Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n<\/p>\n<\/div>\n
\u0110\u1ec0 THI THPT QU\u1ed0C GIA M\u00d4N TO\u00c1N N\u0102M 201<\/strong>6 \u2013 \u0110\u1ec0 S\u1ed0 4<\/strong><\/p>\n Th\u1eddi gian: 180 ph\u00fat<\/strong><\/p>\n C\u00e2u 1 (2\u0111)<\/strong>Cho h\u00e0m s\u1ed1y<\/em>=f<\/em>(x<\/em>) = –x<\/em><\/p>\n + 6x<\/em><\/p>\n \u2013 9x + 2 c\u00f3 \u0111\u1ed3 th\u1ecb l\u00e0 (C).<\/p>\n a, Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb (C) c\u1ee7a h\u00e0m s\u1ed1.<\/p>\n b, Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb (C) t\u1ea1i \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 th\u1ecfa m\u00e3nf\u201d<\/em>(x<\/em>) = 18<\/p>\n C\u00e2u 2 (1\u0111)<\/strong><\/p>\n a, Cho cosx = -3\/5, (\u03c0 < x < 3\u03c0\/2). T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a sin (x – \u03c0\/6)<\/p>\n <\/p>\n C\u00e2u 5 (1\u0111)<\/strong>Cho l\u0103ng tr\u1ee5 \u0111\u1ee9ng ABC.A\u2019B\u2019C\u2019 c\u00f3 \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c vu\u00f4ng t\u1ea1i A , BC = 2a, AB = a v\u00e0 m\u1eb7t b\u00ean BB\u2019C\u2019C l\u00e0 h\u00ecnh vu\u00f4ng . T\u00ednh theo a th\u1ec3 t\u00edch c\u1ee7a kh\u1ed1i l\u0103ng tr\u1ee5 ABC.A\u2019B\u2019C\u2019 v\u00e0 kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng AA\u2019, BC\u2019<\/p>\n C\u00e2u 6 (1\u0111)<\/strong>Trong m\u1eb7t ph\u1eb3ng v\u1edbi h\u1ec7 t\u1ecda \u0111\u1ed9 Oxy , cho h\u00ecnh vu\u00f4ng ABCD . Bi\u1ebft \u0111i\u1ec3m A c\u00f3 tung \u0111\u1ed9 d\u01b0\u01a1ng , \u0111\u01b0\u1eddng th\u1eb3ng AB c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh 3x + 4y \u2013 18 = 0, \u0111i\u1ec3m M (21\/4; -1) thu\u1ed9c c\u1ea1nh BC , \u0111\u01b0\u1eddng th\u1eb3ng AM c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng CD t\u1ea1i N th\u1ecfa m\u00e3n BM.DN = 25 .T\u00ecm t\u1ecda \u0111\u1ed9 c\u00e1c \u0111\u1ec9nh c\u1ee7a h\u00ecnh vu\u00f4ng ABCD .<\/p>\n <\/p>\n <\/strong><\/p>\n<\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia \u0111\u1ec1 s\u1ed1 4 n\u0103m 2016, \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt v\u00e0o th\u1ee9 s\u00e1u ng\u00e0y 2\/10\/2015. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n \u0110\u1ec0 THI THPT QU\u1ed0C GIA M\u00d4N TO\u00c1N N\u0102M 2016 \u2013 \u0110\u1ec0 S\u1ed0 4 Th\u1eddi gian: 180 ph\u00fat C\u00e2u 1 (2\u0111)Cho h\u00e0m s\u1ed1y=f(x) = –x […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[28],"tags":[],"yoast_head":"\n
<\/strong><\/p>\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n n\u0103m 2016 – \u0110\u1ec1 s\u1ed1 4<\/strong><\/h3>\n