ng 10% C.<\/strong>gi\u1ea3m 10% D.<\/strong>gi\u1ea3m 19%<\/p>\n C\u00e2u 14<\/strong>(ID: 96925)<\/strong>:<\/strong>M\u1ed9t ngu\u1ed3n s\u00e1ng c\u00f3 c\u00f4ng su\u1ea5t P=2W, ph\u00e1t ra \u00e1nh s\u00e1ng c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb=0,597\u00b5m t\u1ecfa ra \u0111\u1ec1u theo m\u1ecdi h\u01b0\u1edbng. N\u1ebfu coi \u0111\u01b0\u1eddng k\u00ednh con ng\u01b0\u01a1i c\u1ee7a m\u1eaft l\u00e0 4mm v\u00e0 m\u1eaft c\u00f2n c\u00f3 th\u1ec3 c\u1ea3m nh\u1eadn \u0111\u01b0\u1ee3c \u00e1nh s\u00e1ng khi t\u1ed1i thi\u1ec3u c\u00f3 80 ph\u00f4t\u00f4n l\u1ecdt v\u00e0o m\u1eaft trong 1s. B\u1ecf qua s\u1ef1 h\u1ea5p th\u1ee5 ph\u00f4t\u00f4n c\u1ee7a m\u00f4i tr\u01b0\u1eddng. Kho\u1ea3ng c\u00e1ch xa ngu\u1ed3n s\u00e1ng nh\u1ea5t m\u00e0 m\u1eaft c\u00f2n tr\u00f4ng th\u1ea5y ngu\u1ed3n l\u00e0<\/p>\n A.<\/strong>27 km B.<\/strong>470 km C.<\/strong>6 km D.<\/strong>274 km<\/p>\n C\u00e2u 15<\/strong>(ID: 96926)<\/strong>:<\/strong>C\u00f3 ba con l\u1eafc \u0111\u01a1n c\u00f9ng chi\u1ec1u d\u00e0i c\u00f9ng kh\u1ed1i l\u01b0\u1ee3ng c\u00f9ng \u0111\u01b0\u1ee3c treo trong \u0111i\u1ec7n tr\u01b0\u1eddng \u0111\u1ec1u c\u00f3 th\u1eb3ng \u0111\u1ee9ng. Con l\u1eafc th\u1ee9 nh\u1ea5t v\u00e0 th\u1ee9 hai t\u00edch \u0111i\u1ec7n q<\/p>\n v\u00e0 q<\/p>\n , con l\u1eafc th\u1ee9 ba kh\u00f4ng t\u00edch \u0111i\u1ec7n. Chu k\u1ef3 dao \u0111\u1ed9ng nh\u1ecf c\u1ee7a ch\u00fang l\u1ea7n l\u01b0\u1ee3t l\u00e0 T<\/p>\n , T<\/p>\n , T<\/p>\n c\u00f3 T<\/p>\n = 1\/3T<\/p>\n ; T<\/p>\n = 5\/3T<\/p>\n . T\u1ec9 s\u1ed1 q<\/p>\n \/q<\/p>\n l\u00e0:<\/p>\n A.<\/strong>8 B.<\/strong>12,5 C.<\/strong>-12,5 D.<\/strong>-8<\/p>\n C\u00e2u 16<\/strong>(ID: 96927)<\/strong>:<\/strong>Th\u1ef1c hi\u1ec7n giao thoa s\u00f3ng v\u1edbi hai ngu\u1ed3n c\u00f9ng pha S<\/p>\n S<\/p>\n c\u00e1ch nhau 20(cm). Bi\u1ebft v\u1eadn t\u1ed1c truy\u1ec1n s\u00f3ng tr\u00ean b\u1ec1 m\u1eb7t ch\u1ea5t l\u1ecfng l\u00e0 40(cm\/s), t\u1ea7n s\u1ed1 c\u1ee7a ngu\u1ed3n l\u00e0 f=8(Hz). H\u1ecfi tr\u00ean \u0111o\u1ea1n S<\/p>\n S<\/p>\n c\u00f3 bao nhi\u00eau \u0111i\u1ec3m dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i nh\u01b0ng ng\u01b0\u1ee3c pha v\u1edbi hai ngu\u1ed3n<\/p>\n A.<\/strong>3 B.<\/strong>5 C.<\/strong>4 D.<\/strong>9<\/p>\n C\u00e2u 17<\/strong>(ID: 96928)<\/strong>:<\/strong>Hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch RLC, cu\u1ed9n d\u00e2y thu\u1ea7n c\u1ea3m, \u0111\u01b0\u1ee3c duy tr\u00ec \u0111i\u1ec7n \u00e1p u<\/p>\n =U<\/p>\n cos\u03c9t (V). Thay \u0111\u1ed5i R, khi \u0111i\u1ec7n tr\u1edf c\u00f3 gi\u00e1 tr\u1ecb R=24(\u03a9) th\u00ec c\u00f4ng su\u1ea5t \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i 300W. H\u1ecfi khi \u0111i\u1ec7n tr\u1edf b\u1eb1ng 18(\u03a9) th\u00ec m\u1ea1ch ti\u00eau th\u1ee5 c\u00f4ng su\u1ea5t b\u1eb1ng bao nhi\u00eau<\/p>\n A.<\/strong>168(W) B.<\/strong>144(W) C.<\/strong>288(W) D.<\/strong>248(W)<\/p>\n 1D<\/p>\n<\/td>\n 6A<\/p>\n<\/td>\n 11B<\/p>\n<\/td>\n 16C<\/p>\n<\/td>\n 21A<\/p>\n<\/td>\n 26C<\/p>\n<\/td>\n 31B<\/p>\n<\/td>\n 36B<\/p>\n<\/td>\n 41C<\/p>\n<\/td>\n 54C<\/p>\n<\/td>\n<\/tr>\n 2D<\/p>\n<\/td>\n 7B<\/p>\n<\/td>\n 12C<\/p>\n<\/td>\n 17A<\/p>\n<\/td>\n 22B<\/p>\n<\/td>\n 27A<\/p>\n<\/td>\n 32B<\/p>\n<\/td>\n 37D<\/p>\n<\/td>\n 42D<\/p>\n<\/td>\n 53C<\/p>\n<\/td>\n<\/tr>\n 3A<\/p>\n<\/td>\n 8B<\/p>\n<\/td>\n 13C<\/p>\n<\/td>\n 18C<\/p>\n<\/td>\n 23B<\/p>\n<\/td>\n 28A<\/p>\n<\/td>\n 33C<\/p>\n<\/td>\n 38C<\/p>\n<\/td>\n 43D<\/p>\n<\/td>\n 52B<\/p>\n<\/td>\n<\/tr>\n 4B<\/p>\n<\/td>\n 9B<\/p>\n<\/td>\n 14D<\/p>\n<\/td>\n 19D<\/p>\n<\/td>\n 24D<\/p>\n<\/td>\n 29A<\/p>\n<\/td>\n 34C<\/p>\n<\/td>\n 39A<\/p>\n<\/td>\n 44C<\/p>\n<\/td>\n 51D<\/p>\n<\/td>\n<\/tr>\n 5B<\/p>\n<\/td>\n 10D<\/p>\n<\/td>\n 15C<\/p>\n<\/td>\n 20A<\/p>\n<\/td>\n 25A<\/p>\n<\/td>\n 30A<\/p>\n<\/td>\n 35D<\/p>\n<\/td>\n 40A<\/p>\n<\/td>\n 45D<\/p>\n<\/td>\n 50C<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n v\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 2 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd Cho […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n<\/p>\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd 2016 – \u0110\u1ec1 s\u1ed1 2<\/strong><\/span><\/h3>\n
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