\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u01b0\u1ee3c t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n th\u1ee9 6 theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T, c\u00e1c em tham kh\u1ea3o \u0111\u1ec1 thi d\u01b0\u1edbi \u0111\u00e2y.<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\n\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 6<\/strong><\/span><\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/61_1.png\")
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C\u00e2u 2:<\/strong>(ID:85672)<\/strong>V\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 v\u1edbi t\u1ea7n s\u1ed1 2,5 Hz. T\u1ea1i m\u1ed9t th\u1eddi \u0111i\u1ec3m v\u1eadt c\u00f3 \u0111\u1ed9ng n\u0103ng b\u1eb1ng m\u1ed9t n\u1eeda c\u01a1 n\u0103ng th\u00ec sau th\u1eddi \u0111i\u1ec3m \u0111\u00f3 0,05 s \u0111\u1ed9ng n\u0103ng c\u1ee7a v\u1eadt<\/p>\nA.<\/strong>b\u1eb1ng hai l\u1ea7n th\u1ebf n\u0103ng. B.<\/strong>b\u1eb1ng th\u1ebf n\u0103ng<\/p>\nC.<\/strong>c\u00f3 th\u1ec3 b\u1eb1ng kh\u00f4ng ho\u1eb7c b\u1eb1ng c\u01a1 n\u0103ng. D.<\/strong>b\u1eb1ng m\u1ed9t n\u1eeda th\u1ebf n\u0103ng.<\/p>\nC\u00e2u 3:<\/strong>(ID:85673)<\/strong> Hai \u0111i\u1ec3m M, N n\u1eb1m c\u00f9ng m\u1ed9t ph\u00eda c\u1ee7a ngu\u1ed3n \u00e2m \u0111\u1eb7t t\u1ea1i A, tr\u00ean c\u00f9ng m\u1ed9t ph\u01b0\u01a1ng truy\u1ec1n \u00e2m. Bi\u1ebft m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i M v\u00e0 N l\u1ea7n l\u01b0\u1ee3t l\u00e0 L<\/p>\nM<\/dd>\n=30 dB v\u00e0 L<\/p>\n
N<\/dd>\n=10 dB. Coi nh\u01b0 c\u00f4ng su\u1ea5t truy\u1ec1n \u00e2m kh\u00f4ng \u0111\u1ed5i v\u00e0 \u00e2m truy\u1ec1n \u0111i c\u00f3 t\u00ednh \u0111\u1eb3ng h\u01b0\u1edbng. N\u1ebfu ngu\u1ed3n \u00e2m \u0111\u00f3 d\u1eb7t t\u1ea1i \u0111i\u1ec3m M th\u00ec m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i N l\u00e0<\/p>\n
A.<\/strong>9 dB. B.<\/strong>12 dB. C.<\/strong>7 dB. D.<\/strong>11 dB.<\/p>\nC\u00e2u 4:<\/strong>(ID:85675)<\/strong>M\u1ed9t d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u \u0111i qua \u0111i\u1ec7n tr\u1edf 20 trong th\u1eddi gian 5 ph\u00fat th\u00ec nhi\u1ec7t l\u01b0\u1ee3ng to\u1ea3 ra l\u00e0 Q = 18 kJ. C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng c\u1ee7a d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u l\u00e0<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/62_1.png\")
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C\u00e2u 5: (ID:85676)<\/strong>\u0110\u1ed1i v\u1edbi s\u00f3ng c\u01a1 h\u1ecdc, t\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng …<\/p>\nA.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 s\u00f3ng.<\/p>\nB.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o b\u01b0\u1edbc s\u00f3ng v\u00e0 b\u1ea3n ch\u1ea5t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n s\u00f3ng.<\/p>\nC.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o b\u1ea3n ch\u1ea5t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n s\u00f3ng .<\/p>\nD.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o chu k\u1ef3, b\u01b0\u1edbc s\u00f3ng v\u00e0 b\u1ea3n ch\u1ea5t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n s\u00f3ng.<\/p>\nC\u00e2u 6:<\/strong>(ID:85677)<\/strong> Trong th\u00ed nghi\u1ec7m giao thoa \u00e1nh s\u00e1ng v\u1edbi khe i\u00e2ng, kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe b\u1eb1ng 1mm, kho\u1ea3ng c\u00e1ch t\u1eeb hai khe \u0111\u1ebfn m\u00e0n quan s\u00e1t D = 2 m. Chi\u1ebfu v\u00e0o hai khe \u0111\u1ed3ng th\u1eddi 2 b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb<\/p>\n1<\/dd>\n= 0,6 \u00b5m v\u00e0 b\u01b0\u1edbc s\u00f3ng \u03bb<\/p>\n
2<\/dd>\nch\u01b0a bi\u1ebft. Trong kho\u1ea3ng r\u1ed9ng L = 2,4 cm tr\u00ean m\u00e0n \u0111\u1ebfm \u0111\u01b0\u1ee3c 33 v\u1ea1ch s\u00e1ng, trong \u0111\u00f3 c\u00f3 5 v\u1ea1ch l\u00e0 k\u1ebft qu\u1ea3 tr\u00f9ng nhau c\u1ee7a hai h\u1ec7 v\u00e2n. Bi\u1ebft 2 trong 5 v\u1ea1ch tr\u00f9ng nhau n\u1eb1m \u1edf ngo\u00e0i c\u00f9ng c\u1ee7a kho\u1ea3ng r\u1ed9ng n\u00f3i tr\u00ean. B\u01b0\u1edbc s\u00f3ng \u03bb<\/p>\n
2<\/dd>\nb\u1eb1ng<\/p>\n
A.<\/strong>0,45 \u00b5m. B.<\/strong>0,55 \u00b5m. C.<\/strong>0,75 \u00b5m. D.<\/strong>0,65 \u00b5m.<\/p>\nC\u00e2u 7:<\/strong>(ID:85678)<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m v\u1eadt n\u1eb7ng c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m v\u00e0 l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c b\u1eb1ng 5\u03c0 (rad\/s) \u1edf n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = 10 m\/s<\/p>\n2<\/dd>\n, l\u1ea5y \u03c0<\/p>\n
2<\/dd>\n= 10. Bi\u1ebft gia t\u1ed1c c\u1ef1c \u0111\u1ea1i c\u1ee7a v\u1eadt n\u1eb7ng a<\/p>\n
max<\/dd>\n> g. Trong th\u1eddi gian m\u1ed9t chu k\u00ec dao \u0111\u1ed9ng, th\u1eddi gian l\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo v\u00e0 l\u1ef1c k\u00e9o v\u1ec1 t\u00e1c d\u1ee5ng v\u00e0o v\u1eadt c\u00f9ng h\u01b0\u1edbng l\u00e0 t<\/p>\n
1<\/dd>\n, th\u1eddi gian 2 l\u1ef1c \u0111\u00f3 ng\u01b0\u1ee3c h\u01b0\u1edbng l\u00e0 t<\/p>\n
2<\/dd>\n. Bi\u1ebft t<\/p>\n
1<\/dd>\n= 5t<\/p>\n
2<\/dd>\n. Trong m\u1ed9t chu k\u00ec th\u1eddi gian l\u00f2 xo b\u1ecb n\u00e9n l\u00e0<\/p>\n
A.<\/strong>1\/15 s. B.<\/strong>2\/15 s. C.<\/strong>0,1 s. D.<\/strong>0,15 s.<\/p>\nC\u00e2u 8:<\/strong>(ID:85679)<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo n\u1eb1m ngang g\u1ed3m v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng 200 gam, l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng 10 N\/m, h\u1ec7 s\u1ed1 ma s\u00e1t tr\u01b0\u1ee3t gi\u1eefa v\u1eadt v\u00e0 m\u1eb7t ph\u1eb3ng ngang l\u00e0 0,1. Ban \u0111\u1ea7u v\u1eadt \u0111\u01b0\u1ee3c gi\u1eef \u1edf v\u1ecb tr\u00ed l\u00f2 xo gi\u00e3n 10 cm, r\u1ed3i th\u1ea3 nh\u1eb9 \u0111\u1ec3 con l\u1eafc dao \u0111\u1ed9ng t\u1eaft d\u1ea7n, l\u1ea5y . Trong kho\u1ea3ng th\u1eddi gian k\u1ec3 t\u1eeb l\u00fac th\u1ea3 cho \u0111\u1ebfn khi t\u1ed1c \u0111\u1ed9 c\u1ee7a v\u1eadt b\u1eaft \u0111\u1ea7u gi\u1ea3m th\u00ec \u0111\u1ed9 gi\u1ea3m th\u1ebf n\u0103ng c\u1ee7a con l\u1eafc l\u00e0:<\/p>\nA.<\/strong>48 mJ. B.<\/strong>50 mJ. C.<\/strong>32 mJ. D.<\/strong>20 mJ.<\/p>\nC\u00e2u 9:<\/strong>(ID:85680)<\/strong>T\u1ea1i \u0111i\u1ec3m O tr\u00ean m\u1eb7t n\u01b0\u1edbc c\u00f3 m\u1ed9t ngu\u1ed3n ph\u00e1t s\u00f3ng theo nh\u1eefng v\u00f2ng tr\u00f2n \u0111\u1ed3ng t\u00e2m v\u1edbi b\u01b0\u1edbc s\u00f3ng \u03bb = 8 cm. G\u1ecdi (C<\/p>\n1<\/dd>\n), (C<\/p>\n
2<\/dd>\n)<\/strong>l\u1ea7n l\u01b0\u1ee3t l\u00e0 hai \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m O b\u00e1n k\u00ednh R<\/p>\n1<\/dd>\n= 10 cm v\u00e0 R<\/p>\n
2<\/dd>\n= 20 cm. G\u1ecdi M l\u00e0 m\u1ed9t \u0111i\u1ec3m b\u1ea5t k\u00ec tr\u00ean (C<\/p>\n
1<\/dd>\n). G\u1ecdi A, B, C, D l\u00e0 4 \u0111i\u1ec3m thu\u1ed9c \u0111\u01b0\u1eddng tr\u00f2n (C<\/p>\n
2<\/dd>\n) sao cho AB v\u00e0 CD \u0111\u1ec1u \u0111i qua M v\u00e0 tr\u00ean hai \u0111o\u1ea1n th\u1eb3ng \u0111\u00f3 \u0111\u1ec1u c\u00f3 5 \u0111i\u1ec3m dao \u0111\u1ed9ng ng\u01b0\u1ee3c pha v\u1edbi ngu\u1ed3n. S\u1ed1 \u0111i\u1ec3m t\u1ed1i \u0111a<\/strong> dao \u0111\u1ed9ng vu\u00f4ng pha v\u1edbi ngu\u1ed3n tr\u00ean \u0111o\u1ea1n AC l\u00e0<\/p>\nA.<\/strong> 6. B.<\/strong> 2. C.<\/strong> 8. D.<\/strong> 4.<\/p>\n ![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/63_1.png\")
<\/strong><\/p>\nC\u00e2u 11:<\/strong>(ID:85683)<\/strong>Cho \u0111o\u1ea1n m\u1ea1ch xoay chi\u1ec1u AB g\u1ed3m cu\u1ed9n d\u00e2y, t\u1ee5 \u0111i\u1ec7n C v\u00e0 \u0111i\u1ec7n tr\u1edf thu\u1ea7n R m\u1eafc n\u1ed1i ti\u1ebfp theo th\u1ee9 t\u1ef1 \u0111\u00f3. M l\u00e0 \u0111i\u1ec3m n\u1eb1m gi\u1eefa cu\u1ed9n d\u00e2y v\u00e0 t\u1ee5 \u0111i\u1ec7n, N l\u00e0 \u0111i\u1ec3m n\u1eb1m gi\u1eefa t\u1ee5 \u0111i\u1ec7n v\u00e0 \u0111i\u1ec7n tr\u1edf thu\u1ea7n. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u m\u1ea1ch \u0111i\u1ec7n \u00e1p ; \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng U<\/p>\nC<\/dd>\n= 100(V); \u0111i\u1ec7n \u00e1p t\u1ee9c th\u1eddi u<\/p>\n
AM<\/dd>\ns\u1edbm pha 5\u03c0\/6 so v\u1edbi u<\/p>\n
MN<\/dd>\n, s\u1edbm pha 7\u03c0\/12 so v\u1edbi u<\/p>\n
MB<\/dd>\nv\u00e0 s\u1edbm pha \u03c0\/2 so v\u1edbi u<\/p>\n
AB<\/dd>\n. \u0110i\u1ec7n \u00e1p c\u1ef1c \u0111ai U<\/p>\n
0<\/dd>\nc\u00f3 gi\u00e1 tr\u1ecb x\u1ea5p x\u1ec9 l\u00e0<\/p>\n
A.<\/strong>193,2 V. B.<\/strong>136,6 V. C.<\/strong>51,76 V. D.<\/strong>141,2 V.<\/p>\nC\u00e2u 12: (ID:85684)<\/strong>M\u1ed9t \u0111o\u1ea1n m\u1ea1ch RLC n\u1ed1i ti\u1ebfp \u0111ang c\u00f3 t\u00ednh c\u1ea3m kh\u00e1ng, gi\u1eef nguy\u00ean c\u00e1c th\u00f4ng s\u1ed1 kh\u00e1c n\u1ebfu gi\u1ea3m t\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n th\u00ec k\u1ebft lu\u1eadn n\u00e0o sau \u0111\u00e2y l\u00e0sai<\/strong>?<\/p>\nA.<\/strong>C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 t\u0103ng \u0111\u1ebfn c\u1ef1c \u0111\u1ea1i r\u1ed3i gi\u1ea3m<\/p>\nB.<\/strong>T\u1ed5ng tr\u1edf gi\u1ea3m, sau \u0111\u00f3 t\u0103ng<\/p>\nC.<\/strong>\u0110\u1ed9 l\u1ec7ch pha gi\u1eefa \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u t\u1ee5 v\u00e0 \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch gi\u1ea3m<\/p>\nD.<\/strong>\u0110\u1ed9 l\u1ec7ch pha gi\u1eefa \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u cu\u1ed9n c\u1ea3m v\u00e0 \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch gi\u1ea3m<\/p>\nC\u00e2u 13:<\/strong>(ID:85686)<\/strong>Ch\u1ecdn c\u00e2usai<\/strong>.<\/p>\nA.<\/strong>Khi t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c b\u1eb1ng t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a h\u1ec7 th\u00ec bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i.<\/p>\nB.<\/strong>Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o bi\u00ean \u0111\u1ed9 ngo\u1ea1i l\u1ef1c.<\/p>\nC.<\/strong>Dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c l\u00e0 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a.<\/p>\nD.<\/strong>Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c ph\u1ee5 thu\u1ed9c v\u00e0o m\u1ed1i quan h\u1ec7 gi\u1eefa t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c v\u00e0 t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a h\u1ec7.<\/p>\nC\u00e2u 14:<\/strong>(ID:85687)<\/strong>M\u1ed9t l\u0103ng k\u00ednh c\u00f3 g\u00f3c chi\u1ebft quang A = 45<\/p>\n0<\/dd>\n. Chi\u1ebfu ch\u00f9m tia s\u00e1ng h\u1eb9p \u0111a s\u1eafc SI g\u1ed3m 4 \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc: \u0111\u1ecf, v\u00e0ng, l\u1ee5c v\u00e0 t\u00edm \u0111\u1ebfn g\u1eb7p m\u1eb7t b\u00ean AB theo ph\u01b0\u01a1ng vu\u00f4ng g\u00f3c, th\u00ec tia l\u00f3 ra kh\u1ecfi m\u1eb7t b\u00ean AC g\u1ed3m c\u00e1c \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc (Bi\u1ebft chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng k\u00ednh \u0111\u1ed1i v\u1edbi \u00e1nh s\u00e1ng m\u00e0u lam l\u00e0 ![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/64.png\")
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A.<\/strong>\u0111\u1ecf , v\u00e0ng v\u00e0 t\u00edm B.<\/strong>\u0111\u1ecf, v\u00e0ng, l\u1ee5c v\u00e0 t\u00edm C.<\/strong>\u0111\u1ecf, v\u00e0ng v\u00e0 l\u1ee5c D.<\/strong>t\u00edm <\/p>\nC\u00e2u 15: (ID:85688)<\/strong> M\u1ed9t con l\u1eafc \u0111\u01a1n g\u1ed3m s\u1ee3i d\u00e2y nh\u1eb9 d\u00e0i , \u0111\u01b0\u1ee3c treo t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = \u03c0<\/p>\n2<\/dd>\nm\/s<\/p>\n
2<\/dd>\n. K\u00edch th\u00edch cho con l\u1eafc dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 nh\u1ecf, chu k\u1ef3 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u1ee7a con l\u1eafc l\u00e0<\/p>\n
A.<\/strong>0,98 s. B.<\/strong>1,2 s. C.<\/strong>1 s. D.<\/strong>1,5 s.<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/65.png\")
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\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1 6<\/strong><\/span><\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/66.png\")
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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 6<\/strong><\/span><\/p>\n C\u00e2u 2:<\/strong>(ID:85672)<\/strong>V\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 v\u1edbi t\u1ea7n s\u1ed1 2,5 Hz. T\u1ea1i m\u1ed9t th\u1eddi \u0111i\u1ec3m v\u1eadt c\u00f3 \u0111\u1ed9ng n\u0103ng b\u1eb1ng m\u1ed9t n\u1eeda c\u01a1 n\u0103ng th\u00ec sau th\u1eddi \u0111i\u1ec3m \u0111\u00f3 0,05 s \u0111\u1ed9ng n\u0103ng c\u1ee7a v\u1eadt<\/p>\n A.<\/strong>b\u1eb1ng hai l\u1ea7n th\u1ebf n\u0103ng. B.<\/strong>b\u1eb1ng th\u1ebf n\u0103ng<\/p>\n C.<\/strong>c\u00f3 th\u1ec3 b\u1eb1ng kh\u00f4ng ho\u1eb7c b\u1eb1ng c\u01a1 n\u0103ng. D.<\/strong>b\u1eb1ng m\u1ed9t n\u1eeda th\u1ebf n\u0103ng.<\/p>\n C\u00e2u 3:<\/strong>(ID:85673)<\/strong> Hai \u0111i\u1ec3m M, N n\u1eb1m c\u00f9ng m\u1ed9t ph\u00eda c\u1ee7a ngu\u1ed3n \u00e2m \u0111\u1eb7t t\u1ea1i A, tr\u00ean c\u00f9ng m\u1ed9t ph\u01b0\u01a1ng truy\u1ec1n \u00e2m. Bi\u1ebft m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i M v\u00e0 N l\u1ea7n l\u01b0\u1ee3t l\u00e0 L<\/p>\n =30 dB v\u00e0 L<\/p>\n =10 dB. Coi nh\u01b0 c\u00f4ng su\u1ea5t truy\u1ec1n \u00e2m kh\u00f4ng \u0111\u1ed5i v\u00e0 \u00e2m truy\u1ec1n \u0111i c\u00f3 t\u00ednh \u0111\u1eb3ng h\u01b0\u1edbng. N\u1ebfu ngu\u1ed3n \u00e2m \u0111\u00f3 d\u1eb7t t\u1ea1i \u0111i\u1ec3m M th\u00ec m\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i N l\u00e0<\/p>\n A.<\/strong>9 dB. B.<\/strong>12 dB. C.<\/strong>7 dB. D.<\/strong>11 dB.<\/p>\n C\u00e2u 4:<\/strong>(ID:85675)<\/strong>M\u1ed9t d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u \u0111i qua \u0111i\u1ec7n tr\u1edf 20 trong th\u1eddi gian 5 ph\u00fat th\u00ec nhi\u1ec7t l\u01b0\u1ee3ng to\u1ea3 ra l\u00e0 Q = 18 kJ. C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng c\u1ee7a d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u l\u00e0<\/p>\n C\u00e2u 5: (ID:85676)<\/strong>\u0110\u1ed1i v\u1edbi s\u00f3ng c\u01a1 h\u1ecdc, t\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng …<\/p>\n A.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 s\u00f3ng.<\/p>\n B.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o b\u01b0\u1edbc s\u00f3ng v\u00e0 b\u1ea3n ch\u1ea5t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n s\u00f3ng.<\/p>\n C.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o b\u1ea3n ch\u1ea5t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n s\u00f3ng .<\/p>\n D.<\/strong>ph\u1ee5 thu\u1ed9c v\u00e0o chu k\u1ef3, b\u01b0\u1edbc s\u00f3ng v\u00e0 b\u1ea3n ch\u1ea5t m\u00f4i tr\u01b0\u1eddng truy\u1ec1n s\u00f3ng.<\/p>\n C\u00e2u 6:<\/strong>(ID:85677)<\/strong> Trong th\u00ed nghi\u1ec7m giao thoa \u00e1nh s\u00e1ng v\u1edbi khe i\u00e2ng, kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe b\u1eb1ng 1mm, kho\u1ea3ng c\u00e1ch t\u1eeb hai khe \u0111\u1ebfn m\u00e0n quan s\u00e1t D = 2 m. Chi\u1ebfu v\u00e0o hai khe \u0111\u1ed3ng th\u1eddi 2 b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb<\/p>\n = 0,6 \u00b5m v\u00e0 b\u01b0\u1edbc s\u00f3ng \u03bb<\/p>\n ch\u01b0a bi\u1ebft. Trong kho\u1ea3ng r\u1ed9ng L = 2,4 cm tr\u00ean m\u00e0n \u0111\u1ebfm \u0111\u01b0\u1ee3c 33 v\u1ea1ch s\u00e1ng, trong \u0111\u00f3 c\u00f3 5 v\u1ea1ch l\u00e0 k\u1ebft qu\u1ea3 tr\u00f9ng nhau c\u1ee7a hai h\u1ec7 v\u00e2n. Bi\u1ebft 2 trong 5 v\u1ea1ch tr\u00f9ng nhau n\u1eb1m \u1edf ngo\u00e0i c\u00f9ng c\u1ee7a kho\u1ea3ng r\u1ed9ng n\u00f3i tr\u00ean. B\u01b0\u1edbc s\u00f3ng \u03bb<\/p>\n b\u1eb1ng<\/p>\n A.<\/strong>0,45 \u00b5m. B.<\/strong>0,55 \u00b5m. C.<\/strong>0,75 \u00b5m. D.<\/strong>0,65 \u00b5m.<\/p>\n C\u00e2u 7:<\/strong>(ID:85678)<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m v\u1eadt n\u1eb7ng c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m v\u00e0 l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c b\u1eb1ng 5\u03c0 (rad\/s) \u1edf n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = 10 m\/s<\/p>\n , l\u1ea5y \u03c0<\/p>\n = 10. Bi\u1ebft gia t\u1ed1c c\u1ef1c \u0111\u1ea1i c\u1ee7a v\u1eadt n\u1eb7ng a<\/p>\n > g. Trong th\u1eddi gian m\u1ed9t chu k\u00ec dao \u0111\u1ed9ng, th\u1eddi gian l\u1ef1c \u0111\u00e0n h\u1ed3i c\u1ee7a l\u00f2 xo v\u00e0 l\u1ef1c k\u00e9o v\u1ec1 t\u00e1c d\u1ee5ng v\u00e0o v\u1eadt c\u00f9ng h\u01b0\u1edbng l\u00e0 t<\/p>\n , th\u1eddi gian 2 l\u1ef1c \u0111\u00f3 ng\u01b0\u1ee3c h\u01b0\u1edbng l\u00e0 t<\/p>\n . Bi\u1ebft t<\/p>\n = 5t<\/p>\n . Trong m\u1ed9t chu k\u00ec th\u1eddi gian l\u00f2 xo b\u1ecb n\u00e9n l\u00e0<\/p>\n A.<\/strong>1\/15 s. B.<\/strong>2\/15 s. C.<\/strong>0,1 s. D.<\/strong>0,15 s.<\/p>\n C\u00e2u 8:<\/strong>(ID:85679)<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo n\u1eb1m ngang g\u1ed3m v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng 200 gam, l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng 10 N\/m, h\u1ec7 s\u1ed1 ma s\u00e1t tr\u01b0\u1ee3t gi\u1eefa v\u1eadt v\u00e0 m\u1eb7t ph\u1eb3ng ngang l\u00e0 0,1. Ban \u0111\u1ea7u v\u1eadt \u0111\u01b0\u1ee3c gi\u1eef \u1edf v\u1ecb tr\u00ed l\u00f2 xo gi\u00e3n 10 cm, r\u1ed3i th\u1ea3 nh\u1eb9 \u0111\u1ec3 con l\u1eafc dao \u0111\u1ed9ng t\u1eaft d\u1ea7n, l\u1ea5y . Trong kho\u1ea3ng th\u1eddi gian k\u1ec3 t\u1eeb l\u00fac th\u1ea3 cho \u0111\u1ebfn khi t\u1ed1c \u0111\u1ed9 c\u1ee7a v\u1eadt b\u1eaft \u0111\u1ea7u gi\u1ea3m th\u00ec \u0111\u1ed9 gi\u1ea3m th\u1ebf n\u0103ng c\u1ee7a con l\u1eafc l\u00e0:<\/p>\n A.<\/strong>48 mJ. B.<\/strong>50 mJ. C.<\/strong>32 mJ. D.<\/strong>20 mJ.<\/p>\n C\u00e2u 9:<\/strong>(ID:85680)<\/strong>T\u1ea1i \u0111i\u1ec3m O tr\u00ean m\u1eb7t n\u01b0\u1edbc c\u00f3 m\u1ed9t ngu\u1ed3n ph\u00e1t s\u00f3ng theo nh\u1eefng v\u00f2ng tr\u00f2n \u0111\u1ed3ng t\u00e2m v\u1edbi b\u01b0\u1edbc s\u00f3ng \u03bb = 8 cm. G\u1ecdi (C<\/p>\n ), (C<\/p>\n )<\/strong>l\u1ea7n l\u01b0\u1ee3t l\u00e0 hai \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m O b\u00e1n k\u00ednh R<\/p>\n = 10 cm v\u00e0 R<\/p>\n = 20 cm. G\u1ecdi M l\u00e0 m\u1ed9t \u0111i\u1ec3m b\u1ea5t k\u00ec tr\u00ean (C<\/p>\n ). G\u1ecdi A, B, C, D l\u00e0 4 \u0111i\u1ec3m thu\u1ed9c \u0111\u01b0\u1eddng tr\u00f2n (C<\/p>\n ) sao cho AB v\u00e0 CD \u0111\u1ec1u \u0111i qua M v\u00e0 tr\u00ean hai \u0111o\u1ea1n th\u1eb3ng \u0111\u00f3 \u0111\u1ec1u c\u00f3 5 \u0111i\u1ec3m dao \u0111\u1ed9ng ng\u01b0\u1ee3c pha v\u1edbi ngu\u1ed3n. S\u1ed1 \u0111i\u1ec3m t\u1ed1i \u0111a<\/strong> dao \u0111\u1ed9ng vu\u00f4ng pha v\u1edbi ngu\u1ed3n tr\u00ean \u0111o\u1ea1n AC l\u00e0<\/p>\n A.<\/strong> 6. B.<\/strong> 2. C.<\/strong> 8. D.<\/strong> 4.<\/p>\n C\u00e2u 11:<\/strong>(ID:85683)<\/strong>Cho \u0111o\u1ea1n m\u1ea1ch xoay chi\u1ec1u AB g\u1ed3m cu\u1ed9n d\u00e2y, t\u1ee5 \u0111i\u1ec7n C v\u00e0 \u0111i\u1ec7n tr\u1edf thu\u1ea7n R m\u1eafc n\u1ed1i ti\u1ebfp theo th\u1ee9 t\u1ef1 \u0111\u00f3. M l\u00e0 \u0111i\u1ec3m n\u1eb1m gi\u1eefa cu\u1ed9n d\u00e2y v\u00e0 t\u1ee5 \u0111i\u1ec7n, N l\u00e0 \u0111i\u1ec3m n\u1eb1m gi\u1eefa t\u1ee5 \u0111i\u1ec7n v\u00e0 \u0111i\u1ec7n tr\u1edf thu\u1ea7n. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u m\u1ea1ch \u0111i\u1ec7n \u00e1p ; \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng U<\/p>\n = 100(V); \u0111i\u1ec7n \u00e1p t\u1ee9c th\u1eddi u<\/p>\n s\u1edbm pha 5\u03c0\/6 so v\u1edbi u<\/p>\n , s\u1edbm pha 7\u03c0\/12 so v\u1edbi u<\/p>\n v\u00e0 s\u1edbm pha \u03c0\/2 so v\u1edbi u<\/p>\n . \u0110i\u1ec7n \u00e1p c\u1ef1c \u0111ai U<\/p>\n c\u00f3 gi\u00e1 tr\u1ecb x\u1ea5p x\u1ec9 l\u00e0<\/p>\n A.<\/strong>193,2 V. B.<\/strong>136,6 V. C.<\/strong>51,76 V. D.<\/strong>141,2 V.<\/p>\n C\u00e2u 12: (ID:85684)<\/strong>M\u1ed9t \u0111o\u1ea1n m\u1ea1ch RLC n\u1ed1i ti\u1ebfp \u0111ang c\u00f3 t\u00ednh c\u1ea3m kh\u00e1ng, gi\u1eef nguy\u00ean c\u00e1c th\u00f4ng s\u1ed1 kh\u00e1c n\u1ebfu gi\u1ea3m t\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n th\u00ec k\u1ebft lu\u1eadn n\u00e0o sau \u0111\u00e2y l\u00e0sai<\/strong>?<\/p>\n A.<\/strong>C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 t\u0103ng \u0111\u1ebfn c\u1ef1c \u0111\u1ea1i r\u1ed3i gi\u1ea3m<\/p>\n B.<\/strong>T\u1ed5ng tr\u1edf gi\u1ea3m, sau \u0111\u00f3 t\u0103ng<\/p>\n C.<\/strong>\u0110\u1ed9 l\u1ec7ch pha gi\u1eefa \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u t\u1ee5 v\u00e0 \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch gi\u1ea3m<\/p>\n D.<\/strong>\u0110\u1ed9 l\u1ec7ch pha gi\u1eefa \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u cu\u1ed9n c\u1ea3m v\u00e0 \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch gi\u1ea3m<\/p>\n C\u00e2u 13:<\/strong>(ID:85686)<\/strong>Ch\u1ecdn c\u00e2usai<\/strong>.<\/p>\n A.<\/strong>Khi t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c b\u1eb1ng t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a h\u1ec7 th\u00ec bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i.<\/p>\n B.<\/strong>Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o bi\u00ean \u0111\u1ed9 ngo\u1ea1i l\u1ef1c.<\/p>\n C.<\/strong>Dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c l\u00e0 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a.<\/p>\n D.<\/strong>Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c ph\u1ee5 thu\u1ed9c v\u00e0o m\u1ed1i quan h\u1ec7 gi\u1eefa t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c v\u00e0 t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng ri\u00eang c\u1ee7a h\u1ec7.<\/p>\n C\u00e2u 14:<\/strong>(ID:85687)<\/strong>M\u1ed9t l\u0103ng k\u00ednh c\u00f3 g\u00f3c chi\u1ebft quang A = 45<\/p>\n . Chi\u1ebfu ch\u00f9m tia s\u00e1ng h\u1eb9p \u0111a s\u1eafc SI g\u1ed3m 4 \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc: \u0111\u1ecf, v\u00e0ng, l\u1ee5c v\u00e0 t\u00edm \u0111\u1ebfn g\u1eb7p m\u1eb7t b\u00ean AB theo ph\u01b0\u01a1ng vu\u00f4ng g\u00f3c, th\u00ec tia l\u00f3 ra kh\u1ecfi m\u1eb7t b\u00ean AC g\u1ed3m c\u00e1c \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc (Bi\u1ebft chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng k\u00ednh \u0111\u1ed1i v\u1edbi \u00e1nh s\u00e1ng m\u00e0u lam l\u00e0 A.<\/strong>\u0111\u1ecf , v\u00e0ng v\u00e0 t\u00edm B.<\/strong>\u0111\u1ecf, v\u00e0ng, l\u1ee5c v\u00e0 t\u00edm C.<\/strong>\u0111\u1ecf, v\u00e0ng v\u00e0 l\u1ee5c D.<\/strong>t\u00edm <\/p>\n C\u00e2u 15: (ID:85688)<\/strong> M\u1ed9t con l\u1eafc \u0111\u01a1n g\u1ed3m s\u1ee3i d\u00e2y nh\u1eb9 d\u00e0i , \u0111\u01b0\u1ee3c treo t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = \u03c0<\/p>\n m\/s<\/p>\n . K\u00edch th\u00edch cho con l\u1eafc dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 nh\u1ecf, chu k\u1ef3 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u1ee7a con l\u1eafc l\u00e0<\/p>\n A.<\/strong>0,98 s. B.<\/strong>1,2 s. C.<\/strong>1 s. D.<\/strong>1,5 s.<\/p>\n \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1 6<\/strong><\/span><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u01b0\u1ee3c t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n th\u1ee9 6 theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T, c\u00e1c em tham kh\u1ea3o \u0111\u1ec1 thi d\u01b0\u1edbi \u0111\u00e2y. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n<\/p>\n<\/p>\n<\/strong><\/p>\n<\/p>\n<\/p>\n<\/div>\n<\/span>
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