\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd, thi th\u1eed l\u1ea7n 3 n\u0103m 2016 c\u00f3 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em l\u00e0m b\u00e0i t\u1ed1t h\u01a1n, tham kh\u1ea3o \u0111\u1ec1 thi v\u00e0 \u0111\u00e1p \u00e1n ph\u00eda d\u01b0\u1edbi.<\/strong><\/h2>\n

\n

Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n

Cho bi<\/strong>\u1ebf<\/strong>t:<\/strong>h\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10<\/p>\n

-34<\/dd>\n

J.s; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng trong ch\u00e2n kh\u00f4ng c = 3.10<\/p>\n

8<\/dd>\n

m\/s.<\/p>\n

C\u00e2u 1<\/strong>(ID: 100992) :<\/strong>Dao \u0111\u1ed9ng c\u1ee7a m\u1ed9t v\u1eadt c\u00f3 bi\u00ean \u0111\u1ed9 gi\u1ea3m d\u1ea7n theo th\u1eddi gian g\u1ecdi l\u00e0<\/p>\n

A.<\/strong>dao \u0111\u1ed9ng t\u1ef1 do.                  B.<\/strong>dao \u0111\u1ed9ng t\u1eaft d\u1ea7n.<\/p>\n

C.<\/strong>dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c.              D.<\/strong>dao \u0111\u1ed9ng duy tr\u00ec.<\/p>\n

C\u00e2u 2<\/strong>(ID: 100993):<\/strong>Trong chuy\u1ec3n \u0111\u1ed9ng dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u1ee7a m\u1ed9t v\u1eadt th\u00ec \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o sau \u0111\u00e2y l\u00e0 kh\u00f4ng thay \u0111\u1ed5i theo th\u1eddi gian?<\/p>\n

A.<\/strong>l\u1ef1c k\u00e9o v\u1ec1.        B.<\/strong>gia t\u1ed1c.        C.<\/strong>\u0111\u1ed9ng n\u0103ng.      D.<\/strong>n\u0103ng l\u01b0\u1ee3ng to\u00e0n ph\u1ea7n.<\/p>\n

C\u00e2u<\/strong>3<\/strong>(ID: 100994)<\/strong>:<\/strong>M\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt n\u1eb7ng m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi t\u1ea7n s\u1ed1 f. N\u1ebfu kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt n\u1eb7ng l\u00e0 2m th\u00ec t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0:                        <\/p>\n

A.<\/strong>f .            B.<\/strong>4f.             C.<\/strong>0,5f.         D.<\/strong>2f .<\/p>\n

C\u00e2u<\/strong>4<\/strong>(ID: 100995)<\/strong>:<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u1ee7a m\u1ed9t ch\u1ea5t \u0111i\u1ec3m, \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o sau \u0111\u00e2y dao \u0111\u1ed9ng ng\u01b0\u1ee3c pha v\u1edbi li \u0111\u1ed9?<\/p>\n

A.<\/strong>V\u1eadn t\u1ed1c.                          B.<\/strong>Gia t\u1ed1c.          <\/p>\n

C.<\/strong>Gia t\u1ed1c v\u00e0 l\u1ef1c k\u00e9o v\u1ec1.                     D.<\/strong>L\u1ef1c k\u00e9o v\u1ec1 v\u00e0 v\u1eadn t\u1ed1c.<\/p>\n

C\u00e2u<\/strong>5<\/strong>(ID: 100996)<\/strong>:<\/strong>M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a d\u1ecdc theo tr\u1ee5c Ox v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh a = – 9x. T\u1ea7n s\u1ed1 g\u00f3c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m c\u00f3 gi\u00e1 tr\u1ecb b\u1eb1ng<\/p>\n

A.<\/strong>9 rad\/s.         B.<\/strong>9 rad\/s<\/p>\n

2<\/dd>\n

.       C.<\/strong>3 rad\/s.          D.<\/strong>3 rad\/s<\/p>\n

2<\/dd>\n

.<\/p>\n

C\u00e2u<\/strong>6<\/strong>(ID: 100997)<\/strong>:<\/strong>Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, c\u00f3 \u0111\u1ed9 l\u1ec7ch pha l\u00e0 Dj. N\u1ebfu bi\u00ean \u0111\u1ed9 c\u1ee7a hai dao \u0111\u1ed9ng tr\u00ean tho\u1ea3 h\u1ec7 th\u1ee9c A = A<\/p>\n

1<\/dd>\n

= A<\/p>\n

2<\/dd>\n

v\u00e0 bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p l\u00e0 A th\u00ec Dj  c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o?<\/p>\n

A.<\/strong>\u03c0\/2;                          B.<\/strong>\u03c0\/3                        C.<\/strong>2\u03c0\/3                                  D.<\/strong>\u03c0\/4<\/p>\n

C\u00e2u<\/strong>7<\/strong>(ID: 100998)<\/strong>:<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 d\u1ecdc theo tr\u1ee5c Ox n\u1eb1m ngang, g\u1ed1c O v\u00e0 m\u1ed1c th\u1ebf n\u0103ng \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng. C\u1ee9 sau  th\u00ec \u0111\u1ed9ng n\u0103ng l\u1ea1i b\u1eb1ng th\u1ebf n\u0103ng v\u00e0 trong th\u1eddi gian  v\u1eadt \u0111i \u0111\u01b0\u1ee3c \u0111o\u1ea1n \u0111\u01b0\u1eddng d\u00e0i nh\u1ea5t b\u1eb1ng  Ch\u1ecdnt=0<\/em>l\u00fac v\u1eadt qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng theo chi\u1ec1u d\u01b0\u01a1ng. Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0<\/p>\n

<\/p>\n

C\u00e2u<\/strong>28<\/strong>(ID: 101019)<\/strong>:<\/strong>T\u1ea1i m\u1ed9t \u0111i\u1ec3m M c\u00f3 m\u1ed9t m\u00e1y ph\u00e1t \u0111i\u1ec7n xoay chi\u1ec1u m\u1ed9t pha c\u00f3 c\u00f4ng su\u1ea5t ph\u00e1t \u0111i\u1ec7n v\u00e0  \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng \u1edf hai c\u1ef1c c\u1ee7a m\u00e1y ph\u00e1t \u0111\u1ec1u kh\u00f4ng \u0111\u1ed5i. N\u1ed1i hai c\u1ef1c c\u1ee7a m\u00e1y ph\u00e1t v\u1edbi m\u1ed9t tr\u1ea1m t\u0103ng \u00e1p c\u00f3 h\u1ec7 s\u1ed1 t\u0103ng \u00e1p l\u00e0 k \u0111\u1eb7t t\u1ea1i \u0111\u00f3. T\u1eeb m\u00e1y t\u0103ng \u00e1p \u0111i\u1ec7n n\u0103ng \u0111\u01b0\u1ee3c \u0111\u01b0a l\u00ean d\u00e2y t\u1ea3i cung c\u1ea5p cho m\u1ed9t x\u01b0\u1edfng c\u01a1 kh\u00ed c\u00e1ch xa \u0111i\u1ec3m M. X\u01b0\u1edfng c\u01a1 kh\u00ed c\u00f3 c\u00e1c m\u00e1y ti\u1ec7n c\u00f9ng lo\u1ea1i c\u00f4ng su\u1ea5t khi ho\u1ea1t \u0111\u1ed9ng l\u00e0 nh\u01b0 nhau. Khi h\u1ec7 s\u1ed1 k = 2 th\u00ec \u1edf x\u01b0\u1edfng c\u01a1 kh\u00ed c\u00f3 t\u1ed1i \u0111a 120 m\u00e1y ti\u1ec7n c\u00f9ng ho\u1ea1t \u0111\u1ed9ng. Khi h\u1ec7 s\u1ed1 k = 3 th\u00ec \u1edf x\u01b0\u1edfng c\u01a1 kh\u00ed c\u00f3 t\u1ed1i \u0111a 125 m\u00e1y ti\u1ec7n c\u00f9ng ho\u1ea1t \u0111\u1ed9ng. Do x\u1ea3y ra s\u1ef1 c\u1ed1 \u1edf tr\u1ea1m t\u0103ng \u00e1p, ng\u01b0\u1eddi ta ph\u1ea3i n\u1ed1i tr\u1ef1c ti\u1ebfp d\u00e2y t\u1ea3i \u0111i\u1ec7n v\u00e0o hai c\u1ef1c c\u1ee7a m\u00e1y ph\u00e1t \u0111i\u1ec7n. Coi r\u1eb1ng ch\u1ec9 c\u00f3 hao ph\u00ed tr\u00ean d\u00e2y t\u1ea3i \u0111i\u1ec7n l\u00e0 \u0111\u00e1ng k\u1ec3. \u0110i\u1ec7n \u00e1p v\u00e0 d\u00f2ng \u0111i\u1ec7n tr\u00ean d\u00e2y t\u1ea3i \u0111i\u1ec7n lu\u00f4n c\u00f9ng pha .<\/p>\n

Khi \u0111\u00f3, \u1edf x\u01b0\u1edfng c\u01a1 kh\u00ed c\u00f3 th\u1ec3 cho t\u1ed1i \u0111a s\u1ed1 m\u00e1y ti\u1ec7n c\u00f9ng ho\u1ea1t \u0111\u1ed9ng l\u00e0<\/p>\n

A.<\/strong>93                B.<\/strong>112           C.<\/strong>84             D.<\/strong>108<\/p>\n

C\u00e2u<\/strong>29<\/strong>(ID: 101020)<\/strong>:<\/strong>Nh\u1eadn x\u00e9t n\u00e0o sau \u0111\u00e2y l\u00e0sai<\/strong>khi n\u00f3i v\u1ec1 s\u00f3ng \u0111i\u1ec7n t\u1eeb?<\/p>\n

A. S\u00f3ng \u0111i\u1ec7n t\u1eeb truy\u1ec1n \u0111i \u0111\u01b0\u1ee3c c\u1ea3 trong m\u00f4i tr\u01b0\u1eddng ch\u00e2n kh\u00f4ng v\u00e0 m\u00f4i tr\u01b0\u1eddng v\u1eadt ch\u1ea5t.<\/p>\n

B. S\u00f3ng \u0111i\u1ec7n t\u1eeb l\u00e0 qu\u00e1 tr\u00ecnh lan truy\u1ec1n \u0111i\u1ec7n t\u1eeb tr\u01b0\u1eddng bi\u1ebfn thi\u00ean trong kh\u00f4ng gian theo th\u1eddi gian.<\/p>\n

C. T\u1ed1c \u0111\u1ed9 lan truy\u1ec1n c\u1ee7a s\u00f3ng \u0111i\u1ec7n t\u1eeb l\u00e0 3.10<\/p>\n

8<\/dd>\n

m\/s.<\/p>\n

D. S\u00f3ng \u0111i\u1ec7n t\u1eeb l\u00e0 s\u00f3ng ngang.<\/p>\n

C\u00e2u<\/strong>30<\/strong>(ID: 101021)<\/strong>:<\/strong>M\u1ed9t ch\u1ecdn s\u00f3ng l\u00e0  m\u1ea1ch dao \u0111\u1ed9ng LC c\u00f3 L = 2mH, C = 8pF . M\u1ea1ch tr\u00ean thu \u0111\u01b0\u1ee3c s\u00f3ng v\u00f4 tuy\u1ebfn  n\u00e0o d\u01b0\u1edbi \u0111\u00e2y ?<\/p>\n

A.<\/strong>s\u00f3ng trung,                       B.<\/strong>s\u00f3ng ng\u1eafn,     <\/p>\n

C.<\/strong>s\u00f3ng c\u1ef1c ng\u1eafn ,                       D.<\/strong>s\u00f3ng d\u00e0i ,<\/p>\n

C\u00e2u<\/strong>31<\/strong>(ID: 101022)<\/strong>:<\/strong>M\u1ea1ch dao \u0111\u1ed9ng L, C l\u00ed t\u01b0\u1edfng. Khi C = C<\/p>\n

1<\/dd>\n

th\u00ec t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a m\u1ea1ch l\u00e0 30 kHz v\u00e0 khi C = C<\/p>\n

2<\/dd>\n

th\u00ec t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a m\u1ea1ch l\u00e0 40 kHz. Gh\u00e9p t\u1ee5 \u0111i\u1ec7n \u0111\u1ec3 c\u00f3 C = C<\/p>\n

1<\/dd>\n

+ C<\/p>\n

2<\/dd>\n

th\u00ec t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a m\u1ea1ch l\u00e0<\/p>\n

  A.<\/strong>f = 10 kHz         B.<\/strong>f = 70 kHz              C.<\/strong>f = 50 kHz         D.<\/strong>f = 24 kHz<\/p>\n

C\u00e2u<\/strong>32<\/strong>(ID: 101023)<\/strong>:<\/strong>M\u1ed9t s\u00f3ng \u0111i\u1ec7n t\u1eeb truy\u1ec1n t\u1eeb m\u1ed9t \u0111\u00e0i ph\u00e1t s\u00f3ng \u0111\u1eb7t \u1edf Tr\u01b0\u1eddng Sa \u0111\u1ebfn m\u00e1y thu. T\u1ea1i \u0111i\u1ec3m A c\u00f3 s\u00f3ng truy\u1ec1n v\u1ec1 h\u01b0\u1edbng T\u00e2y, \u1edf m\u1ed9t th\u1eddi \u0111i\u1ec3m n\u00e0o \u0111\u00f3, khi c\u01b0\u1eddng \u0111\u1ed9 \u0111i\u1ec7n tr\u01b0\u1eddng l\u00e0 6 V\/m v\u00e0 \u0111ang c\u00f3 h\u01b0\u1edbng Nam th\u00ec c\u1ea3m \u1ee9ng t\u1eeb l\u00e0 . Bi\u1ebft c\u01b0\u1eddng \u0111\u1ed9 \u0111i\u1ec7n tr\u01b0\u1eddng c\u1ef1c \u0111\u1ea1i l\u00e0 10 V\/m v\u00e0 c\u1ea3m \u1ee9ng t\u1eeb c\u1ef1c \u0111\u1ea1i l\u00e0 0,12 T. C\u1ea3m \u1ee9ng t\u1eeb  c\u00f3 h\u01b0\u1edbng v\u00e0 \u0111\u1ed9 l\u1edbn l\u00e0<\/p>\n

A.<\/strong>th\u1eb3ng \u0111\u1ee9ng xu\u1ed1ng d\u01b0\u1edbi; 0,072 T.            B.<\/strong>th\u1eb3ng \u0111\u1ee9ng l\u00ean tr\u00ean; 0,072 T.<\/p>\n

C.<\/strong>th\u1eb3ng \u0111\u1ee9ng l\u00ean tr\u00ean; 0,06 T.              D.<\/strong>th\u1eb3ng \u0111\u1ee9ng xu\u1ed1ng d\u01b0\u1edbi; 0,06 T<\/p>\n

C\u00e2u<\/strong>33<\/strong>(ID: 101024)<\/strong>:<\/strong>Ch\u1ecdn c\u00e2usai<\/strong>trong c\u00e1c ph\u00e1t bi\u1ec3u sau.<\/p>\n

A.<\/strong>Tia t\u1eed ngo\u1ea1i  c\u00f3 th\u1ec3 ion h\u00f3a ch\u1ea5t kh\u00ed, l\u00e0m ph\u00e1t quang m\u1ed9t s\u1ed1 ch\u1ea5t.<\/p>\n

B.<\/strong>Tia X   \u0111\u01b0\u1ee3c d\u00f9ng \u0111\u1ec3 ch\u1eefa b\u1ec7nh c\u00f2i x\u01b0\u01a1ng<\/p>\n

C.<\/strong>C\u00f3 th\u1ec3 d\u00f9ng tia h\u1ed3ng ngo\u1ea1i \u0111\u1ec3 s\u01b0\u1edfi \u1ea5m v\u00ec n\u00f3 c\u00f3 t\u00e1c d\u1ee5ng nhi\u1ec7t r\u1ea5t m\u1ea1nh.<\/p>\n

D.<\/strong>Tia X c\u00f3 t\u00e1c d\u1ee5ng r\u1ea5t m\u1ea1nh l\u00ean k\u00ednh \u1ea3nh.<\/p>\n

C\u00e2u<\/strong>34<\/strong>(ID: 101025)<\/strong>:<\/strong>Tia t\u1eed ngo\u1ea1i \u0111\u01b0\u1ee3c d\u00f9ng<\/p>\n

A.<\/strong>\u0111\u1ec3 t\u00ecm v\u1ebft n\u1ee9t tr\u00ean b\u1ec1 m\u1eb7t s\u1ea3n ph\u1ea9m b\u1eb1ng kim lo\u1ea1i.   <\/p>\n

B.<\/strong>\u0111\u1ec3 t\u00ecm khuy\u1ebft t\u1eadt b\u00ean trong s\u1ea3n ph\u1ea9m b\u1eb1ng kim lo\u1ea1i.<\/p>\n

C.<\/strong>trong y t\u1ebf \u0111\u1ec3 ch\u1ee5p \u0111i\u1ec7n, chi\u1ebfu \u0111i\u1ec7n.            <\/p>\n

D<\/strong>. \u0111\u1ec3 ch\u1ee5p \u1ea3nh b\u1ec1 m\u1eb7t Tr\u00e1i \u0110\u1ea5t t\u1eeb v\u1ec7 tinh.<\/p>\n

C\u00e2u<\/strong>35<\/strong>(ID: 101026)<\/strong>:<\/strong>Ch\u1ecdn c\u00e2u\u0111\u00fang<\/strong>khi n\u00f3i v\u1ec1 \u00e1nh s\u00e1ng?<\/p>\n

A.<\/strong>Ch\u1ec9 nh\u1eefng \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y m\u1edbi c\u00f3 kh\u1ea3 n\u0103ng t\u00e1n s\u1eafc, giao thoa.<\/p>\n

B.<\/strong>Ph\u00f4ton c\u00f3 b\u01b0\u1edbc s\u00f3ng c\u00e0ng d\u00e0i th\u00ec c\u00f3 n\u0103ng l\u01b0\u1ee3ng c\u00e0ng l\u1edbn.<\/p>\n

C.<\/strong>\u00c1nh s\u00e1ng c\u00f3 b\u01b0\u1edbc s\u00f3ng ng\u1eafn th\u1ec3 hi\u1ec7n r\u00f5 t\u00ednh ch\u1ea5t h\u1ea1t, \u00e1nh s\u00e1ng c\u00f3 b\u01b0\u1edbc s\u00f3ng d\u00e0i th\u1ec3 hi\u1ec7n r\u00f5 t\u00ednh ch\u1ea5t s\u00f3ng.<\/p>\n

D.<\/strong>Tia h\u1ed3ng ngo\u1ea1i kh\u00f4ng c\u00f3 t\u00ednh h\u1ea1t , tia t\u1eed ngo\u1ea1i kh\u00f4ng c\u00f3 t\u00ednh ch\u1ea5t s\u00f3ng.<\/p>\n

C\u00e2u<\/strong>36<\/strong>(ID: 101027)<\/strong>:<\/strong>Khi chi\u1ebfu ch\u00f9m s\u00e1ng song song g\u1ed3m hai tia \u0111\u1ecf v\u00e0 t\u00edm t\u1edbi song song v\u1edbi \u0111\u00e1y c\u1ee7a l\u0103ng k\u00ednh th\u00ec khi qua l\u0103ng k\u00ednh n\u00e0y<\/p>\n

A.<\/strong>hai tia tr\u00f9ng nhau.             B.<\/strong>tia \u0111\u1ecf l\u1ec7ch nhi\u1ec1u h\u01a1n tia t\u00edm.
C.<\/strong>tia t\u00edm l\u1ec7ch nhi\u1ec1u h\u01a1n tia \u0111\u1ecf.        D.<\/strong>hai tia l\u1ec7ch nh\u01b0 nhau.<\/p>\n

C\u00e2u<\/strong>37<\/strong>(ID: 101028)<\/strong>:<\/strong>Trong th\u00ed nghi\u1ec7m giao thoa \u00e1nh s\u00e1ng d\u00f9ng hai khe Y-\u00e2ng, bi\u1ebft kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe l\u00e0 a = 0,35mm, kho\u1ea3ng c\u00e1ch D = 1,5m v\u00e0 b\u01b0\u1edbc s\u00f3ng \u03bb = 0,7\u00b5m. Kho\u1ea3ng c\u00e1ch gi\u1eefa v\u00e2n s\u00e1ng v\u00e0 v\u00e2n t\u1ed1i c\u1ea1nh nhau l\u00e0<\/p>\n

A.<\/strong>4mm.               B.<\/strong>3mm.            C.<\/strong>1,5mm.            D.<\/strong>2mm.<\/p>\n

C\u00e2u<\/strong>38<\/strong>(ID: 101029)<\/strong>:<\/strong>Trong th\u00ed nghi\u1ec7m v\u1ec1 giao thoa \u00e1nh s\u00e1ng b\u01b0\u1edbc s\u00f3ng \u00e1nh s\u00e1ng b\u1eb1ng \u03bb, kho\u1ea3ng c\u00e1ch t\u1eeb hai khe \u0111\u1ebfn m\u00e0n l\u00e0 D.Bi\u1ebft khi kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe l\u00e0 a+2\u0394a th\u00ec kho\u1ea3ng v\u00e2n b\u1eb1ng 3mm, khi kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe l\u00e0 a-3\u0394a th\u00ec kho\u1ea3ng v\u00e2n l\u00e0 4mm. Khi kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe l\u00e0 a th\u00ec kho\u1ea3ng v\u00e2n b\u1eb1ng<\/p>\n

A.<\/strong>10\/3 mm         B.<\/strong>16\/5 mm        C.<\/strong>18\/5 mm        D.<\/strong>7\/2 mm.<\/p>\n

C\u00e2u<\/strong>39<\/strong>(ID: 101030)<\/strong>:<\/strong>Hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n trong l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng gi\u1ea3i ph\u00f3ng \u00ealectron kh\u1ecfi<\/p>\n

A.<\/strong>kim lo\u1ea1i b\u1eb1ng \u00e1nh s\u00e1ng th\u00edch h\u1ee3p.                  <\/p>\n

B.<\/strong>m\u1ed9t ch\u1ea5t b\u00e1n d\u1eabn b\u1eb1ng \u00e1nh s\u00e1ng th\u00edch h\u1ee3p.<\/p>\n

C.<\/strong>m\u1ed1i li\u00ean k\u1ebft v\u1edbi nguy\u00ean t\u1eed kim lo\u1ea1i b\u1eb1ng \u00e1nh s\u00e1ng th\u00edch h\u1ee3p.   <\/p>\n

D.<\/strong>m\u1ed1i li\u00ean k\u1ebft b\u00ean trong ch\u1ea5t b\u00e1n d\u1eabn b\u1eb1ng \u00e1nh s\u00e1ng th\u00edch h\u1ee3p.<\/p>\n

C\u00e2u<\/strong>40<\/strong>(ID: 101031)<\/strong>:<\/strong>D\u00f9ng thuy\u1ebft l\u01b0\u1ee3ng t\u1eed \u00e1nh s\u00e1ng kh\u00f4ng gi\u1ea3i th\u00edch \u0111\u01b0\u1ee3c<\/p>\n

A.<\/strong>nguy\u00ean t\u1eafc ho\u1ea1t \u0111\u1ed9ng c\u1ee7a pin quang \u0111i\u1ec7n.      B.<\/strong>hi\u1ec7n t\u01b0\u1ee3ng quang – ph\u00e1t quang.<\/p>\n

C.<\/strong>hi\u1ec7n t\u01b0\u1ee3ng giao thoa \u00e1nh s\u00e1ng.           D.<\/strong>hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n ngo\u00e0i<\/p>\n

C\u00e2u<\/strong>41<\/strong>(ID: 101032)<\/strong>:<\/strong>Trong hi\u1ec7n t\u01b0\u1ee3ng quang \u2013 ph\u00e1t quang, n\u1ebfu \u00e1nh s\u00e1ng ph\u00e1t quang l\u00e0 \u00e1nh s\u00e1ng m\u00e0u l\u1ee5c th\u00ec \u00e1nh s\u00e1ng k\u00edch th\u00edchkh\u00f4ng th\u1ec3<\/strong>l\u00e0 \u00e1nh s\u00e1ng n\u00e0o sau \u0111\u00e2y?<\/p>\n

A.<\/strong>\u00c1nh s\u00e1ng cam.    B.<\/strong>\u00c1nh s\u00e1ng ch\u00e0m.         C.<\/strong>\u00c1nh s\u00e1ng lam.     D.<\/strong>\u00c1nh s\u00e1ng t\u00edm.<\/p>\n

C\u00e2u<\/strong>42<\/strong>(ID: 101033)<\/strong>:<\/strong>Bi\u1ebft c\u00f4ng tho\u00e1t c\u1ee7a \u00ealectron kh\u1ecfi m\u1ed9t kim lo\u1ea1i l\u00e0 4,14 eV. Gi\u1edbi h\u1ea1n quang \u0111i\u1ec7n c\u1ee7a kim lo\u1ea1i \u0111\u00f3 l\u00e0<\/p>\n

A.<\/strong>0,50 mm.      B.<\/strong>0,26 mm.            C.<\/strong>0,30 mm.        D.<\/strong>0,35 mm.<\/p>\n

C\u00e2u<\/strong>43<\/strong>(ID: 101034)<\/strong>:<\/strong>C\u00e1c m\u1ee9c n\u0103ng l\u01b0\u1ee3ng c\u1ee7a c\u00e1c tr\u1ea1ng th\u00e1i d\u1eebng c\u1ee7a nguy\u00ean t\u1eed hi\u0111r\u00f4 E<\/p>\n

n<\/dd>\n

= -eV (n = 1, 2, 3, \u2026). T\u1eeb tr\u1ea1ng th\u00e1i c\u01a1 b\u1ea3n, nguy\u00ean t\u1eed hi\u0111r\u00f4 h\u1ea5p th\u1ee5 ph\u00f4t\u00f4n th\u00edch h\u1ee3p n\u00ean b\u00e1n k\u00ednh qu\u1ef9 \u0111\u1ea1o d\u1eebng t\u0103ng 16 l\u1ea7n. Khi \u0111\u00f3 b\u01b0\u1edbc s\u00f3ng nh\u1ecf nh\u1ea5t c\u1ee7a b\u1ee9c x\u1ea1 do nguy\u00ean t\u1eed hi\u0111r\u00f4 ph\u00e1t ra l\u00e0<\/p>\n

A<\/strong>. 0,0972 mm.      B.<\/strong>0,9523 mm.          C.<\/strong>0,5520 mm.          D.<\/strong>0,0952 mm. <\/p>\n

C\u00e2u<\/strong>44<\/strong>(ID: 101035)<\/strong>:<\/strong>H\u1ea1t nh\u00e2n nguy\u00ean t\u1eed c\u1ea5u t\u1ea1o b\u1edfi c\u00e1c h\u1ea1t<\/p>\n

A.<\/strong>n\u01a1tron v\u00e0 \u00ealectron.                B.<\/strong>pr\u00f4t\u00f4n, n\u01a1tron.    <\/p>\n

C.<\/strong>pr\u00f4t\u00f4n, n\u01a1tron v\u00e0 \u00ealectron.             D.<\/strong>pr\u00f4t\u00f4n v\u00e0 \u00ealectron.<\/p>\n

C\u00e2u<\/strong>45<\/strong>(ID: 101036)<\/strong>:<\/strong>S\u1ef1 ph\u00f3ng x\u1ea1, s\u1ef1 ph\u00e2n h\u1ea1ch v\u00e0 ph\u1ea3n \u1ee9ng nhi\u1ec7t h\u1ea1ch gi\u1ed1ng nhau \u1edf nh\u1eefng \u0111i\u1ec3m n\u00e0o sau \u0111\u00e2y?<\/p>\n

A.<\/strong>\u0110\u1ec1u l\u00e0 c\u00e1c ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n x\u1ea3y ra m\u1ed9t c\u00e1ch t\u1ef1 ph\u00e1t .<\/p>\n

B.<\/strong>\u0110\u1ec1u l\u00e0 s\u1ef1 ph\u00e2n t\u00e1ch m\u1ed9t h\u1ea1t nh\u00e2n ra th\u00e0nh c\u00e1c h\u1ea1t nh\u00e2n trung b\u00ecnh.<\/p>\n

C.<\/strong>T\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a c\u00e1c h\u1ea1t sau ph\u1ea3n \u1ee9ng nh\u1ecf h\u01a1n t\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a c\u00e1c h\u1ea1t tr\u01b0\u1edbc ph\u1ea3n \u1ee9ng.<\/p>\n

D.<\/strong>T\u1ed5ng \u0111\u1ed9 h\u1ee5t kh\u1ed1i c\u1ee7a c\u00e1c h\u1ea1t sau ph\u1ea3n \u1ee9ng nh\u1ecf h\u01a1n t\u1ed5ng \u0111\u1ed9 h\u1ee5t kh\u1ed1i c\u1ee7a c\u00e1c h\u1ea1t tr\u01b0\u1edbc ph\u1ea3n \u1ee9ng.<\/p>\n

C\u00e2u<\/strong>46<\/strong>(ID: 101037)<\/strong>:<\/strong>\u0110\u1ec3 so s\u00e1nh \u0111\u1ed9 b\u1ec1n v\u1eefng gi\u1eefa hai h\u1ea1t nh\u00e2n, ch\u00fang ta d\u1ef1a v\u00e0o<\/p>\n

A.<\/strong>n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u1ee7a h\u1ea1t nh\u00e2n.               <\/p>\n

B.<\/strong>\u0111\u1ed9 h\u1ee5t kh\u1ed1i c\u1ee7a h\u1ea1t nh\u00e2n.<\/p>\n

C.<\/strong>s\u1ed1 kh\u1ed1i A c\u1ee7a h\u1ea1t nh\u00e2n.              <\/p>\n

D.<\/strong>t\u1ec9 s\u1ed1 gi\u1eefa \u0111\u1ed9 h\u1ee5t kh\u1ed1i v\u00e0 s\u1ed1 kh\u1ed1i c\u1ee7a h\u1ea1t nh\u00e2n.<\/p>\n

C\u00e2u<\/strong>47<\/strong>(ID: 101038)<\/strong>:<\/strong>H\u1ea1t nh\u00e2n X trong ph\u1ea3n \u1ee9ng h\u1ea1t nh\u00e2n:  + a \u00ae  + X l\u00e0<\/p>\n

A.<\/strong>tri-ti.            B<\/strong>. n\u01a1tron.         C.<\/strong>\u0111\u01a1-te-ri.             D.<\/strong>pr\u00f4t\u00f4n.<\/p>\n

C\u00e2u<\/strong>48<\/strong>(ID: 101039)<\/strong>:<\/strong>Cho ph\u1ea3n \u1ee9ng: . Bi\u1ebft m<\/p>\n

p<\/dd>\n

= 1,0073u; m<\/p>\n

He<\/dd>\n

= 4,0015u; m<\/p>\n

Li<\/dd>\n

= 7,0144u. Cho 1u.c<\/p>\n

2<\/dd>\n

= 931,5 MeV, N<\/p>\n

A<\/dd>\n

= 6,02.10<\/p>\n

23<\/dd>\n

mol<\/p>\n

-1<\/dd>\n

.  N\u0103ng l\u01b0\u1ee3ng to\u1ea3 ra khi 2 gam He \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh c\u1ee1 b\u1eb1ng<\/p>\n

 A.<\/strong>17,42MeV         B.<\/strong>5,25.10<\/p>\n

24<\/dd>\n

MeV     C.<\/strong>1,31.10<\/p>\n

24<\/dd>\n

MeV           D.<\/strong>2,62.10<\/p>\n

24<\/dd>\n

MeV<\/p>\n

C\u00e2u<\/strong>49<\/strong>(ID: 101040)<\/strong>:<\/strong>H\u1ea1t nh\u00e2n urani U234 \u0111\u1ee9ng y\u00ean, ph\u00e2n r\u00e3 a v\u00e0 bi\u1ebfn th\u00e0nh h\u1ea1t nh\u00e2n th\u00f4ri (Th230). Coi kh\u1ed1i l\u01b0\u1ee3ng x\u1ea5p x\u1ec9 b\u1eb1ng s\u1ed1 kh\u1ed1i. So v\u1edbi n\u0103ng l\u01b0\u1ee3ng ph\u00e2n r\u00e3 1 h\u1ea1t U234 th\u00ec \u0111\u1ed9ng n\u0103ng c\u1ee7a h\u1ea1t a chi\u1ebfm c\u1ee1 kho\u1ea3ng<\/p>\n

A.<\/strong>1,68%           B.<\/strong>98,3%          C.<\/strong>16,8%         D.<\/strong>96,7%<\/p>\n

C\u00e2u<\/strong>50<\/strong>(ID: 101041)<\/strong>:<\/strong>Urani<\/p>\n

238<\/dd>\n

U ph\u00e2n r\u00e3 th\u00e0nh ch\u00ec<\/p>\n

206<\/dd>\n

Pb v\u1edbi chu k\u1ef3 b\u00e1n r\u00e3 T = 4,47.10<\/p>\n

9<\/dd>\n

n\u0103m. M\u1ed9t kh\u1ed1i \u0111\u00e1 \u0111\u01b0\u1ee3c ph\u00e1t hi\u1ec7n c\u00f3 ch\u1ee9a 46,97 (mg) ch\u1ea5t<\/p>\n

238<\/dd>\n

U v\u00e0 2,135 (mg) ch\u1ea5t<\/p>\n

206<\/dd>\n

Pb. Gi\u1ea3 s\u1eed l\u00fac kh\u1ed1i \u0111\u00e1 m\u1edbi h\u00ecnh th\u00e0nh kh\u00f4ng ch\u1ee9a nguy\u00ean t\u1ed1 ch\u00ec v\u00e0 t\u1ea5t c\u1ea3 l\u01b0\u1ee3ng ch\u00ec c\u00f3 m\u1eb7t trong \u0111\u00f3 \u0111\u1ec1u l\u00e0 s\u1ea3n ph\u1ea9m ph\u00e2n r\u00e3 c\u1ee7a<\/p>\n

238<\/dd>\n

U. Tu\u1ed5i c\u1ee7a kh\u1ed1i \u0111\u00e1 hi\u1ec7n nay l\u00e0<\/p>\n

A.<\/strong>2,5.10<\/p>\n

6<\/dd>\n

n\u0103m.       B.<\/strong>3,3.10<\/p>\n

8<\/dd>\n

n\u0103m.       C.<\/strong>3,5.10<\/p>\n

7<\/dd>\n

n\u0103m      D.<\/strong>6.10<\/p>\n

9<\/dd>\n

n\u0103m.<\/p>\n

\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd n\u0103m 2016 – \u0110\u1ec1 3<\/strong><\/span><\/h3>\n\n\n\n\n\n\n\n

\n 1B<\/strong><\/p>\n<\/td>\n	\n 2D<\/strong><\/p>\n<\/td>\n	\n 3A<\/strong><\/p>\n<\/td>\n	\n 4C<\/strong><\/p>\n<\/td>\n	\n 5C<\/strong><\/p>\n<\/td>\n	\n 6C<\/strong><\/p>\n<\/td>\n	\n 7D<\/strong><\/p>\n<\/td>\n	\n 8C<\/strong><\/p>\n<\/td>\n	\n 9B<\/strong><\/p>\n<\/td>\n	\n 10A<\/strong><\/p>\n<\/td>\n<\/tr>\n
\n 11D<\/strong><\/p>\n<\/td>\n	\n 12C<\/strong><\/p>\n<\/td>\n	\n 13A<\/strong><\/p>\n<\/td>\n	\n 14D<\/strong><\/p>\n<\/td>\n	\n 15A<\/strong><\/p>\n<\/td>\n	\n 16D<\/strong><\/p>\n<\/td>\n	\n 17B<\/strong><\/p>\n<\/td>\n	\n 18A<\/strong><\/p>\n<\/td>\n	\n 19D<\/strong><\/p>\n<\/td>\n	\n 20C<\/strong><\/p>\n<\/td>\n<\/tr>\n
\n 21C<\/strong><\/p>\n<\/td>\n	\n 22C<\/strong><\/p>\n<\/td>\n	\n 23C<\/strong><\/p>\n<\/td>\n	\n 24C<\/strong><\/p>\n<\/td>\n	\n 25A<\/strong><\/p>\n<\/td>\n	\n 26A<\/strong><\/p>\n<\/td>\n	\n 27A<\/strong><\/p>\n<\/td>\n	\n 28A<\/strong><\/p>\n<\/td>\n	\n 29C<\/strong><\/p>\n<\/td>\n	\n 30A<\/strong><\/p>\n<\/td>\n<\/tr>\n
\n 31D<\/strong><\/p>\n<\/td>\n	\n 32C<\/strong><\/p>\n<\/td>\n	\n 33B<\/strong><\/p>\n<\/td>\n	\n 34A<\/strong><\/p>\n<\/td>\n	\n 35C<\/strong><\/p>\n<\/td>\n	\n 36C<\/strong><\/p>\n<\/td>\n	\n 37C<\/strong><\/p>\n<\/td>\n	\n 38A<\/strong><\/p>\n<\/td>\n	\n 39D<\/strong><\/p>\n<\/td>\n	\n 40C<\/strong><\/p>\n<\/td>\n<\/tr>\n
\n 41A<\/strong><\/p>\n<\/td>\n	\n 42C<\/strong><\/p>\n<\/td>\n	\n 43A<\/strong><\/p>\n<\/td>\n	\n 44B<\/strong><\/p>\n<\/td>\n	\n 45C<\/strong><\/p>\n<\/td>\n	\n 46D<\/strong><\/p>\n<\/td>\n	\n 47B<\/strong><\/p>\n<\/td>\n	\n 48D<\/strong><\/p>\n<\/td>\n	\n 49B<\/strong><\/p>\n<\/td>\n	\n 50B<\/strong><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n <\/strong><\/span><\/p>\n <\/strong><\/span><\/p>\n <\/strong><\/span><\/p>\n L\u1eddi gi\u1ea3i chi ti\u1ebft c\u00e1c em xem trong file \u0111\u00ednh k\u00e8m.<\/p>\n<\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd, thi th\u1eed l\u1ea7n 3 n\u0103m 2016 c\u00f3 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em l\u00e0m b\u00e0i t\u1ed1t h\u01a1n, tham kh\u1ea3o \u0111\u1ec1 thi v\u00e0 \u0111\u00e1p \u00e1n ph\u00eda d\u01b0\u1edbi. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd Cho bi\u1ebft:h\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10 -34 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n