Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n<\/p>\n<\/div>\n
C\u00e2u 2.<\/strong><\/strong>Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh l\u01b0\u1ee3ng gi\u00e1c cos2x + cos(x + \u03c0\/2) = 1 <\/p>\n C\u00e2u 5.<\/strong> Cho h\u00ecnh ch\u00f3p S.ABCD<\/em> c\u00f3 \u0111\u00e1y ABCD<\/em> l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt, SA = a\u221a3 v\u00e0 SA<\/em> vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng \u0111\u00e1y. Bi\u1ebft tam gi\u00e1c SAB<\/em> c\u00e2n v\u00e0 g\u00f3c gi\u1eefa SD<\/em> v\u1edbi m\u1eb7t \u0111\u00e1y b\u1eb1ng 30<\/p>\n .<\/p>\n a. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABCD<\/em> theo a<\/em>.<\/p>\n b. T\u00ednh kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng BD<\/em> v\u00e0 SC<\/em>.<\/p>\n C\u00e2u 6.<\/strong> Cho hi\u0300nh ch\u01b0\u0303 nh\u00e2\u0323t ABCD<\/em> co\u0301 A<\/em>(1;5), AB = 2BC v\u00e0 \u0111i\u00ea\u0309m C<\/em> thu\u00f4\u0323c \u0111\u01b0\u01a1\u0300ng th\u0103\u0309ng d: x + 3y + 7 = 0. Go\u0323i M<\/em> la\u0300 \u0111i\u00ea\u0309m n\u0103\u0300m tr\u00ean tia \u0111\u00f4\u0301i cu\u0309a tia CB<\/em>, N<\/em> la\u0300 hi\u0300nh chi\u00ea\u0301u vu\u00f4ng go\u0301c cu\u0309a B<\/em> tr\u00ean MD<\/em>. Ti\u0300m to\u0323a \u0111\u00f4\u0323 ca\u0301c \u0111i\u00ea\u0309m B<\/em> va\u0300 C<\/em> bi\u00ea\u0301t N(-5\/2; \u00bd)v\u00e0 \u0111i\u1ec3m B<\/em> c\u00f3 tung \u0111\u1ed9 nguy\u00ean.<\/p>\n <\/p>\n <\/strong><\/strong><\/p>\n <\/strong><\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u00e1p \u00e1n v\u00e0 \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n n\u0103m 2016 c\u1ee7a tr\u01b0\u1eddng THPT \u0110\u1ed9i C\u1ea5n c\u1ee7a t\u1ec9nh V\u0129nh Ph\u00fac thi th\u1eed l\u1ea7n 1. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n C\u00e2u 2.Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh l\u01b0\u1ee3ng gi\u00e1c cos2x + cos(x + \u03c0\/2) = 1 C\u00e2u 5. Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[28],"tags":[],"yoast_head":"\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n THPT \u0110\u1ed9i C\u1ea5n n\u0103m 2016 – L\u1ea7n 1<\/strong><\/h3>\n