\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u01b0\u1ee3c t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n th\u1ee9 8 theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T, c\u00e1c em tham kh\u1ea3o \u0111\u1ec1 thi d\u01b0\u1edbi \u0111\u00e2y.<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 8<\/strong><\/strong><\/span><\/p>\nC\u00e2u 1: (ID:84545)<\/strong>M\u1ea1ch \u0111i\u1ec7n R,L,C m\u1eafc n\u1ed1i ti\u1ebfp. \u0110i\u00ean \u00e1p xoay chi\u1ec1u \u0111\u1eb7t v\u00e0o hai \u0111\u1ea7u m\u1ea1ch c\u00f3 gi\u00e1 tr\u1ecb hi\u1ec7u \u0111i\u1ec7n th\u1ebf U= 120 V. Khi thay \u0111\u1ed5i C th\u00ec th\u1ea5y \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai b\u00e0n \u0111i\u1ec7n t\u1ee5 \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i U<\/p>\nCmax=![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/81.png\")
<\/dd>\n H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t \u0111o\u1ea1n m\u1ea1ch l\u00e0:<\/p>\n
C\u00e2u 2: (ID:84546)<\/strong>Ch\u1ea5t \u0111i\u1ec3m 1 v\u00e0 ch\u1ea5t \u0111i\u1ec3m 2 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng t\u1ea7n s\u1ed1, v\u1edbi li \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t l\u00e0 x<\/p>\n1<\/dd>\nv\u00e0 x<\/p>\n
2<\/dd>\n. Bi\u1ebft r\u1eb1ng: 2x<\/p>\n
1<\/dd>\n2<\/dd>\n+ 3x<\/p>\n
2<\/dd>\n2<\/dd>\n= 39. T\u1ea1i th\u1eddi \u0111i\u1ec3m t, ch\u1ea5t \u0111i\u1ec3m 1 c\u00f3 li \u0111\u1ed9 1 cm v\u00e0 v\u1eadn t\u1ed1c 30cm\/s v\u00e0 ch\u1ea5t \u0111i\u1ec3m 2 c\u00f3 v\u1eadn t\u1ed1c l\u00e0 5cm\/s. T\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111\u00f3, ch\u1ea5t \u0111i\u1ec3m 2 c\u00f3 li \u0111\u1ed9 l\u00e0<\/p>\n
A. <\/strong>2cm <\/span>B.<\/strong>-2cm <\/span>C.<\/strong>4cm <\/span>D.-<\/strong>4cm<\/span><\/p>\nC\u00e2u 3: (ID:84547)<\/strong>M\u1ed9t d\u00e2y \u0111\u00e0n c\u00f3 chi\u1ec1u d\u00e0i l = 5cm. Khi d\u00e2y \u0111\u00e0n \u0111\u01b0\u1ee3c g\u1ea3y l\u00ean, n\u00f3 ph\u00e1t ra m\u1ed9t \u00e2m thanh m\u00e0 h\u1ecda \u00e2m b\u1eadc 2 c\u00f3 t\u1ea7n s\u1ed1 l\u00e0 400 Hz. T\u1ed1c \u0111\u1ed9 truy\u1ec3n s\u00f3ng tr\u00ean d\u00e2y l\u00e0<\/p>\nC\u00e2u 4: (ID:84548)<\/strong>Nh\u1eadn x\u00e9t n\u00e0o sau \u0111\u00e2y v\u1ec1 m\u00e1y bi\u1ebfn \u00e1p l\u00e0 kh\u00f4ng \u0111\u00fang?<\/p>\nA. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 th\u1ec3 t\u0103ng \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u.<\/p>\nB. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 th\u1ec3 thay \u0111\u1ed5i t\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u.<\/p>\nC. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 th\u1ec3 gi\u1ea3m \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u.<\/p>\nD. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 t\u00e1c d\u1ee5ng bi\u1ebfn \u0111\u1ed5i c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u.<\/p>\nC\u00e2u 5: (ID:84549)<\/strong>M\u1ed9t con l\u1eafc \u0111\u01a1n \u0111\u01a1n dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c \u03b1<\/p>\n0<\/dd>\n= 8<\/p>\n
0<\/dd>\n. Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng, l\u1ef1c c\u0103ng d\u00e2y c\u1ef1c \u0111\u1ea1i l\u00e0 1,2488 N. Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng t\u1ea1i n\u01a1i treo con l\u1eafc l\u00e0 9,80 N\/m<\/p>\n
2<\/dd>\n. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a qu\u1ea3 c\u1ea7u con l\u1eafc l\u00e0<\/p>\n
A. <\/strong>125 g. B.<\/strong>115 g. C.<\/strong>130 g. D.<\/strong>135 g.<\/p>\nC\u00e2u 6: (ID:84550)<\/strong>Trong th\u00ed nghi\u1ec7m Y-\u00e2ng (Young) v\u1ec1 giao thoa \u00e1nh s\u00e1ng, khi chi\u1ec1u v\u00e0o hai khe \u0111\u1ed3ng th\u1eddi hai b\u1ee9c x\u1ea1 \u0111\u01a1n s\u1eafc th\u00ec ta quan s\u00e1t \u0111\u01b0\u1ee3c tr\u00ean m\u00e0n hai h\u1ec7 v\u00e2n giao thoa v\u1edbi c\u00e1c kho\u1ea3ng v\u00e2n l\u1ea7n l\u01b0\u1ee3t \u00e0 0,3mm v\u00e0 0,2 mm. Tr\u00ean m\u00e0n quan s\u00e1t, kho\u1ea3ng c\u00e1ch gi\u1eefa hai v\u00e2n s\u00e1ng li\u00ean ti\u1ebfp c\u00f3 c\u00f9ng m\u00e0u v\u1edbi v\u00e2n s\u00e1ng trung t\u00e2m l\u00e0<\/p>\nA. <\/strong>1,2 mm. B.<\/strong>0,6 mm. C.<\/strong>0,3 mm. D.<\/strong>0,2 mm.<\/p>\nC\u00e2u 7: (ID:84551)<\/strong>M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = 8cos(\u03c0t + \u03c0\/4) (x t\u00ednh b\u1eb1ng cm, t t\u00ednh b\u1eb1ng s) th\u00ec<\/p>\nA. <\/strong>\u0110\u1ed9 d\u00e0i qu\u0129 \u0111\u1ea1o l\u00e0 8 cm.<\/p>\nB. <\/strong>L\u00fac t = 0, ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng theo chi\u1ec1u \u00e2m.<\/p>\nC. <\/strong>Chi k\u00ec dao \u0111\u1ed9ng l\u00e0 1s.<\/p>\nD. <\/strong>Khi qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, v\u1eadn t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m c\u00f3 \u0111\u1ed9 l\u1edbn 8 cm\/s.<\/p>\nC\u00e2u 8 :<\/strong>(ID:84552)<\/strong>Tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng, m\u1ed9t ch\u1ea5t \u0111i\u1ec3m kh\u1ed1i l\u01b0\u1ee3ng 750 g, dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, c\u00f3 chu k\u00ec dao \u0111\u1ed9ng l\u00e0 2s v\u00e0 n\u0103ng l\u01b0\u1ee3ng dao \u0111\u1ed9ng l\u00e0 6 mJ. L\u1ea5y \u03c0<\/p>\n2<\/dd>\n= 10. Chi\u1ec1u d\u00e0i qu\u0129 \u0111\u1ea1o c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0<\/p>\n
A. <\/strong>8 cm. B.<\/strong>5 cm. C.<\/strong>4 cm. D.<\/strong>10 cm.<\/p>\nC\u00e2u 9 :<\/strong>(ID:84553)<\/strong>m\u1ed9t ng\u01b0\u1eddi nghe th\u1ea5y \u00e2m do m\u1ed9t nh\u1ea1c c\u1ee5 ph\u00e1t ra c\u00f3 t\u1ea7n s\u1ed1 f v\u00e0 t\u1ea1i v\u1ecb tr\u00ed c\u1ee7a ng\u01b0\u1eddi \u0111\u00f3 c\u00f3 c\u01b0\u1eddng \u0111\u1ed9 l\u00e0 I. N\u1ebfu t\u1ea7n s\u1ed1 v\u00e0 c\u01b0\u1eddng \u0111\u1ed9 \u00e2m l\u00e0 f \u2019 = 10f v\u00e0 I\u2019 = 10I th\u00ec ng\u01b0\u1eddi \u1ea5y nghe th\u1ea5y \u00e2m c\u00f3<\/p>\nA. <\/strong>\u0110\u1ed9 cao t\u0103ng 10 l\u1ea7n B.<\/strong>\u0111\u1ed9 to t\u0103ng 10 l\u1ea7n<\/p>\nB. <\/strong>\u0110\u1ed9 to t\u0103ng th\u00eam 10 (dB) . D.<\/strong>\u0111\u1ed9 cao t\u0103ng l\u00ean<\/p>\nC\u00e2u 10. (ID:84554)<\/strong>M\u1ed9t \u0111\u01b0\u1eddng d\u00e2y t\u1ea3i \u0111ien\u1eb9 gi\u1eefa hai \u0111\u1ecba \u0111i\u1ec3m A v\u00e0 B c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t b\u1eb1ng 1. T\u1ea1i A \u0111\u1eb7t m\u00e1y t\u0103ng \u00e1p, t\u1ea1i B \u0111\u1eb7t m\u00e1y h\u1ea1 \u00e1p. \u0110\u01b0\u1eddng d\u00e2y t\u1ea3i \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n tr\u1edf t\u1ed5ng c\u1ed9ng 20\u03a9. C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng c\u1ee7a d\u00f2ng \u0111i\u1ec7n tr\u00ean d\u00e2y t\u1ea3i l\u00e0 110A. C\u00f4ng su\u1ea5t hao ph\u00ed tr\u00ean \u0111\u01b0\u1eddng d\u00e2y t\u1ea3i b\u1eb1ng 5% c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 \u1edf B. \u0110i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u cu\u1ed9n th\u1ee9 c\u1ea5p c\u1ee7a m\u00e1y h\u1ea1 \u00e1p l\u00e0 220V. \u1ede m\u00e1y h\u1ea1 \u00e1p, t\u1ec9 s\u1ed1 gi\u1eefa s\u1ed1 v\u00f2ng d\u00e2y cu\u1ed9n s\u01a1 c\u1ea5p v\u00e0 th\u1ee9 c\u1ea5p l\u00e0<\/p>\nA. <\/strong>20. 100. 250. 200.<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/82.png\")
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![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/83.png\")
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C\u00e2u 13:<\/strong>(ID:84557)<\/strong>Khi v\u1eadt n\u1eb7ng c\u1ee7a m\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m = 100g v\u00e0 mang \u0111i\u1ec7n t\u00edch q = 10<\/p>\n-5<\/dd>\n\u0111ang dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c \u03b1 = 6<\/p>\n
0<\/dd>\n. Khi v\u1eadt n\u1eb7ng qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng th\u00ec ng\u01b0\u1eddithi\u1ebft l\u1eadp m\u1ed9t \u0111i\u1ec7n tr\u01b0\u1eddng \u0111\u1ec1u theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng, h\u01b0\u1edbng l\u00ean, v\u1edbi c\u01b0\u1eddng \u0111\u1ed9 \u0111i\u1ec7n tr\u01b0\u1eddng E = 25kV\/m. L\u1ea5y g = 10m\/s<\/p>\n
2<\/dd>\n. Bi\u00ean \u0111\u1ed9 g\u00f3c c\u1ee7a v\u1eadt sau \u0111\u00f3 l\u00e0![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/84.png\")
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\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1 8<\/strong><\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/86.png\")
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<\/strong><\/p>\n<\/p>\nT\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u01b0\u1ee3c t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n th\u1ee9 8 theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T, c\u00e1c em tham kh\u1ea3o \u0111\u1ec1 thi d\u01b0\u1edbi \u0111\u00e2y. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd 2016 - \u0110\u1ec1 s\u1ed1 8<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-thu-thpt-quoc-gia-mon-vat-ly-2016-de-so-8\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd 2016 - \u0110\u1ec1 s\u1ed1 8\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u01b0\u1ee3c t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n th\u1ee9 8 theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T, c\u00e1c em tham kh\u1ea3o \u0111\u1ec1 thi d\u01b0\u1edbi \u0111\u00e2y. 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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 8<\/strong><\/strong><\/span><\/p>\n C\u00e2u 1: (ID:84545)<\/strong>M\u1ea1ch \u0111i\u1ec7n R,L,C m\u1eafc n\u1ed1i ti\u1ebfp. \u0110i\u00ean \u00e1p xoay chi\u1ec1u \u0111\u1eb7t v\u00e0o hai \u0111\u1ea7u m\u1ea1ch c\u00f3 gi\u00e1 tr\u1ecb hi\u1ec7u \u0111i\u1ec7n th\u1ebf U= 120 V. Khi thay \u0111\u1ed5i C th\u00ec th\u1ea5y \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai b\u00e0n \u0111i\u1ec7n t\u1ee5 \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i U<\/p>\n H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t \u0111o\u1ea1n m\u1ea1ch l\u00e0:<\/p>\n C\u00e2u 2: (ID:84546)<\/strong>Ch\u1ea5t \u0111i\u1ec3m 1 v\u00e0 ch\u1ea5t \u0111i\u1ec3m 2 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng t\u1ea7n s\u1ed1, v\u1edbi li \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t l\u00e0 x<\/p>\n v\u00e0 x<\/p>\n . Bi\u1ebft r\u1eb1ng: 2x<\/p>\n + 3x<\/p>\n = 39. T\u1ea1i th\u1eddi \u0111i\u1ec3m t, ch\u1ea5t \u0111i\u1ec3m 1 c\u00f3 li \u0111\u1ed9 1 cm v\u00e0 v\u1eadn t\u1ed1c 30cm\/s v\u00e0 ch\u1ea5t \u0111i\u1ec3m 2 c\u00f3 v\u1eadn t\u1ed1c l\u00e0 5cm\/s. T\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111\u00f3, ch\u1ea5t \u0111i\u1ec3m 2 c\u00f3 li \u0111\u1ed9 l\u00e0<\/p>\n A. <\/strong>2cm <\/span>B.<\/strong>-2cm <\/span>C.<\/strong>4cm <\/span>D.-<\/strong>4cm<\/span><\/p>\n C\u00e2u 3: (ID:84547)<\/strong>M\u1ed9t d\u00e2y \u0111\u00e0n c\u00f3 chi\u1ec1u d\u00e0i l = 5cm. Khi d\u00e2y \u0111\u00e0n \u0111\u01b0\u1ee3c g\u1ea3y l\u00ean, n\u00f3 ph\u00e1t ra m\u1ed9t \u00e2m thanh m\u00e0 h\u1ecda \u00e2m b\u1eadc 2 c\u00f3 t\u1ea7n s\u1ed1 l\u00e0 400 Hz. T\u1ed1c \u0111\u1ed9 truy\u1ec3n s\u00f3ng tr\u00ean d\u00e2y l\u00e0<\/p>\n C\u00e2u 4: (ID:84548)<\/strong>Nh\u1eadn x\u00e9t n\u00e0o sau \u0111\u00e2y v\u1ec1 m\u00e1y bi\u1ebfn \u00e1p l\u00e0 kh\u00f4ng \u0111\u00fang?<\/p>\n A. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 th\u1ec3 t\u0103ng \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u.<\/p>\n B. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 th\u1ec3 thay \u0111\u1ed5i t\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u.<\/p>\n C. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 th\u1ec3 gi\u1ea3m \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u.<\/p>\n D. <\/strong>M\u00e1y bi\u1ebfn \u00e1p c\u00f3 t\u00e1c d\u1ee5ng bi\u1ebfn \u0111\u1ed5i c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u.<\/p>\n C\u00e2u 5: (ID:84549)<\/strong>M\u1ed9t con l\u1eafc \u0111\u01a1n \u0111\u01a1n dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c \u03b1<\/p>\n = 8<\/p>\n . Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng, l\u1ef1c c\u0103ng d\u00e2y c\u1ef1c \u0111\u1ea1i l\u00e0 1,2488 N. Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng t\u1ea1i n\u01a1i treo con l\u1eafc l\u00e0 9,80 N\/m<\/p>\n . Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a qu\u1ea3 c\u1ea7u con l\u1eafc l\u00e0<\/p>\n A. <\/strong>125 g. B.<\/strong>115 g. C.<\/strong>130 g. D.<\/strong>135 g.<\/p>\n C\u00e2u 6: (ID:84550)<\/strong>Trong th\u00ed nghi\u1ec7m Y-\u00e2ng (Young) v\u1ec1 giao thoa \u00e1nh s\u00e1ng, khi chi\u1ec1u v\u00e0o hai khe \u0111\u1ed3ng th\u1eddi hai b\u1ee9c x\u1ea1 \u0111\u01a1n s\u1eafc th\u00ec ta quan s\u00e1t \u0111\u01b0\u1ee3c tr\u00ean m\u00e0n hai h\u1ec7 v\u00e2n giao thoa v\u1edbi c\u00e1c kho\u1ea3ng v\u00e2n l\u1ea7n l\u01b0\u1ee3t \u00e0 0,3mm v\u00e0 0,2 mm. Tr\u00ean m\u00e0n quan s\u00e1t, kho\u1ea3ng c\u00e1ch gi\u1eefa hai v\u00e2n s\u00e1ng li\u00ean ti\u1ebfp c\u00f3 c\u00f9ng m\u00e0u v\u1edbi v\u00e2n s\u00e1ng trung t\u00e2m l\u00e0<\/p>\n A. <\/strong>1,2 mm. B.<\/strong>0,6 mm. C.<\/strong>0,3 mm. D.<\/strong>0,2 mm.<\/p>\n C\u00e2u 7: (ID:84551)<\/strong>M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = 8cos(\u03c0t + \u03c0\/4) (x t\u00ednh b\u1eb1ng cm, t t\u00ednh b\u1eb1ng s) th\u00ec<\/p>\n A. <\/strong>\u0110\u1ed9 d\u00e0i qu\u0129 \u0111\u1ea1o l\u00e0 8 cm.<\/p>\n B. <\/strong>L\u00fac t = 0, ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng theo chi\u1ec1u \u00e2m.<\/p>\n C. <\/strong>Chi k\u00ec dao \u0111\u1ed9ng l\u00e0 1s.<\/p>\n D. <\/strong>Khi qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, v\u1eadn t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m c\u00f3 \u0111\u1ed9 l\u1edbn 8 cm\/s.<\/p>\n C\u00e2u 8 :<\/strong>(ID:84552)<\/strong>Tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng, m\u1ed9t ch\u1ea5t \u0111i\u1ec3m kh\u1ed1i l\u01b0\u1ee3ng 750 g, dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, c\u00f3 chu k\u00ec dao \u0111\u1ed9ng l\u00e0 2s v\u00e0 n\u0103ng l\u01b0\u1ee3ng dao \u0111\u1ed9ng l\u00e0 6 mJ. L\u1ea5y \u03c0<\/p>\n = 10. Chi\u1ec1u d\u00e0i qu\u0129 \u0111\u1ea1o c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0<\/p>\n A. <\/strong>8 cm. B.<\/strong>5 cm. C.<\/strong>4 cm. D.<\/strong>10 cm.<\/p>\n C\u00e2u 9 :<\/strong>(ID:84553)<\/strong>m\u1ed9t ng\u01b0\u1eddi nghe th\u1ea5y \u00e2m do m\u1ed9t nh\u1ea1c c\u1ee5 ph\u00e1t ra c\u00f3 t\u1ea7n s\u1ed1 f v\u00e0 t\u1ea1i v\u1ecb tr\u00ed c\u1ee7a ng\u01b0\u1eddi \u0111\u00f3 c\u00f3 c\u01b0\u1eddng \u0111\u1ed9 l\u00e0 I. N\u1ebfu t\u1ea7n s\u1ed1 v\u00e0 c\u01b0\u1eddng \u0111\u1ed9 \u00e2m l\u00e0 f \u2019 = 10f v\u00e0 I\u2019 = 10I th\u00ec ng\u01b0\u1eddi \u1ea5y nghe th\u1ea5y \u00e2m c\u00f3<\/p>\n A. <\/strong>\u0110\u1ed9 cao t\u0103ng 10 l\u1ea7n B.<\/strong>\u0111\u1ed9 to t\u0103ng 10 l\u1ea7n<\/p>\n B. <\/strong>\u0110\u1ed9 to t\u0103ng th\u00eam 10 (dB) . D.<\/strong>\u0111\u1ed9 cao t\u0103ng l\u00ean<\/p>\n C\u00e2u 10. (ID:84554)<\/strong>M\u1ed9t \u0111\u01b0\u1eddng d\u00e2y t\u1ea3i \u0111ien\u1eb9 gi\u1eefa hai \u0111\u1ecba \u0111i\u1ec3m A v\u00e0 B c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t b\u1eb1ng 1. T\u1ea1i A \u0111\u1eb7t m\u00e1y t\u0103ng \u00e1p, t\u1ea1i B \u0111\u1eb7t m\u00e1y h\u1ea1 \u00e1p. \u0110\u01b0\u1eddng d\u00e2y t\u1ea3i \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n tr\u1edf t\u1ed5ng c\u1ed9ng 20\u03a9. C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng c\u1ee7a d\u00f2ng \u0111i\u1ec7n tr\u00ean d\u00e2y t\u1ea3i l\u00e0 110A. C\u00f4ng su\u1ea5t hao ph\u00ed tr\u00ean \u0111\u01b0\u1eddng d\u00e2y t\u1ea3i b\u1eb1ng 5% c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 \u1edf B. \u0110i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u cu\u1ed9n th\u1ee9 c\u1ea5p c\u1ee7a m\u00e1y h\u1ea1 \u00e1p l\u00e0 220V. \u1ede m\u00e1y h\u1ea1 \u00e1p, t\u1ec9 s\u1ed1 gi\u1eefa s\u1ed1 v\u00f2ng d\u00e2y cu\u1ed9n s\u01a1 c\u1ea5p v\u00e0 th\u1ee9 c\u1ea5p l\u00e0<\/p>\n A. <\/strong>20. 100. 250. 200.<\/p>\n C\u00e2u 13:<\/strong>(ID:84557)<\/strong>Khi v\u1eadt n\u1eb7ng c\u1ee7a m\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m = 100g v\u00e0 mang \u0111i\u1ec7n t\u00edch q = 10<\/p>\n \u0111ang dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c \u03b1 = 6<\/p>\n . Khi v\u1eadt n\u1eb7ng qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng th\u00ec ng\u01b0\u1eddithi\u1ebft l\u1eadp m\u1ed9t \u0111i\u1ec7n tr\u01b0\u1eddng \u0111\u1ec1u theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng, h\u01b0\u1edbng l\u00ean, v\u1edbi c\u01b0\u1eddng \u0111\u1ed9 \u0111i\u1ec7n tr\u01b0\u1eddng E = 25kV\/m. L\u1ea5y g = 10m\/s<\/p>\n . Bi\u00ean \u0111\u1ed9 g\u00f3c c\u1ee7a v\u1eadt sau \u0111\u00f3 l\u00e0 \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1 8<\/strong><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia n\u0103m 2016 m\u00f4n V\u1eadt L\u00fd \u0111\u01b0\u1ee3c t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n th\u1ee9 8 theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T, c\u00e1c em tham kh\u1ea3o \u0111\u1ec1 thi d\u01b0\u1edbi \u0111\u00e2y. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n<\/dd>\n<\/p>\n<\/p>\n<\/p>\n<\/p>\n<\/span>
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