Tham kh\u1ea3o \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u1ec1 s\u1ed1 5 c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em th\u1eed s\u1ee9c v\u1edbi k\u1ef3 thi s\u1eafp t\u1edbi.<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 5<\/span><\/h3>\nC\u00e2u 1: (ID:79609) <\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u1ee7a m\u1ed9t v\u1eadt th\u00ec t\u1eadp h\u1ee3p ba \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o sau \u0111\u00e2y l\u00e0kh\u00f4ng<\/strong> \u0111\u1ed5i theo th\u1eddi gian?<\/p>\nA.<\/strong>L\u1ef1c ph\u1ee5c h\u1ed3i, v\u1eadn t\u1ed1c, c\u01a1 n\u0103ng dao \u0111\u1ed9ng. B.<\/strong>Bi\u00ean \u0111\u1ed9, t\u1ea7n s\u1ed1, c\u01a1 n\u0103ng dao \u0111\u1ed9ng.<\/p>\nC.<\/strong>Bi\u00ean \u0111\u1ed9, t\u1ea7n s\u1ed1, gia t\u1ed1c. D.<\/strong>\u0110\u1ed9ng n\u0103ng, t\u1ea7n s\u1ed1, l\u1ef1c h\u1ed3i ph\u1ee5c.<\/p>\nC\u00e2u 2: (ID:79610)<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng dao \u0111\u1ed9ng c\u00f9ng t\u1ea7n s\u1ed1 v\u1edbi ly \u0111\u1ed9 l\u00e0<\/p>\nA.<\/strong>\u0111\u1ed9ng n\u0103ng, th\u1ebf n\u0103ng v\u00e0 l\u1ef1c k\u00e9o v\u1ec1. B.<\/strong>v\u1eadn t\u1ed1c, gia t\u1ed1c v\u00e0 \u0111\u1ed9ng n\u0103ng.<\/p>\nC.<\/strong>v\u1eadn t\u1ed1c, \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng. D.<\/strong>v\u1eadn t\u1ed1c, gia t\u1ed1c v\u00e0 l\u1ef1c k\u00e9o v\u1ec1.<\/p>\nC\u00e2u 3: (ID:79611)<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y sai<\/strong>? \u0110\u1ed1i v\u1edbi dao \u0111\u1ed9ng t\u1eaft d\u1ea7n th\u00ec<\/p>\nA.<\/strong>c\u01a1 n\u0103ng gi\u1ea3m d\u1ea7n theo th\u1eddi gian. B.<\/strong>t\u1ea7n s\u1ed1 gi\u1ea3m d\u1ea7n theo th\u1eddi gian.<\/p>\nC.<\/strong>ma s\u00e1t v\u00e0 l\u1ef1c c\u1ea3n c\u00e0ng l\u1edbn th\u00ec dao \u0111\u1ed9ng t\u1eaft d\u1ea7n c\u00e0ng nhanh. D.<\/strong>bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng gi\u1ea3m d\u1ea7n theo th\u1eddi gian.<\/p>\nC\u00e2u 4:<\/strong> (ID:79612)<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo \u0111\u1eb7t tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang g\u1ed3m l\u00f2 xo nh\u1eb9 c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 100N\/m m\u1ed9t \u0111\u1ea7u c\u1ed1 \u0111\u1ecbnh, \u0111\u1ea7u kia g\u1eafn v\u1edbi v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m<\/p>\n1<\/dd>\n = 600g. Ban \u0111\u1ea7u v\u1eadt m<\/p>\n
1<\/dd>\n n\u1eb1m t\u1ea1i v\u1ecb tr\u00ed l\u00f2 xo kh\u00f4ng bi\u1ebfn d\u1ea1ng. \u0110\u1eb7t v\u1eadt nh\u1ecf m<\/p>\n
2<\/dd>\n = 400g c\u00e1ch m<\/p>\n
1<\/dd>\n m\u1ed9t kho\u1ea3ng 50cm. H\u1ec7 s\u1ed1 ma s\u00e1t gi\u1eefa hai v\u1eadt v\u00e0 m\u1eb7t ph\u1eb3ng ngang l\u00e0 0,1. H\u1ecfi l\u00fac \u0111\u1ea7u ph\u1ea3i truy\u1ec1n cho v\u1eadt m<\/p>\n
2<\/dd>\n v\u1eadn t\u1ed1c b\u1eb1ng bao nhi\u00eau \u0111\u1ec3 khi m<\/p>\n
2<\/dd>\n \u0111\u1ebfn g\u0103m ch\u1eb7t v\u00e0o m<\/p>\n
1<\/dd>\n l\u00e0m cho c\u1ea3 hai v\u1eadt c\u00f9ng dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng c\u1ee7a tr\u1ee5c l\u00f2 xo v\u1edbi bi\u00ean \u0111\u1ed9 l\u1edbn nh\u1ea5t l\u00e0 6cm. L\u1ea5y g = 10m\/s<\/p>\n
2<\/dd>\n<\/p>\nA<\/strong>. 1,8m\/s B<\/strong>. 1,9m\/s C<\/strong>. 2m\/s D<\/strong>. 2,1m\/s<\/p>\nC\u00e2u 5: (ID:79613)<\/strong>Hai ngu\u1ed3n ph\u00e1t s\u00f3ng k\u1ebft h\u1ee3p S<\/p>\n1<\/dd>\n, S<\/p>\n
2<\/dd>\n c\u00e1ch nhau 12cm dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh u<\/p>\n
S1<\/dd>\n = u<\/p>\n
S2<\/dd>\n = 2.cos40pt (cm, s). X\u00e9t \u0111i\u1ec3m M tr\u00ean m\u1eb7t n\u01b0\u1edbc c\u00e1ch S<\/p>\n
1<\/dd>\nS<\/p>\n
2<\/dd>\n nh\u1eefng kho\u1ea3ng t\u01b0\u01a1ng \u1ee9ng l\u00e0 d<\/p>\n
1<\/dd>\n = 4,2cm v\u00e0 d<\/p>\n
2<\/dd>\n = 9cm. Coi bi\u00ean \u0111\u1ed9 s\u00f3ng kh\u00f4ng \u0111\u1ed5i v\u00e0 t\u1ed1c \u0111\u1ed9 s\u00f3ng tr\u00ean m\u1eb7t n\u01b0\u1edbc v = 32cm\/s. Gi\u1eef nguy\u00ean t\u1ea7n s\u1ed1 f v\u00e0 c\u00e1c v\u1ecb tr\u00ed M, S<\/p>\n
1<\/dd>\n. H\u1ecfi mu\u1ed1n \u0111i\u1ec3m M n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng c\u1ef1c ti\u1ec3u giao thoa th\u00ec ph\u1ea3i d\u1ecbch chuy\u1ec3n ngu\u1ed3n S<\/p>\n
2<\/dd>\n d\u1ecdc theo ph\u01b0\u01a1ng S<\/p>\n
1<\/dd>\nS<\/p>\n
2<\/dd>\n chi\u1ec1u ra xa S<\/p>\n
1<\/dd>\n t\u1eeb v\u1ecb tr\u00ed ban \u0111\u1ea7u m\u1ed9t kho\u1ea3ng nh\u1ecf nh\u1ea5t b\u1eb1ng bao nhi\u00eau?<\/p>\n
A<\/strong>. 0,36cm B<\/strong>. 0,42cm C<\/strong>. 0,6cm D<\/strong>. 0,83cm <\/p>\nC\u00e2u 7: (ID:79617)<\/strong>M\u1ed9t con l\u1eafc g\u1ed3m qu\u1ea3 c\u1ea7u nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m = 200g v\u00e0 m\u1ed9t l\u00f2 xo l\u00ed t\u01b0\u1edfng, c\u00f3 \u0111\u1ed9 d\u00e0i t\u1ef1 nhi\u00ean , \u0111\u1ed9 c\u1ee9ng k = 49N\/m. Cho qu\u1ea3 c\u1ea7u dao \u0111\u00f4ng \u0111i\u1ec1u ho\u00e0 v\u1edbi bi\u00ean \u0111\u1ed9 4cm xung quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng tr\u00ean \u0111\u01b0\u1eddng d\u1ed1c ch\u00ednh c\u1ee7a m\u1ed9t m\u1eb7t ph\u1eb3ng nghi\u00eang (g\u00f3c nghi\u00eang so v\u1edbi m\u1eb7t ph\u1eb3n ngang, gi\u00e1 \u0111\u1ee1 ph\u00eda tr\u00ean). L\u1ea5y g = 9,8m\/s<\/p>\n2<\/dd>\n, b\u1ecf qua m\u1ecdi ma s\u00e1t.Chi\u1ec1u d\u00e0i l\u00f2 xo thay \u0111\u1ed5i trong ph\u1ea1m vi:<\/p>\n
A<\/strong>. t\u1eeb 20cm \u0111\u1ebfn 28 cm B.<\/strong>t\u1eeb 22cm \u0111\u1ebfn 30cm<\/p>\nC<\/strong>. t\u1eeb 24cm \u0111\u1ebfn 32cm D<\/strong>. t\u1eeb 18cm \u0111\u1ebfn 26cm<\/p>\nC\u00e2u 8: (ID:79619)<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo \u0111\u01b0\u1ee3c treo th\u1eb3ng \u0111\u1ee9ng t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g. Khi v\u1eadt nh\u1ecf \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, l\u00f2 xo gi\u00e3n 4cm. K\u00e9o v\u1eadt nh\u1ecf th\u1eb3ng \u0111\u1ee9ng xu\u1ed1ng d\u01b0\u1edbi \u0111\u1ebfn c\u00e1ch v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng 4cm r\u1ed3i th\u1ea3 nh\u1eb9 (kh\u00f4ng v\u1eadn t\u1ed1c ban \u0111\u1ea7u) \u0111\u1ec3 con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u1ea5y . Trong m\u1ed9t chu k\u00ec, th\u1eddi gian l\u00f2 xo kh\u00f4ng d\u00e3n l\u00e0:<\/p>\n A<\/strong>. 0,20s B<\/strong>. 0,13s C<\/strong>. 0,05s D<\/strong>. 0,10s<\/p>\nC\u00e2u 9: (ID:79620)<\/strong>Khi m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 th\u00ec v\u00e9c t\u01a1 v\u1eadn t\u1ed1c<\/p>\nA<\/strong>. lu\u00f4n \u0111\u1ed5i chi\u1ec1u khi \u0111i qua g\u1ed1c to\u1ea1 \u0111\u1ed9 <\/p>\n B.<\/strong> lu\u00f4n c\u00f9ng chi\u1ec1u v\u1edbi v\u00e9c t\u01a1 gia t\u1ed1c<\/p>\nC<\/strong>. lu\u00f4n \u0111\u1ed5i chi\u1ec1u khi v\u1eadt chuy\u1ec3n \u0111\u1ed9ng \u0111\u1ebfn v\u1ecb tr\u00ed bi\u00ean <\/p>\n D<\/strong>. lu\u00f4n ng\u01b0\u1ee3c chi\u1ec1u v\u1edbi v\u00e9c t\u01a1 gia t\u1ed1c <\/p>\n C\u00e2u 10: (ID:79621)<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y kh\u00f4ng<\/strong> \u0111\u00fang?<\/p>\nA<\/strong>. \u0111\u1ed9 cao c\u1ee7a \u00e2m ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 c\u1ee7a ngu\u1ed3n \u00e2m<\/p>\nB.<\/strong>S\u00f3ng \u00e2m ch\u1ec9 truy\u1ec1n \u0111\u01b0\u1ee3c trong kh\u00f4ng kh\u00ed<\/p>\nC<\/strong>.S\u00f3ng \u00e2m v\u00e0 s\u00f3ng c\u01a1 h\u1ecdc c\u00f3 c\u00f9ng b\u1ea3n ch\u1ea5t v\u1eadt l\u00ed<\/p>\nD<\/strong>. S\u00f3ng \u0111\u00e0n h\u1ed3i c\u00f3 t\u1ea7n s\u1ed1 l\u1edbn h\u01a1n 20000Hz g\u1ecdi l\u00e0 s\u00f3ng si\u00eau \u00e2m. <\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/52.png\")
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\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1<\/span> <\/strong><\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/53.png\")
<\/strong><\/p>\n<\/p>\n
<\/strong><\/p>\nT\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"Tham kh\u1ea3o \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u1ec1 s\u1ed1 5 c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em th\u1eed s\u1ee9c v\u1edbi k\u1ef3 thi s\u1eafp t\u1edbi. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n
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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 5<\/span><\/h3>\nC\u00e2u 1: (ID:79609) <\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u1ee7a m\u1ed9t v\u1eadt th\u00ec t\u1eadp h\u1ee3p ba \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o sau \u0111\u00e2y l\u00e0kh\u00f4ng<\/strong> \u0111\u1ed5i theo th\u1eddi gian?<\/p>\nA.<\/strong>L\u1ef1c ph\u1ee5c h\u1ed3i, v\u1eadn t\u1ed1c, c\u01a1 n\u0103ng dao \u0111\u1ed9ng. B.<\/strong>Bi\u00ean \u0111\u1ed9, t\u1ea7n s\u1ed1, c\u01a1 n\u0103ng dao \u0111\u1ed9ng.<\/p>\nC.<\/strong>Bi\u00ean \u0111\u1ed9, t\u1ea7n s\u1ed1, gia t\u1ed1c. D.<\/strong>\u0110\u1ed9ng n\u0103ng, t\u1ea7n s\u1ed1, l\u1ef1c h\u1ed3i ph\u1ee5c.<\/p>\nC\u00e2u 2: (ID:79610)<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng dao \u0111\u1ed9ng c\u00f9ng t\u1ea7n s\u1ed1 v\u1edbi ly \u0111\u1ed9 l\u00e0<\/p>\nA.<\/strong>\u0111\u1ed9ng n\u0103ng, th\u1ebf n\u0103ng v\u00e0 l\u1ef1c k\u00e9o v\u1ec1. B.<\/strong>v\u1eadn t\u1ed1c, gia t\u1ed1c v\u00e0 \u0111\u1ed9ng n\u0103ng.<\/p>\nC.<\/strong>v\u1eadn t\u1ed1c, \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng. D.<\/strong>v\u1eadn t\u1ed1c, gia t\u1ed1c v\u00e0 l\u1ef1c k\u00e9o v\u1ec1.<\/p>\nC\u00e2u 3: (ID:79611)<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y sai<\/strong>? \u0110\u1ed1i v\u1edbi dao \u0111\u1ed9ng t\u1eaft d\u1ea7n th\u00ec<\/p>\nA.<\/strong>c\u01a1 n\u0103ng gi\u1ea3m d\u1ea7n theo th\u1eddi gian. B.<\/strong>t\u1ea7n s\u1ed1 gi\u1ea3m d\u1ea7n theo th\u1eddi gian.<\/p>\nC.<\/strong>ma s\u00e1t v\u00e0 l\u1ef1c c\u1ea3n c\u00e0ng l\u1edbn th\u00ec dao \u0111\u1ed9ng t\u1eaft d\u1ea7n c\u00e0ng nhanh. D.<\/strong>bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng gi\u1ea3m d\u1ea7n theo th\u1eddi gian.<\/p>\nC\u00e2u 4:<\/strong> (ID:79612)<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo \u0111\u1eb7t tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang g\u1ed3m l\u00f2 xo nh\u1eb9 c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 100N\/m m\u1ed9t \u0111\u1ea7u c\u1ed1 \u0111\u1ecbnh, \u0111\u1ea7u kia g\u1eafn v\u1edbi v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m<\/p>\n1<\/dd>\n = 600g. Ban \u0111\u1ea7u v\u1eadt m<\/p>\n
1<\/dd>\n n\u1eb1m t\u1ea1i v\u1ecb tr\u00ed l\u00f2 xo kh\u00f4ng bi\u1ebfn d\u1ea1ng. \u0110\u1eb7t v\u1eadt nh\u1ecf m<\/p>\n
2<\/dd>\n = 400g c\u00e1ch m<\/p>\n
1<\/dd>\n m\u1ed9t kho\u1ea3ng 50cm. H\u1ec7 s\u1ed1 ma s\u00e1t gi\u1eefa hai v\u1eadt v\u00e0 m\u1eb7t ph\u1eb3ng ngang l\u00e0 0,1. H\u1ecfi l\u00fac \u0111\u1ea7u ph\u1ea3i truy\u1ec1n cho v\u1eadt m<\/p>\n
2<\/dd>\n v\u1eadn t\u1ed1c b\u1eb1ng bao nhi\u00eau \u0111\u1ec3 khi m<\/p>\n
2<\/dd>\n \u0111\u1ebfn g\u0103m ch\u1eb7t v\u00e0o m<\/p>\n
1<\/dd>\n l\u00e0m cho c\u1ea3 hai v\u1eadt c\u00f9ng dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng c\u1ee7a tr\u1ee5c l\u00f2 xo v\u1edbi bi\u00ean \u0111\u1ed9 l\u1edbn nh\u1ea5t l\u00e0 6cm. L\u1ea5y g = 10m\/s<\/p>\n
2<\/dd>\n<\/p>\nA<\/strong>. 1,8m\/s B<\/strong>. 1,9m\/s C<\/strong>. 2m\/s D<\/strong>. 2,1m\/s<\/p>\nC\u00e2u 5: (ID:79613)<\/strong>Hai ngu\u1ed3n ph\u00e1t s\u00f3ng k\u1ebft h\u1ee3p S<\/p>\n1<\/dd>\n, S<\/p>\n
2<\/dd>\n c\u00e1ch nhau 12cm dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh u<\/p>\n
S1<\/dd>\n = u<\/p>\n
S2<\/dd>\n = 2.cos40pt (cm, s). X\u00e9t \u0111i\u1ec3m M tr\u00ean m\u1eb7t n\u01b0\u1edbc c\u00e1ch S<\/p>\n
1<\/dd>\nS<\/p>\n
2<\/dd>\n nh\u1eefng kho\u1ea3ng t\u01b0\u01a1ng \u1ee9ng l\u00e0 d<\/p>\n
1<\/dd>\n = 4,2cm v\u00e0 d<\/p>\n
2<\/dd>\n = 9cm. Coi bi\u00ean \u0111\u1ed9 s\u00f3ng kh\u00f4ng \u0111\u1ed5i v\u00e0 t\u1ed1c \u0111\u1ed9 s\u00f3ng tr\u00ean m\u1eb7t n\u01b0\u1edbc v = 32cm\/s. Gi\u1eef nguy\u00ean t\u1ea7n s\u1ed1 f v\u00e0 c\u00e1c v\u1ecb tr\u00ed M, S<\/p>\n
1<\/dd>\n. H\u1ecfi mu\u1ed1n \u0111i\u1ec3m M n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng c\u1ef1c ti\u1ec3u giao thoa th\u00ec ph\u1ea3i d\u1ecbch chuy\u1ec3n ngu\u1ed3n S<\/p>\n
2<\/dd>\n d\u1ecdc theo ph\u01b0\u01a1ng S<\/p>\n
1<\/dd>\nS<\/p>\n
2<\/dd>\n chi\u1ec1u ra xa S<\/p>\n
1<\/dd>\n t\u1eeb v\u1ecb tr\u00ed ban \u0111\u1ea7u m\u1ed9t kho\u1ea3ng nh\u1ecf nh\u1ea5t b\u1eb1ng bao nhi\u00eau?<\/p>\n
A<\/strong>. 0,36cm B<\/strong>. 0,42cm C<\/strong>. 0,6cm D<\/strong>. 0,83cm <\/p>\nC\u00e2u 7: (ID:79617)<\/strong>M\u1ed9t con l\u1eafc g\u1ed3m qu\u1ea3 c\u1ea7u nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m = 200g v\u00e0 m\u1ed9t l\u00f2 xo l\u00ed t\u01b0\u1edfng, c\u00f3 \u0111\u1ed9 d\u00e0i t\u1ef1 nhi\u00ean , \u0111\u1ed9 c\u1ee9ng k = 49N\/m. Cho qu\u1ea3 c\u1ea7u dao \u0111\u00f4ng \u0111i\u1ec1u ho\u00e0 v\u1edbi bi\u00ean \u0111\u1ed9 4cm xung quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng tr\u00ean \u0111\u01b0\u1eddng d\u1ed1c ch\u00ednh c\u1ee7a m\u1ed9t m\u1eb7t ph\u1eb3ng nghi\u00eang (g\u00f3c nghi\u00eang so v\u1edbi m\u1eb7t ph\u1eb3n ngang, gi\u00e1 \u0111\u1ee1 ph\u00eda tr\u00ean). L\u1ea5y g = 9,8m\/s<\/p>\n2<\/dd>\n, b\u1ecf qua m\u1ecdi ma s\u00e1t.Chi\u1ec1u d\u00e0i l\u00f2 xo thay \u0111\u1ed5i trong ph\u1ea1m vi:<\/p>\n
A<\/strong>. t\u1eeb 20cm \u0111\u1ebfn 28 cm B.<\/strong>t\u1eeb 22cm \u0111\u1ebfn 30cm<\/p>\nC<\/strong>. t\u1eeb 24cm \u0111\u1ebfn 32cm D<\/strong>. t\u1eeb 18cm \u0111\u1ebfn 26cm<\/p>\nC\u00e2u 8: (ID:79619)<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo \u0111\u01b0\u1ee3c treo th\u1eb3ng \u0111\u1ee9ng t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g. Khi v\u1eadt nh\u1ecf \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, l\u00f2 xo gi\u00e3n 4cm. K\u00e9o v\u1eadt nh\u1ecf th\u1eb3ng \u0111\u1ee9ng xu\u1ed1ng d\u01b0\u1edbi \u0111\u1ebfn c\u00e1ch v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng 4cm r\u1ed3i th\u1ea3 nh\u1eb9 (kh\u00f4ng v\u1eadn t\u1ed1c ban \u0111\u1ea7u) \u0111\u1ec3 con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u1ea5y . Trong m\u1ed9t chu k\u00ec, th\u1eddi gian l\u00f2 xo kh\u00f4ng d\u00e3n l\u00e0:<\/p>\n A<\/strong>. 0,20s B<\/strong>. 0,13s C<\/strong>. 0,05s D<\/strong>. 0,10s<\/p>\nC\u00e2u 9: (ID:79620)<\/strong>Khi m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 th\u00ec v\u00e9c t\u01a1 v\u1eadn t\u1ed1c<\/p>\nA<\/strong>. lu\u00f4n \u0111\u1ed5i chi\u1ec1u khi \u0111i qua g\u1ed1c to\u1ea1 \u0111\u1ed9 <\/p>\n B.<\/strong> lu\u00f4n c\u00f9ng chi\u1ec1u v\u1edbi v\u00e9c t\u01a1 gia t\u1ed1c<\/p>\nC<\/strong>. lu\u00f4n \u0111\u1ed5i chi\u1ec1u khi v\u1eadt chuy\u1ec3n \u0111\u1ed9ng \u0111\u1ebfn v\u1ecb tr\u00ed bi\u00ean <\/p>\n D<\/strong>. lu\u00f4n ng\u01b0\u1ee3c chi\u1ec1u v\u1edbi v\u00e9c t\u01a1 gia t\u1ed1c <\/p>\n C\u00e2u 10: (ID:79621)<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y kh\u00f4ng<\/strong> \u0111\u00fang?<\/p>\nA<\/strong>. \u0111\u1ed9 cao c\u1ee7a \u00e2m ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 c\u1ee7a ngu\u1ed3n \u00e2m<\/p>\nB.<\/strong>S\u00f3ng \u00e2m ch\u1ec9 truy\u1ec1n \u0111\u01b0\u1ee3c trong kh\u00f4ng kh\u00ed<\/p>\nC<\/strong>.S\u00f3ng \u00e2m v\u00e0 s\u00f3ng c\u01a1 h\u1ecdc c\u00f3 c\u00f9ng b\u1ea3n ch\u1ea5t v\u1eadt l\u00ed<\/p>\nD<\/strong>. S\u00f3ng \u0111\u00e0n h\u1ed3i c\u00f3 t\u1ea7n s\u1ed1 l\u1edbn h\u01a1n 20000Hz g\u1ecdi l\u00e0 s\u00f3ng si\u00eau \u00e2m. <\/p>\n<\/p>\n
\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1<\/span> <\/strong><\/p>\n
<\/strong><\/p>\n<\/p>\n
<\/strong><\/p>\nT\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"Tham kh\u1ea3o \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u1ec1 s\u1ed1 5 c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em th\u1eed s\u1ee9c v\u1edbi k\u1ef3 thi s\u1eafp t\u1edbi. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n
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A.<\/strong>L\u1ef1c ph\u1ee5c h\u1ed3i, v\u1eadn t\u1ed1c, c\u01a1 n\u0103ng dao \u0111\u1ed9ng. B.<\/strong>Bi\u00ean \u0111\u1ed9, t\u1ea7n s\u1ed1, c\u01a1 n\u0103ng dao \u0111\u1ed9ng.<\/p>\n C.<\/strong>Bi\u00ean \u0111\u1ed9, t\u1ea7n s\u1ed1, gia t\u1ed1c. D.<\/strong>\u0110\u1ed9ng n\u0103ng, t\u1ea7n s\u1ed1, l\u1ef1c h\u1ed3i ph\u1ee5c.<\/p>\n C\u00e2u 2: (ID:79610)<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng dao \u0111\u1ed9ng c\u00f9ng t\u1ea7n s\u1ed1 v\u1edbi ly \u0111\u1ed9 l\u00e0<\/p>\n A.<\/strong>\u0111\u1ed9ng n\u0103ng, th\u1ebf n\u0103ng v\u00e0 l\u1ef1c k\u00e9o v\u1ec1. B.<\/strong>v\u1eadn t\u1ed1c, gia t\u1ed1c v\u00e0 \u0111\u1ed9ng n\u0103ng.<\/p>\n C.<\/strong>v\u1eadn t\u1ed1c, \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng. D.<\/strong>v\u1eadn t\u1ed1c, gia t\u1ed1c v\u00e0 l\u1ef1c k\u00e9o v\u1ec1.<\/p>\n C\u00e2u 3: (ID:79611)<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y sai<\/strong>? \u0110\u1ed1i v\u1edbi dao \u0111\u1ed9ng t\u1eaft d\u1ea7n th\u00ec<\/p>\n A.<\/strong>c\u01a1 n\u0103ng gi\u1ea3m d\u1ea7n theo th\u1eddi gian. B.<\/strong>t\u1ea7n s\u1ed1 gi\u1ea3m d\u1ea7n theo th\u1eddi gian.<\/p>\n C.<\/strong>ma s\u00e1t v\u00e0 l\u1ef1c c\u1ea3n c\u00e0ng l\u1edbn th\u00ec dao \u0111\u1ed9ng t\u1eaft d\u1ea7n c\u00e0ng nhanh. D.<\/strong>bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng gi\u1ea3m d\u1ea7n theo th\u1eddi gian.<\/p>\n C\u00e2u 4:<\/strong> (ID:79612)<\/strong>M\u1ed9t con l\u1eafc l\u00f2 xo \u0111\u1eb7t tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang g\u1ed3m l\u00f2 xo nh\u1eb9 c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 100N\/m m\u1ed9t \u0111\u1ea7u c\u1ed1 \u0111\u1ecbnh, \u0111\u1ea7u kia g\u1eafn v\u1edbi v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m<\/p>\n = 600g. Ban \u0111\u1ea7u v\u1eadt m<\/p>\n n\u1eb1m t\u1ea1i v\u1ecb tr\u00ed l\u00f2 xo kh\u00f4ng bi\u1ebfn d\u1ea1ng. \u0110\u1eb7t v\u1eadt nh\u1ecf m<\/p>\n = 400g c\u00e1ch m<\/p>\n m\u1ed9t kho\u1ea3ng 50cm. H\u1ec7 s\u1ed1 ma s\u00e1t gi\u1eefa hai v\u1eadt v\u00e0 m\u1eb7t ph\u1eb3ng ngang l\u00e0 0,1. H\u1ecfi l\u00fac \u0111\u1ea7u ph\u1ea3i truy\u1ec1n cho v\u1eadt m<\/p>\n v\u1eadn t\u1ed1c b\u1eb1ng bao nhi\u00eau \u0111\u1ec3 khi m<\/p>\n \u0111\u1ebfn g\u0103m ch\u1eb7t v\u00e0o m<\/p>\n l\u00e0m cho c\u1ea3 hai v\u1eadt c\u00f9ng dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng c\u1ee7a tr\u1ee5c l\u00f2 xo v\u1edbi bi\u00ean \u0111\u1ed9 l\u1edbn nh\u1ea5t l\u00e0 6cm. L\u1ea5y g = 10m\/s<\/p>\n A<\/strong>. 1,8m\/s B<\/strong>. 1,9m\/s C<\/strong>. 2m\/s D<\/strong>. 2,1m\/s<\/p>\n C\u00e2u 5: (ID:79613)<\/strong>Hai ngu\u1ed3n ph\u00e1t s\u00f3ng k\u1ebft h\u1ee3p S<\/p>\n , S<\/p>\n c\u00e1ch nhau 12cm dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh u<\/p>\n = u<\/p>\n = 2.cos40pt (cm, s). X\u00e9t \u0111i\u1ec3m M tr\u00ean m\u1eb7t n\u01b0\u1edbc c\u00e1ch S<\/p>\n S<\/p>\n nh\u1eefng kho\u1ea3ng t\u01b0\u01a1ng \u1ee9ng l\u00e0 d<\/p>\n = 4,2cm v\u00e0 d<\/p>\n = 9cm. Coi bi\u00ean \u0111\u1ed9 s\u00f3ng kh\u00f4ng \u0111\u1ed5i v\u00e0 t\u1ed1c \u0111\u1ed9 s\u00f3ng tr\u00ean m\u1eb7t n\u01b0\u1edbc v = 32cm\/s. Gi\u1eef nguy\u00ean t\u1ea7n s\u1ed1 f v\u00e0 c\u00e1c v\u1ecb tr\u00ed M, S<\/p>\n . H\u1ecfi mu\u1ed1n \u0111i\u1ec3m M n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng c\u1ef1c ti\u1ec3u giao thoa th\u00ec ph\u1ea3i d\u1ecbch chuy\u1ec3n ngu\u1ed3n S<\/p>\n d\u1ecdc theo ph\u01b0\u01a1ng S<\/p>\n S<\/p>\n chi\u1ec1u ra xa S<\/p>\n t\u1eeb v\u1ecb tr\u00ed ban \u0111\u1ea7u m\u1ed9t kho\u1ea3ng nh\u1ecf nh\u1ea5t b\u1eb1ng bao nhi\u00eau?<\/p>\n A<\/strong>. 0,36cm B<\/strong>. 0,42cm C<\/strong>. 0,6cm D<\/strong>. 0,83cm <\/p>\n C\u00e2u 7: (ID:79617)<\/strong>M\u1ed9t con l\u1eafc g\u1ed3m qu\u1ea3 c\u1ea7u nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng m = 200g v\u00e0 m\u1ed9t l\u00f2 xo l\u00ed t\u01b0\u1edfng, c\u00f3 \u0111\u1ed9 d\u00e0i t\u1ef1 nhi\u00ean , \u0111\u1ed9 c\u1ee9ng k = 49N\/m. Cho qu\u1ea3 c\u1ea7u dao \u0111\u00f4ng \u0111i\u1ec1u ho\u00e0 v\u1edbi bi\u00ean \u0111\u1ed9 4cm xung quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng tr\u00ean \u0111\u01b0\u1eddng d\u1ed1c ch\u00ednh c\u1ee7a m\u1ed9t m\u1eb7t ph\u1eb3ng nghi\u00eang (g\u00f3c nghi\u00eang so v\u1edbi m\u1eb7t ph\u1eb3n ngang, gi\u00e1 \u0111\u1ee1 ph\u00eda tr\u00ean). L\u1ea5y g = 9,8m\/s<\/p>\n , b\u1ecf qua m\u1ecdi ma s\u00e1t.Chi\u1ec1u d\u00e0i l\u00f2 xo thay \u0111\u1ed5i trong ph\u1ea1m vi:<\/p>\n A<\/strong>. t\u1eeb 20cm \u0111\u1ebfn 28 cm B.<\/strong>t\u1eeb 22cm \u0111\u1ebfn 30cm<\/p>\n C<\/strong>. t\u1eeb 24cm \u0111\u1ebfn 32cm D<\/strong>. t\u1eeb 18cm \u0111\u1ebfn 26cm<\/p>\n C\u00e2u 8: (ID:79619)<\/strong> M\u1ed9t con l\u1eafc l\u00f2 xo \u0111\u01b0\u1ee3c treo th\u1eb3ng \u0111\u1ee9ng t\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g. Khi v\u1eadt nh\u1ecf \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, l\u00f2 xo gi\u00e3n 4cm. K\u00e9o v\u1eadt nh\u1ecf th\u1eb3ng \u0111\u1ee9ng xu\u1ed1ng d\u01b0\u1edbi \u0111\u1ebfn c\u00e1ch v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng 4cm r\u1ed3i th\u1ea3 nh\u1eb9 (kh\u00f4ng v\u1eadn t\u1ed1c ban \u0111\u1ea7u) \u0111\u1ec3 con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u1ea5y . Trong m\u1ed9t chu k\u00ec, th\u1eddi gian l\u00f2 xo kh\u00f4ng d\u00e3n l\u00e0:<\/p>\n A<\/strong>. 0,20s B<\/strong>. 0,13s C<\/strong>. 0,05s D<\/strong>. 0,10s<\/p>\n C\u00e2u 9: (ID:79620)<\/strong>Khi m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 th\u00ec v\u00e9c t\u01a1 v\u1eadn t\u1ed1c<\/p>\n A<\/strong>. lu\u00f4n \u0111\u1ed5i chi\u1ec1u khi \u0111i qua g\u1ed1c to\u1ea1 \u0111\u1ed9 <\/p>\n B.<\/strong> lu\u00f4n c\u00f9ng chi\u1ec1u v\u1edbi v\u00e9c t\u01a1 gia t\u1ed1c<\/p>\n C<\/strong>. lu\u00f4n \u0111\u1ed5i chi\u1ec1u khi v\u1eadt chuy\u1ec3n \u0111\u1ed9ng \u0111\u1ebfn v\u1ecb tr\u00ed bi\u00ean <\/p>\n D<\/strong>. lu\u00f4n ng\u01b0\u1ee3c chi\u1ec1u v\u1edbi v\u00e9c t\u01a1 gia t\u1ed1c <\/p>\n C\u00e2u 10: (ID:79621)<\/strong> Ph\u00e1t bi\u1ec3u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y kh\u00f4ng<\/strong> \u0111\u00fang?<\/p>\n A<\/strong>. \u0111\u1ed9 cao c\u1ee7a \u00e2m ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 c\u1ee7a ngu\u1ed3n \u00e2m<\/p>\n B.<\/strong>S\u00f3ng \u00e2m ch\u1ec9 truy\u1ec1n \u0111\u01b0\u1ee3c trong kh\u00f4ng kh\u00ed<\/p>\n C<\/strong>.S\u00f3ng \u00e2m v\u00e0 s\u00f3ng c\u01a1 h\u1ecdc c\u00f3 c\u00f9ng b\u1ea3n ch\u1ea5t v\u1eadt l\u00ed<\/p>\n D<\/strong>. S\u00f3ng \u0111\u00e0n h\u1ed3i c\u00f3 t\u1ea7n s\u1ed1 l\u1edbn h\u01a1n 20000Hz g\u1ecdi l\u00e0 s\u00f3ng si\u00eau \u00e2m. <\/p>\n \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1<\/span> <\/strong><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" Tham kh\u1ea3o \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u1ec1 s\u1ed1 5 c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em th\u1eed s\u1ee9c v\u1edbi k\u1ef3 thi s\u1eafp t\u1edbi. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n<\/p>\n
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