\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 10 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n.<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 10<\/strong><\/span><\/p>\nCho bi\u1ebft: H\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10<\/p>\n
-34<\/dd>\nJ.s; \u0111\u1ed9 l\u1edbn \u0111i\u1ec7n t\u00edch nguy\u00ean t\u1ed1 e = 1,6.10<\/p>\n
-19<\/dd>\nC; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng trong ch\u00e2n kh\u00f4ng c = 3.10<\/p>\n
8<\/dd>\n\u00ad<\/dd>\n(m\/s); 1uc<\/p>\n
2<\/dd>\n= 931,5 MeV.<\/p>\n
C\u00e2u 1: (ID: 89749 )<\/strong>Ba b\u1ea1n Vi\u1ec7t, Nam, H\u00e0 c\u00f9ng ng\u1ed3i xem ch\u01b0\u01a1ng tr\u00ecnh truy\u1ec1n h\u00ecnh tr\u1ef1c ti\u1ebfp \u201c H\u00e1t v\u1ec1 bi\u1ec3n \u0111\u1ea3o qu\u00ea h\u01b0\u01a1ng\u201d. B\u1ea1n Vi\u1ec7t v\u00e0 Nam xem tr\u1ef1c ti\u1ebfp t\u1ea1i tr\u01b0\u1eddng quay c\u1ee7a \u0111\u00e0i truy\u1ec1n h\u00ecnh Vi\u1ec7t Nam, Vi\u1ec7t ng\u1ed3i c\u00e1ch loa 30m, Nam ng\u1ed3i c\u00e1ch loa 40m, H\u00e0 \u1edf Ba v\u00ec ng\u1ed3i c\u1ea1nh ti vi xem ch\u01b0\u01a1ng tr\u00ecnh qua ti vi . Th\u1ee9 t\u1ef1 c\u00e1c b\u1ea1n nghe \u0111\u01b0\u1ee3c \u00e2m thanh tr\u01b0\u1edbc l\u00e0:<\/p>\nA.<\/strong>Vi\u1ec7t, Nam, H\u00e0 B.<\/strong>Nam, Vi\u1ec7t , H\u00e0 C.<\/strong>H\u00e0, Vi\u1ec7t , Nam D.<\/strong>H\u00e0, Nam, Vi\u1ec7t<\/p>\nC\u00e2u 2: (ID: 89750)<\/strong> M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a . \u0110\u1ed9 l\u1edbn gia t\u1ed1c c\u1ee7a n\u00f3 t\u1ea1i v\u1ecb tr\u00ed bi\u00ean l\u00e0 2m\/s<\/p>\n2<\/dd>\n. Khi \u0111i qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng t\u1ed1c \u0111\u1ed9 c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0 40cm\/s. Bi\u00ean \u0111\u1ed9 dao \u0111\u00f4ng c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0:<\/p>\n
A.<\/strong>0,8m B.<\/strong>5cm C.<\/strong>8cm D.<\/strong>4cm<\/p>\nC\u00e2u 3: (ID: 89751)<\/strong> Khi n\u00f3i v\u1ec1 s\u00f3ng c\u01a1 h\u1ecdc ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0sai<\/em><\/strong>?<\/p>\nA.<\/strong>S\u00f3ng c\u01a1 h\u1ecdc lan truy\u1ec1n tr\u00ean m\u1eb7t n\u01b0\u1edbc l\u00e0 s\u00f3ng ngang.<\/p>\nB.<\/strong>S\u00f3ng c\u01a1 h\u1ecdc truy\u1ec1n \u0111\u01b0\u1ee3c trong t\u1ea5t c\u1ea3 c\u00e1c m\u00f4i tr\u01b0\u1eddng r\u1eafn, l\u1ecfng, kh\u00ed v\u00e0 ch\u00e2n kh\u00f4ng.<\/p>\nC.<\/strong>S\u00f3ng c\u01a1 l\u00e0 s\u1ef1 lan truy\u1ec1n dao \u0111\u1ed9ng c\u01a1 trong m\u00f4i tr\u01b0\u1eddng v\u1eadt ch\u1ea5t.<\/p>\nD.<\/strong>S\u00f3ng \u00e2m truy\u1ec1n trong kh\u00f4ng kh\u00ed l\u00e0 s\u00f3ng d\u1ecdc<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/101.png\")
<\/p>\n
C\u00e2u 6:<\/strong>(ID: 89754)<\/strong>Nguy\u00ean t\u1eed hydro \u1edf tr\u1ea1ng th\u00e1i d\u1eebng c\u00f3 m\u1ee9c n\u0103ng l\u01b0\u1ee3ng th\u1ee9 n tu\u00e2n theo c\u00f4ng th\u1ee9c .<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/102.png\")
Nguy\u00ean t\u1eed \u0111ang \u1edf tr\u1ea1ng th\u00e1i k\u00edch th\u00edch th\u1ee9 nh\u1ea5t. K\u00edch th\u00edch nguy\u00ean t\u1eed \u0111\u1ebfn tr\u1ea1ng th\u00e1i m\u00e0 \u0111\u1ed9ng n\u0103ng c\u1ee7a electron gi\u1ea3m \u0111i 9 l\u1ea7n. T\u1ec9 s\u1ed1 gi\u1eefa b\u01b0\u1edbc s\u00f3ng l\u1edbn nh\u1ea5t v\u00e0 b\u01b0\u1edbc s\u00f3ng \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y nh\u1ecf nh\u1ea5t m\u00e0 nguy\u00ean t\u1eed n\u00e0y c\u00f3 th\u1ec3 ph\u00e1t rag\u1ea7n \u0111\u00fang<\/strong>b\u1eb1ng:<\/p>\nA.<\/strong>33,4 B.<\/strong>0,0023 C.<\/strong>0,055 D.<\/strong>18,2<\/p>\nC\u00e2u 7: (ID: 89755)<\/strong> Trong dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0:<\/p>\nA.<\/strong>v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c lu\u00f4n ng\u01b0\u1ee3c chi\u1ec1u B.<\/strong>gia t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n ng\u01b0\u1ee3c d\u1ea5u<\/p>\nC.<\/strong>v\u1eadn t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n c\u00f9ng d\u1ea5u D.<\/strong>gia t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n c\u00f9ng d\u1ea5u<\/p>\nC\u00e2u 8:<\/strong>(ID: 89756)<\/strong>\u0110\u1ed3 th\u1ecb v\u1eadn t\u1ed1c c\u1ee7a m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 d\u1ea1ng nh\u01b0 h\u00ecnh v\u1ebd. L\u1ea5y . Ph\u01b0\u01a1ng tr\u00ecnh li \u0111\u1ed9 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt n\u1eb7ng l\u00e0:<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/103.png\")
<\/p>\n
C\u00e2u 9:<\/strong>(ID: 89757)<\/strong>Trong m\u1ed9t m\u1ea1ch dao \u0111\u1ed9ng, \u0111i\u1ec7n t\u00edch c\u1ee7a t\u1ee5 \u0111i\u1ec7n bi\u1ebfn thi\u00ean theo quy lu\u1eadt:<\/p>\nq = 2,5.10<\/p>\n
-6<\/dd>\ncos(2.10<\/p>\n
3<\/dd>\nt)(C). C\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n hi\u1ec7u d\u1ee5ng qua cu\u1ed9n d\u00e2y l\u00e0:<\/p>\n
![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/104.png\")
<\/p>\n
![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/105.png\")
<\/p>\n
C\u00e2u 13:<\/strong>(ID: 89761)<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 tr\u00ean qu\u1ef9 \u0111\u1ea1o d\u00e0i 10cm. Sau 0,5s k\u1ec3 t\u1eeb th\u1eddi \u0111i\u1ec3m ban \u0111\u1ea7u v\u1eadt \u0111i \u0111\u01b0\u1ee3c 5cm m\u00e0 ch\u01b0a \u0111\u1ed5i chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng v\u00e0 v\u1eadt \u0111\u1ebfn v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 2,5cm. T\u1ea7n s\u1ed1 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0:<\/span><\/p>\nA.<\/strong>0,5 Hz B.<\/strong>3 Hz C.<\/strong>1\/3 Hz D.<\/strong>1 Hz<\/p>\nC\u00e2u 14: (ID: 89762)<\/strong> Trong th\u00ed nghi\u1ec7m Young v\u1ec1 giao thoa \u00e1nh s\u00e1ng v\u1edbi \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb, kho\u1ea3ng c\u00e1ch hai khe a = 1 mm. V\u00e2n giao thoa \u0111\u01b0\u1ee3c nh\u00ecn qua m\u1ed9t k\u00ednh l\u00fap c\u00f3 ti\u00eau c\u1ef1 5 cm \u0111\u1eb7t c\u00e1ch m\u1eb7t ph\u1eb3ng hai khe m\u1ed9t kho\u1ea3ng L = 55 cm. M\u1ed9t ng\u01b0\u1eddi c\u00f3 m\u1eaft b\u00ecnh th\u01b0\u1eddng \u0111\u1eb7t m\u1eaft s\u00e1t k\u00ednh l\u00fap v\u00e0 quan s\u00e1t h\u1ec7 v\u00e2n trong tr\u1ea1ng th\u00e1i kh\u00f4ng \u0111i\u1ec1u ti\u1ebft th\u00ec th\u1ea5y g\u00f3c tr\u00f4ng kho\u1ea3ng v\u00e2n l\u00e0 0,006rad . B\u01b0\u1edbc s\u00f3ng \u03bb c\u1ee7a \u00e1nh s\u00e1ng l\u00e0<\/span><\/p>\nA.<\/strong>0,58 \u00b5m B.<\/strong>0,5 \u00b5m C.<\/strong>0,6 \u00b5m D.<\/strong>0,55 \u00b5m<\/p>\nC\u00e2u 15:<\/strong>(ID: 89763)<\/strong>Hai ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 tr\u00ean c\u00f9ng m\u1ed9t tr\u1ee5c t\u1ecda \u0111\u1ed9 0x, coi trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng ch\u00fang<\/p>\n kh\u00f4ng va ch\u1ea1m v\u00e0o nhau. Bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a hai ch\u1ea5t \u0111i\u1ec3m l\u1ea7n l\u01b0\u1ee3t l\u00e0: <\/p>\n
![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/106.png\")
<\/span><\/strong><\/span>(Th\u1eddi gian t\u00ednh b\u1eb1ng s). Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng, hai ch\u1ea5t \u0111i\u1ec3m c\u00e1ch nhau 2,5 cm l\u1ea7n th\u1ee9 2013 v\u00e0o th\u1eddi \u0111i\u1ec3m:<\/span><\/p>\nA.<\/strong>1006,25 s B.<\/strong>503,25 s C.<\/strong>2012,5 s D.<\/strong>503,5 s<\/p>\nC\u00e2u 16: (ID: 89764)<\/strong> Hai ngu\u1ed3n s\u00f3ng k\u1ebft h\u1ee3p A, B tr\u00ean m\u1eb7t tho\u00e1ng ch\u1ea5t l\u1ecfng dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh Coi bi\u00ean \u0111\u1ed9 s\u00f3ng kh\u00f4ng \u0111\u1ed5i, t\u1ed1c \u0111\u1ed9 s\u00f3ng . Hai \u0111i\u1ec3m c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t elip nh\u1eadn A, B l\u00e0m ti\u00eau \u0111i\u1ec3m c\u00f3 v\u00e0 T\u1ea1i th\u1eddi \u0111i\u1ec3m v\u1eadn t\u1ed1c c\u1ee7a M<\/p>\n1<\/dd>\nl\u00e0 30mm\/s th\u00ec v\u1eadn t\u1ed1c c\u1ee7a M<\/p>\n
2<\/dd>\nt\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111\u00f3 l\u00e0:<\/p>\n
![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/107.png\")
<\/p>\n
C\u00e2u 17:<\/strong>(ID: 89765)<\/strong>M\u1ea1ch dao \u0111\u1ed9ng l\u00ed t\u01b0\u1edfng g\u1ed3m cu\u1ed9n d\u00e2y c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m L = 0,2H v\u00e0 t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C = 20mF. Ng\u01b0\u1eddi ta t\u00edch \u0111i\u1ec7n cho t\u1ee5 \u0111i\u1ec7n \u0111\u1ebfn hi\u1ec7u \u0111i\u1ec7n th\u1ebf c\u1ef1c \u0111\u1ea1i U<\/p>\n0<\/dd>\n= 4V. Ch\u1ecdn th\u1eddi \u0111i\u1ec3m ban \u0111\u1ea7u (t = 0) l\u00e0 l\u00fac t\u1ee5 \u0111i\u1ec7n b\u1eaft \u0111\u1ea7u ph\u00f3ng \u0111i\u1ec7n. T\u00ednh n\u0103ng l\u01b0\u1ee3ng \u0111i\u1ec7n tr\u01b0\u1eddng t\u1ea1i th\u1eddi \u0111i\u1ec3m T\/8, T l\u00e0 chu k\u00ec dao \u0111\u1ed9ng.Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang:<\/p>\n
A.<\/strong>40mJ B.<\/strong>160mJ C.<\/strong>80mJ D.<\/strong>120mJ<\/p>\nC\u00e2u 18:<\/strong>H(ID: 89766)<\/strong>ai ngu\u1ed3n k\u1ebft h\u1ee3p O<\/p>\n1<\/dd>\n; O<\/p>\n
2<\/dd>\nc\u00f9ng pha, c\u00f9ng bi\u00ean \u0111\u1ed9, c\u00e1ch nhau 40cm. Kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111i\u1ec3m c\u00f3 bi\u00ean \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i g\u1ea7n nhau nh\u1ea5t tr\u00ean \u0111o\u1ea1n O<\/p>\n
1<\/dd>\nO<\/p>\n
2<\/dd>\nl\u00e0 0,8cm. \u0110i\u1ec3m M thu\u1ed9c mi\u1ec1n giao thoa c\u00e1ch O<\/p>\n
1<\/dd>\nm\u1ed9t \u0111o\u1ea1n 25 cm, c\u00e1ch O<\/p>\n
2<\/dd>\nm\u1ed9t \u0111o\u1ea1n 22 cm . D\u1ecbch chuy\u1ec3n ngu\u1ed3n O<\/p>\n
2<\/dd>\nt\u1eeb t\u1eeb d\u1ecdc theo ph\u01b0\u01a1ng O<\/p>\n
1<\/dd>\nO<\/p>\n
2<\/dd>\nra xa ngu\u1ed3n O<\/p>\n
2<\/dd>\nm\u1ed9t \u0111o\u1ea1n 10cm th\u00ec s\u1ed1 l\u1ea7n \u0111i\u1ec3m M chuy\u1ec3n th\u00e0nh \u0111i\u1ec3m c\u00f3 bi\u00ean \u0111\u1ed9 c\u1ef1c ti\u1ec3u l\u00e0:<\/p>\n
A.<\/strong>8 B.<\/strong>6 C.<\/strong>5 D.<\/strong>7<\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/108.png\")
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\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1 10<\/strong><\/p>\n![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1109\/109.png\")
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<\/strong><\/p>\n<\/p>\nT\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 10 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd 2016 - \u0110\u1ec1 s\u1ed1 10<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-thi-thu-thpt-quoc-gia-mon-vat-ly-2016-de-so-10\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd 2016 - \u0110\u1ec1 s\u1ed1 10\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 10 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n. 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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 10<\/strong><\/span><\/p>\n Cho bi\u1ebft: H\u1eb1ng s\u1ed1 Pl\u0103ng h = 6,625.10<\/p>\n J.s; \u0111\u1ed9 l\u1edbn \u0111i\u1ec7n t\u00edch nguy\u00ean t\u1ed1 e = 1,6.10<\/p>\n C; t\u1ed1c \u0111\u1ed9 \u00e1nh s\u00e1ng trong ch\u00e2n kh\u00f4ng c = 3.10<\/p>\n (m\/s); 1uc<\/p>\n = 931,5 MeV.<\/p>\n C\u00e2u 1: (ID: 89749 )<\/strong>Ba b\u1ea1n Vi\u1ec7t, Nam, H\u00e0 c\u00f9ng ng\u1ed3i xem ch\u01b0\u01a1ng tr\u00ecnh truy\u1ec1n h\u00ecnh tr\u1ef1c ti\u1ebfp \u201c H\u00e1t v\u1ec1 bi\u1ec3n \u0111\u1ea3o qu\u00ea h\u01b0\u01a1ng\u201d. B\u1ea1n Vi\u1ec7t v\u00e0 Nam xem tr\u1ef1c ti\u1ebfp t\u1ea1i tr\u01b0\u1eddng quay c\u1ee7a \u0111\u00e0i truy\u1ec1n h\u00ecnh Vi\u1ec7t Nam, Vi\u1ec7t ng\u1ed3i c\u00e1ch loa 30m, Nam ng\u1ed3i c\u00e1ch loa 40m, H\u00e0 \u1edf Ba v\u00ec ng\u1ed3i c\u1ea1nh ti vi xem ch\u01b0\u01a1ng tr\u00ecnh qua ti vi . Th\u1ee9 t\u1ef1 c\u00e1c b\u1ea1n nghe \u0111\u01b0\u1ee3c \u00e2m thanh tr\u01b0\u1edbc l\u00e0:<\/p>\n A.<\/strong>Vi\u1ec7t, Nam, H\u00e0 B.<\/strong>Nam, Vi\u1ec7t , H\u00e0 C.<\/strong>H\u00e0, Vi\u1ec7t , Nam D.<\/strong>H\u00e0, Nam, Vi\u1ec7t<\/p>\n C\u00e2u 2: (ID: 89750)<\/strong> M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a . \u0110\u1ed9 l\u1edbn gia t\u1ed1c c\u1ee7a n\u00f3 t\u1ea1i v\u1ecb tr\u00ed bi\u00ean l\u00e0 2m\/s<\/p>\n . Khi \u0111i qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng t\u1ed1c \u0111\u1ed9 c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0 40cm\/s. Bi\u00ean \u0111\u1ed9 dao \u0111\u00f4ng c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0:<\/p>\n A.<\/strong>0,8m B.<\/strong>5cm C.<\/strong>8cm D.<\/strong>4cm<\/p>\n C\u00e2u 3: (ID: 89751)<\/strong> Khi n\u00f3i v\u1ec1 s\u00f3ng c\u01a1 h\u1ecdc ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0sai<\/em><\/strong>?<\/p>\n A.<\/strong>S\u00f3ng c\u01a1 h\u1ecdc lan truy\u1ec1n tr\u00ean m\u1eb7t n\u01b0\u1edbc l\u00e0 s\u00f3ng ngang.<\/p>\n B.<\/strong>S\u00f3ng c\u01a1 h\u1ecdc truy\u1ec1n \u0111\u01b0\u1ee3c trong t\u1ea5t c\u1ea3 c\u00e1c m\u00f4i tr\u01b0\u1eddng r\u1eafn, l\u1ecfng, kh\u00ed v\u00e0 ch\u00e2n kh\u00f4ng.<\/p>\n C.<\/strong>S\u00f3ng c\u01a1 l\u00e0 s\u1ef1 lan truy\u1ec1n dao \u0111\u1ed9ng c\u01a1 trong m\u00f4i tr\u01b0\u1eddng v\u1eadt ch\u1ea5t.<\/p>\n D.<\/strong>S\u00f3ng \u00e2m truy\u1ec1n trong kh\u00f4ng kh\u00ed l\u00e0 s\u00f3ng d\u1ecdc<\/p>\n C\u00e2u 6:<\/strong>(ID: 89754)<\/strong>Nguy\u00ean t\u1eed hydro \u1edf tr\u1ea1ng th\u00e1i d\u1eebng c\u00f3 m\u1ee9c n\u0103ng l\u01b0\u1ee3ng th\u1ee9 n tu\u00e2n theo c\u00f4ng th\u1ee9c .<\/p>\n A.<\/strong>33,4 B.<\/strong>0,0023 C.<\/strong>0,055 D.<\/strong>18,2<\/p>\n C\u00e2u 7: (ID: 89755)<\/strong> Trong dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0:<\/p>\n A.<\/strong>v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c lu\u00f4n ng\u01b0\u1ee3c chi\u1ec1u B.<\/strong>gia t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n ng\u01b0\u1ee3c d\u1ea5u<\/p>\n C.<\/strong>v\u1eadn t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n c\u00f9ng d\u1ea5u D.<\/strong>gia t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n c\u00f9ng d\u1ea5u<\/p>\n C\u00e2u 8:<\/strong>(ID: 89756)<\/strong>\u0110\u1ed3 th\u1ecb v\u1eadn t\u1ed1c c\u1ee7a m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 d\u1ea1ng nh\u01b0 h\u00ecnh v\u1ebd. L\u1ea5y . Ph\u01b0\u01a1ng tr\u00ecnh li \u0111\u1ed9 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt n\u1eb7ng l\u00e0:<\/p>\n C\u00e2u 9:<\/strong>(ID: 89757)<\/strong>Trong m\u1ed9t m\u1ea1ch dao \u0111\u1ed9ng, \u0111i\u1ec7n t\u00edch c\u1ee7a t\u1ee5 \u0111i\u1ec7n bi\u1ebfn thi\u00ean theo quy lu\u1eadt:<\/p>\n q = 2,5.10<\/p>\n cos(2.10<\/p>\n t)(C). C\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n hi\u1ec7u d\u1ee5ng qua cu\u1ed9n d\u00e2y l\u00e0:<\/p>\n C\u00e2u 13:<\/strong>(ID: 89761)<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 tr\u00ean qu\u1ef9 \u0111\u1ea1o d\u00e0i 10cm. Sau 0,5s k\u1ec3 t\u1eeb th\u1eddi \u0111i\u1ec3m ban \u0111\u1ea7u v\u1eadt \u0111i \u0111\u01b0\u1ee3c 5cm m\u00e0 ch\u01b0a \u0111\u1ed5i chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng v\u00e0 v\u1eadt \u0111\u1ebfn v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 2,5cm. T\u1ea7n s\u1ed1 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0:<\/span><\/p>\n A.<\/strong>0,5 Hz B.<\/strong>3 Hz C.<\/strong>1\/3 Hz D.<\/strong>1 Hz<\/p>\n C\u00e2u 14: (ID: 89762)<\/strong> Trong th\u00ed nghi\u1ec7m Young v\u1ec1 giao thoa \u00e1nh s\u00e1ng v\u1edbi \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb, kho\u1ea3ng c\u00e1ch hai khe a = 1 mm. V\u00e2n giao thoa \u0111\u01b0\u1ee3c nh\u00ecn qua m\u1ed9t k\u00ednh l\u00fap c\u00f3 ti\u00eau c\u1ef1 5 cm \u0111\u1eb7t c\u00e1ch m\u1eb7t ph\u1eb3ng hai khe m\u1ed9t kho\u1ea3ng L = 55 cm. M\u1ed9t ng\u01b0\u1eddi c\u00f3 m\u1eaft b\u00ecnh th\u01b0\u1eddng \u0111\u1eb7t m\u1eaft s\u00e1t k\u00ednh l\u00fap v\u00e0 quan s\u00e1t h\u1ec7 v\u00e2n trong tr\u1ea1ng th\u00e1i kh\u00f4ng \u0111i\u1ec1u ti\u1ebft th\u00ec th\u1ea5y g\u00f3c tr\u00f4ng kho\u1ea3ng v\u00e2n l\u00e0 0,006rad . B\u01b0\u1edbc s\u00f3ng \u03bb c\u1ee7a \u00e1nh s\u00e1ng l\u00e0<\/span><\/p>\n A.<\/strong>0,58 \u00b5m B.<\/strong>0,5 \u00b5m C.<\/strong>0,6 \u00b5m D.<\/strong>0,55 \u00b5m<\/p>\n C\u00e2u 15:<\/strong>(ID: 89763)<\/strong>Hai ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 tr\u00ean c\u00f9ng m\u1ed9t tr\u1ee5c t\u1ecda \u0111\u1ed9 0x, coi trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng ch\u00fang<\/p>\n kh\u00f4ng va ch\u1ea1m v\u00e0o nhau. Bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a hai ch\u1ea5t \u0111i\u1ec3m l\u1ea7n l\u01b0\u1ee3t l\u00e0: <\/p>\n A.<\/strong>1006,25 s B.<\/strong>503,25 s C.<\/strong>2012,5 s D.<\/strong>503,5 s<\/p>\n C\u00e2u 16: (ID: 89764)<\/strong> Hai ngu\u1ed3n s\u00f3ng k\u1ebft h\u1ee3p A, B tr\u00ean m\u1eb7t tho\u00e1ng ch\u1ea5t l\u1ecfng dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh Coi bi\u00ean \u0111\u1ed9 s\u00f3ng kh\u00f4ng \u0111\u1ed5i, t\u1ed1c \u0111\u1ed9 s\u00f3ng . Hai \u0111i\u1ec3m c\u00f9ng n\u1eb1m tr\u00ean m\u1ed9t elip nh\u1eadn A, B l\u00e0m ti\u00eau \u0111i\u1ec3m c\u00f3 v\u00e0 T\u1ea1i th\u1eddi \u0111i\u1ec3m v\u1eadn t\u1ed1c c\u1ee7a M<\/p>\n l\u00e0 30mm\/s th\u00ec v\u1eadn t\u1ed1c c\u1ee7a M<\/p>\n t\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111\u00f3 l\u00e0:<\/p>\n C\u00e2u 17:<\/strong>(ID: 89765)<\/strong>M\u1ea1ch dao \u0111\u1ed9ng l\u00ed t\u01b0\u1edfng g\u1ed3m cu\u1ed9n d\u00e2y c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m L = 0,2H v\u00e0 t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C = 20mF. Ng\u01b0\u1eddi ta t\u00edch \u0111i\u1ec7n cho t\u1ee5 \u0111i\u1ec7n \u0111\u1ebfn hi\u1ec7u \u0111i\u1ec7n th\u1ebf c\u1ef1c \u0111\u1ea1i U<\/p>\n = 4V. Ch\u1ecdn th\u1eddi \u0111i\u1ec3m ban \u0111\u1ea7u (t = 0) l\u00e0 l\u00fac t\u1ee5 \u0111i\u1ec7n b\u1eaft \u0111\u1ea7u ph\u00f3ng \u0111i\u1ec7n. T\u00ednh n\u0103ng l\u01b0\u1ee3ng \u0111i\u1ec7n tr\u01b0\u1eddng t\u1ea1i th\u1eddi \u0111i\u1ec3m T\/8, T l\u00e0 chu k\u00ec dao \u0111\u1ed9ng.Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang:<\/p>\n A.<\/strong>40mJ B.<\/strong>160mJ C.<\/strong>80mJ D.<\/strong>120mJ<\/p>\n C\u00e2u 18:<\/strong>H(ID: 89766)<\/strong>ai ngu\u1ed3n k\u1ebft h\u1ee3p O<\/p>\n ; O<\/p>\n c\u00f9ng pha, c\u00f9ng bi\u00ean \u0111\u1ed9, c\u00e1ch nhau 40cm. Kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111i\u1ec3m c\u00f3 bi\u00ean \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i g\u1ea7n nhau nh\u1ea5t tr\u00ean \u0111o\u1ea1n O<\/p>\n O<\/p>\n l\u00e0 0,8cm. \u0110i\u1ec3m M thu\u1ed9c mi\u1ec1n giao thoa c\u00e1ch O<\/p>\n m\u1ed9t \u0111o\u1ea1n 25 cm, c\u00e1ch O<\/p>\n m\u1ed9t \u0111o\u1ea1n 22 cm . D\u1ecbch chuy\u1ec3n ngu\u1ed3n O<\/p>\n t\u1eeb t\u1eeb d\u1ecdc theo ph\u01b0\u01a1ng O<\/p>\n O<\/p>\n ra xa ngu\u1ed3n O<\/p>\n m\u1ed9t \u0111o\u1ea1n 10cm th\u00ec s\u1ed1 l\u1ea7n \u0111i\u1ec3m M chuy\u1ec3n th\u00e0nh \u0111i\u1ec3m c\u00f3 bi\u00ean \u0111\u1ed9 c\u1ef1c ti\u1ec3u l\u00e0:<\/p>\n A.<\/strong>8 B.<\/strong>6 C.<\/strong>5 D.<\/strong>7<\/p>\n \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt L\u00fd n\u0103m 2016- \u0110\u1ec1 s\u1ed1 10<\/strong><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n V\u1eadt l\u00fd n\u0103m 2016 – \u0111\u1ec1 thi th\u1eed s\u1ed1 10 g\u1ed3m c\u00f3 50 c\u00e2u theo c\u1ea5u tr\u00fac m\u1edbi nh\u1ea5t c\u1ee7a B\u1ed9 GD&\u0110T c\u00f3 \u0111\u00e1p \u00e1n v\u00e0 l\u1eddi gi\u1ea3i chi ti\u1ebft gi\u00fap c\u00e1c em \u00f4n luy\u1ec7n t\u1ed1t h\u01a1n. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd \u0110\u1ec1 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n<\/p>\n Nguy\u00ean t\u1eed \u0111ang \u1edf tr\u1ea1ng th\u00e1i k\u00edch th\u00edch th\u1ee9 nh\u1ea5t. K\u00edch th\u00edch nguy\u00ean t\u1eed \u0111\u1ebfn tr\u1ea1ng th\u00e1i m\u00e0 \u0111\u1ed9ng n\u0103ng c\u1ee7a electron gi\u1ea3m \u0111i 9 l\u1ea7n. T\u1ec9 s\u1ed1 gi\u1eefa b\u01b0\u1edbc s\u00f3ng l\u1edbn nh\u1ea5t v\u00e0 b\u01b0\u1edbc s\u00f3ng \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y nh\u1ecf nh\u1ea5t m\u00e0 nguy\u00ean t\u1eed n\u00e0y c\u00f3 th\u1ec3 ph\u00e1t rag\u1ea7n \u0111\u00fang<\/strong>b\u1eb1ng:<\/p>\n<\/p>\n<\/p>\n<\/p>\n <\/span><\/strong><\/span>(Th\u1eddi gian t\u00ednh b\u1eb1ng s). Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng, hai ch\u1ea5t \u0111i\u1ec3m c\u00e1ch nhau 2,5 cm l\u1ea7n th\u1ee9 2013 v\u00e0o th\u1eddi \u0111i\u1ec3m:<\/span><\/p>\n<\/p>\n<\/p>\n
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