Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n<\/p>\n<\/div>\n
\u0110\u1ec1 thi th\u1eed THPTQG m\u00f4n To\u00e1n n\u0103m 2016 – THPT Xu\u00e2n Tr\u01b0\u1eddng L\u1ea7n 1<\/strong><\/p>\n C\u00e2u 4 <\/strong>(1,0\u0111i\u1ec3m<\/em><\/strong>).<\/strong>Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh 2.4<\/p>\n <\/em>+ 6<\/p>\n <\/em>= 9<\/p>\n C\u00e2u 6 (1,0\u0111i\u1ec3m<\/em>).<\/strong>Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt. Tam gi\u00e1c SAB \u0111\u1ec1u v\u00e0 n\u1eb1m trong m\u1eb7t ph\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng \u0111\u00e1y (ABCD). Bi\u1ebft SD = 2a<\/em>\u221a3 v\u00e0 g\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng SC v\u1edbi m\u1eb7t ph\u1eb3ng (ABCD) b\u1eb1ng 30<\/p>\n . T\u00ednh theoa<\/em>th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABCD v\u00e0 kho\u1ea3ng c\u00e1ch t\u1eeb \u0111i\u1ec3m B \u0111\u1ebfn m\u1eb7t ph\u1eb3ng (SAC). <\/p>\n C\u00e2u 7 (1,0\u0111i\u1ec3m<\/em>).<\/strong>Trong m\u1eb7t ph\u1eb3ng v\u1edbi h\u1ec7 t\u1ecda \u0111\u1ed9 Oxy, cho h\u00ecnh ch\u1eef nh\u1eadt ABCD.G\u1ecdi M l\u00e0 \u0111i\u1ec3m \u0111\u1ed1i x\u1ee9ng c\u1ee7a B qua C v\u00e0 N l\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a B tr\u00ean MD.Tam gi\u00e1c BDM n\u1ed9i ti\u1ebfp \u0111\u01b0\u1eddng tr\u00f2n (T) c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh: (x<\/em>\u2013 4)<\/p>\n + (y<\/em>\u2013 1)<\/p>\n = 25. X\u00e1c \u0111\u1ecbnh t\u1ecda \u0111\u1ed9 c\u00e1c \u0111\u1ec9nh c\u1ee7a h\u00ecnh ch\u1eef nh\u1eadt ABCD bi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng CN l\u00e0: 3x<\/em>\u2013 4y<\/em>\u2013 17 = 0; \u0111\u01b0\u1eddng th\u1eb3ng BC \u0111i qua \u0111i\u1ec3m E(7;0) v\u00e0 \u0111i\u1ec3m M c\u00f3 tung \u0111\u1ed9 \u00e2m <\/p>\n <\/p>\n <\/strong><\/p>\n<\/p>\n T\u1ea5t c\u1ea3 n\u1ed9i dung b\u00e0i vi\u1ebft. C\u00e1c em h\u00e3y xem th\u00eam v\u00e0 t\u1ea3i file chi ti\u1ebft t\u1ea1i \u0111\u00e2y:<\/strong>Download<\/p>\n","protected":false},"excerpt":{"rendered":" \u0110\u1ec1 thi v\u00e0 \u0111\u00e1p \u00e1n m\u00f4n To\u00e1n thi th\u1eed l\u1ea7n 1 n\u0103m 2016 c\u1ee7a tr\u01b0\u1eddng THPT Xu\u00e2n Tr\u01b0\u1eddng, t\u1ec9nh Nam \u0110\u1ecbnh. Xem th\u00eam: \u0110\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia m\u00f4n To\u00e1n \u0110\u1ec1 thi th\u1eed THPTQG m\u00f4n To\u00e1n n\u0103m 2016 – THPT Xu\u00e2n Tr\u01b0\u1eddng L\u1ea7n 1 C\u00e2u 4 (1,0\u0111i\u1ec3m).Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh 2.4 x + 6 x = […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[28],"tags":[],"yoast_head":"\n\u0110\u00e1p \u00e1n \u0111\u1ec1 thi th\u1eed THPT Qu\u1ed1c gia 2016 m\u00f4n To\u00e1n THPT Xu\u00e2n Tr\u01b0\u1eddng L\u1ea7n 1<\/strong><\/h3>\n