\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd c\u1ee7a tr\u01b0\u1eddng THPT H\u00e0n Thuy\u00ean, t\u1ec9nh B\u1eafc Ninh t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 1 n\u0103m 2016 c\u00f3 \u0111\u00e1p \u00e1n nh\u01b0 sau:<\/strong><\/h2>\n\nXem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
C\u00e2u 1:<\/strong>T\u1eeb th\u00f4ng qua m\u1ed9t v\u00f2ng d\u00e2y d\u1eabn l\u00e0 \u03a6 = [(2.10-2)\/ \u03c0] cos ( 100 \u03c0 t + \u03c0\/4 )(Wb) Bi\u1ec3u th\u1ee9c c\u1ee7a su\u1ea5t \u0111i\u1ec7n \u0111\u1ed9ng c\u1ea3m \u1ee9ng xu\u1ea5t hi\u1ec7n trong v\u00f2ng d\u00e2y n\u00e0y l\u00e0<\/p>\nA. e = 2cos(100 \u03c0 t – \u03c0 \/2(V) B. e = 2cos (100 \u03c0 t \u2013 \u03c0\/4) (V) .<\/p>\n
C. e = 2cos(100 \u03c0 t + \u03c0 \/2(V). D. e = e = 2cos(100 \u03c0 t + \u03c0 \/4)(V)<\/p>\n
C\u00e2u 2:<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u1ef3 T th\u00ec pha c\u1ee7a dao \u0111\u1ed9ng<\/p>\nA. Bi\u1ebfn thi\u00ean \u0111i\u1ec1u h\u00f2a theo th\u1eddi gian. B. L\u00e0 h\u00e0m b\u1eadc nh\u1ea5t v\u1edbi th\u1eddi gian.<\/p>\n
C. Kh\u00f4ng \u0111\u1ed5i theo th\u1eddi gian. D. L\u00e0 h\u00e0m b\u1eadc hai c\u1ee7a th\u1eddi<\/p>\n
C\u00e2u 3:<\/strong>Khi n\u00f3i v\u1ec1 s\u00f3ng \u0111i\u1ec7n t\u1eeb, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 sai?<\/p>\nA. S\u00f3ng \u0111i\u1ec7n t\u1eeb kh\u00f4ng truy\u1ec1n \u0111\u01b0\u1ee3c trong ch\u00e2n kh\u00f4ng<\/p>\n
B. S\u00f3ng \u0111i\u1ec7n t\u1eeb l\u00e0 s\u00f3ng ngang<\/p>\n
C. S\u00f3ng \u0111i\u1ec7n t\u1eeb mang n\u0103ng l\u01b0\u1ee3ng.<\/p>\n
D. S\u00f3ng \u0111i\u1ec7n t\u1eeb tu\u00e2n theo c\u00e1c quy lu\u1eadt giao thoa, nhi\u1ec5u x\u1ea1.<\/p>\n
C\u00e2u 4: Trong m\u1ea1ch dao \u0111\u1ed9ng LC kh\u00f4ng c\u00f3 \u0111i\u1ec7n tr\u1edf thu\u1ea7n, t\u1ed3n t\u1ea1i m\u1ed9t dao \u0111\u1ed9ng \u0111i\u1ec7n t\u1eeb t\u1ef1 do. \u0110i\u1ec7n \u00e1p c\u1ef1c \u0111\u1ea1i v\u00e0 c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n c\u1ef1c \u0111\u1ea1i qua m\u1ea1ch l\u1ea7n l\u01b0\u1ee3t l\u00e0 U<\/p>\n
0<\/dd>\nv\u00e0 I<\/p>\n
0<\/dd>\n. T\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111i\u1ec7n \u00e1p gi\u1eefa hai b\u1ea3n t\u1ee5 \u0111i\u1ec7n l\u00e0 U<\/p>\n
0<\/dd>\n\/\u221a3 th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua m\u1ea1ch l\u00e0<\/p>\n
![](\"http:\/\/img.toanhoc247.com\/picture\/2015\/1227\/de-thi-thu-thptqg-ly-han-thuyen-2016-lan-1.png\")
<\/p>\n
\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd 2016 – THPT H\u00e0n Thuy\u00ean<\/span><\/strong><\/h3>\n\n\n\n\n\n<\/dd>\n\n\nC\u00e2u<\/strong><\/td>\n\u0110\u00e1p \u00e1n<\/strong><\/td>\nC\u00e2u<\/strong><\/td>\n\u0110\u00e1p \u00e1n<\/strong><\/td>\n<\/tr>\n\n1<\/td>\n B<\/td>\n 26<\/td>\n D<\/td>\n<\/tr>\n \n2<\/td>\n B<\/td>\n 27<\/td>\n A<\/td>\n<\/tr>\n \n3<\/td>\n A<\/td>\n 28<\/td>\n B<\/td>\n<\/tr>\n \n4<\/td>\n C<\/td>\n 29<\/td>\n C<\/td>\n<\/tr>\n \n5<\/td>\n D<\/td>\n 30<\/td>\n A<\/td>\n<\/tr>\n \n6<\/td>\n B<\/td>\n 31<\/td>\n D<\/td>\n<\/tr>\n \n7<\/td>\n D<\/td>\n 32<\/td>\n C<\/td>\n<\/tr>\n \n8<\/td>\n A<\/td>\n 33<\/td>\n C<\/td>\n<\/tr>\n \n9<\/td>\n A<\/td>\n 34<\/td>\n B<\/td>\n<\/tr>\n \n10<\/td>\n C<\/td>\n 35<\/td>\n B<\/td>\n<\/tr>\n \n11<\/td>\n C<\/td>\n 36<\/td>\n D<\/td>\n<\/tr>\n \n12<\/td>\n C<\/td>\n 37<\/td>\n C<\/td>\n<\/tr>\n \n13<\/td>\n A<\/td>\n 38<\/td>\n D<\/td>\n<\/tr>\n \n14<\/td>\n A<\/td>\n 39<\/td>\n C<\/td>\n<\/tr>\n \n15<\/td>\n C<\/td>\n 40<\/td>\n A<\/td>\n<\/tr>\n \n16<\/td>\n D<\/td>\n 41<\/td>\n C<\/td>\n<\/tr>\n \n17<\/td>\n C<\/td>\n 42<\/td>\n B<\/td>\n<\/tr>\n \n18<\/td>\n A<\/td>\n 43<\/td>\n B<\/td>\n<\/tr>\n \n19<\/td>\n D<\/td>\n 44<\/td>\n D<\/td>\n<\/tr>\n \n20<\/td>\n B<\/td>\n 45<\/td>\n D<\/td>\n<\/tr>\n \n21<\/td>\n D<\/td>\n 46<\/td>\n B<\/td>\n<\/tr>\n \n22<\/td>\n A<\/td>\n 47<\/td>\n A<\/td>\n<\/tr>\n \n23<\/td>\n B<\/td>\n 48<\/td>\n C<\/td>\n<\/tr>\n \n24<\/td>\n B<\/td>\n 49<\/td>\n B<\/td>\n<\/tr>\n \n25<\/td>\n D<\/td>\n 50<\/td>\n C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/strong><\/p>\nT\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":"\u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd c\u1ee7a tr\u01b0\u1eddng THPT H\u00e0n Thuy\u00ean, t\u1ec9nh B\u1eafc Ninh t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 1 n\u0103m 2016 c\u00f3 \u0111\u00e1p \u00e1n nh\u01b0 sau: Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd C\u00e2u 1:T\u1eeb th\u00f4ng qua m\u1ed9t v\u00f2ng d\u00e2y d\u1eabn l\u00e0 \u03a6 = [(2.10-2)\/ \u03c0] cos ( 100 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n
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Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd<\/p>\n<\/div>\n
C\u00e2u 1:<\/strong>T\u1eeb th\u00f4ng qua m\u1ed9t v\u00f2ng d\u00e2y d\u1eabn l\u00e0 \u03a6 = [(2.10-2)\/ \u03c0] cos ( 100 \u03c0 t + \u03c0\/4 )(Wb) Bi\u1ec3u th\u1ee9c c\u1ee7a su\u1ea5t \u0111i\u1ec7n \u0111\u1ed9ng c\u1ea3m \u1ee9ng xu\u1ea5t hi\u1ec7n trong v\u00f2ng d\u00e2y n\u00e0y l\u00e0<\/p>\n A. e = 2cos(100 \u03c0 t – \u03c0 \/2(V) B. e = 2cos (100 \u03c0 t \u2013 \u03c0\/4) (V) .<\/p>\n C. e = 2cos(100 \u03c0 t + \u03c0 \/2(V). D. e = e = 2cos(100 \u03c0 t + \u03c0 \/4)(V)<\/p>\n C\u00e2u 2:<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u1ef3 T th\u00ec pha c\u1ee7a dao \u0111\u1ed9ng<\/p>\n A. Bi\u1ebfn thi\u00ean \u0111i\u1ec1u h\u00f2a theo th\u1eddi gian. B. L\u00e0 h\u00e0m b\u1eadc nh\u1ea5t v\u1edbi th\u1eddi gian.<\/p>\n C. Kh\u00f4ng \u0111\u1ed5i theo th\u1eddi gian. D. L\u00e0 h\u00e0m b\u1eadc hai c\u1ee7a th\u1eddi<\/p>\n C\u00e2u 3:<\/strong>Khi n\u00f3i v\u1ec1 s\u00f3ng \u0111i\u1ec7n t\u1eeb, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 sai?<\/p>\n A. S\u00f3ng \u0111i\u1ec7n t\u1eeb kh\u00f4ng truy\u1ec1n \u0111\u01b0\u1ee3c trong ch\u00e2n kh\u00f4ng<\/p>\n B. S\u00f3ng \u0111i\u1ec7n t\u1eeb l\u00e0 s\u00f3ng ngang<\/p>\n C. S\u00f3ng \u0111i\u1ec7n t\u1eeb mang n\u0103ng l\u01b0\u1ee3ng.<\/p>\n D. S\u00f3ng \u0111i\u1ec7n t\u1eeb tu\u00e2n theo c\u00e1c quy lu\u1eadt giao thoa, nhi\u1ec5u x\u1ea1.<\/p>\n C\u00e2u 4: Trong m\u1ea1ch dao \u0111\u1ed9ng LC kh\u00f4ng c\u00f3 \u0111i\u1ec7n tr\u1edf thu\u1ea7n, t\u1ed3n t\u1ea1i m\u1ed9t dao \u0111\u1ed9ng \u0111i\u1ec7n t\u1eeb t\u1ef1 do. \u0110i\u1ec7n \u00e1p c\u1ef1c \u0111\u1ea1i v\u00e0 c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n c\u1ef1c \u0111\u1ea1i qua m\u1ea1ch l\u1ea7n l\u01b0\u1ee3t l\u00e0 U<\/p>\n v\u00e0 I<\/p>\n . T\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111i\u1ec7n \u00e1p gi\u1eefa hai b\u1ea3n t\u1ee5 \u0111i\u1ec7n l\u00e0 U<\/p>\n \/\u221a3 th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua m\u1ea1ch l\u00e0<\/p>\n <\/strong><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd c\u1ee7a tr\u01b0\u1eddng THPT H\u00e0n Thuy\u00ean, t\u1ec9nh B\u1eafc Ninh t\u1ed5 ch\u1ee9c thi th\u1eed l\u1ea7n 1 n\u0103m 2016 c\u00f3 \u0111\u00e1p \u00e1n nh\u01b0 sau: Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd C\u00e2u 1:T\u1eeb th\u00f4ng qua m\u1ed9t v\u00f2ng d\u00e2y d\u1eabn l\u00e0 \u03a6 = [(2.10-2)\/ \u03c0] cos ( 100 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[25],"tags":[],"yoast_head":"\n<\/p>\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n L\u00fd 2016 – THPT H\u00e0n Thuy\u00ean<\/span><\/strong><\/h3>\n
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\n C\u00e2u<\/strong><\/td>\n \u0110\u00e1p \u00e1n<\/strong><\/td>\n C\u00e2u<\/strong><\/td>\n \u0110\u00e1p \u00e1n<\/strong><\/td>\n<\/tr>\n \n 1<\/td>\n B<\/td>\n 26<\/td>\n D<\/td>\n<\/tr>\n \n 2<\/td>\n B<\/td>\n 27<\/td>\n A<\/td>\n<\/tr>\n \n 3<\/td>\n A<\/td>\n 28<\/td>\n B<\/td>\n<\/tr>\n \n 4<\/td>\n C<\/td>\n 29<\/td>\n C<\/td>\n<\/tr>\n \n 5<\/td>\n D<\/td>\n 30<\/td>\n A<\/td>\n<\/tr>\n \n 6<\/td>\n B<\/td>\n 31<\/td>\n D<\/td>\n<\/tr>\n \n 7<\/td>\n D<\/td>\n 32<\/td>\n C<\/td>\n<\/tr>\n \n 8<\/td>\n A<\/td>\n 33<\/td>\n C<\/td>\n<\/tr>\n \n 9<\/td>\n A<\/td>\n 34<\/td>\n B<\/td>\n<\/tr>\n \n 10<\/td>\n C<\/td>\n 35<\/td>\n B<\/td>\n<\/tr>\n \n 11<\/td>\n C<\/td>\n 36<\/td>\n D<\/td>\n<\/tr>\n \n 12<\/td>\n C<\/td>\n 37<\/td>\n C<\/td>\n<\/tr>\n \n 13<\/td>\n A<\/td>\n 38<\/td>\n D<\/td>\n<\/tr>\n \n 14<\/td>\n A<\/td>\n 39<\/td>\n C<\/td>\n<\/tr>\n \n 15<\/td>\n C<\/td>\n 40<\/td>\n A<\/td>\n<\/tr>\n \n 16<\/td>\n D<\/td>\n 41<\/td>\n C<\/td>\n<\/tr>\n \n 17<\/td>\n C<\/td>\n 42<\/td>\n B<\/td>\n<\/tr>\n \n 18<\/td>\n A<\/td>\n 43<\/td>\n B<\/td>\n<\/tr>\n \n 19<\/td>\n D<\/td>\n 44<\/td>\n D<\/td>\n<\/tr>\n \n 20<\/td>\n B<\/td>\n 45<\/td>\n D<\/td>\n<\/tr>\n \n 21<\/td>\n D<\/td>\n 46<\/td>\n B<\/td>\n<\/tr>\n \n 22<\/td>\n A<\/td>\n 47<\/td>\n A<\/td>\n<\/tr>\n \n 23<\/td>\n B<\/td>\n 48<\/td>\n C<\/td>\n<\/tr>\n \n 24<\/td>\n B<\/td>\n 49<\/td>\n B<\/td>\n<\/tr>\n \n 25<\/td>\n D<\/td>\n 50<\/td>\n C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n