Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n<\/p>\n<\/div>\n
C\u00e2u 6<\/strong> (1,0 \u0111i\u1ec3m<\/em>).<\/strong><\/p>\n Cho h\u00ecnh ch\u00f3pS.ABC<\/em> c\u00f3 \u0111\u00e1y ABC<\/em> l\u00e0 tam gi\u00e1c vu\u00f4ng t\u1ea1i B<\/em>, BA<\/em> = 3a<\/em>, BC<\/em> = 4a<\/em>v\u00e0 A<\/em>B<\/em> vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (S<\/em>BC<\/em>). Bi\u1ebft SB<\/em> = 2a\u221a3<\/em> v\u00e0 g\u00f3c SBC = 30 \u0111\u1ed9. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABC<\/em> v\u00e0 kho\u1ea3ng c\u00e1ch t\u1eeb \u0111i\u1ec3m B<\/em> \u0111\u1ebfn m\u1eb7t ph\u1eb3ng (SAC<\/em>) theo a<\/em>.<\/p>\n C\u00e2u 7<\/strong> (1,0 \u0111i\u1ec3m<\/em>).<\/strong><\/p>\n Trong m\u1eb7t ph\u1eb3ng v\u1edbi h\u1ec7 t\u1ecda \u0111\u1ed9 Oxy<\/em>, cho h\u00ecnh ch\u1eef nh\u1eadt ABCD<\/em> c\u00f3 \u0111i\u1ec3m C<\/em> thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng d: 2x + y + 5 = 0 v\u00e0 A<\/em>(4; 8). G\u1ecdi E<\/em> l\u00e0 \u0111i\u1ec3m \u0111\u1ed1i x\u1ee9ng v\u1edbi B<\/em> qua C<\/em>, F<\/em>(5; 4) l\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a B <\/em>tr\u00ean \u0111\u01b0\u1eddng th\u1eb3ng ED<\/em>. T\u00ecm t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m C<\/em> v\u00e0 t\u00ednh di\u1ec7n t\u00edch h\u00ecnh ch\u1eef nh\u1eadt ABCD<\/em>.<\/p>\n <\/p>\n <\/p>\n <\/em><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n n\u0103m 2016 – THPT Ng\u00f4 S\u0129 Li\u00ean, c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft, c\u00e1c em tham kh\u1ea3o d\u01b0\u1edbi \u0111\u00e2y: Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n C\u00e2u 6 (1,0 \u0111i\u1ec3m). Cho h\u00ecnh ch\u00f3pS.ABC c\u00f3 \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c vu\u00f4ng t\u1ea1i B, BA = 3a, BC = 4av\u00e0 AB vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (SBC). Bi\u1ebft SB = […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[28],"tags":[],"yoast_head":"\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n n\u0103m 2016 – THPT Ng\u00f4 S\u0129 Li\u00ean <\/h2>\n